Buffer Calculations

[@Arsemaesubalew]

This is the only video which helped me understand these questions thanks a bunch!

[@ahmedelewah488]

الله يعطيك العافية،استفدت منك كثير ⁦❤️⁩

[@Shahad-mr2ws]

السلام عليكم … تذكر كيف طلعت ال ١٠؟

[@shamsahmedradwan7583]

هي ليه طرحت 0.2-0.05في الدقيقة 4:58

[@loloezt933]

عشان تم استهلاك الجزء دا من الحمض لما تفاعل مع القاعدة

[@udayreddynarapureddy5586]

Pka is acid dissociation constant which is used to indicate the strength of an acid

[@snowythecat9159]

thank you a lot you just saved my life keep going :)

[@princesiddiki7354]

How 😏

[@snowythecat9159]

@@princesiddiki7354 😂

[@eyosiaskassu479]

You comitted mistake as you plugged in number of moles in Henderson Husselbatch equation

[@fegosmrhighmass4610]

It's still correct because the volumes given for acid & base are different.

[@Mustafa-zy9mh]

I love you miss thank you for this shirt formula it made my exam very easier than my teacher way

[@PhilomenaOsei]

Please why did you use - 0.05 for the acid

[@Omphile-e1x]

great stuff!

[@RRr-ew8bz]

شكراً جزيلا متابعيك من العراق

[@namonjemwamulima3539]

What if the added concentration of NaOH is larger than 0.2 when subtracting it will produce a negative?

[@rajtigris]

Lucid explanation. Thank you very much.

[@serperior2569]

May I know how you got 10 at 2:57?

[@FalmataAdem-o8x]

No of log is common so base is 10 😊

[@clarencedelacruz4399]

Expound​@@FalmataAdem-o8x

[@LillianChungu-s5m]

What if u have been asked to find the ph when given constant volume and two moles

[@pradeeppatil2922]

How would you prepare a 50 mL buffer using 0.5 M acetic acid and 0.4 M NaOH. Target pH is 4.3.

[@ratburger546]

What is pKa of solution?

[@patrickstar7693]

It gets always talked about the addition of a strong acid or strong base to a buffer... my question would be how to calculate the ph with the addition of a weak acid?? Lets say the addition of acetic acid to a phosphate buffer

[@إسراءمهديسليمانكردي]

اول شخص عراقي

[@SylviaNyaguthii-d5g]

i finally understood buffers...thank you

[@EvansNgambi-iz5uw]

How did you get that 0.30

[@DuruRuth-db6uy]

I thought you will add the pka + the log but, you minus it

[@skyblue7066]

Amazing !! It really helped me

[@jamaleejarana5701]

where did you get the 0.30?pls explain

[@paulinefrancez]

log(0.1 / 0.2) = approximately -0.30

[@afnan_omar]

Plz why there is not arabic translation??😭💔

[@tahirtantary7438]

Lots of love from KASHMIR

[@acount1666]

how did we get 10/1 as an answer ?

[@jadenicoletteespina6231]

Same question

[@vidhatrighat5868]

we need to find the log of what gives one. we know that log of 10 is equal to 1, hence the ratio of base/acid should be 10, making the ratio 10/1

[@zuzu133]

you need to do antilog because you dont need log there as ratio is the only division

[@abdulaisumaila8438]

It's a ratio . She was just trying to write the answers in a ratio form 😊

[@WesleyMears-l9j]

On the last equation it should be 0.025/0.02= 1.25 Log (1.25)=0.0961 PH= 2.125+0.0961 = PH 2.22 this is a better equation

[@ahsanakram4348]

Thank you so much i understand very well

[@hannademese7448]

Thank u u're life savor

[@jonassiborurema8733]

Thanks 🙏

[@anandkishor3260]

What is. 'pKa' pls ans anyone

[@UAa320]

pka is the -log(Ka)

[@Raka96876]

acid disscociation constant

[@gedelaravikumar3972]

-log ka

[@خلوديحيي-ظ2ط]

​@@Raka96876بالظبط كده

[@Abuumuqbil4994]

Calculation very easy

[@avokardoes7]

thank you so much

[@زكرياالنعيمي-ظ1ق]

حلوو

[@unfriended7573]

Thanks alot😍

[@harsheetavashishth2645]

Thnku so much

[@Raka96876]

no problem

[@Chembynlsir]

Thanks

[@lazhapeshraw9487]

Thank youuuuu 💗

[@yessumify]

so helpful

[@rohiniwasekar8827]

Thanks