Reaction Rate Laws

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[@angelicawatkins8602]

This was much more helpful than the lecture class I paid $1500 for,

[@lixx1414]

+Angelica Watkins this is so so sos osososososososo true...like what are we paying these people for you know??? especially Pogil ??

[@tiannaduffey9050]

use rate my professor

[@thatonedevastatingleek380]

Angelica Watkins yeah because rate law is high school chem and ur teacher assumes that you know that as highschool chem is a pre req to higher lvl chem lol

[@MissAdanna13]

no its not. its more so AP chem...

[@Emk315]

I ask the same thing.

[@surfnbrettb3452]

She is making it fast so it isn't like a 15 minute video. It is for the person who wants to get to the point without lots of time being spent. Teachers teach long lessons, youtube is for the quick review of what you learn in class

[@kodymontes2017]

And, for all the people who are saying that she is talking too fast: if you notice, all of her videos are under 10 minutes in length, so she has to compress half an hour of lecture to within ten minutes meaning that she had to rehearse this video and talk faster than usual in order to fit it into a ten-minute timeframe. You might have to go back and watch it a few times, but that is how this format works.

[@alvin117799]

For anyone confused on how she derived "n", she uses: natural log (ln) 1/4 divided by: natural log (ln) 1/2 = 2

[@hiram1336]

The Observer thankyou😭

[@hinachan6298]

Hira Mazhar and how’d she get “m”

[@hiram1336]

Hina Chan log(1/2) / log(1/2)

[@cloverplays1706]

Hina Chan you just have to make the bases same!

[@freefiresam9457]

@@hinachan6298 by division of trial 1and2ofA=rate of trial A

[@sandragonzalez443]

Thank you sooo much. I wish you were my actual teacher, because my teacher doesn't really explain and then expects us to be able to take a quiz on it the next day..

[@zore4686]

Perfect explanations! Thank you so much!

[@ProDxB]

thank you very much. the video was full of detailed information and clear notes. keep up the good videos.

[@brightstorm]

+ProDxB Happy to hear that. We upload new videos daily Mon-Fri. Subscribe to our channel(bit.ly/1kVXqu6) for updates!

[@lalilali8513]

+Brightstorm this was amazing... u cleared alot.. but theres one thing which i stilll didnt understand why did we divide them by o.oo1 on both sides....plss do reply rather than that ur video was excelllelent😃

[@abduljawadgalib]

+Brightstorm Can't access this video in HD

[@yosefkap]

kaity dean [A] is 1st order, so it's value is (.1) ¹ =.1 [B] is 2nd order so it's value is (.1)² =. 01 .01 x. 1 =. 001

[@crazzydaissy7915]

Yosef mendel Kap a litttle late but thanks😃😃

[@smartaleck05]

You just explained 50 minutes of lecture in less that 10 minutes. Thank you. :D

[@kodymontes2017]

My professor would probably be offended by me saying this, but I watch your videos to learn chemistry because he may as well be speaking Latin when he talks. Thanks for uploading these videos

[@ShyanTheLegend]

do you go to university

[@Sam2260my]

Great video... One thing though. When you were finding what m and n were, you skips the steps that shows how to transpose the equation for [ B ]2. For newbie, that may have been a bit confusing to figure out how you got the equation : (.100/.200)m =(2x 10-3/4x10-3) Really appreciate the video, its pretty detailed... Please keep making more.

[@luffymonkeyd7029]

Can't believe those people asking you to slow down, im so happy that I found someone like you who doesn't blabble for 20 minutes and that gets straight to the point and fast. Absolutely love it !! Thank you

[@elenacalvillo158]

This video was certainly helpful! Thank you so much for taking the time to make this review to have clearer understanding for us college students. General Chemistry does get harder!

[@sonyapegues5658]

Nice...clear, concise and to the point. Thank you clearing up the units. I was just gonna skip that part on the test. Got it now.

[@kassymartinez8636]

if you think she's talking too fast you can change the speed of the video by going to the bottom right corner of the video, click on settings and change from "normal" to "0.5".

