Buffer Calculations

[@Arsemaesubalew]

This is the only video which helped me understand these questions thanks a bunch!

[@snowythecat9159]

thank you a lot you just saved my life keep going :)

[@princesiddiki7354]

How 😏

[@snowythecat9159]

@@princesiddiki7354 😂

[@udayreddynarapureddy5586]

Pka is acid dissociation constant which is used to indicate the strength of an acid

[@GeorgeCronigen]

The problem at 3:36 has an issue. Your initial solution has a certain volume which is not declaired then you add some more volume which is also not declaired. You cannot arrive at a reliable result if you have only the concentration because concentration says nothing about the amount of substance that reacted with another substance. If you had just only one solution and you wanted to calculate the ph it would be ok because you start with a specific volume that is unknow but the concentratiions are derived from the same volume. Plz remove them video or at least this part cause its totaly unacceptable. My only hesitance not to give a huge hug is that the concentration of Naoh is dervided after it was added to the solution.

[@ahmedelewah488]

الله يعطيك العافية،استفدت منك كثير ⁦❤️⁩

[@Shahad-mr2ws]

السلام عليكم … تذكر كيف طلعت ال ١٠؟

[@shamsahmedradwan7583]

هي ليه طرحت 0.2-0.05في الدقيقة 4:58

[@loloezt933]

عشان تم استهلاك الجزء دا من الحمض لما تفاعل مع القاعدة

[@Mustafa-zy9mh]

I love you miss thank you for this shirt formula it made my exam very easier than my teacher way

[@serperior2569]

May I know how you got 10 at 2:57?

[@FalmataAdem-o8x]

No of log is common so base is 10 😊

[@clarencedelacruz4399]

Expound​@@FalmataAdem-o8x

[@eyosiaskassu479]

You comitted mistake as you plugged in number of moles in Henderson Husselbatch equation

[@fegosmrhighmass4610]

It's still correct because the volumes given for acid & base are different.

[@rajtigris]

Lucid explanation. Thank you very much.

[@AbdulfataiKamilaoiza]

Pls the second question how did u get the 10 which was given as 10:1

[@adelemoniquejose703]

from the logarithm, thru base 10

[@RRr-ew8bz]

شكراً جزيلا متابعيك من العراق

[@PhilomenaOsei]

Please why did you use - 0.05 for the acid

[@SylviaNyaguthii-d5g]

i finally understood buffers...thank you

[@namonjemwamulima3539]

What if the added concentration of NaOH is larger than 0.2 when subtracting it will produce a negative?

[@patrickstar7693]

It gets always talked about the addition of a strong acid or strong base to a buffer... my question would be how to calculate the ph with the addition of a weak acid?? Lets say the addition of acetic acid to a phosphate buffer

[@LillianChungu-s5m]

What if u have been asked to find the ph when given constant volume and two moles

[@Omphile-e1x]

great stuff!

[@skyblue7066]

Amazing !! It really helped me

[@EvansNgambi-iz5uw]

How did you get that 0.30

[@pradeeppatil2922]

How would you prepare a 50 mL buffer using 0.5 M acetic acid and 0.4 M NaOH. Target pH is 4.3.

[@ratburger546]

What is pKa of solution?

[@DuruRuth-db6uy]

I thought you will add the pka + the log but, you minus it

[@WesleyMears-l9j]

On the last equation it should be 0.025/0.02= 1.25 Log (1.25)=0.0961 PH= 2.125+0.0961 = PH 2.22 this is a better equation

[@tahirtantary7438]

Lots of love from KASHMIR

[@jamaleejarana5701]

where did you get the 0.30?pls explain

[@paulinefrancez]

log(0.1 / 0.2) = approximately -0.30

[@ameernitroglycerineiraq9003]

هم بيكم واحد من المعهد التقني قسم التحليلات 🙂

[@ahsanakram4348]

Thank you so much i understand very well

[@إسراءمهديسليمانكردي]

اول شخص عراقي

[@afnan_omar]

Plz why there is not arabic translation??😭💔

[@hannademese7448]

Thank u u're life savor

[@acount1666]

how did we get 10/1 as an answer ?

[@jadenicoletteespina6231]

Same question

[@vidhatrighat5868]

we need to find the log of what gives one. we know that log of 10 is equal to 1, hence the ratio of base/acid should be 10, making the ratio 10/1

[@zuzu133]

you need to do antilog because you dont need log there as ratio is the only division

[@abdulaisumaila8438]

It's a ratio . She was just trying to write the answers in a ratio form 😊

[@jonassiborurema8733]

Thanks 🙏

[@زكرياالنعيمي-ظ1ق]

حلوو

[@unfriended7573]

Thanks alot😍

[@harsheetavashishth2645]

Thnku so much

[@Raka96876]

no problem

[@avokardoes7]

thank you so much

[@Chembynlsir]

Thanks

[@Abuumuqbil4994]

Calculation very easy

[@anandkishor3260]

What is. 'pKa' pls ans anyone

[@UAa320]

pka is the -log(Ka)

[@Raka96876]

acid disscociation constant

[@gedelaravikumar3972]

-log ka

[@خلوديحيي-ظ2ط]

​@@Raka96876بالظبط كده

[@yessumify]

so helpful

[@lazhapeshraw9487]

Thank youuuuu 💗

[@rohiniwasekar8827]

Thanks