Basics of Bending Stress Part 1 - Section Modulus

[@atan7260]

10 minutes taught me more than my professor managed in a 2 hour lecture, thank you for taking the time to explain this so clearly.

[@prometheusengineeringgroup7825]

Thanks!

[@surendersingal2192]

Thank you sir Great explanation of section modulus Cross sectional property of material in elastic range to oppose bending.

[@shivamsharanlall672]

7:50 isn't that the total tension or compression produced is equal to product of half the area of beam to the average stress. Since the stress induced in the section is changing at different points from the extreme fibre to the neutral axis. The change is obiviously a linear change from the point of neutral axis to the extreme fibre. So, T or C = area * average stress = [ (1/2)*b*d] * (1/2) sigma

[@CZWhitek]

Very nicely explained - well done. Looking forward for the next parts!

[@prometheusengineeringgroup7825]

+CZWhitek Check out part 4 of the series on Beam deflection kzbin.info/www/bejne/n56zeZSVq7iFatE Reply ·

[@prometheusengineeringgroup7825]

Thanks! See link below for the next part (Part 6) kzbin.info/www/bejne/h6bdf2ulec92mas

[@prometheusengineeringgroup7825]

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[@prometheusengineeringgroup7825]

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[@affanahmedkhan7362]

Omg what a brilliant way of teaching love from PAKISTAN

[@prometheusengineeringgroup7825]

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[@elliashah]

it was very useful for my understanding. Tq for the lecture. will trying to finish listen to your material. Tq

[@prometheusengineeringgroup7825]

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[@محمدعبداللهزاده-ش3غ]

I enjoyed your teaching

[@prometheusengineeringgroup7825]

Thank you

[@cstechguruji.Hari5]

Nice #cstechguruji !!ur all lectures are awesome subscribed to ur channel 🙏

[@prometheusengineeringgroup7825]

Thanks you

[@prometheusengineeringgroup7825]

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[@rehabiamtileni3145]

thanks good friends. great job and keep it up.

[@prometheusengineeringgroup7825]

+Rehabiam Tileni Check out part 4 of the series on Beam deflection kzbin.info/www/bejne/n56zeZSVq7iFatE Reply ·

[@prometheusengineeringgroup7825]

Here is another video for our loyal fans! This one breaks down the concept of shear stresses in beams! kzbin.info/www/bejne/nHvMe4xma86Lbbs

[@prometheusengineeringgroup7825]

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[@Structure-Dubai]

Nice work... keep it up Man...thank you..

[@prometheusengineeringgroup7825]

Here is another video for our loyal fans! This one breaks down the concept of shear stresses in beams! kzbin.info/www/bejne/nHvMe4xma86Lbbs

[@prometheusengineeringgroup7825]

Please see our latest video (on structural dynamics) kzbin.info/www/bejne/kKnZfXZjbpaEgdU

[@jihawnajohnson5188]

Well done.

[@iecivil]

Very well explained!

[@prometheusengineeringgroup7825]

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[@gabrielreyes9768]

Thank you! this help me so much

[@prometheusengineeringgroup7825]

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[@dipeshjaisipoudel9543]

Never understood what a bending moment is, now realized that it is the moment experienced by a member due to the equal and opposite tensile and compressive forces acting at the centroid of the stress diagram for the section... please correct me if i am understanding this wrong..

[@prometheusengineeringgroup7825]

EXACTLY!!!

[@faisalmayanja1]

I was following up until you went from the red u-shape (bent member) to the red rectangle (straight member). I can't seem to visualize which orientation that's in. My professor did the same thing and I can't make that relationship.

[@prometheusengineeringgroup7825]

The red rectangle is the beam cross section (not the side view) however the stress and strain diagrams are in side view orientation. I Know it can be confusing. Perhaps I can give you a 3D illustration. Let me know if this clears things up and thanks for being an engaged fan!!!

[@prometheusengineeringgroup7825]

Sure. What's the problem? Note that the only difference is the shape of the cross section which means that the section modulus (c / I) will be different. We can derive the parameters or use the formula for moment of inertia of a triangle to tackle the problem.

[@prometheusengineeringgroup7825]

Here is another video for our loyal fans! This one breaks down the concept of shear stresses in beams! kzbin.info/www/bejne/nHvMe4xma86Lbbs

[@arjunsr3379]

@@prometheusengineeringgroup7825 red rectangle is the beam cross sectional side view right??

[@prometheusengineeringgroup7825]

@@arjunsr3379 No. Sorry for the confusion. the moment sign makes it confusing

[@michaelwoodland1232]

Are you sure the cross section rotates clockwise?

[@rafianmara2480]

Hey its amazing explaination, but is there any chance for me to have your references? It'll be great!

[@PatrickPereiraVieira04]

Hello! Thank you for the video! How would I do this for a hollow cylinder? I want to find out the maximum force a pipe can hold before reaching the elastic limit.

[@prometheusengineeringgroup7825]

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[@Rajkumarraj-su3kw]

How much factor of safety to be considered for A36 steel to find allowable stress ..I considered 4 Safety of factor and max allowable stress as 62MPa.

[@prometheusengineeringgroup7825]

This is something that the particular jurisdiction code will prescribe depending on bending, shear, compression etc.