[@srsrcinemas5877]

It works great😀😀 I change it into 0.75

[@srsrcinemas5877]

Thankyou....

[@jamieomalley453]

Thank you for making this video; it's helping me prepare to teach HS chemistry. Your obvious intelligence is impressive!

[@MayBlaze0]

very helpful. thanks. I have a test tomorrow and i didn't know what i was going to do because rate laws was one think i couldn't understand.

[@christineantonio7589]

Thankyou so much! You're videos are the only studying i look forward to after school . I love your teaching method and you make everything seem so easy.Go Brightstorm- and this chemistry teacher!

[@1elitefighter]

Extremely helpful, I have an upcoming quiz and didn't understand anything from lecture. The explanation here is much clearer, thanks a lot!

[@josephrappold]

Great video, helped me lots! Thanks!

[@jonofthesnares]

It took just over 9 minutes to help me understand something that my professor has yet to be able to do in a week! Awesome video!

[@zainabz5365]

hi dr... please answer my question :: a solution of adrug contained 500unit/ml when prepared it was analyzed after 40 days and was found to contain 300unit/ml assuming the decompostion is first order at what time will the drug have decomposed to one half of its original concentration?? how to be the right solution???

[@Bigfootuss]

this is very educational! thank you very much. i have a test in 30 minutes and for 9 minutes i learned more than i did for 3 weeks

[@pruehealy5215]

Thank you! Struggled with this for awhile as I couldn't find anyone who would break it down sufficiently.

[@AzhunkWorld]

Thank you, this video explains clearly on how to calculate rate order of each concentration of ion and how to calculate the overall rate constant. It helped me in finishing my chemistry laboratory report.

[@TheDieHard777]

Man, thank god for KZbin. I understood bits and pieces in my teachers lecture, but this made it much more clear.

[@MrThenewdude66]

put 3 days of work into a 9:16 minute video.

[@francisgregoryku1689]

Fast, Clear and Direct to the point. Perfect for Reviewing and Last Minute Studying.

[@offwhitey]

Hey! At 5:30 how do you get from 1/2 and 1/2 to 1, and 1/2 nd 1/4 to 2? Sorry if I'm being stupid but I can't seem to get a whole number with my example question

[@ricodiaz8099]

haha dude thanks for asking cause i'm wondering too

[@offwhitey]

If you were wondering how she got to second order: Think of n being the subject of the equation, change the fractions into decimals simply for clarity. You are then left with, n = 0.5/0.25 n= 2 Simple as that :)

[@MrFatperson]

If you know how natural log works then you just take ln of both sides of the eqn. m*ln(0.1/0.2)=ln(1/2) m = [ln(1/2)]/[ln(0.1/0.2)] m = 1 Her examples were easy enough that you can do it intuitively but for more complex problems you gotta use ln.

[@1994ours]

guys just flip the numbers and it would fit perfectly without using ln just divide the big number over the small one and you would have the correct number

[@superJohnnydeppfan]

it's ln(1/4)/ln(1/2) to get x=2

[@ikarelis]

Just wanted to thank you guys for explaining it so well!!

[@seismicc]

Yea this video helped more than a year of chemistry with Ms Trela.

[@nateewing600]

What up yi

[@seismicc]

@@nateewing600 hello Nathaniel Ewing

[@yuri778]

Thank god for this. Needed a refresher as this just popped up for the first time in 2 years.

[@HauzPlant]

I swear you are an angel...i struggle with these problems last week ended up not finishing my HW...after i watched your videos, i sailed through those problems!...Thank YOU

[@cooltop1]

I watched 7 videos... and this is the BEST!!.... She is SOO much better than all 5 of my chem teachers...

[@reena3124]

Wonderful explanation... Simple....

[@spaingirl87]

Where have you been my entire life in college? I am studying for the OAT and you are soooooo awesome. I love how simple and easy you explain everything and with great depth to where anyone can understand.

[@lauryn1190]

Whaaat you were doing this in college? I’m doing this in high school right now

[@HeyDeeXoxo]

Wow, this was really clear and helpful.

