Boolean Algebra and Theorems tutorial

[@tanudhanvi5812]

this video helped me in my exams sooo thank you so much...

[@nadujayawardana7820]

THANKYOU SO MUCH.IT HELPED ME A LOT.THIS GAVE ME A GREAT SUPPORT IN MY EXAMS

[@sophiasarikaya3614]

THIS VIDEO IS TOO MUCH HELP FULL THANKS RESPECTED SIR

[@james77011]

This is a wonderful video... Thanks a lot

[@rolandodiaz6139]

I learned a lot here. but last problem should not be... AB(A(2bars) + BC(bars)) = AB(A(2bars)) + A(B(Bbar))(Cbar) = ABA + 0 = AB ??.. Anyways, in the upper diagram it does not matter what C is, as long as A = 1 and B = 1 then Y = 1. otherwise Y = 0.

[@jzmistymorning2967]

+eTechTom 19:10 can't you then go AbarBbar + AB (can't we swap around the A and B due to commutative law?) would then be 1? Or am I missing something here?

[@shudipttashuvro8950]

That was so helpful ...thanks :)

[@gauravawad8926]

nice easy to understand

[@70abod]

you are the best!

[@omrsd]

Can you please also explain the Absorption Theorem?

[@ThuyNguyen-bu9ge]

For the last problem: AB(Abar + BC)bar, wouldn't the circuit diagram for that have an inverter at the tip of the OR gate?

[@tmc200527]

+Tiffastic Nguyen You are correct. Thank you for catching that. I have added an annotation indicating the error.

[@engrxtianbautista]

Is the boolean algebra in 20:52 correct? hmm

[@tmc200527]

Christian Rey Bautista Yes. First use DeMorgan's Theorem to break the inverter sign over the two terms. That gives you A double inverted and with BC inverted. The double inversion cancels giving you A. You now have ABA AND BC inverted . ABA=AB. Use DeMorgan's Theorem to break BC inverted to B inverted OR'd with C inverted. And that expression with AB. That gives you AB AND with B inverted OR'd with AB AND with C inverted. The first term goes to zero because B AND B NOT = 0 leaving just X= AB C inverted.

[@james77011]

Nice video but, he moves to the next slide to fast when done with something...

[@shudipttashuvro8950]

That was so helpful ...thanks :)