The government should give grants for this , has helped me and thousands of others. Thank you for what you do and don't stop !
@AlleryChemistry Жыл бұрын
No problem, thanks for your kind words 😊
@salehasiddiqa221010 ай бұрын
I love all your videos so much, without them I would be failing chemistry. My teacher can not teach at all so your videos are my only source of explanations
@niaxverse Жыл бұрын
Couldn't get my head around this topic for ages and this video finally helped me to understand, thank you!
@AlleryChemistry Жыл бұрын
You're very welcome 😀
@elliottbeddow18412 жыл бұрын
you my friend are preventing me from failing
@ea63342 жыл бұрын
Thank you so much for all the work you do, we all appreciate you so much! 👩🏻🔬
@AlleryChemistry2 жыл бұрын
You are so welcome
@heyyy77132 жыл бұрын
Thank you so much your videos are saving me so much time so i can spend it more on practice questions rather than just learning the content
@willcussins50182 жыл бұрын
i’ve been watching these for 2 years and seen every comment as everyone panicking about they’re exam tomorrow mines coming up but wow
@Cars.r.us20232 жыл бұрын
day before the exam and just started my revision gang where we at
@Luca_Talis2 жыл бұрын
🙋♂️
@zahidy55432 жыл бұрын
preachhh
@etragun2 жыл бұрын
Right here, just glanced at the advanced info, starting from the top down :P
@Cars.r.us20232 жыл бұрын
@@etragun exact same here skipped the transition metal 1 though finna fall asleep watching it
@lilo31692 жыл бұрын
how did you do?
@flora43492 жыл бұрын
These videos are so clear and my favourite for revision - thank you!
@JamieWojtasinska Жыл бұрын
At 4:08 wouldn't the equation for the formation of ethane require 3 lots of H2 rather than 2?
@favourebohon52592 жыл бұрын
This is such a great video! I missed a few classes of this topic and always avoided it in revision but you’ve made it so so clear. I’m really thankful, hopefully I can smash my exam 🥰
@AlleryChemistry2 жыл бұрын
You're welcome! Hope your exam goes well. 👍
@i_am_gods_child2 жыл бұрын
your videos just make it so easy and clear for *understanding* !! thankyou so much.
@thainfamous4 жыл бұрын
very concise and informative video. cheers sir.
@AlleryChemistry4 жыл бұрын
Glad you liked it
@raagalayalu3 жыл бұрын
Thank you Allery chemistry !!!
@manalmalik26914 жыл бұрын
With regards to the born haber cycle of MgO. Why is O2. Shouldn't it be half O2 because only one oxygen is being used.
@miinziiiiiii3 жыл бұрын
Yeah that whole slide was wrong. Google ‘MgO Born Haber cycle’ and it comes up
@AS-mw6pw3 жыл бұрын
Yeah I noticed that. The MgO born Hager cycle is shown on page 25 of the CGP revision guide if you need it. Although it’s also a bit misleading because it doesn’t show an upwards arrow for second electron affinity of oxygen. Other than that it’s fine.
@sarah5138Ай бұрын
@@AS-mw6pwit doenst need an upwards arrow!
@ik53773 жыл бұрын
16:33 isn't the value of atomisation of chlorine wrong here, as one mole of Cl is being formed, meaning it should be 242 instead?
@victoriaovenseri80543 жыл бұрын
No because the value of 242 is for Cl2, but in the equation you only have Cl, so you need to divide the original atomisation number to get the value for only on Cl atom instead of Cl2, if that makes any sense 💕
@joshuaroney2 жыл бұрын
yeah i am pretty sure that part is wrong
@joshuaroney2 жыл бұрын
@@victoriaovenseri8054 pretty sure you are incorrect, atomisation is when you form one mole of gaseous atom from its element in its standard state, we form one mole of Cl of gaseous atom so its it is ONE ATOMISATION ENERGY
@abbabbcbbcbb2 жыл бұрын
@@joshuaroney but if you calculate the bond enthalpy for Cl2, you produce TWO moles of Cl, we only need one mole of Cl, so half of a Cl2 molecule is used, so half the bond enthalpy
@AcryllixGD2 жыл бұрын
@@joshuaroney from its element in its standard states, therefore it needs to be Cl2 as chlorine is diatomic in its standard state. Therefore it is 121.
@ligmaman9mm70928 күн бұрын
great video! could i ask, can i watch this video instead of watching the year 12 energetics one? like does it include all the concepts i need for year 12 energetics as well? thanks
@Dkwksmcmmsmwmwwm26 күн бұрын
No they are two seperate topics.
