Brooklyn Brain Teasers | Brooklyn Nine-Nine

BONE!
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ABOUT BROOKLYN NINE-NINE
"Brooklyn Nine-Nine" follows the exploits of hilarious Det. Jake Peralta (Andy Samberg) and his stoically ever-professional captain, Raymond Holt (Andre Braugher), along with their diverse, lovable colleagues as they police the NYPD's 99th Precinct. In this final season of the series, Jake and the squad must try to balance their personal lives and their professional lives over the course of a very difficult year.
Rounding out the ensemble is Sgt. Amy Santiago (Melissa Fumera), who has a passion for organization and a weakness for dork dancing; Lt. Terry Jeffords (Terry Crews), a mountain of a man whose most powerful muscle is his sweetheart; Jake's best friend and human puppy dog, Det. Charles Boyle (Joe Lo Truglio); and the incredibly secretive, tough-as-nails Rosa Diaz (Stephanie Beatriz). Also part of the Nine-Nine are veteran officers Det. Scully (Joel McKinnon Miller) and Det. Hitchcock (Dirk Blocker), whose only skill as police officers is their ability to make a passable pot of coffee.
Created by Emmy Award-winning writer/producers Dan Goor and Michael Schur, "Brooklyn Nine-Nine" won the 2014 Golden Globe Awards for Best Television Series - Comedy or Musical and Best Performance by an Actor in a Television Series - Comedy or Musical (Samberg). Emmy winner Braugher earned four Emmy nominations for Outstanding Supporting Actor in a Comedy Series for his role as Capt. Holt.
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Welcome to the OFFICIAL Brooklyn Nine-Nine KZbin channel. Here you'll find the best moments from Jake, Amy, Boyle, Terry, Holt, Gina and Rosa. Nine-Nine!!

[@jameswest9388]

Andre Braugher has one of the best voices of all time I swear. The way he says “Detective Diaz” in the Bone rant is just epic.

[@VANhasVOICE]

I still get chills when he screams VINDICATION! xD that was so MUCH emotion in one word xD

[@CortezHoratio]

Velvet. Thunder.

[@AnnoyingAsianWitch]

According to the podcast, he was mainly a dramatic actor in reality but he wanted this gig just to understand how the cast manages to improv and adlib on the fly. So in a sense, Andre really is Holt.

[@areebasad7032]

@@AnnoyingAsianWitch ??.?

[@maxvogt3515]

“Greeting, All.”

[@robynalexandra]

How dare you detective Diaz? I’m your SUPERIOR officer! I just can’t.

[@TheFLAMEXD]

Robyn K Bone!

[@basedbattledroid3507]

Just how he gets so mad at Rosa but he still takes her advice anyway.

[@shogrran]

BOOOOONE!

[@lennon30790]

whatdidusay?

[@ilyaszainal3899]

Seriously, what's so funny about it?

[@lostinthewoods2010]

Kind of amusing that Jake doesnt show up in any of these brainy bits 😁😂😂😂😂

[@ron.c0re]

lost in the woods They film it again and again until they get it right.

[@arhamhasan6485]

I’d love it if he showed up on them and got it right immediately

[@yatindrakumar4676]

And the fact that there's Hitchcock and Scully

[@therecklesswarlock6439]

jake doesn't show up is, he'd just figure it out on the spot.

[@arpitdas4263]

He has none

[@jimhirsby7154]

That whole Monty Hall story might have been the single funniest subplot in the entire series.

[@Bergen98]

It was. I actually rewatch the whole story sometimes, because of the BONEEEEEEE

[@maacpiash]

*BOOOOOOOOOOONE??*

[@jameswest9388]

BOOONNNNNEEEEE!!!

[@sentostar]

*_How dare you Detective Diaz I. Am. Your. SUPERIOR OFFICER!!!_*

[@MrDrElectricon]

funniest subplot in television history.

[@badjokes1016]

how did they film the "BOOOOOOOOONEEEEE" scene without SOMEBODY giggling?

[@goodisgood153]

Oh the people on the set probably giggled all the time. The actors just have so much iron will not laugh in acting such a funny scene.

[@dendaems96]

they learned it from monthy python. biggus dickus

[@optimaltt6070]

Well, there were multiple cuts between each "BONE!", so they only REALLY needed to keep a straight face for a few seconds at a time; combined with them being skilled/trained actors, and it's easy to imagine.

[@tylermellors4506]

Bad Jokes 101 the first BOOOOOOONEEEEE they filmed it 4 times before no one was giggling

[@dr.s.choudhury8089]

BOOONNEEEEE!! 😂😂😂

[@tastyboogeryummmymmmm]

Aww it made me sad when Scully was talking about his dad as a korean war prisoner and then got cut off

[@ollyravenhill7341]

Declaration of Independance yeah the poor guy

[@gloriouswaterbottle8968]

I really want to know the full story ngl

[@lavaot5207]

Yeah Gina is quite a jerk

[@Tiffany-ov2jf]

@@lavaot5207 I mean Gina is a meanie and very sassy that's just her character

[@mermidion7552]

Not me, i wish Scully and his Partner would get "cut off" from the series completly, i think there wasn't a single time where there were not Cringy

[@malaikarana9612]

I'M TEACHING FATHER THE MATH! 😂

[@hainsay]

Captain Dad is just my boss

[@marco-ws7bq]

what? those are our dads!

