Applications of First Order Differential Equations - Mixing Concentrations 2

[@Mathispower4u]

Thank you for the message. There was one (300-t) that should have been 300+t. I annotated the correction. R2 should be 3/(300+t) because the amount of liquid in increasing by 1 gallon each minute since the inflow rate is higher than the outflow rate.

[@matthewrocky1888]

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[@zaynemaxwell5169]

@Matthew Rocky try Flixzone. You can find it by googling =)

[@bridgerzeke3694]

@Matthew Rocky I would suggest flixzone. Just search on google for it =)

[@robertsonjoshua87]

Thank you sir! You have no idea how much this helped!

[@ODogg870]

When integrating after multiplying the integrating factor through the equation, you do not need the additional dt on the left-hand side of the equation... It is understood that the derivative with respect to t, (d/dt), is the portion of the equation being integrated.

[@vvhead]

Thank You! This was very helpful for reviewing before an exam.

[@SkOSn123]

Thanks for the clear explanation. Subscribed and appreciation from Singapore :)

[@AhmadNAlshammariKU]

I just wanna thank you because I understand the modeling of first order differential equations.. I will appreciate it to do some problems for economic or finance ... because they kinda different.. and I don't get it thank you !!

[@kimbryanduenas]

If you substitute infinity to t, you will also get infinity because of the +2t. I think the differential equation should have a cap of 600 lbs since the liquid pumped in has aconcentration of 2lbs/gal. At time equals infinity, the tank would have overflowed and the overflowing mixture will have a concentration of 2lbs/gal.

[@AhmadNAlshammariKU]

Sir thanks for the video but i think you had a mistake it should've been (3/300-t) and thanks .. that was really helpful

[@danialdunson]

You need to make a playlist... your videos rarely come up on youtube recommended.

[@dv5855]

Excellent presentation. Thank you.

[@slamtoo4582]

i got the extra gallon added to the tank over time but why you replaced it with (t?) Thank you.

[@abal4lyf]

great explanation! Thanks

[@josecohen3121]

I really enjoyed your video thanks! just one quick question if you get a chance, right before you made an integrating factor couldnt you have just separated the equation? or is it was 8 + the rest of the right side it was non separable?

[@UnbornAssassin7]

It is not a seperable eqn

[@MsLouloulepou]

Thank you so much. It was very well-explained :)

[@neilrayno5437]

i dont understand why t (which is time) is added to 300 (which is a volume)

[@puravpatel0926]

the inflow rate is 4gal and outflow is 3gal so the net change in the tank is +1, over time there is more water coming in the tank than leaving. If the inflow was 3gal and outflow was 4gal then the net change in the tank would be -1, and eventually the tank would have no more water. Does that help?

[@ericoduroboateng5269]

Pls can u explain Hy u had 300+t

[@sebastianlopespereira1696]

im sorry around 7:40 you simplify your eqn, but im struggling to see how this is simplified.. to me it looks like a mistake .. but i could very well be wrong (Left hand side, 2nd line from the bottom) pls confirm

[@taylorlewis4197]

thank you.

[@Mathispower4u]

You are very welcome!

[@mahbubulhaque3137]

great............

[@sebastianlopespereira1696]

i think d/dt should be replaced with (d/dt)+(3/(300+t))... again good chance i could be wrong

[@Daan87423]

Gallons :(