[@mehtaflix7598]

Absolutely 👍👌

[@wheremakeysat]

Amazing job, this saved my grade

[@youssefazouz]

Calculate the rate of words/secs of this instructor answer:39/sec

[@edahphiri9742]

Great presentation! Really helpful... I need to watch more of your videos.

[@BenedictaEzike]

She explained this better in less than ten minutes than my teacher did in over two hours.

[@beybladematters7107]

Thanks Mam it really helped me out

[@aakaashkodati9285]

She thought order in a great way, previously I saw many vedioes but I little bit of confusion is get pending by this she had cleared all my doubts

[@Ferdinaand]

This is a fantastic video of you've learned this before and are looking for clarification / review

[@ali_jeez53]

Thnx alot and btw the ppl who are bitching about the vid quality (it was uploaded in 2010 where 240p was the standard) and if you find it fast paced just change the playback to 0.75 as I did and it helped me alot.

[@ibrahimomoyayi9325]

thank you very much dear... I only knew how to get m and n by mere thinking or reasoning.. now I know there is a calculation for it.

[@TarzanInScrubs]

Just failed a quiz over this- wish I would have watched this video sooner! Thanks for the help, I'm defintely getting this question right on the test!

[@MisterSML]

thank you for all your help. this comes might handy the day before finals!

[@binashbobby8891]

Great video.....You made it easy with detail explanations

[@varun009]

what you're referring to is the order of the reaction. this is not the rate of the reaction itself. that 1/2 that she calculated was the ratio of the first concentration of a to the second concentration of a raised to m which was equal to the ratio of the first rate of reaction to the second rate of reaction. since m is an exponent we needed to prove that 1/2 raised to m was equal to 1/2 hence finding m. since anything raised to one is that number we say that m was equal to 1.

[@prateeksrivastava4112]

thanks for this video this video is really helpful for me it make my concepts more clear

[@viviananica3775]

Thank you! This really ties this chapter off and I can understand the lab we are doing today.

[@chiuuuuuuuuuu]

its was so confusing when I first learn in school. but now i understand it thank you so much!

[@xhesidap6990]

very helpful and to the point, thank you

[@xMyShatteredDreams]

Omg now I know how to find the order of reaction. I like your way better than my lecturer way thank you so much.

[@EntFunny]

Hi, how can does this work when non of the concentrations stay constant and changing at the same time

[@mohammedsami220]

Thanks for nicely explaining I am Indian people very very thankfully

[@plantbasedkavin]

This video helped me alot, thank you

[@lidiyaz.7354]

It makes so much more sense now. Thank you!!

[@ragabanation]

You are the best , because you are so clear and you don't leave a single thing out. Thank you!

[@melodyh8807]

I can learn more in less than ten minutes for each chemistry subject with these videos, than I can in my actual chemistry class.

[@FallenSkater1940]

at 7:00, why is [B] squared? i thought it was first order in trial 1

[@musicology101]

Exponents and logarithms helped me here. The first question was what is her ratio of concentrations. it was 1:2 (.1M of A, compared to .2M of A) and then looked at the difference in her rates of change 1:2 as well (2e-3 compared to 4e-3). 2 to 4 is the same as 1 to 2... so we ask ourselves, what number do we raise 1/2 to, to give us 1/2 and that number is 1. Yet when we looked at [B] we saw the rates went from 4, to 16! and we had only doubled our [B]. So we need to compare the 2 values again.

[@lukep4714]

Wonderful Video, Very helpful, 150% better than the other videos or textbooks out there.

[@jnaswor4]

Amazing how simply you put this. Great job!

[@nattcattt]

Wooooow thank you so much this makes so much more sense now. I was trying to keep awake in lecture this day and I couldn't make sense of any of it, but this was a huge help. Thanks so much!

[@prayersgono3518]

You are amazing ...l was cracking my head trying to understand this .May God bless you richly

[@stevecollet9884]

Very direct explanation..soo helpful thnks

[@GroundZ3R0Gamer]

i was so lost when my teacher did this but she explained it like a pro and now i understand. THANK YOU

[@nyleesianicome4325]

Very helpful once again.