[@kwdkwon]

Ok Rosa

[@totheendandbeyond]

@@kwdkwon *OK ROSA*

[@akroplex699]

*G R O S S R O S A* Those are our dads!

[@joejoe9163]

I've never noticed before that at 0:27 Scully and Hitchcock have marked their side of the pizza 😂😂

[@ndirangugichuki6260]

😂😂😂

[@mozi11a90]

Omg holy crap yeah. Nice find Joe Joe

[@emadalmoalem1326]

🤣🤣🤣

[@pratikparikh8027]

You need to be on the 99 team man!

[@robertwilliamsonsbathrooma1034]

It looks like it says NHS

[@basedbattledroid3507]

"You use the see-saw to press down on their necks until fatty confesses." "Incorrect... and disturbing."

[@ali94hn]

Isn't a seesaw a playground thing?

[@Goldy01]

@@ali94hn Yes and it's usually made out of metal or wood, which is perfect to press down on some fatty's neck lmao

[@ali94hn]

@@Goldy01 lmao

[@ali94hn]

@@Goldy01 but what if there is no fatty? What if the odd one out weighs less than the others? Lmao

[@Laura-hn3tf]

I laughed out loud when I heard that

[@demoneddrogade6968]

Plot twist: holt's mentor doesn't know the answer either.

[@scottunderwood839]

he was asked by his mentor and its just a vicious cycle going round and round and round

[@konodioda7755]

Lmao

[@aakarshasoka6335]

I know the answer. Let one guy stand in one side, and keep swapping out the guy in the other end. If our constant has the equal weight, then everyone except the imposter would give us a balanced see saw. For the imposter, the Direction in which the see saw falls is the answer. If the constant is the imposter, then after the second guy the answer would be obvious.

[@jean-thecrazyone8267]

That would work in a regular setting but the riddle states that you could only sue the scale three times . I believe that there is a ted Ed video about this riddle. (They swapped people for coins )

[@danielshore1457]

@@jean-thecrazyone8267 split the group in half to have 6 on each side which other side weighs down you split that group into 3 each and then the side that is heavier you put one person on each end if its equal its the person who isn't on the see saw if they are on the seesaw it would tip to one end

[@nafridemmahom8391]

Holt:You're fired! Amy: what! Rosa: he he 😂😂😂💕💕😂😂

[@edofluit6568]

cancerous emoji's

[@joemanekshaw3013]

Edo Fluit indeed

[@asthabhardwaj6103]

Gina: Rosa my mind is ready *literally one second later* Gina: Uhhhh I'm so bored i cannot do it - Me trying to study

[@3kylajsmith]

I usually start strong and 30 secs later start chanting "too hard, too hard."

[@smartkyler391]

Too accurate...

[@denji5426]

@@3kylajsmith that's what she said... i couldn't resist

[@SmilingCorpse]

@@denji5426 If you didn't say it, someone would have. Thanks for taking one for the team.

[@SuryaGupta-te7fq]

They shouldve picked a harder problem, complete dummies could figure this out in ten seconds. Balance 6 people on both sides, pick the group of 6 weighing down the seesaw. Out of those 6 balance 2 on each side, if they weigh the same you know the abnormality is one of the two remaining not on the seesaw, and if they dont weigh the same you choose the heavier group of 2 once again. with the last 2 remaining people use the seesaw for the third and final time to see who is heavier. Easy, problem solved. Holt and Amy really arent smart at all in the slightest if neither can even figure this out, now all their rantings seem to me like two dummies that are trying to convince you they know math and they are smart. Neither is the case.

[@sparriax3379]

2:30 Amy: “believe me, no one is more disappointed in me than me” Holt: “than I, Santiago” Amy: “...” *That level of disappointment must’ve peaked*

[@captainbritain7379]

I felt so bad for Amy in that moment, because she’s actually right. It’s only “and I” when it’s in the nominative case.

[@wordplay1527]

Cliiiiiiiiick

[@darkviper1875]

*Cliiiiiiiiiiiiiiiiiiiiick*

[@miakarl8429]

​@@captainbritain7379 edzźż

[@SuryaGupta-te7fq]

They shouldve picked a harder problem, complete dummies could figure this out in ten seconds. Balance 6 people on both sides, pick the group of 6 weighing down the seesaw. Out of those 6 balance 2 on each side, if they weigh the same you know the abnormality is one of the two remaining not on the seesaw, and if they dont weigh the same you choose the heavier group of 2 once again. with the last 2 remaining people use the seesaw for the third and final time to see who is heavier. Easy, problem solved. Holt and Amy really arent smart at all in the slightest if neither can even figure this out, now all their rantings seem to me like two dummies that are trying to convince you they know math and they are smart. Neither is the case.

