C_18 Operators in C - Part 6 | Bitwise Operators | C Programming Tutorials

[@syedalifathimaa9618]

The way you're teaching, presenting problems to us, and claiming for answers in the comment box is quite convenient to grasp the concepts and make us feel the classroom environment.

[@RukhaySukhayPakwaan]

I can proudly say that this mam is the reason why i scored good marks while i was doing my engineering. Lots of love from nepal ❤️🙏

[@shrur3527]

dear mam thank you will be very less for your videos , praying for all happiness n success to u n to ur family , i m benefited a lot by your videos , you are an excellent teacher

[@alehegnmandefro8111]

It very good lecturing about general concept of C++ programming and she continuous this the work teacher.

[@BrendonJeje]

Thank you mamm for the wonderful explanation. a&b = 2, a | b = 14, a ^ b = 12 and and the last is 1

[@alluarjunfan813]

mam your classes are super I am listening u r class 50 % for subject and 50% for you

[@marufqureshi8429]

Nice session Ma'am My doubts are always cleared by watching your session. Thanks a lot for this awesome session.

[@itzscouter1795]

Output will be 1 and b will be 7...Also you are best Ma'am..Today is my exam and I was so tense now my mood is good too after watching your video...Your teaching is best☺

[@MECH-to-IT]

1 and b = 6... bcoz 0 && b++ then first false then second not checked in and op.

[@akashpraveen9814]

Far better than my college professor..she is just a noob in front of you..😂

[@shashwat4299]

Again jenny ma'am you nailed it up to mark very clear and smart teaching

[@kingvideos1862]

Mam thankyou you are better than my teacher it's very helpfully for me

[@sailendrachettri8521]

I learned alot Thank You ma'am :) Now let's got for part 2

[@PalliSeetaram-qz7fu]

Mam super explanation 🎉🎉🎉🎉🎉❤❤❤❤❤

[@abhishek9471]

In second the output will be 1 in(&&)case And b++ will print 7

[@shuchianush4028]

No brother the precedence changes and 0 && b++ will be evaluated first and then 1 || (value of 0 && b++) …so output will be 1 but again b value will not be affected

[@SadhanaSharma]

13:07 output of first three statement is 2 14 12

[@dasariemima2082]

bro can you plz explain y 14 and 12

[@pareshitaliya8294]

bro hear we get 2 15 12

[@pratikrajverma696]

I love you ma'am as a student and teacher relationship ☺️💛

[@hassanrizvi5934]

Mam the way you teach to us is the best way and we understand and resolve our problems easily 👍👍

[@tithighosh2169]

Ma'am please upload videos of pointers, structure,union,enum, files handling, command line argument of c.❤️

[@princechoudhary1025]

Yes 🙏

[@nitishkumarsingh1980]

@@princechoudhary1025 mam has uploaded it

[@MechMonty]

in the last case after adding && b++ and printing b only gives value of 6 so that means it doesnt execute the expression && b++ as per left presidency and OR operator before on left

[@hariparuchuru3858]

after changing the logical or operator to logical and the final output of the statement will be 1 and B value will be updated as 7.

[@SaraswotiKhadka]

how 7? can you explain??I'm confused

[@hariparuchuru3858]

@@SaraswotiKhadka at last mam changed the question i.e ( a&b && b+1 || 0 || b++) first mam explain with this example later, The question is ( a&b && b+1 || 0 && b++) bitwise & has higher precedence so, now the expression on solving ( 2 & 7 || 0 && b++) so, 2&7 = 1 So expression changes as follows (1 || 0 && b++) here && has higher precedence and also b is updated to 7 here as we used b++ in our expression. so, 0 && b++ is done first i.e 0&&6 output is 0, now ( 1 || (0 && 6)) BECOME (1 || 0) Finally output of this expression is one bcoz of logical or.

[@SaraswotiKhadka]

@@hariparuchuru3858 may be i got it. Thank you

[@udaysingh6621]

@@hariparuchuru3858 bro, in logical and (&&) , if 0 is one of the operand then we don't fetch the second operand and the result is 0 , as in this 0 && 6 output is 0 and we don't consider the second operand So b++ value remains same i.e. 6

[@hariparuchuru3858]

@@udaysingh6621 we don't get 7 but result is 1 only

[@aditiraj8147]

Ans for 1st 3 Q are 2, 14, 12

[@sumityadavazamgarh8023]

🎉🎉🎉

[@soham11_2]

Hello, want your insta id 👋🏻

[@ananthu4141]

Which part can u mention it?

[@ananthu4141]

​@@sumityadavazamgarh8023Bruh where it is?

[@hokagekonehamaru-ec7kw]

​@@ananthu414111:11

[@codingwithrehan1503]

Mam ,you use very simple English words. Thanks 😊

[@Shopsupreme1]

like seriously ma'am u are really good, u just thought me a shortcut for this...

[@samk11-YO]

mam you best from my all c teachers . i saw your all videos and inspiration from your video love you mam and make new best videos on c language .

[@padduvadlamani7619]

kzbin.info/www/bejne/g2KqqHWOZd-beZY

[@vinayshukla6316]

You can fast forward the video, Actual content started from 2:30,before this all just the unacademy promotion.

[@arshadtv7744]

Very good teaching every topic is covered 🤗

[@ashishtayade047]

Thank you mam very nice gide & very nice best information bitwise operator teaching video.👍

[@sixtusagbo]

God bless you a million times

[@mamuni2006]

Technically you r correct and you are technically sound. Don't get nervous or fast while teaching. But teaching is good. But you can make it better because you are technically sound.