@marianna0944 жыл бұрын
Thank you so much, these videos are helping my understanding of chemistry vastly. I'd like to point out a small error at 25:33, where I think, the ionic compound on the bottom line should be MgO rather than LiCl?
@technophobetortoise96463 жыл бұрын
He does mention this 24:45
@leahlester26204 жыл бұрын
great summary videos! please can you do videos for aqa required practicals
@ahmetaskar6432 Жыл бұрын
51:50 delta H is measured in kjmol not jmol
@Elias.04 Жыл бұрын
Not in Gibbs Free Energy calculations, he highlights that you have to convert to Jmol-1.
@leonachang46944 жыл бұрын
Hi, thanks for these videos - they're super helpful. you mention at around 21:35 a way you check your answers where you start at any point and get 0 as an answer. can you elaborate or maybe give an example? I keep checking but im not getting zero. thank you :)
@AlleryChemistry4 жыл бұрын
Yes, if you put all the numbers in the cycle and go round the cycle (remember when you go with the arrow you keep the sign the same, when you go against the arrow you change the sign). The numbers should add up to zero.
@leonachang46944 жыл бұрын
@@AlleryChemistry got it now, thanks!
@sarahm5376Ай бұрын
@@AlleryChemistrywhich way please give an example
@sarahm5376Ай бұрын
@@AlleryChemistrycan u explain please
@francismannion7075 Жыл бұрын
Thank you I find this to be very helpful, it is clear and concise.
@AlleryChemistry Жыл бұрын
Glad it was helpful! 🙂
@ImranAwan-n9s Жыл бұрын
Is there a playlist for AQA Year 1 Chemistry?
@bz45144 жыл бұрын
At 26:27 when the arrow goes down, why has 2O changed into just O? Where did the second oxygen go?
@ruhakana3 жыл бұрын
I think at some point it should have been 1/2O2 and not 2O
@rebeccatiffany73943 жыл бұрын
I'm a bit confused. At 31:00 when you talk about the experimental v theoretical enthalpies you say that the experimental value is higher, but as they are negative numbers surely -845 is higher than -852?
@ajtrott13 жыл бұрын
The negative sign is just there to show it is an exothermic reaction (and conversely a positive sign is used for endothermic values). Ignoring the sign, the experimental values are always greater (ie bigger number) than theoretical values. This is because theoretical values are based on pure ionic model ie does NOT take into account that covalent character is also present. This is referred to as polarisation - which is greater for highly charged ions (eg +2/-2 ions) and also larger anions( eg I- higher than Cl- as larger electron cloud is more easily distorted by adjacent positive ion). Hope that helps!
@AS-mw6pw3 жыл бұрын
@@ajtrott1 this is really helpful thanks
@nero3462Ай бұрын
@@ajtrott1 hi, i know you wrote this three years ago but i was wondering, does that mean in an exam they wouldn’t put the negative signs, like is this just only part of this video?
@seanbaxter4429 күн бұрын
yeah thhats what i was thinking
@declanm92894 жыл бұрын
These videos really help, thank you
@AlleryChemistry3 жыл бұрын
Happy to help!
@Kadiraram2 жыл бұрын
A level chem 2022 let me hear your voices! (The night before the exam as well lol)
@puddleduck14052 жыл бұрын
how did it go
@rashidbinhendi653 Жыл бұрын
I'm pretty sure delta G (Gibbs free energy change) is measured in KJ/mol
@gianna31324 жыл бұрын
Thank you so much for this video. Very helpful.
@AlleryChemistry3 жыл бұрын
You are so welcome!
@Michael28pc6 ай бұрын
40:00
@Izzy-jb5sw4 жыл бұрын
Thank you so much!
@AlleryChemistry3 жыл бұрын
You're welcome!
@spitefulsaiyan469010 ай бұрын
Thank you!
@AlleryChemistry10 ай бұрын
You're welcome!
@mayaaharonx21236 ай бұрын
I’m in love with u
@mayaaharonx21236 ай бұрын
Shush
@marahalsabbagh37937 ай бұрын
Thank you
@AlleryChemistry7 ай бұрын
You're welcome
@aaronappadoo64456 ай бұрын
thank you, I love you, Jesus loves you too im sure. xxxxxx
@Xap-i5q6 ай бұрын
thx
@georgeashby48524 жыл бұрын
Cheers
@mahadismail23610 ай бұрын
The magnesium born harber is wrong its meant to be 1/2 02