[@risaarsadi]

Amy’s facial expression during the entire BOOOOONE scene is priceless 😂

[@scarletsky2614]

I love how at BOOONE Amy goes through despair while Rosa explores the varying stages of not giving a fuck

[@ssssophieeee]

BOOOOOONEEEE?!?!?!?!

[@maureenchibaya7348]

And she looks unbothered

[@lnzekro6987]

I know but its so funny

[@scottish-hero6664]

Who was unbothered? Diaz or Amy? Cause Santiago’s reaction to that was hilarious like she was just shown the backstory of batman, Amy Santiago DLC

[@soupboi2448]

how dare yoU DeTEcTIve DIaz I am your suPERIOR OFFICER

[@darshans583]

Don't ever speak to me like that again

[@seanharmon713]

“There are three doors, behind one of which is a car-“ “-you’re telling it wrong. There are three doors, behind one of which is a car...”

[@guilhermeferrao5968]

Yep. Few people ever mention this. What an underrated joke

[@mrseveneight5355]

Holt said "There are three doors behind which is car" whereas it's one of which so technically he was saying it wrongg😂😂😂 Also r/iamverysmart

[@justanordinaryguy658]

@@mrseveneight5355 also, you're wrong 😂 he didn't say that, he said it correctly

[@ramiros_benitez]

I love the Rosa's reaction when the captain says to Amy "you're fired"

[@soggybread6393]

9:14 the fact that amy curls up in her chair and freaks out makes the scene even better

[@muskaangupta8546]

Scully is such a sweetie no one should be rude to him.

[@chatonsacrement7454]

Right? He's so talented, man can sing, decode morse and fake a heart attack like no one. 🥰

[@TeddyG221]

hitchcock on the other hand is completely useless and very gross

[@kylecoates5344]

I'M TEACHING FATHER THE MATH!!

[@kolhetbtw3477]

Lol

[@allowit.4855]

*"Captain dad is just my boss"*

[@poofy1652]

Title of your sex tape

[@aadisahni]

@@allowit.4855 Gross. Rosa those are our dads.

[@aadisahni]

@@allowit.4855 Never Mind Rosa

[@Muneeb08]

Everyone treats the homie Scully like crap and I've had enough!

[@saf3200]

Scully's fine, Hitchcock on the other hand

[@SuperFartyman]

@@saf3200 hitchcock should be cut from the show. hes not funny at all just annoying.

[@saf3200]

@@SuperFartyman yeah, a bit but with scully he's ok

[@Tiffany-ov2jf]

I mean he's not really useful u kno

[@mermidion7552]

@@SuperFartyman they are both cringy and i wouldn:t miss either of them.

[@John20826]

Amy: Kevin is right Captain holt: Santiago you’re fired

[@ramon6783]

Gina: "I was able to rally the best and brightest of those available." *Scully and Hitchcock appear* Holt: "OH, DEAR GOD." 😂😂😂😂😂

[@damianhudson6399]

What ep is this

[@billkoul9780]

3-14 Karen Peralta

[@shahinhalim648]

The level of disappointment🤣🤣

[@beateasy]

you should do a compilation of all the times jake (or anyone really) gets excited about how awesome a case is before quickly realizing it's actually tragic and horrifying.

[@thenlnlkn]

Sam Donald number 5 killed my brother

[@joyanl]

he said/she said cold open

[@ren09rn]

*Don't just tease my brain, Captain, really go to town on it.* I can't wait to use this quote in real life!

[@derekstanyer]

For those who are interested in the first riddle, its actually quite difficult. You weigh balls 1-4 against balls 5-8, leaving balls 9 to 12 on the side. There are 3 different outcomes for weigh # 1 If weigh #1 is BALANCED, then you weight balls 8 and 9 against balls 10 and 11 (remember that we know ball 8 is normal). If weigh #2 is balanced then you know ball 12 is different so just weight it against any other ball to find out if it is heavier or lighter. If balls 8 and 9 are heavier then for weigh #3 balance ball 10 against ball 11. If they don't balance, then whichever one is lighter is the fake one. If they balance then ball 9 is fake and it is heavier. If balls 8 and 9 are lighter than 10 and 11 in weight #2, once again balance ball 10 against ball 11 for weigh #3 and use the same logic to find the result. If weigh #1 is uneven and balls 1-4 are heavier, we know that either the fake ball is a heavy 1-4 ball or a light 5-8 ball, and that balls 9-12 are normal. This is where it gets tricky. You weigh balls 1, 2 and 5 against balls 3, 6 and 9 (knowing that 9 is normal). If they balance, then either ball 4 is heavy, or balls 7 or 8 are light. repeat the same step as the time, and weigh ball 7 against ball 8. If they balance then ball 4 is heavy, if they don't balance then the lighter side is fake. If during weigh #2, balls 1, 2 and 5 are heavier, then either ball 1 or 2 is heavy, or ball 6 is light. For weigh #3 compare ball 1 and 2. If they balance then ball 6 is light, if they don't balance then the heavier side is fake. If during weigh #2 balls 3, 6 and 9 are heavier, then either ball 3 is heavy or ball 5 is light. For weigh #3, use ball 3 (or 5) against ball 9 (which you know is neutral). If they balance then ball 3 is a heavy fake, otherwise ball 5 is a light fake. If weigh #1 is uneven and balls 5-9 are heavier, just repeat the same steps as if balls 1-4 were heavier, it is exactly the same process. Hopefully this is understandable, it was difficult to write it in a way that explained it well!

