I love how he says "Good luck" at the end, as if he knows that we're watching this to prepare for a test.
@ragingcow8 ай бұрын
i was stuck on one problem for 8 hours today, i didint even need to get halfway through your vid to completely understand how to do it now. After 10 years you are still helping students thanks
@hartsparky11 жыл бұрын
As someone who was sitting right next to him attempting to figure this out, thanks for the reply! We've been using your video pretty extensively to figure these things out, I have to say your cheat sheet is really useful.
@soulafide68249 жыл бұрын
This is great man. Look forward to watching more of your videos for help as I go through uni.
@protostar53515 жыл бұрын
Great video Matthew! You literally saved me... I didn't understand a thing from lecture and the book
@ivanmathias77245 жыл бұрын
This video was awesome, you just clearified a lot of things for me and surely helped me with my test tomorrow :)
@tomas89179 жыл бұрын
Learning more here than I did the whole semester! Nice job! Thanks! But would be much more helpful, if had harder and/or different examples... even if you go trough them a little faster.
@LTIcombatarms9 жыл бұрын
I have my circuits exam in a little bit less than 3 weeks and this will certainly help with passing, as it is the most complicated subject we will have on the exam. Thanks a lot for posting this! You did an amazing job!
@BrownieX0019 жыл бұрын
I have my midterm tomorrow and I am still lost.
@kursatsaimtuna71635 жыл бұрын
@@BrownieX001 same :/
@manoum111 жыл бұрын
YOU JUST SAVED MY LIFE!!! YOU ARE THE BEST!!!!
@DavidWest111 жыл бұрын
Thanks for the quick reply and sorry for wasting your time with that one. Really appreciate the videos, keep up the good work!
@El650Jefe8 жыл бұрын
Awesome video! This really helped out a lot.
@baronfillpot11 жыл бұрын
you do an awesome job of demystifying first and second order circuits. I've watched both videos and you just saved my test grade for tomorrow. Thanks!
@mrtoast2442 жыл бұрын
literally me rn, 9 year old comment
@redsky_gaming13167 жыл бұрын
You should provide that cheat sheet in the description :)
@golski48784 жыл бұрын
My last quiz is exactly that question even the values was same i take 100 👍 thank you
@LuisHGarcia-nu7vs8 жыл бұрын
Great video, thank's a million!!!
@ElberG0910 жыл бұрын
Really helpful video. However I have this question: in the derivative di / dt that you get at 21:57, where do you get the second term +B2e^(-5t)?
@neroarchon54799 жыл бұрын
he made a mistake which you can see but he corrects it by using a describtion....in the vid its B2 t e^(-5t) that you derivate....(not B2 e^(-5t) as written in the vid)... which equals to B2 t' e^(-5t) + B2 t e^(-5t)'....(same way when you derivate [f(x)g(x)] '= f'(x)g(x) + f(x)g'(x)
@AnalogGuy110 жыл бұрын
Really nice job, Matt. Do you mind telling me what software you are using? I'd love to be able to follow your example with digital signal processing problems.
@gwemlins10 жыл бұрын
"Just a happy coincidence" Officially the Bob Ross of circuits.
@seonghkim529 жыл бұрын
Thank you for this vid!
@AraujoMatt11 жыл бұрын
Thanks for the feedback!
@rathydalion3 жыл бұрын
It’s probably not necessary, but how would you go about finding the voltage drop across the 5 ohm res in the middle branch in series with the inductor when t=(0-)
@maximilianobarac80668 жыл бұрын
Hi friend , i have to get the initial conditions from a circuit with 2 storage devices (L & C) but it also has 2 power supplies and they are always present even before and after the switch closes or opens , how can i get the initial conditions ? may i use superposition ? i mean , passivate one power supply & get the initial condition , then passivate the other power supply & get the initial condition , afterwards my 2nd system initial condition will be the sum of those partial ones ? thanks
@wilsonmandie87868 жыл бұрын
much appreciated help..just subscribed
@chetanbahadur67654 жыл бұрын
Thank you sir I understand very well...
@othesss11 жыл бұрын
thank you for share aroujomatt . its gonna help me
@BLUFFIRL8 жыл бұрын
do you imagine capacitors as open and inductors as shorts initially no matter what? does it make a difference if the switch is originally open or closed?
@chronicler1611 Жыл бұрын
if the source is connected for the time such that the capacitor will be charged fully and inductor stores maximum energy, than we consider them as open and short cause they don't have the capacity anymore. That's my concept. Correct me if I am wrong..
@AS-nk1hk7 жыл бұрын
In the first kvl the voltage contribution from the capacitor is +vc and the last time you do kvl with one minute left the contribution is -vc. This is not consistent. Why does the "passivity" change? Thanks
@amandafalke76709 жыл бұрын
Thank you so much!
