Beams - Example 1

Lecture Series on Mechanics of Solids by Prof.M.S.Siva Kumar , Department of Applied Mechanics ,I.I.T.Madras.
Analysis of beams
For more details on NPTEL visit nptel.iitm.ac.in
To access the translated content:
1. The translated content of this course is available in regional languages. For details please visit nptel.ac.in/translation
The video course content can be accessed in the form of regional language text transcripts, books which can be accessed under downloads of each course, subtitles in the video and Video Text Track below the video.
Your feedback is highly appreciated. Kindly fill this form forms.gle/XFZhSnHsCLML2LXA6
2. Regional language subtitles available for this course
To watch the subtitles in regional languages:
1. Click on the lecture under Course Details.
2. Play the video.
3. Now click on the Settings icon and a list of features will display
4. From that select the option Subtitles/CC.
5. Now select the Language from the available languages to read the subtitle in the regional language.

[@iitmssiva]

praman0: Do you think I should continue with this effort of putting up these videos on the net. What other topics do you feel you may need covered in Statics and Dynamics? Sivakumar

[@thatoneguy9102]

Sivakumar Srinivasan sir plz sfd bmd plzzz

[@thatoneguy9102]

sorry its in the next lec sir you are awesome your explanation is so basic

[@viveksharma8977]

You are best

[@mutiurrehman4418]

I came for Free Body Diagram. Modern Books gives so much focus on these in introductory lectures. and I ma a beginner.

[@aravindhvijayanandan3010]

Thank you very much, Sir.

[@manjulavani3515]

sir basics are clearly explained.students definitely get benifited.

[@praman0]

prof: shiva you have been doing a great job wit these videos. the other day , i did tell my dean how your lectures have been helping me out. we follow engineering mechanics statics 12th edition by rc hibler.

[@devrajshellagi9843]

Hey

[@viper3120312]

in the image at 40:43, why isn't the shear force pointing downwards if the face is to the left.

[@manishn403]

thanx a ton prof, it's really helpful... the best part is u make them look simple anyways thanx again..

[@akshaysaraf6865]

thank u sir! nptelhrd, I request u if u could add small animations in between to explain few confusing points then the total concept will be crystal clear for students! anyways, great work, thank u!

[@TheBelsi]

You should definetly continue the big effort, is has been a great help..

[@nanz2009]

This video helped me a lot .. thank you Mr Siva Kumar

[@Priyankgag]

this is one of the best prof. of iit

[@pratikmirgane333]

Thank you sir, today I understood the concept which was troubling me for 2 sems.

[@joseortega9712]

thank you sir.. this videos really really help in the concept of statics..

[@sarangeetam]

this video is very good to improve our basics

[@rajendra281]

Very helpful video. Thanks to you sir.

[@Senefleder55]

do u know? u explained much clearer than my lecture :D, and I've been understanding a lot at the time I'm watching this :D

[@sanket.tripathi]

Sir, i hav seen ur viseos which are vry great so plzz continue dis and sir iwant lec on flexural formula, area center n m.i of common cross section w.r.t centroidal n parallel axis etc... so if u cud plz help out..

[@immanenikarthik7565]

thank u very much sir its very usefull to one

[@therawscholar]

sir in the very first example the way you calculated the bending moment is very confusing as the sign convention which u have followed is totally different from the one which u have told earlier.

[@building225]

Thank you teacher.........^-^

[@slownightsolongg]

anyone know where I can find videos like this about distributed loads?

[@birudevsalgar8025]

Thank U...sir.

[@atuljha7622]

thank u so much sir

[@XC20248]

Prof. Siva Kumar I just wanted to know why at 25.49 is it -4P/3 and not +4P/3 when it is pointing in the upwards direction when x is also point in the +x axis direction.

[@harimyoldpal]

For static equilibrium condition, the shear force that was assumed to be along +ve y direction turns out to be -ve.Hence he has written -4P/3, you may as well denote the shear force downwards(along -ve Y-axis )and replace -4P/3 with a positive value of the same magnitude. Hope it helps :)

[@Nikhilkumar-on8vg]

I miss these old blackboard lectures of nptel. Lectures through ppt presentation or writing on paper is no match to old style

[@sahilrajeshgajbhiye4968]

tyvm sir

[@praman0]

i dont get the concept that my teacher here in oklahoma explains. his videos has been my only help..

[@shaantubes]

how is it one dimensional?

[@sittoonagesh6668]

Professor is talking about beam which is considered as 1D element. To make you clear, here only length along x is dominating over other two lengths (which are along y and z). Moreover, you can assume a curvilinear element as 1D for analysis as well. So now questions arise, what are the 2D adn 3D structures or elements. Suppose you are interested to solve a problem of plate (in which two dimensions are dominated over third) can be considered as 2D element or structure. And the last type of structures are 3D (all the dimensions are dominated), for instance, lathe machine, bike, bridge etc. Hope that this helps. Write us again for further clarification.