[@diderius]

Wait, why are you weighing the men's balls?

[@gavinmacmillan9336]

HOT DAMN! So happy the 99 is coming back for a 7th season. Best show ever.

[@kdagsla3704]

Holt: "There are three doors, behind one of which is a car" Kevin: You're telling it wrong... "There are three doors, behind one of which is a car" :/

[@pulguinha682]

Cool, we watched the same video.

[@ankit99ize]

He said "imagine" that's why he was wrong

[@ADAM-uf3my]

In that Breakout game Scully is the only one who was actually useful. Lolz

[@fahadalajmi6565]

00:08 I love the way Amy looks at Holt, so heartwarming.

[@nikonastrougkakos159]

A lot of people don't take into account that originally we don't know if the person we are trying to find is heavier or lighter and post wrong solutions. Here is a thorough and correct solution to the seesaw puzzle: 1. Split the 12 into three groups of 4. Let's call the groups A, B and C. Let's also call the person we are looking for X. Weigh A and B. Now you get the first idea about where X is: If the balance is equal, then it means all the persons in A and B weigh the same and therefore X is in group C. Otherwise, we know that it's in either A or B, but we don't know in which one because we don't know if X is lighter or heavier. We mark which group is heavier and which is lighter that the other, A or B, and that will help us later. In either case, we now have a control group that we know has only people of "normal" weight: if the balance was equal, the control group are all the persons from A and B, if the balance was unequal, the control group is C. (1st Weighting) 2.1 (A == B) If X was in C, we weigh 3 from C vs 3 from the control group and leave 1 of C unweighted (2nd Weighting). If they balance out, it means that the 3 people we weighted weigh the same as 3 normal people and therefore we know that X is the one we left unweighted (DONE in 2 Weightings). If however the 3 from C weigh less or more than the control group, we know that X is in those 3 AND because we weighted against "normal" people, we know whether he is Heavier or Lighter than normal. Now all we have to do is weigh any 2 of those 3 and we find X (3rd Weighting): if they weigh the same, it's the person we left out, if the weigh differently we find out who it is because we know if the person is heavier or lighter from the 2nd weighting. (DONE in 3 Weightings) 2.2 (A > B or A < B) If X was in A or B, we have 8 people to choose from. We also have a control group of 4 (group C). Here lies the trick: We have already seen the direction the seesaw tilted from the first weighting. We also know that the 3rd Weighting can only determine X if we are left with 2 or 3 people like we did in step 2.1, 4 are too many! So here is what we do: We take 3 people from group A and put them on one side of the seesaw, and we put 2 people from group B plus 1 from the control group on the other side of the seesaw but before weighing them, we switch one from the A group with one from the B group. That way we end up with this 3v3 (2nd Weighting): 2 from group A + 1 from group B (let's call it group D) vs 1 from group A + 1 from group B + 1 from the control group (let's call it group E) 2.2.1 (A > B or A < B) and (D == E) This means D and E consist of "normal" people and therefore X is one of those we didn't weigh (we didn't weigh 1 person from A group and 2 people from B group). We also know from the 1st weighting whether A group is heavier/lighter than B group. So we weigh the 2 people from B group (let's call them B1 and B2) (3rd weighting): If B1 == B2, it means that X is the one left from A group. If B1 =/= B2 then we know that either B1 or B2 is X and that A group had all normal people all along. That means that if A was heavier than B then we know that X is lighter than the others and consequently if A was lighter than B then X was heavier than the others. So if B1 > B2 and A > B then B2 is X, if B1 < B2 and A > B then B1 is X, if B1 > B2 and A < B then B1 is X, if B1 < B2 and A < B then B2 is X. (DONE in 3 weightings) 2.2.2 (A > B or A < B) and (D > E or D < E) This means that X is either on D or E. We already know from the 1st weighting whether A > B or A < B. We also know that the person in E group that we took from the control group won't affect the balance. That means that if during the 2nd weighting the balance changed direction, say A > B but D < E or A < B but D > E, we know X was one of the 2 that switched groups between A and B. We weigh either one vs one from the control group, if they weigh the same as the one from the control group then X is the other one, if they weigh differently then X is the one we weighted (DONE in 3 weightings). If however during the 2nd weighting the balanced didn't change direction, say A > B and D > E or A < B and D < E, we know that X was one of those that remained in their group when we switched one person between A and B. We weigh the 2 people from D group that were originally from A group (let's call them A1 and A2). If A1 == A2, it means X was the one we weighted from B group that is now in E. if A1 =/= A2 , it means that either A1 or A2 is X and that B group had all normal people all along. That means that if during the first weighting A was heavier than B then X is heavier than the others and consequently if A was lighter than B then X was lighter than the others. It's pretty much the inverse situation than 2.2.1. So: if A1 > A2 and A > B then A1 is X, if A1 < A2 and A > B then A2 is X, if A1 > A2 and A < B then A2 is X, if A1 < A2 and A < B then A1 is X. (DONE in 3 weightings)