@brandonleblanc96117 жыл бұрын
could you do a video, solving it using laplace transforms?
@vladyslavkorenyak8724 жыл бұрын
The voltage in a capacitor can change instantaneously if there is a pulse (deltax). So this is right only in some situations
@ultikintil6 жыл бұрын
Thanks Matthew!
@AraujoMatt11 жыл бұрын
notice that i(l) = 3. when you plug this into the purple equation at 26:00 you get di/dt = 15 - 30
@shivpalpatine8 жыл бұрын
Im in a Elements of Electrical Eng. class and we dont get a cheat sheet........... life would be so much easier with a cheat sheet
@ishaqaminu50999 жыл бұрын
i see in some questions that you dont have to solve till i(infinity) you just stop at i(0) please can you tell me when to go till i(infinity)
@jericoyabut19433 жыл бұрын
I don't get how you derive i(t) to get di/dt. why does the middle term of di/dt seems unchanged from i(t)?
@muhdsafwan4018 жыл бұрын
Great video! Just a happy coincidence haha
@oneinabillion6544 жыл бұрын
Hi. At 26:00 why is there a current through the resistors at t=0? Also, what if the question asks us to find v(t) across capacitor for t>0 instead?
@allenjonesstyles6112 Жыл бұрын
Find vc(0-/0+) , then find dvc/dt , and same equation , btw it's ur comment from almost 3 years ago, 😅 you know it
@piglink105 жыл бұрын
So is the initial closed or open ?
@eduardojosecanessaquesada7319Ай бұрын
Very useful!
@tomas89179 жыл бұрын
PLEASE, where did the Theta in case 2 of the Cheat sheet come from?? What is it?
@johnnolen83384 жыл бұрын
@ 17:22 "This means the circuit is critically damped." Indeed it does, but you still need to mind your initial conditions. I solved this circuit in the s-domain and found the expression: I(s) = 3(s + 5)/(s + 5)^2. The zero in the numerator cancels one of the poles in the denominator and you get I(s) = 3/(s+5). This is a 2nd order circuit that exhibits first order behavior. Performing the ILT on I(s), you obtain: i(t) = 3*e^(-5t) ∎
@BlownAwayByBordom137 жыл бұрын
Could you upload a pdf of the cheatsheet? Thanks for the video
@rafmunr353210 жыл бұрын
for the V_cap equation @8:15,10-5i+Vc=0. Why do we not consider the 5 ohms resistor
@sebaogal19 жыл бұрын
Because there's no current passing through it :)
@AraujoMatt9 жыл бұрын
***** Capacitors and resistors can't be treated the same in transient circuits. There is a voltage on the cap, but there is no current flowing in that branch the resistor is still bound by ohm's law. No current, no voltage. The reason there is no current is that the capacitor is fully charged in this instance - therefore it acts as an open
@abdullaomar14217 жыл бұрын
sebaogal1 are you an engineer now
@sebaogal17 жыл бұрын
+Abdulla Omar still on it :)
@danielolivera26187 жыл бұрын
so i think it was because the cap was fully charged
@DavidWest111 жыл бұрын
At 26:00 when di/dt is solved for -15, shouldn't it be positive 15?
@jimbytobehappy7209 жыл бұрын
Well explained! XD
@ty4nak132 Жыл бұрын
man its a 9 year old video but imma ask anyway.. So I applied Laplace transform to this example circuit, solved it and got the same expression of i(t)= 3e^(-5t). Same answer for less work it seems like. So what are the cases where the Laplace approach cannot be used?
@kyllemosuela89987 ай бұрын
Hello sir can i ask? On how can you determine the polarity of a conductor if not given
@tduong298 жыл бұрын
Hi Matthew, nice video. Just a little confusion from what you said at 23:43, "we're looking for an equation for ALL-TIME AFTER t=0". It that were the case, then why would there be a 5v across the capacitor? wouldn't it be -10v? did you mean just when t first =0? sorry, not trying to nitpick, I just have a really hard time with 2nd order RCL and trying to learn.
@manoum111 жыл бұрын
could you please make more videos about how to solve problems?
@CanardErrant9 жыл бұрын
At around 26:19, when di/dt is isolated, what happened to the value of L? Eqn: -10 - 5+10i + Ldi/dt = 0; shouldn't it be di/dt = (-15)/L?
@waibamugo65399 жыл бұрын
L = 1. Look at the circuit. -15/1 = -15
@CanardErrant9 жыл бұрын
Oh, I see. My bad. Thanks!
@alexgeo61772 жыл бұрын
At 13:55 i don't get why we were changing the sign of the capacitors voltage. Why does it not remain a minus? I mean the current is entering though the negative terminal so by my understanding it should remain that way. Thanks to anyone replying.