[@prometheusengineeringgroup7825]

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[@shadabshaikh3061]

Good job.. Sir try to upload tutorial in a way from zero or starting base of rcc And proposed structure manually...and try to derived all necessary formulae

[@prometheusengineeringgroup7825]

Indeed. That is a worthy admonishment. :)

[@prometheusengineeringgroup7825]

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[@Rajkumarraj-su3kw]

Hi sir ..there is two question in one of my exam ..they asked to select the correct A36 steel Universal beam which can carry 150 kn-m moment ..and also they given four options of UB sizes with Sx value ..how can I find it ..I tried same procedure to find Sx as u mentioned in this video but Sx value not matching ..I have considered allowable stress for A36 63 MPa and 150 knm moment they already given..but my final answer coming .please suggest 2419cm3 ..but all option is like 780cm3 , 569cm3 like that ..please help In this

[@prometheusengineeringgroup7825]

The was the shape of the beams?

[@jaygurung2734]

thank u

[@prometheusengineeringgroup7825]

you are welcome.

[@prometheusengineeringgroup7825]

Here is another video for our loyal fans! This one breaks down the concept of shear stresses in beams! kzbin.info/www/bejne/nHvMe4xma86Lbbs

[@prometheusengineeringgroup7825]

Please see our latest video (on structural dynamics) kzbin.info/www/bejne/kKnZfXZjbpaEgdU

[@MahendraHarishInti]

Helped me

[@prometheusengineeringgroup7825]

+Mahendra Harish Inti Check out part 4 of the series on Beam deflection kzbin.info/www/bejne/n56zeZSVq7iFatE Reply ·

[@prometheusengineeringgroup7825]

Here is another video for our loyal fans! This one breaks down the concept of shear stresses in beams! kzbin.info/www/bejne/nHvMe4xma86Lbbs

[@prometheusengineeringgroup7825]

Please see our latest video (on structural dynamics) kzbin.info/www/bejne/kKnZfXZjbpaEgdU

[@ParthPatel-vs7le]

Upload athors too

[@prometheusengineeringgroup7825]

Do you mean Textbook Authors from which the material is sourced?

[@ParthPatel-vs7le]

Prometheus Engineering Group Yes sir... Sorry for the spelling mistake

[@prometheusengineeringgroup7825]

Will do!

[@prometheusengineeringgroup7825]

Here is another video for our loyal fans! This one breaks down the concept of shear stresses in beams! kzbin.info/www/bejne/nHvMe4xma86Lbbs

[@prometheusengineeringgroup7825]

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[@masudrana3774]

this is good...

[@prometheusengineeringgroup7825]

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[@prometheusengineeringgroup7825]

Here is another video for our loyal fans! This one breaks down the concept of shear stresses in beams! kzbin.info/www/bejne/nHvMe4xma86Lbbs

[@prometheusengineeringgroup7825]

Please see our latest video (on structural dynamics) kzbin.info/www/bejne/kKnZfXZjbpaEgdU

[@crebbo9476]

good

[@prometheusengineeringgroup7825]

Here is another video for our loyal fans! This one breaks down the concept of shear stresses in beams! kzbin.info/www/bejne/nHvMe4xma86Lbbs

[@prometheusengineeringgroup7825]

Please see our latest video (on structural dynamics) kzbin.info/www/bejne/kKnZfXZjbpaEgdU

[@adamsmith3242]

Don’t see where this 2/3 x d/2 comes from. The mean stress acts at 1/2 x d/2 and the mean moment at 1/ 3^0.5 x d/2.

[@prometheusengineeringgroup7825]

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[@mersal898]

it is useful thank yooooooooooooooooooooooooooooooooooou i want that ----z describe distribution moment now i understand thank you i watched few video about it but that was no deep like this

[@prometheusengineeringgroup7825]

THANK YOU! and you are welcome

[@prometheusengineeringgroup7825]

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[@prometheusengineeringgroup7825]

Check out part 4 of the series on Beam deflection kzbin.info/www/bejne/n56zeZSVq7iFatE

[@ogagaritsesakpa5533]

I thought the bending moment is maximum at the supports, I really don't understand how the bending moments is represented on the cross section.

[@ogagaritsesakpa5533]

Also, how is it that there's linear change from compression to tension? What's the phenomenon?

[@calvoh9715]

@@ogagaritsesakpa5533 remember he said strains and stresses go in hand. in elastic range, strain and stress are directly proportional. strains occur most at extream ends of a section or longitudinally, along the top side and bottom side. this is where the stresses are extreme too in the material fibre. as you move from the top edges towards the middle(neutral axis), the stresses and strains reduce, the increase again past the mid-point (neutral axis) top strains and bottom strains are equal and generate a force that creates a turning effect and makes the beam deflect downwards. these forces are equal and opposite. one at the top tends to squeeze together the material i.e compression. one at the bottom tends to pull apart the material that is tension. the distance between them multiplied by either compression or tension results to moment.

[@muhammadhaeef432]

good mate u done a good job

[@prometheusengineeringgroup7825]

+MH hani Check out part 4 of the series on Beam deflection kzbin.info/www/bejne/n56zeZSVq7iFatE Reply ·

[@prometheusengineeringgroup7825]

Here is another video for our loyal fans! This one breaks down the concept of shear stresses in beams! kzbin.info/www/bejne/nHvMe4xma86Lbbs

[@prometheusengineeringgroup7825]

Please see our latest video (on structural dynamics) kzbin.info/www/bejne/kKnZfXZjbpaEgdU

[@stuartrobertson331]

how would you calculate strain in a beam from experimental data ?

[@prometheusengineeringgroup7825]

Yes. The experimental data confirms the elastic behavior and and the linear transition from compression to tension etc.

[@prometheusengineeringgroup7825]

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[@prometheusengineeringgroup7825]

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[@prometheusengineeringgroup7825]

Check out part two of the series on bending stress (moment of inertia} here: kzbin.info/www/bejne/hWPad2aOnZJ9d68

[@prometheusengineeringgroup7825]

Please see our latest video (on structural dynamics) kzbin.info/www/bejne/kKnZfXZjbpaEgdU