[@harriskhan1137]

cool math So whats the answer

[@beholdiamglamdringsbane89]

Ooooooooh, I'm so booooored I cannot do iiiiiitttttt.

[@firstnamelastname4216]

5 and 5 works too. If they are equal, weigh the other two to figure out which is heavier. If one side is heavier, split that 5 up into 2 and 2. If they are equal, the remainder is the fatty. If they aren't, you weigh the heavier 2. Done in 2-3 weighings.

[@Reb0rnLP]

@@firstnamelastname4216 How do you know which of the heavier two is the lighter/heavier one? You would need to compare both to the rest of the competition somehow. And for that you don't have enough tries to weigh.

[@firstnamelastname4216]

@@Reb0rnLP Oh, you're right. I misheard the problem and didn't realize the heavy or lighter part was an unknown.

[@Nullllus]

I vote for the 'BONE!' scene to be put alongside with Mona Lisa.

[@Sentinel851]

for the curious weigh 4 against 4. if it's balanced, step a, if not, b. a) the anomaly is in the other 4. weight 3 of the other 4 against 3 from the original group. if they're still balanced, it's the last dude, check him against anyone to figure out. otherwise (the 3 new ones are unbalanced), they're either heavier than the norm or lighter, either way, you know which. weigh 1 against 1 from the 3. if they're balanced, it's the last dude, if one's heavier/lighter, you know out of heavier/lighter the anomaly is, and you've found them. b) the anomaly is either a lighter one in the 4 that were lighter, or heavier in the 4 that were heavier. either way, we have 4 people we know aren't the anomaly (the unweighed) do 3 of the 'lighter' group, with 1 of the heavier group (we'll call them c), against 3 of the unweighed group, and 1 of the lighter (we'll call them d). now, if it's heavy on c's side, it means the one of the 'lighter' men you moved was actually lighter, simply measure 1 v 1 out of them, the lighter one is the lighter, if they match, it's the 1 you didn't check. if it's heavy on d's side, either one who didn't move (c's heavier or d's lighter) is out of balance, and we weight them against any other man. if they match, one of the 3 heavier that came off is heavier, we measure them 1v1, heavier is the anomaly, or if they balance too, it's the last guy. in terms of monty hall, you just look at the outcomes. if you don't switch, you have a 1/3 chance. however, if you picked the wrong door, either way you're going to win. if you picked right, you'd lose. this makes it a logical fact, that if you pick a wrong door first, and switch, you will always win, and the opposite, if you always switch and happen to pick the correct door, you'll lose. 2/3. if you scale it up to 100 doors, and he opened every door but yours and one other door, you'll be able to visualise it much clearer the chance of picking the correct door out of 100 is 1%, if you had the chance to swap, knowing that you only had a 1% chance of getting it right then, you had a 99% of getting it wrong, and that doesn't change.

[@AllyLai]

this hurt my brain but thank you !!

[@DiaXisHD]

Except there are 12 men on the island

[@Sentinel851]

ಠ_ಠ I'm aware. You measure 4 v 4, with 4 not on the scale. It gives you info about three groups of 4, which is then divided into 2 groups of 3 and 1, then divide the group of 3 into a group of 2 and a group of 1. 3 divisions and 3 weighings

[@christianwai1796]

@@Sentinel851 i tried the problem but figuered it out with a slightly different solution in part b. For the second step you take 2 people from the lighter side and one from the heavier side on one side against one from the heavier side one from the lighter side and a normie. With either result youve narrowed it down to three people, two of which from one side of the first step and one from the other side. Then you weigh those two from one side againt each other and have a result. In step a i also had that you put 2 from the 4 remaining against 1 of the remaining and a normie with similar consequences than your solution but thats just more complicated. Either way i think it works as well

[@nikonastrougkakos159]

@@christianwai1796 This doesn't make sense. What if the first step was equal weight? You don't have a light or heavy side. You also don't know if the person is heaver or lighter than the others.

[@sunnyfirmino6467]

Andre braugher deserves every acting award for the 'bone' scene

[@cameravice1825]

I love it when Amy’s rocking back and forth in her chair while Holt shout bone

[@zaru10]

Scully knowing morse code is a life lesson, never underestimate a person's abilities.

[@adamsmailes5484]

So was Holt yelling about Bone for 75 minutes or 45 minutes? All the 'laters' imply the former.