@squiliumfancypants Жыл бұрын
I also wondered that but cant explain why he does that
@WMTeWu9 жыл бұрын
I knew from the start it going to be critically dumb !
@yasserel-azab70339 жыл бұрын
how ... ?
@mrtoast2442 жыл бұрын
"this is the cheatsheet that I've created, you can pause the video and look at it but we'll come back to it throughout the video" every single student: 📸📸📸📸
@rajaryansharma66344 жыл бұрын
Thanks!
@yousefsrour33162 жыл бұрын
Shouldn't the second kvl be -10 + 5 + 10 iL + L di/dt =0 ??
@mansouralyahya6375 Жыл бұрын
aren't you missing a particular solution, since we have the 10v voltage source which produces a forced response?
@johnrobenault31405 жыл бұрын
I love this... It's beautiful.
@protostar53515 жыл бұрын
I find it to be quite the opposite.
@user-fx8gb9vs4j3 жыл бұрын
GUYS I CONFUSE AT 22.41 HOW B2e^-5T COME?
@Corrodant9 жыл бұрын
isn't i(0+) suppose to be the same as i(infinity)? and shouldnt iL equal to i(o-) which is before changing the switch?
@BrownieX0019 жыл бұрын
Capacitor and Inductor will act differently when switch is on or off depending on circuit. For this when switch on at 0-/0+ inductor will be short and capacitor will be open. But for infinite the switch is open and the source is therefor not connected to circuit so inductor and capacitor discharge away after the battery after the inductor dies. The resistor on top left doesn't get affected because its open there so it doesn't matter. Now again inductor is short and capacitor is open and making the entire circuit not connected with anything else so its nothing, 0. But when it was 0-/0+ the circuit was still connected and power was running so there would still be current since current depends on resistor and voltage and we still had those so we can calculate it.
@soulafide68249 жыл бұрын
Marc Zapatero i(0+) is the instant right after the switch is flipped. i(infinity) is after a long time, which is when the circuit has reached steady state. For inductors: iL(0-)=iL(0+)
@soulafide68249 жыл бұрын
Marc Zapatero sorry for being seven months late lol
@Nick-wj5gw8 жыл бұрын
Looking to do more problems like this. What book is this problem out of? Anyone know?
@T4BoyRobot8 жыл бұрын
+Nick Spoutz The name of the book is on the title screen in the first few seconds of the video. You can get that book online for less than $20 usually. It's pretty good.
@Nick-wj5gw8 жыл бұрын
+Thomas Henley Duh! Thanks for pointing that out! Didn't even think to look there lol
@angelojunior95074 жыл бұрын
Hello, why in the characteristic equation you didn't consider the initial capacitor voltage?
@jefferytownsend77874 жыл бұрын
The initial and final conditions are dealt with in the beginning of the video. The characteristic equation is to get the natural response of the circuit. By superposition they will sum together to get the final response. Check out forced second order ODEs.
@angelojunior95074 жыл бұрын
Thanks
@angelojunior95074 жыл бұрын
Can you help me with a second order circuit? If so, how can I send you?
@jefferytownsend77874 жыл бұрын
@@angelojunior9507 There are better forums to ask on. Try groups like r/ECE or r/Electrical Engineering on reddit. You can also try #electronics on the freenode IRC network.
@ShamanRing7 жыл бұрын
speed 1.5 (=
@ruandurand39717 жыл бұрын
I did the same
@uhhidk82533 жыл бұрын
Rookie numbers. You can understand him at 2.5x as well.
@fredchiopsya45515 жыл бұрын
nice video
@quitetube50644 жыл бұрын
thank you
@jinshikami75256 жыл бұрын
Hey could you try this software? Pin Point: 'Circuit Solver' by Phasor Systems on Google Play.
@KHALIDALIABBOODALOGA10 жыл бұрын
Can you post your cheat sheet?
@ntuthukomthiyane50178 жыл бұрын
great
@rohithsrisai42266 жыл бұрын
Thanks
@jacobkotecki86169 жыл бұрын
why does i(0+) = i(L) at the 4:50 mark
@citiesflicker7 жыл бұрын
the current is the same throughout the loop, and there is only one loop in the initial conditions.
@ChandanKumar-kw4dd6 жыл бұрын
but current 3 amp is will be after a long time not at 0+.
@robinmaikle92126 жыл бұрын
Can anyone test this out and give feedback? Pin Point: 'Circuit Solver' by Phasor Systems on Google Play.
@chrisw22813 жыл бұрын
Missing t at B2e^(-5t), should be B2te^(-5t). This cracks my head when seeing the differentiation
@SuperHovik5 жыл бұрын
21:10 you missed a t between B2 and e. but overall great vid!
