Block Diagrams

An example of drawing a block diagram to represent a difference equation

[@mightyparry]

This is exactly how my prof wants us to draw it but his explanation is a super rushed. This is great, love the color illustration. Thank you!

[@glennmacionJIKInc]

thank you so much for making this sir.... you have a great day....

[@ErrorNameNotFound123]

Thanks for the great video John! I can finally live up to my profile pic.

[@Q_98]

i was struggling with this so much until now, thank you!

[@caochloe7023]

Thank you so much!

[@edsonsumbane124]

Best Coach

[@mordehaym3239]

How cam we combine these two big blocks(the forward and the feedback blocks)??

[@omar0553889776]

.. thank you for posting helpful video

[@ProfJohnBuck]

+Ibn Shehab You are welcome. I originally made these for students in my class - it's a great bonus others find them helpful.

[@rathumnoyes4014]

easy to understand, thanks.

[@alireza_mhda]

Thank You, It was great👌🏻❤

[@neelkamalsemwal4072]

Thanks dude..it really was a simple explanation..

[@melusishoko6809]

Thank you so much

[@Peacefulness-AM]

This's amazing . Thank yoou soo much sir!!

[@muhammadwaqas8389]

THnk , Great Explanation Sir

[@SuatKara]

clear! Thank you so much sir..

[@alberto8899]

Sir, thanks for your video!

[@christoffere425]

when you say that you add a "scale" what is that block actually called? Or is it just called a "scale block" when you multiply?

[@ProfJohnBuck]

Hi Eric, There are different names for the block: "scaling block" "gain" "gain block" "amplifier" or "scaler" all get used to describe a block that multiplies the input signal by a constant to produce the output.

[@christoffere425]

@@ProfJohnBuck Thank you! By the way, how can you see that we need a "delay block"? and how long is that delay?

[@christoffere425]

is a delay block the same as writing Z^-1 ?

[@ProfJohnBuck]

Yes. A delay by one sample in time corresponds to multiplying by z^-1 for z transforms, so this is sometimes used as a way to indicate a delay block.

[@christoffere425]

@@ProfJohnBuck so [n-2] equals z^2 then? and z^1 is [n-1]?

[@ProfJohnBuck]

@@christoffere425 Yes. A delay of 2 in the time domain, i.e., x[n-2] becomes multiplying by z^{-2} for the z-transform, so x[n-2] becomes z^{-2}X(z), and similarly for other delays or other signals. y[n-4] becomes z^{-4}Y(z) when we take the z-transform.

[@fatihmehmetkaya3321]

Thanks, very very great explanation!!!

[@ProfJohnBuck]

Glad you found it helpful.

[@airsh0w]

Thank you for the help!

[@almutassim1]

Thanks so much Sir

[@kingcobra777]

Thanks, great explanation!!

[@ProfJohnBuck]

+lewis nesbitt You're welcome.

[@adityajoshi6524]

it helped a lot thank you...!!!!!

[@ahmadhasan8355]

Thanks so much.

[@randomthoughts2721]

love you

[@mernaemad2356]

hello could you help me please ? do you have fb?