Boyle Temperature

At a certain temperature, known as the Boyle temperature, a real gas behaves ideally due to a cancellation of non-ideal effects.

[@rajnibala5963]

From India, helped a lot for school thank you ❤❤

[@diligentmist23]

life of jee Students like us! btw which class r u in?

[@andrewjustin256]

Mr Steven, I have seen a large percentage of your videos where in Compresssibilty Factor, you wrote it as Z=PV/RT instead of Z=PV/nRT. Why is it so? Similarly you did not include number of moles in Van der Waals equation while deriving the equation for Boyle temperature?

[@sashacn1518]

It’s because the volume is molar volume…

[@PhysicalChemistry]

@SashaCN is right. Pay close attention to when I use V (for volume) and when I use V-with-a-bar-on-top (which is molar volume). This difference between volume and molar volume is introduced in this earlier video: kzbin.info/www/bejne/q2i5gJhqlMegh7c

[@g8ming4noobs32]

Subscribed! Many thanks

[@PhysicalChemistry]

Great, thanks

[@vardaanpahariya]

Thanks a lot! You explained it really well :D

[@johnkimuelbello3453]

Thank you so much!

[@PhysicalChemistry]

You're welcome!

[@ekingursoz]

thank you!!

[@PhysicalChemistry]

You're welcome!

[@chamalikodikara2290]

Thank you this helped a lot

[@PhysicalChemistry]

That's what I like to hear!

[@jineshajalathge4144]

Thank you so much..

[@PhysicalChemistry]

You're welcome, thanks for the comment

[@shashitomar7466]

Thank you sir

[@PhysicalChemistry]

You're quite welcome

[@joemama-wx8zv]

thanks

[@PhysicalChemistry]

You're welcome

[@sussushi]

sir in my text and on the net boyles temp of nitrigen is given 323K ie 50C

[@PhysicalChemistry]

Yes, you're right. 325 K is the experimental (correct) Boyle temperature. The equation used here shows how to predict the Boyle temperature from the van der Waals model. Since the van der Waals model is just a model, it's not always accurate.

[@sussushi]

@@PhysicalChemistry oh ok thank you so much

[@legendofrandomness2522]

Tyy

[@PhysicalChemistry]

yw

[@方佳怡-f8f]

Thank you so much

[@PhysicalChemistry]

You're very welcome