@peronkop4 жыл бұрын
That t=0 so he shouldn't have written B2 at all.
@user-fx8gb9vs4j3 жыл бұрын
@@peronkop yes but he wrote
@WATTNOT6910 жыл бұрын
electrical engineer, but cant spell characteristic, great video regardless ;)
@narpatrajgehlot14438 жыл бұрын
at 24:28 the di/dt should be -5B1(e^-5t)-5B2(e^-5t) ||
@narpatrajgehlot14438 жыл бұрын
+narpatraj gehlot in equation of i(t) at 20:20 you do not write there t in 2nd term so i get confused.
@Devrhoid8 жыл бұрын
+narpatraj gehlot I realised that as well. I just inserted it. He actually took it into account in the line below thoat though.
@brothercavil4917 жыл бұрын
Your initial Vc is incorrect; since there are 2 supplies, you need to use superposition when you perform KVL. Total voltage should be 15V when you add the 10V from the 20V supply. Said another way, since the cap is an O.C., the right most resistor is removed from the circuit, leaving a 1/2 voltage divider in series with a single 30V supply.
@laurenhilley17017 жыл бұрын
Ran circuit on Multisim, Voltage across the cap is indeed: 15V
@Jarrettmonty997 жыл бұрын
This is wrong. First, Superposition is unecessary. KVL works fine. Second, the 10V source is pointing downward, so (20Vs - 10vs) or 10V - 5V = 5V. I also checked this with a simulation (5V), not sure what clifford ayer did, except maybe make the same mistake.
@nnje33716 жыл бұрын
Jarrett Montgomery Well if you do kvl on the left loop then you'll see that 20v and 10v are in the same orientation. So... it is in fact 15v..
@Jarrettmonty996 жыл бұрын
KVL left loop: 20 = iL(5) + iL(5) - 10 (iL = 3) => 20 = 15 + 15 - 10 == 0 Voltage at 3-resistor node (Vc) using Nodal: [Vc - (-10)] / 5 = 3; Vc = 5V KVL in the left loop has nothing to do with it.
@nnje33716 жыл бұрын
Jarrett Montgomery no
@David_948 жыл бұрын
when you wrote the voltage of the capacitor in the characteristic equation you forgot to put the initial condition
@El650Jefe8 жыл бұрын
+David Rodriguez Since he took the derivative it would of became zero anyways so it wouldn't have changed the final answer.
@David_948 жыл бұрын
ok, but I think it is necessary to write it, because sometimes it does not become zero
@tedsvenstrup827711 жыл бұрын
Hey Batman.
@magnusonx17 жыл бұрын
In the first loop, you referenced the technique as the "KVL" when you should have said "KCL". Using KVL=Kirchhoff's Voltage Law means that you are using the node voltage analysis to calculate voltage.
@AraluenSparr6 жыл бұрын
Mesh uses KVL (adding up the voltages) and Nodal uses KCL (adding up the currents). He was correct when saying he was using KVL. I'm not sure what you're referring to, because when using Nodal analysis, your equations are set up as V/R + V/R . . . etc, which is current. Mesh uses R(I) + R(I) . . . etc, which is voltage. You may have gotten that backwards if I interpreted your comment correctly.
@jinshikami75257 жыл бұрын
If anyone could test this app i'd be grateful! Search: 'Circuit Solver' by Phasor Systems on Google Play.
@chend79489 жыл бұрын
Kvl 2 should be 10 -5il +5il +vc = 0
@CardinalTreehouse4 жыл бұрын
A little late now, but I believe it is correct the way he wrote it. If you do a mesh current for i2 (which is going to equal 0 A), you will get an equation of: 10V + 5(i2-i1) + 5(i2) + Vc = 0 Since i2 is 0A, this equation goes to: 10V + 5(0-i1) + 5(0) + Vc = 0 ----> 10V -5i1 + Vc = 0 Vc = 5i1 - 10V = [5ohms x (3A)] - 10V = 15V - 10V = 5V
@khalid47155 жыл бұрын
math is difficult
@GotxMilk229 жыл бұрын
I solved this using Laplace and got B2 = -5 not 0
@Kieonis2 жыл бұрын
I stop watching at 16:48. I’m upset that while you were deriving your characteristic equations that you didn’t show all the steps. Now I’m left wondering how you got the expression you found. You should have brought the equation you were working with over. If you are teaching people show all the steps. Everything is important to people trying to learn.
@jakethedoggo85393 жыл бұрын
You made a mistake while writing homogenious equation.
@Karlwojo110 жыл бұрын
"Just a happy coincidence" Officially the Bob Ross of circuits.