[@mingoliver1608]

thank youuu so much i finally understand it after 1000 vids and 3 books you saved me

[@wintercast1337]

this is so helpful

[@alexanderanguiano2961]

I was taught the same steps but that it was final over initial (with both rates and concentrations. So my professor taught me that it was Rate 2 over Rate 1 = k [A]final^m [B]final^n all over k [A]initial^m [B]initial^n. Help me please

[@footprints2012]

You are literally saving my Chemistry grade! Thank you so much!

[@nannyb1234555]

words can't express how happy i am to have found this channel! omg thank you sooo much!

[@kejikubari]

Super helpful! Thanks so much!

[@juggly1238]

Thank u so much I'm really bad at chem but i understood the explanation really helpful

[@tommydennen9563]

Love your videos! but PLEASE film in higher resolution, I can barely read the board!

[@akankshasrivastava9710]

Thankyou so much Really helpful video.........👍😊

[@LAKLAND5502MAN]

You use log rules. If you take the natural log of both sides, you can bring the exponent down... (1/2)^m=1/2 take natural log of both sides ln(1/2)^m=ln(1/2) because of log rules, the exponent "m" becomes coefficient m x ln(1/2)=ln(1/2) divide to get m by itself m=ln(1/2)/ln(1/2) m=1

[@cynthiav9774]

SHE'S AWESOME. I've been trying to understand this forever!

[@webbjsabrina]

This is a much easier method than the one my teacher taught me. She wants us to make a graph to using the integrated rate laws every time to see if what order of reaction it is.

[@uzmagulnaz]

thank you sooooo much!!! I was so stressed becuase I didn't know how to do it before! you are amazing

[@cassandraolsen875]

She was solving for “m” in the equation. So the problem was: (½)^m =½ You can probably see intuitively that for ½ to equal ½, then “m” must equal 1 (Any number to the first power equals itself). Alternatively, you can prove that m=1 by solving with logarithms. :)

[@funnyviralespn5878]

thanks but do you have a video on how to work out the initial rate plsssss

[@TheNurseAaron]

Can you explain how you determined the order for [B]^n? I 'm not understanding what you're doing to get [B] is 2?

[@satellitel305ds5895]

quick and insightful...... why aren't all teachers like that? short and to the point.....

[@RosaLopez-cw8me]

Could you have compared experiment 1 and 3? Or can you only compare experiments that are in numerical order?

[@Sam2260my]

at 4:43, you said the rate of reaction for [a] is 1 although the answer was 1/2 ^m = 1/2. Why is the rate 1 when you calculated it as 1/2 ?

[@azooz4fun]

Wish you emphasize on why we chose trials to find m and n. But great explination.

[@ditt0nee]

Aah thank you so much! i was so confused before from other tutorials.

[@AG-xi8mn]

Wish I would've seen this earlier! so helpful!!

[@malona23]

because you have 1/2 on each side and to isolate the variable "m" you must take the reciprocal and mult. each side by 2/1 which gets rid of the 1/2 on the "m" and turns 1/2 on the left to 1 because 1/2 x 2/1 = 1

[@anthonysaintlouis3217]

Thank you very much, great video! Chemistry II is tough for me!

[@SeemaK]

Hello professor, For the reaction A-->B and 2A-->2B, do we get 2 different rate constants (irrespective of the reaction order)?

[@martinlimwengo8606]

Thanks so much Madam Chemistry.

[@jaelonrutley87]

could you please explain to me how I go about choosing which trials I'm going to use ? if I was looking for the order of a reaction with respect to A , same for B

[@hitecfeatures7462]

thanks it,s helpful video

[@lixx1414]

YOU ARE AWESOME!!! I am in analytical and we do pogil :/ so we have to figure all this out by ourselves..and at the end of the class...we've learned ....some things but ....we never know how right it is.

[@LettuceCoke]

Very clear. Thanks!

[@cloverplays1706]

A 9 years old video helped me alot thanks alot!