[@otisdelion795]

Adam Smailes 76 or 46 actually

[@otisdelion795]

76 or 40 sorry

[@aadisahni]

45 since it the timing works as from the beginning of the count, not adding up

[@Grace-pb6og]

"I'm teaching father the math" 😂😂

[@robertbuth]

That's probably one of the best lines she's said in the show! Lol

[@ChaoticCobra]

Amy is the brains of the 99 ... WHY COULDN'T SHE SOLVED THE SEESAW PROBLEM???!!! ❤❤❤

[@etjh0071]

she only got it wrong because there is no solution

[@Thomas-gj1zn]

She probably did, the first step is to put 6 vs 6 (or 4 vs 4).

[@irialefe13]

because terry kept eating the islanders

[@jasonfrancis9262]

As framed the puzzle is unsolvable

[@Thomas-gj1zn]

@@jasonfrancis9262 It's not. Place 6 people on each end of the see saw. The heaviest side contains the fat person. Split those six in two groups of three, place them on the see saw, the heaviest group contains the fat person. Place one of the remaining three on each side of the see saw, if they are balanced, the remaining dude is the fat one, if not the heaviest of the people on the see saw is.

[@aabidamn]

As I am writing this there are 31 people that had down voted this clip. The video wasn't the problem, those 31 people just need to bone.

[@caitlin3963]

BOOOOOOOOONE!

[@nikhilgupta9683]

HOW DARE YOU, ABIDAMN?!

[@nobody3622]

BOOOOOOOOOONE!

[@PriyaDharshini-cp7hw]

What happens in my bedroom abidamn is none of your business

[@ChinmaiNaregal]

What is the answer to the see saw question though?

[@ChinmaiNaregal]

@@hanasong685 Thanks dude!!

[@sbwa4575]

So you separate the 12 men into groups of 6 and weigh one of them 3-3, if the seesaw stays level the man is not in that group, it it doesn't he is. Having levelled it down to 6 men you split this group into two 3s and measure it against 3 of the 6 confirmed not to contain the man. If the seesaw does not move, the man is not within the group of 3 you have weighed, so weigh the other group against 3 of the confirmed not to contain the man, and depending on which side the seesaw leans towards tells you whether the man is heavier or lighter.

[@TheSaitham]

@@sbwa4575 I hate the same solution but with 3 groups of 4

[@mujtabaellari2597]

@@sbwa4575 excuse me but doesn't that just say that the person that's lighter or heavier is in that group of three? Because according to the question there is only one man with a different weight. You've narrowed it down to three but we still don't know who is the with he difference in weight.

[@sbwa4575]

@@mujtabaellari2597 You don't have to find out which person it is, you only have to find out whether the person is lighter or heavier.

[@piperstojkovich2534]

Kevin is right about the Monty hall question, I'm going to explain it: If there is 100 doors and you choose 1 then the game show host opens 98 doors that the car isn't in, so now there is 2 doors left, do you switch? Yes, because you had a very low chance of picking the right door first try

[@zintlemvana7955]

Amy: Kevin's right Holt: You're fired. That's a high price for telling your boss he's wrong 😂

[@GTisJAVO1996]

He's not right because the act of not changing is still a new desicion you made. Thus it's 50/50.

[@revv5]

@@GTisJAVO1996 Haha wow. Make them return your school money dude. You didn't learn anything.

[@GTisJAVO1996]

@@revv5 choosing not to change is an action in its own right. It's essentially the same thing as being asked to pick again and going with the same door as before

[@finneon5881]

@@GTisJAVO1996 I'm a bit late on this one, but in case you haven't found out by now, I'll try to explain it in a different/more elaborate way: There are two doors with goats in them and one door with a car, so when you make your initial guess you have a 66% chance of hitting a goat, right? That doesn't change when the person reveals the second goat; there's still a 33% chance that you chose the car on your initial guess, so switching to the other option gives you a better chance, since now you KNOW that it obviously doesn't contain the "second" goat, and you still most likely (66%) also hit a goat on your first guess. :)

[@hotdamndan9892]

"Is this you really wanna die, Hitchcock?" "Incorrect,... And disturbing.." Those lines,. Are just, perfectly delivered..

[@shubhamlale5946]

1:50 that's so me everytime I start something new

[@Bibiyoshika]

9:40 is the reason why I LOVE Detective Rosa Diaz 😂😂😂

[@TheMelbournelad]

I paid no mind to the see saw teaser first time around. Then re watched the ep today and I was like wait there are 12 islanders and 3 tries got it. So happy, and Amy was on the right track of course.

[@yuzutranslationch.8516]

what's the answer? can i get it please?

[@Ankerus]

@@yuzutranslationch.8516it's simple, split the 12 into 3 groups of 4. Then put 2 groups (4v4) on the see saw; if it tilts, it's 1 of them, if it's balance, it's the 3rd group. Now you have a group of 4 and 2 tries, just put them on 1v1 and single out the fatty.

