AS Physics Exam Question: Materials

[@jakey66161]

i swear this guy could teach me the whole physics course in less than like 5 hours. he teaches like 412543524363% faster than any teacher ive ever had.

[@DrPhysicsA]

Youngs Modulus (Stress over strain) is constant for a particular material within the range for which it applies. Once you get beyond the limits then of course it no longer helps.

[@DrPhysicsA]

Thanks and well spotted. I must had mis-read the calculator. It should indeed be 1.56 m/s. And good luck in the exam.

[@ramansb1213]

This is just what I WANTED, EXAM QUESTIONS. THANK YOU SIR

[@DrPhysicsA]

I'll see if I can find it.

[@alank1246]

Thank you for your videos Dr. Eagle. They are immensely useful!

[@ameeraasif160]

the questions r easy! i saw some other videos of urs and they were equally helpful as this video. when i practiced past paper after seeing ur video, i could actually see some questions there that were taught by u ..thanku

[@alexjohanson3599]

@DrPhysicsA , 18:47 , u said " the net force we've calculated " ... wrong ... ' F ' in stock's law is for viscous drag not the net force ... There is no net force ( terminal velocity ) .

[@medievalmusiclover]

Love your videos. ❤ Thank U for downloading these gems. !

[@DrPhysicsA]

The Electricity AS questions are being uploaded now. Should be online in 3-4 hours.

[@talhaamin5470]

Those times😂😂😂

[@WiseFoolTrades]

5:28 I thought that strain is change in length divided by original length? So wouldn't that be 0.003m/0.002m?

[@DrPhysicsA]

Wise Fool The original length was 2 metres.

[@aajw98]

This video was very helpful, are you by any chance planning on making another one?

[@Silex93]

These are fantastic timing! got an exam tommorow on Experimental physics edexcel..!

[@sea5205]

Really helpful video, thanks a lot!

[@041Mgiga]

Would it be possible for you to upload a walk through of tge answers for tomorrow's Edexcel paper as is done with maths?

[@reemobella3297]

will this help me for as level cie board ??

[@Son96601]

is the value of stress and strain for a particular material always true for that material no matter what

[@lak5499]

hi been watching ur videos lately...they are seriously amazing :D ...just wanted to know have u done any questions from january 2013 aqa a physics paper? there is a materials question which is really mind boggling relating to a crane holding onto some load...so wondering if you have done it? thanks

[@madtigger24]

Such a great video! Thanks so much, have exam on Monday and this has really helped :) Isn't the last answer meant to be 1.56 m/s?

[@fahim4654]

Is this for edexcel??

[@blacklovespurple]

so helpful! thank you so much, you're an awesome teacher :D

[@taniyan7322]

Lifesaver! Thank u so much

[@EpicEditsBySaz]

physics is awesome, thanks a lot sir.

[@catherinehong6171]

Physics Exam Question is very clearly explained

[@DrPhysicsA]

Catherine Hong Thanks. Hope your exams go well.

[@juhainashakir3722]

Sir in 14:06 u said that the cross section area is 33x10^-3 but I got 3.3x10^-7

[@MiniNinjaUK1]

He said x10^-8

[@DrPhysicsA]

Sorry if my writing wasn't clear. I said 33 x 10^-8 which is 3.3 x 10^-7.

[@MermaFX]

Real hot opinions, thanks for sharing.

[@premn7725]

Very much appreciated, but that 360p though 😂

[@Motivation2Advance]

The video is 8 years old dumbo 😐

[@BoyTheGenius]

I cant thank you enough.

[@kovar.youdisappointmedimit7548]

So helpful thank you !!

[@JayLikesLasers]

I didn't do physics at A level, but have just finished a mechanical engineering masters degree. This stuff is super basic, yo.

[@ZyNeEnZyNe]

Edexcel As-level physics unit one today!

[@DrPhysicsA]

I hope the exam goes/went well.

[@ZyNeEnZyNe]

It went worse than expected, unfortunately

[@ZyNeEnZyNe]

There was this one question that said copper and I think steel wire is soldered at the middle with length l. A F is applied and the length is extended by 0.010m. It gave us the youngs modulus and and cross sectional area of the 2 pieces of wire and asked us to show copper has extended 2* more than steel. What even sort of question is that, I couldn't see enough information to solve it. Damn

[@DrPhysicsA]

***** You can think of the two wires as separate, each with the same force applied. Then in each case E = F/A / x/l. I assume you were given YM, area and length for each wire. (or they might say that both lengths were the same). The force is the same.

[@ZyNeEnZyNe]

I was given the youngs modulus for both wires, and the cross sectional area for both wires and that the overall extension was 0.010m that's all