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[@IFASMaths]

Dear Aspirants, Want to crack CSIR NET? Talk to Academic Expert: bit.ly/417WLLf Need help? Call @ 9172266888 Telegram: t.me/NET_GATE_SET_Maths_Discussion Instagram- instagram.com/csir_net_mathematical_science/ Facebook- facebook.com/IFASMaths/photos_by

[@parveensingh-wc9uf]

Sir live online course kab se start hoga ?

[@IFASMaths]

To get detailed free counselling session for CSIR NET Mathematics, you can fill the form 👉: bit.ly/417WLLf Need help? Call @ 9172266888

[@Nainagour-l1h]

Sir abstract algebra ke question ka answer Solution, since is the number of m.I. Of Z125 M= number of distinct prime divisor of 125=1 N= no of non unit of Z125 N=125-o(U(125)) =125-100 =25 Hence m+n=1+25 =26 is correct sir Thank you sir 🙏 radhe radhe 📚

[@IFASMaths]

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