[@yuzutranslationch.8516]

@@Ankerus how do you know it's the fatty, and not the skinny? There wasn't a clue whether the odd one out has more weight or has less weight

[@solarflare4047]

number them and then repeat the process. and on the second try, weigh 3 against 3, taking the first 3 from the first batch of 4 (they weigh the same) and numbers 9, 10 and 11 (assuming 1 through 4 and 5 through 8 were weighed in the first try). if 1 2 3 are the same weight as 9, 10, 11, then we use the thrid try to determine wether 12 is heavier or lighter. however, if the second bit yeilds an unequal result, weighing an 2 men from 9, 10, 11 will give you the answer.

[@edvardsstugis46]

@@yuzutranslationch.8516 It actually can be done in 2! First you do 6v6, weirdly what Holt said would never work. Obviously one side will be heavier than the other. Take any side (lets say heavier) and divide it into 2 groups of 3 - put those against eachother. If they are the same, you know that the guy was in the other group of 6 and is lighter because that whole group was lighter. If they are not balanced, you know he was in that one and so is heavier. And as you said, you do not need to find the person, you just need to find out if they weigh more or less!

[@shiarsenio9501]

I am a simp at Amy's "oh mama" 6:44

[@uncomfortablecat]

2:00 gina was on the left side and then she "moved" faster than the speed of light! That's why i love Gina.

[@saratemer6634]

I love how the bone scene is able to made into every single compilation

[@biswadas8109]

4:22 I seriously laughed like a pig😂😂😂😂😂😂😂...and Still laughing 🤣🤣🤣

[@royalalhaji910]

Oh captain how could you? 😂 Hitchcock Coursed a problem put the blame on Holt 😂

[@crazy_dummie6498]

R/boneappletea

[@karintmz9878]

Seeing Amy's reaction throught the bone scene is the best😂😂

[@lenaschiettecatte3592]

Kevin was right about the problem, but I mean I understand Holt, I tried to convince my grandmother once that you should pick another door, she didn't want to believe me, now she's gone and I still haven't been able to explain it to her...

[@JimmySteller]

2:32 Santiago and Holt’s relationship was the best part of this show

[@TheOneTrueLeo2002]

We need the full 40 minute version.

[@paolomagno5059]

9:41 Sweet turn 😉

[@jonnnyren6245]

The Brooklyn 99 family is the best family. I mean imagine all the unexpected and spontaneous brain teasers and deep deep excerpts from the English language generated from Holt's fascinating and colorful thoughts and emotions. This one family that can never have a boring day. 🤣

[@Pantsmode]

"I was able to rally the best and brightest of those available" (Hitchcock and Sully enter) *"Oh dear god"*

[@borojugovic8178]

The H and S on the pizza box in the beginning is so funny for some reason. They are the best

[@fakebetch1155]

1:20 😂😂

[@chrismellor9634]

Monty Hall problem. Flipping priceless. Bone?????. Hahaha

[@DingoDIDeatmybaby]

"Yeah, what about Rosa, Gina and me?" *Is this how you wanna die, Hitchcock?*

[@genildomiranda1690]

"Cap. Dad is just my boss" gets me every time

[@322ndgaming9]

Come to join us for lunch sir? No, I’ve already consumed the required calories for this day period. Yummy.

[@ecaldas18]

anyone want to hear all skullys stories about his life?

[@VishakanSubramanian]

6:08 "Booyakasha!"

[@soulphase8244]

"see what happened is: Your dads had sex" "okay Rosaaaa"

[@i.7525]

Love this, still not giving up on the Rosa and Charles Friendship Goals compilation though!

[@georgiabolland5499]

Don't you just love the fact that Hitchcock and scully have split the pizza box so that they can have equal amounts of pizza like I'm sorry THEY are the geniuses

[@FulminantLogician]

This puzzle was fun. Standard idea: We solve it by giving people good names. The first thing to notice is that because we don't know if the special weight is higher or lower, we need to "identify" possible outcomes. For example, say we actually weigh the special person all 3 times, we need to be able to pick them out whether the left is lower all three times or if the right is lower all three times. Essentially, for each round, we have three possible measurements: I'll record 0 if the left side is lower, 1 if the right side is lower, and 2 if the sides are equal. Now, name each person from A to L, and have them be weighed in the following way: Test 1: LJHE on left, FGIK on right, DCBA off Test 2: IHBA on left, CFGL on right, KJED off Test 3: KJGA on left, BDFL on right, IHEC off To be explicit, here is how the data is identified and I've written how outcomes correspond to the special person. Note 222, 010, and 101 are impossible. 222 000=111 F 001=110 G 002=112 H 010=101 011=100 L 012=102 I 020=121 J 021=120 K 022=122 E 200=211 A 201=210 B 202=212 C 220=221 D If you want to doublecheck my work without thinking it through, you can just check what happens when you declare one of the people to be special (either heavier or lighter), and see what happens. :) To be clear, when solving such a problem, you write the possible data and then write the names as you style the tests. It feels a bit like sudoku and is why the names and the data might look like they're in a funny correspondence! Also, for the Monty Hall problem, of course you should switch. You get the car if and only if your first guess was wrong (which has probability 2/3). Holt is definitely bad at math haha

