Thanks a lot sir! I was literally very confused between morkonikov's and anti-morkonikov's! Now it's alright! Thanks a lot sir! 🙏🏻
@SCORPION898989 ай бұрын
Thankyou sir you teaching al the concept sshort and sweet
@vijaysiva20694 жыл бұрын
Thks sir now have more clarity on anti-mark rule
@srivathsanp19512 жыл бұрын
Hats off explanation sir Concept is now crystal clear
@coolvideos89384 жыл бұрын
Super explanation sir
@dr.balaschemistrybalanagak16324 жыл бұрын
Welcome , keep watching...
@manojmsd23043 жыл бұрын
Sir CH3-CHBr-CH3 is the secondary carbon so,this is more stable
@jeevabharathi16514 жыл бұрын
Superb work sir
@dr.balaschemistrybalanagak16324 жыл бұрын
Welcome...
@Mahitoomyluv4 жыл бұрын
Super explanation sir!!!!
@s.rajasekharansiva84413 жыл бұрын
Sir, so reaction with HBr undergoes both anti markovnikov and markovnikov's rule? and the deciding factor is organic peroxide ?
@dr.balaschemistrybalanagak16323 жыл бұрын
Yes
@rajeshwariathiyamaan59624 жыл бұрын
sir but in your previous markonikovs rule video you have mentioned that C-H carbon as 2degree but here you are explaining it as one degree.
@dr.balaschemistrybalanagak16324 жыл бұрын
No here I explained CH CARBON as two degree only... Stability of 2 degree free radical gives 1 degree product.... I think so now you got idea... All the best...
@tncubegamer67553 жыл бұрын
Sir how u r telling that is 1° and 2°.I KNOW what is it sir. But how calculated there sir
@dr.balaschemistrybalanagak16323 жыл бұрын
Functional group attached with the carbon .. noe this carbon is attached with one carbon it is 1 degree, if that carbon attached with 2 carbons on 2 sides then it is 2 degree... If the carbon attached with 3 carbon , 3 sides is 3 degree..
@tncubegamer67553 жыл бұрын
Sir both r attached to 2 carbon sir
@tncubegamer67553 жыл бұрын
Sir how u r selection that star carbon.in what perception u r selecting it sir
@dr.balaschemistrybalanagak16323 жыл бұрын
Free radical one dot is present in CH2 and one in CH..
@Sv-rz9oy2 жыл бұрын
sir since 2 degree carbon is stable, y br is attached to beta carbon?
@rah6644 Жыл бұрын
2 degree carbon is stable for free radical pa, so only Br leaves it and attacks other carbon so that the secondary carbon still has free radical
@asxwiney3 жыл бұрын
Sir keep doing sir... Plz very usefull.. ♥️
@dr.balaschemistrybalanagak16323 жыл бұрын
Yes pl check our playlist too..
@pravinkarthick752 жыл бұрын
Nalla nadathuringa sir Ana konjam sound ah pesunga sir my kind request
@dr.balaschemistrybalanagak16322 жыл бұрын
Ok
@durgas21654 жыл бұрын
Sir,why don't you do more videos on organic and physical chemistry?!
@dr.balaschemistrybalanagak16324 жыл бұрын
Yes I am doing videos in organic and physical chemistry... Now Haloalkane and Electrochemistry is going ...
@durgas21654 жыл бұрын
@@dr.balaschemistrybalanagak1632 ok sir🙂
@theja_ramesh_._83594 жыл бұрын
Thank u sir👍
@karthikakarthi92042 жыл бұрын
Sir electrophilic addition bimolecular explain pannuga sir plz
@dhanyaganesan11052 жыл бұрын
Sir..kadaisilae ch3ch2ch2br..andha br vandhu join aiduchu ok andha h epdi vandhu Anga vanchunu neenga solalayae
@mohamedfaaris28823 жыл бұрын
Sir 2degree carbon na ,it want to attach to 2carbon atom Thana then you wrote wrong sir
@dr.balaschemistrybalanagak16323 жыл бұрын
2 carbon attached to the alpha or star carbon .
@mohamedfaaris28823 жыл бұрын
@@dr.balaschemistrybalanagak1632 no sir at last step sir
@mohamedfaaris28823 жыл бұрын
Br attached carbon 2degree in first case Br attached carbon 1 degree in second case
@mohamedfaaris28823 жыл бұрын
Carbocations stability sir
@nandhithaanarayanan14213 жыл бұрын
5.40 how is 1- 2degree and 2 -1degree sir
@sangavai8933 жыл бұрын
CH3-CH2-CH2-BR 1 bromopropyl sir 🙄
@dr.balaschemistrybalanagak16323 жыл бұрын
1 bromo propane
@veeramuthud47084 жыл бұрын
Itha mattum konjom simple aa sollunga
@dr.balaschemistrybalanagak16324 жыл бұрын
In presence of peroxide, the negative entity adhavadhu Br- irukilaya Adhu double bondla enga hydrogen atom adhigama iruko anga join aidum... Yen na Adhu than more stable radical...