Circuits I: Example with RLC Circuit (Series, Natural Response)

This video works through a problem involving a circuit with resistor, capacitor, and inductor in a series configuration. We examine the natural response of the capacitor voltage following a switching event.
University of California, Davis
ENG17: Circuits I, Spring Quarter 2015
Instructor: Dr. Kyle Montgomery
Course Website: www.kmontgomery.net/teaching/e...

[@DATRATMANZ]

Good man my professor made us derive these equations and expected us to derive them on the final. This is a great stepping stone in understand what we are doing and taking things down and simplifying them. Awesome thank you very much.

[@ThePhDEngineer]

Happy to help

[@draxlevi9267]

you're awesome dude, thanks for carrying my university's entire electrical engineering program on your back

[@ThePhDEngineer]

Unfortunately...many of these basic courses get assigned to teachers that honestly suck at teaching. But, glad I could help in some way...

[@kabandajamir9844]

So nice the world's best teacher

[@ThePhDEngineer]

Thanks!

[@ATTO2020]

hmm isn't overdamped series a1+a2=di(0+)/dt ?

[@ghinasalsabila3982]

can you help me to answering the practice questions?

[@bonaviafx9434]

What will be the function of i(t)? I tried finding the derivative of Vc(t) and multiplying it by C, but the current curve obtained doesn't match my simulation.

[@aidanmacdougall5530]

ever work that one out? im thinking the same rn

[@aidanmacdougall5530]

nvm

[@nickkenny1789]

(1/L) * integral of v(t)

[@despapitoxaa6331]

Sir, how did you get the values of A1 and A2?

[@swalker157]

Cramer’s rule: 1/det A^(-1) *B

[@DATRATMANZ]

@@swalker157 Indeed

[@salieugbla1542]

waiting for the same response

[@nickkenny1789]

Why is the answer v(t) and not i(t)? Would the constants just be different for i(t)?

[@JeffReams]

yes

[@HollowBxstion]

I have no idea how you got A1 and A2, even with the brief explanation

[@pkbadshah4734]

Sir I think v at infinity is same as v+ that is -3v . Not zero can anyone explain how its zero

[@danielmonahan6127]

For posterity; without any active components to maintain the potential across the capacitor, the voltage across the capacitor Vc has to decrease over time, so at infinity the voltage will drop to zero. It is due to coulomb forces as the electrons dissipate into the wire and the charges reach an equilibrium.

[@baseballphenom512]

is he writing backwards

[@bloop000]

no, the video has been mirrored

[@bloop000]

most people wear their watch on their left hand, his is on his right on the video, plus the logo on his polo is on his right chest, where usually a logo will be over the left

[@arthurc.3747]

Ohh you are left-handed! ;-)

[@ThePhDEngineer]

I can also write with my feet...

[@farhanwakil3800]

s1 is not -.0.006 when I did the calculation is -0.555 I think you need to re-check the calculation for s1.

[@user-co6pi1nj5q]

-5.556 milli 😂😂😂

[@farhanwakil3800]

@@user-co6pi1nj5q so i got it wrong?