Springs in Parallel and Series - A Level Physics

This video explains how springs behave in parallel and in series for A Level Physics.
If you understand how one spring extends when a load is applied you can then extend this knowledge to investigate combinations of springs in parallel and series. This also has many similarities to the way that combinations of capacitors behave when in a circuit.
Thanks for watching,
Lewis
This video is recommended (although not always mentioned explicitly) for anyone studying A Level Physics in the following exam boards:
AQA
CIE
Edexcel
Edexcel IAL
Eduqas
IB
OCR A
OCR B
WJEC
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[@youdontneedyourairplanemod6197]

i swear you're the reason im coming from U's to B's thank you so much man your great!!

[@DunkOnEmGaming]

How come this isn't in the textbook yet I see it in past papers

[@fbdjwjflac]

Because it isn't explicitly mentioned in the spec, it won't be in most textbooks. This is an application of your current knowledge of springs, so they can ask it in the exam.

[@husseinmohamud6506]

@@fbdjwjflac What a levels are you doing?

[@fbdjwjflac]

@@husseinmohamud6506 Physics, Chem, Maths, FM

[@husseinmohamud6506]

Lewis Hows further maths going?

[@fbdjwjflac]

@@husseinmohamud6506 It's fine lol

[@breadstick4443]

studying gcse physics this video was great in explaining exactly why parallel springs are stiff. thanks!

[@mithroshan1160]

Just in time,tommorow is my unit 1 Physics test,Thank you

[@MunkyChunk]

Good luck! Hope I'm not too late!

[@TheTinkushal]

Amazing explanation my professor completed the full book on vibrations and never showed us what a spring even looks like...

[@reezl85]

what a stupid lie

[@robertfield7532]

Quick question with solving the equation 1/kt = 1/k + 1/2k Why not solve it how you solve other fractions in mathematics, simply by making the 1/k an equivalent fraction like so: 1/kt = 2/2k +1/2k 1/kt = 3/2k Then invert both sides: kt = 2k/3 Extremely useful video though, I missed the lessons where springs were explained so this made for some much needed catch up revision.

[@PhysicsOnline]

robert field That could work too.

[@natahx2787]

Not me watching this video 10 minutes before the exam 😂

[@MunkyChunk]

Why is this not in textbooks yet I see it in every other past paper!? Thank you for this!!

[@leifyy4673]

Didnt even need to put on 1.5x speed. Great explanation!

[@haniyabatool7978]

Man you helped me so much. Thanks

[@aniruddhasharma5738]

what about the extension? how does extension get added up when you have a series and parallel case(2 in parallel which is connected to one other in series) same as the one in the last few minutes of the video?

[@LukeHaslerMusic]

I got this question on Monday and I really wish I'd seen this video thsn

[@warrendsouza9571]

Thank you very much for explaining this so clearly! It has really helped

[@bellabarlow6739]

If you had three springs in series, would the extension be multiplied by three instead of 2??

[@PhysicsOnline]

Bella Barlow yes

[@mistervoldemort7540]

Thank you, learnt a lot

[@justinxin8733]

Super useful thank you!

[@solarsynapse]

Parallel is stronger and series is longer?

[@sarujan02thangavel93]

Thank you very much sir

[@kyugreywolf6801]

Thanks for the video.

[@trendytrenessh462]

This was really helpful thanks

[@Cardifyz]

When you have K and 2K can you just do product over sum trick!

[@PhysicsOnline]

Cardifyz Yep, well spotted.

[@alfieg7596]

Maybe do a physics at university video!

[@PhysicsOnline]

Alfie Gilmour Excellent idea. What kind of questions do you have about it? The topics studied, structure if a course etc?

[@alfieg7596]

A Level Physics Online How much time you spend in lectures/practicals? Would it be better to pick a more specialised course or one that covers more physics topics? Would it be more benefitial to taking a year in industry or doing the final year doing something academic? And maybe your personal expiriences!

[@knockknock3physics165]

Are the spring diagrams you used in the video standard like circuit diagrams or just your own visualisation?

[@PhysicsOnline]

Just my own way of representing it, although similar to many other diagrams I’ve seen other teachers using.

[@kaivanshah4304]

it was really good

[@oneinabillion654]

Springs in parallel and series done!

[@juliageronimo2855]

quick question, approximately where would the line of k be for the parallel/series system on the F vs X graph (in comparison to a regular system, series system, and parallel system)?

[@sumedh7130]

is there a difference if the springs were horizontal and the weight force would no longer have an affect on the total acceleration?

[@kelly-anndowner861]

which is greater the spring constant in series or the spring constant in parallel

[@solarsynapse]

If I want to change the strength only, the material and/or the diameter of the wire would change. True?

[@victoriacorcimaru1731]

Thank you so much! I've been trying to understand this for quite a while! One quick question, how can you explain this difference in the spring constant using Young's modulus?

[@qvixfy8529]

I think since young modulus of a material is directly proportional to its stiffness or constant K, you can say that for two springs in a series arrangement the young modulus decreases relative than to that of one spring since the stress over strain ratio of both two springs in series decreases and the opposite will be true for a parallel arrangement. So i guess the answer to your question would be that since the stress over strain ratio ( young modulus) decreases of a series arrangement relative to one of its spring, the constant K will also decrease as young modulus and K are directly proportional

[@ftech9096]

Sir I need a topic:- Two masses with two springs hang vertical

[@Physics-Momentum]

Sir how do I know to how many significant figures my answers should be?

[@arsal16]

legend

[@PhysicsOnline]

It has been said

[@unownssssn6448]

Thank uuuu

[@lemonlover5011]

Saved me

[@sunilkamboj4476]

thanks sir

[@Yash-df5jo]

Why is it 1 over k for springs in series?

[@nobleofftrack741]

Spings?

[@PhysicsOnline]

+Joss Noble Now corrected! Thanks

[@nobleofftrack741]

Thanks for replying 😄

[@mattwhitelock4725]

How come you cannot solve the equation like this: 1/k(total) = 1/k + 1/2k k(total) = 1/(1/k + 1/2k) k(total) = k/1 + 2k/1 k(total) = k + 2k k(total) = 3k

[@afc8981]

Matt Whitelock Does 1/(1+2) = 1/1 + 1/2 or does it equal 1/3?

[@mattwhitelock4725]

That makes sense, but I'm still confused to the actual reasons for this - if you raise something to the power of -1, you flip the fraction, right? So why can't you just raise both sides of the 1/k(total) equation to the power of -1, and get k(total) = k + 2k?

[@afc8981]

Matt Whitelock 1/(a + b) DOES NOT equal 1/a + 1/b. Therefore 1/(1/k + 1/2k) doesn't equal 1/(1/k) + 1/(1/2k). This is wrong. You need do this: 1/(1/k + 1/2k) = 1/(2/2k +1/2k) = 1/(3/2k) Now you can flip it to get 3k/2 or 1.5k.

[@hassanabdellatief5290]

i dont get the thing when theyre in series

[@Khadijahx238]

Thank you Sir, these videos are helping me alot. If you don't mind can you please explain a few things to me. 1:45 Why is the spring constant halved, when the same amount of force is applied? Is it because the force is shared between the two springs? Say they were 4 springs in parralel, would that mean that the spring constant is 1/4?

[@joriscoolen3700]

corona time

[@jozifff.]

like what is this?? it's not even mentioned in the textbook or pmt but it's in past papers. so dumb

[@yuki002x]

you have to read from multiple textbooks to cover your whole syllables

[@doingnothing3712]

who is katie?

[@catalyzt7162]

dead joke

[@oneinabillion654]

Intro hurts my ears. Nice vid anyways.