Back to basics: Practical capacitor charging currents by LTspice demonstration

[@PavolFilek]

Thank you very much. I need this to my MPPT DC-DC BUCK 2-phase.

[@sambenyaakov]

👍😊

[@KratosGhostofSparta-pp1cr]

Hi sir. I have a question about LTspice. Is there a way that add TI models in to ltspice and use it? Thank you

[@sambenyaakov]

You may be lucky and the model might be compatible, but if it includes non generic sources or syntax it will take an expert to convert.

[@yinan8719]

Thanks Dr Sam Ben-Yaakov. Is that also concluded that no matter how large the inductance is the energy dissipation is the same? Also seems it may takes a bit longer to dissipate the same amount of energy than no inductance at all.

[@sambenyaakov]

Indeed. Hold on to my next video an eye opener.

[@zaikindenis1775]

Thank you for the video. So, the maximum current will no be higher than Uin/sqrt(L/C). And the same effect one can see in gate drivers, where we need high gate current in hard switching aplication.

[@sambenyaakov]

Yes, correct. 👍. Hold on to my next, eye opener video.

[@nikolaivic9987]

Very nice. Keep in mind that LTSpice by defualt adds Rser=1mOhm to every inductor in the model to improve convergency. This can be changed to 0Ohmin Control Panel -> Hacks -> Always default inductors to Rser=0. Not sure though what is applied when L=0, whcih may be the rootcause of the difference in Energy you see :)

[@sambenyaakov]

All this is known. But...you missed the REAL question: is the loss with L dependent on R?

[@zaikindenis1775]

​@@sambenyaakov Interesting question, thank you. Intuitively, not. Battery provide energy E*q. And capacitor is charged finally to E*q/2 energy. So we always lose E*q/2 in heat, we assume charge save in the circuit.

[@sambenyaakov]

@@zaikindenis1775 Hold on to my next video on losses. Coming soon😊

[@nikolaivic4480]

⁠@@sambenyaakovI mean that the total energy is not measured only over R2 if Rser=1mOh, hence the difference between L=0 and L!=0 energies. L is irrelevant for the E 🙂

[@sambenyaakov]

@@nikolaivic4480 OK, Got you now. You are of course correct.

[@krish2nasa]

Very informative, Thank you very much.

[@sambenyaakov]

Thanks

[@richardandrews573]

At 4:46 I calculated 28mJ not 38mJ?

[@sambenyaakov]

75/2= 28? Or you used another method?

[@biswajit681]

Great insight...Sir could you please make video on smps input filter design with respect to voltage mode and current mode control and input filter impact on loop characteristics

[@sambenyaakov]

Will try

[@tamaseduard5145]

👍🙏❤️

[@sambenyaakov]

Numero uno😊

[@petarsimic4097]

🙏❤