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Bellman Ford Single Source Shortest Paths Algorithm with Example

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Algorithms with Attitude

Algorithms with Attitude

Күн бұрын

Пікірлер: 10
@amitranganathan2015
@amitranganathan2015 7 жыл бұрын
At 1:03, shouldn't the path to B have a distance of -2?
@AlgorithmswithAttitude
@AlgorithmswithAttitude 7 жыл бұрын
Only if you know basic arithmetic. Which, apparently, I do not.
@ashutoshkushwaha5326
@ashutoshkushwaha5326 3 жыл бұрын
This video really makes the concepts crystal clear
@MCBPZ
@MCBPZ 6 жыл бұрын
great content! I love the enthusiasm!
@jTay111
@jTay111 5 жыл бұрын
shouldn't the x in O(|V|+x*|E|) be the number of levels in the shortest path tree with the greatest height since it's an upper bound?
@jTay111
@jTay111 5 жыл бұрын
great content by the way
@AlgorithmswithAttitude
@AlgorithmswithAttitude 5 жыл бұрын
After |V| levels, you will have all vertices in the graph, so for sure it is O(|V|). Of course, it is also O(x) for any x > |V|, but that is not as useful as the smaller bound.
@celstone
@celstone 4 жыл бұрын
Great video as always! Which shortest-path algorithm(s) do you recommend for undirected graphs that contain negative edges and fail via Dijkstra (see your Dijkstra video) or even contain negative-weight cycles (you mention it here: kzbin.info/www/bejne/bXyqoJt5ecqdZ9Um41s )?
@AlgorithmswithAttitude
@AlgorithmswithAttitude 4 жыл бұрын
Wow, I probably should have clarified that. Watching what I said, I had to think about it myself... If the graph is undirected, any negative edge reachable from the source vertex gives you a negative infinite path to everything connected to the source vertex, by just going to that negative edge, traversing it as much as you want, and then moving on. So, in an undirected graph, we could run Dijkstra, and if we run into any negative edge at all, just do DFS from your source, everything reachable gets negative infinity. Sorry it took so long for me to answer, I don't get too many specific content questions like this one. With the link to the specific time, it makes answering it fairly painless. This is how I envisioned answering questions when I put the videos up, and yours is a nice one.
@christianasnelngoulla9868
@christianasnelngoulla9868 7 жыл бұрын
ahahah funny & easy to understand :+1:
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