[@rashmideshpande9141]

Thanks I spent a long time thinking about the problem

[@JMTchongMbami]

what's your algorithm to divide those 12 people, even your first test doesn't seem to follow a simple pattern. I'd thought of dividing simply as ABCD / EFGH / IJKL but you're way off this pattern. So, how did you choose the 1st and how did you modifiy it for the 2nd and 3rd test? And why did you test again some people that you are 100% sure are not the special one ? At your 1st test, if the scale isn't balanced, you can just cast aside the reserve and vice versa. So, i began with something like, weigh 3 vs 3, leave 6 off. With one test you skim 6 people right away. But with my method , you cannot determine the special with 3 test.

[@Monstrick1]

@@JMTchongMbamiYou can split remaining 6 into 3 groups in the 2nd round, and weigh 2v2, so you can figure out which duo has the lighter or heavier person from just one weigh in. So third round is just 1v1. But it implies that there is a "balanced" state availiable to be read from scales. So, i think people are overthinking it.

[@narfeyfjola]

Monty Hall is always phrased in an absurdly complicated fashion when it's actually so so so simple. 2/3 doors have a goat or something behind them, so 2/3 times you pick the wrong door. Literally, that's it

[@tanyawastaken]

I’d love to see the whole team on an escape room quest once

[@moosen1207]

While the captain screams BOOOOOONE Santiago is just there looking like she's dying of some inner torment whenever Holt yells

[@ImKarl]

3:56 I cant get over this fact

[@gibranbengolea1818]

4:27 lmao, I love Hitchcock

[@marciii411]

8:19 I canttttttttt

[@ludo9093]

Divide the 12 into 3 groups of 4 Let two groups of 4 weigh If one is heavier you can continue with those four. If they weigh the same you continue with the group not present on the seesaw. Than weigh two against two And in the end weigh one against one Problem solved

[@thisisme3161]

Genius, captain Holt would be proud

[@nicolasryal6666]

It's slightly heavier or lighter so if one side is heavier you dont know what group to continue with

[@ludo9093]

@@nicolasryal6666 ah shit

[@hamilmiller8940]

Everyone made fun of Jake for calling captain dad the way most of us called our teachers mom once but Amy fully goes “ROSA GROSS THOSE ARE DADS?!? I mean captain dad is just my boss, I mean, I’m teaching father the math”

[@sandygehrmann6309]

Far out Rosa is such a good character

[@architchitre7867]

You guys just need a reason to include "booooooone!"

[@uauuauuauu]

Santiago- Kevin's Right Holt- You're Fired!! 'Rosa Laughs'

[@Bob-jy4ju]

BOOOOOOOOOOOOOOOOOOOONEEEEEE

[@calebshaw6632]

“BONE?!?!?!?!” Is still so great 😂

[@sksksksksks_]

“My daughters were conceived to bootylicious” 😂😂

[@AnnoyingAsianWitch]

Don't tell Sharon I said that

[@OleandyrTheGreatDragonGod]

I love that moment when Holt says "What'd you just say?" in that sassy way. lolz

[@vakaredob6520]

At 0:16 did Gina have a cheese board for lunch? Bcos honestly mood

[@t.j.rossbach4049]

Gina steals Scully’s Lunch every day so Scully is the real mood

[@stepanserdyuk4589]

Scully knowing Morse code and solving the problem instantly is genius

[@moocowandsnake]

I can't pick my favorite scene or episode, I just love them all!

[@tavleenkaur5414]

Compilation idea: Scully's talents like Opera, Speaking French, Knowing Morse Code

[@glutenfreemuffincake4267]

Rosa: See what happened is your dads had *** Amy: Ok rosa *runs away* Lol I can’t even

[@thebakalord]

They will do anything to add the Bone Scene no matter what, which is one of the best scenes ever in this show.

[@simeonpetkov768]

BONE! BOOOOOOONE!

[@RB_90]

When Captain Holt turned up in that red bowler hat I spat out my tea on my dog and almost choked to death.

[@sayedmiah3549]

Boneeeee!!

[@ChaosCrumpet24]

Hitchcock on the phone with 3 questions.... I died of laughter! 😂

[@nyx.8254]

It took me AGES to figure out why Amy's seesaw answer was wrong

[@actionjackson52]

WHY IS IT

[@edvardsstugis46]

6v6 works and is the fastest solution to the problem! It can be done with only 2 tries.

[@maxpatana9906]

I Like How They Find Any Reason To Include The Booooooooooooooooonnnnnnnnnnnneeeeeeeeeee Clip

[@amazingalin]

8:58 ʷʰᵃᵗ ᵈⁱᵈ ʸᵒᵘ ʲᵘˢᵗ ˢᵃⁱᵈ

[@mokiiyu4950]

CAN'T STOP SEEING KEVIN AS BIG SHAWN KSDJDHKAJKADHSD