Biot Savart law (vector form) | Moving charges & magnetism | Khan Academy

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@@Devilhunter69 college tends to deepen what you learn in highschool in my experience. well actually i'm in university but anyway. i'm doing computer science so the physics level is closer to high school level but still bit higher than what i learned in highschool. it uses basically the same material but has more explanation and where the formulas are from and uses more calculus.

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@@tasneem6427 Around 4-8 hours! :)

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i ike the way u teach.. well explained sir.

[@gustavoteles5994]

It helped a lot. Thank u

[@user-cc7ks7re3w]

Sir one doubt, in the textbook and other sources the vector form of Biot-Savart law has r^(3) but yours is r^(2)... Can you please clear my doubt??

[@felixwegmuller351]

You have to use r^3 if you dont use the unit vector. the guy used unit vectors which is why he uses r^2. for more info you can look at the english wikipedia article about biot-savart

[@user-cc7ks7re3w]

@@felixwegmuller351 Thank you ☺️

[@oreowithurea5018]

@@user-cc7ks7re3w the other explained it pretty well, you can either use unit vector in the direction of radius to denote the vector for radius, or just simplify the unit vector which turns out to be *r* /r , plug this value instead of unit vector and you'll get the textbook equation

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Can you make a video explaining capacitors

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For each tiny segment, do we have to do a vector sum?

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[@kaushikb2819]

Hey here's a doubt, our NCERT books say idl*r^ ^3 but u hv written r^2 instead of r^3 so which one's right?

[@rinzler3202]

hello kaushik rcap can also be said as r vector . r = so it becomes rvector / r^3

[@hemavathy9806]

Did you mean by substituting r cap=(r vector/magnitude of r vector)?

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[@allison7612]

Isn’t this finding just the magnetic field as it is affected by the length of dl? So to find the total force applied on a single point you would need to do multiple equations? Or should you just use the perpendicular measurement (since it is where force is strongest) for an estimate?

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Sir can you make video on Capacitor RC circut?

[@Gitruv]

Is it r^2 or r^3 in vector form, i am confused.

[@demonking2508]

shouldnt it be r3 up

[@chetanganachari4882]

Sir in NCERT it is given that in vector form the distance is r^3 but you mentioned it as r^2...please clarify it

[@TripuriansYT]

We know r is a unit vector So, r^ = r(vector)/ |r| Or, r^ = r(vector)/r Since, |r| = r So, put the value of r^ then you get r³

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0:01

[@namenotfound1118]

why only dl vector cross r vector why not r vector cross dl vector. Could anyone explain or which one of your videos explain this?

[@whitedaisy2263]

Concept: Vectors - Cross Product Suppose we have two vectors, A=2i+3j and B=4i−j where i and j are unit vectors along the x and y axes, respectively. The cross product A×B is given by: A×B= ∣ i j k ∣ 2 3 0 4 -1 0 Now, calculating the cross product; A×B=(3×0−(−1)×0)i−(2×0−4×0)j+(2×(−1)−3×4)k we get: AxB =0i-0j-12k A×B= −12k. [It is in the negative z- axis] But in this case if we do B x A: By doing the same method again as shown above but putting values accordingly. Mathematically the relationship is expressed as: B x A = - ( A x B ) A x B= -12 (as calculated) B X A = - (-12k) = +12k [it is in Positive Z axis] Difference in the direction!! Similarly, we cannot write r x dl.

[@EmpyreanLightASMR]

If physic were taught by Disney (i'm referring to the stellar handwriting) :D

[@catherinefernandez9654]

Why is it r^3 in my textbook not r^2..

[@joenuts3308]

In his equation, he has taken the unit vector of r that is r cap. But in textbook it is vector r which is equal to the unit vector times the magnitude of r so we have to multiply r on numerator and denominator to get db = μ0/4π x I dl × vector r/r^3

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Beo savar law😳

[@saurabhkapse697]

In India we pronounced as it is given in book like biot savart law 😅😅

[@iqraafzal517]

I appreciate your efforts. But you lacked in explaining why magnetic field changes when we change angle. You just explained the effect but skipped the cause...!

[@whitedaisy2263]

Watch previous videos.