[@nagagopi4448]

Mam in this above video u said ,printf("%d %d",a&b&&b+1|0&&b++), it will print b value as7 but it is giving only b++ old value as 6

[@neerajaneeraja6971]

Yes ,I also got the same answer

[@AnkitKumar-ud4vt]

@@neerajaneeraja6971 me too

[@farzanaashraf8136]

@@AnkitKumar-ud4vt @Neeraja Neeraja Because at second last evaluation of expression, first && operator will be evaluated then || operator will be evaluated and there is 0 as first operand in && operator then there is no need to check for the second operand and consequently b value will not be incremented. I hope you will get it, what I tried to explain. 🙂

[@madhubantu5180]

​@@farzanaashraf8136 bhai insta id chahiye aapka

[@farzanaashraf8136]

@@madhubantu5180 Why

[@SandeepKumar-pm5op]

Thank you for teaching us in an excellent manner you are extremely better than my college faculty they don't taught me all this so that I'm stuck with lot of doubts So because of you I'm able to i understand everything thank a lot mam 💟💟💟💟💟💟💟💟💟💟💟💟💟

[@pcj0949]

Our sir in our college explained the same topic for 40mins but I understood after watching your video mam

[@5j9harishguggilla23]

Mam ur explanation is so nice like you😍😍

[@mehakrafiya5481]

Video starts at 2:26

[@fiazwaris1185]

You are such a cute teacher i like all your vedios that understand able 😊😊😊

[@starkendeavours7072]

Yes mam please take some good, hard, and really tricky examples on Logical and Bitwise, and Relational operators combined

[@SARIKICULTURE804]

mam your teaching method is very impressive

[@sonakshitripathi30]

Thankyou so much mam it’s an amazing experience , learning from you ❤

[@agni_pranay799]

Mam apko dekh ke hi sb samajh me a gya🤤🤤🤤

[@anusha_pathivada]

Im with zero doubts mam thats bcoz of you tq so much mam ❤

[@shahsufi1374]

amazing thanks mam BANGLADESH

[@codehawkofficial]

The guy named Ladesh: ○_○

[@poornimab8877]

Excellent ma'am ❤️

[@ogfactboy1977]

Best teacher 🎉

[@yashsharma-td6ii]

mam in the logical AND(&&) operator the final output will be 1 and 7 right. I didn't understood how did we got 2 there. Can you please clear this doubt mam?

[@kunabhavani]

The one is below 2 so

[@Sindhuuu99]

Tqq so much mam for ur clear cut explanation 🎉🎉❤

[@oteikwufrancis1108]

Good day Ma'am. 2 years later and your course is still very much relevant! Thank you for what you do. So I have a question, when performing certain operations on while working with binary in jpeg mode, we usually have to check if the first four digits of the 4th byte of a specific amount of data is a certain value. Here, we use the bitwise & operator. My question is, when checking to see if the first four values are similar to 0xe0, why do we use the & operator with 0xf0 on one side and 0xe0 on the other? Why don't we have 0xe0 on both sides? An example code is as shown below: if (buffer[0] == 0xff && buffer[1] == 0xd8 && buffer[2] == 0xff && (buffer[3] & 0xf0) == 0xe0) Look forward to hearing from you soon ma.

[@tithighosh2169]

Great ma'am ❤️.

[@mayureshdalvi8808]

Thank You for clarified our doubts

[@asu253941simi]

Hi, you are the best.. thanks for your help...

[@durgalankipalli2541]

a&b= 2, a|b= 14, a^b= 12, lastOne= 1

[@SaidabeeShaik-n2o]

Excellent explanation

[@vishalKumar-dd7pg]

Really like your explanation ma'am superb 🔥🔥🔥🔥👌👌👌👌👌👌👌

[@gurubarathi4954]

I am impressed on your 💕

[@gaganshuyadav6613]

Thanks for help Ma'am 🙏🙏🙂

[@nihadkv2976]

You are very beautiful ❤️ And the video helped me a lot

[@ShivamKumar-yd3ix]

It's a very helpful video mam thank you

[@Mr.Yaragonda]

Thank you❤🌹😊 so much for your lectures madam...... Gratitude from bottom of my heart❤💖

[@AnuradhaChelluri-b3n]

Good explanation

[@vaishnavinalabolu9603]

It's very cleary😊

[@abiramis5683]

Int a=10 b=6 a&b is 2 a | b is 1 a^b is 1

[@mohammedfayis6487]

will you make a separate video for bitwise operation examples??

[@sabloktantr9718]

You are my best guru

[@adityaprakash6248]

can you please tell why when a=10,b=5,a&b is 0. while when a=10 and b=6, a&b is 2.

[@Rimuruchloe3722]

thank you for this video mam😃

[@LoshnaDash]

a&b =2 a|b = 14 a^b = 12

[@kovvadapavankumar5209]

super explanation madam

[@abdulrahimjalloh363]

print1=2 print2=14 print3=12 print4=1

[@judymuroki8869]

In the very last example question, printf is 1 and b is 7.

[@dhruvilpatel6099]

thank you ma'am😊😊😊

[@RAJESHS-df8io]

hi mam, nice explanation , in this video , which first prior , & ,+ , pervious video you explain high priorty each by binary.but while combination how we can identity which first for example & ,+ .

[@emmyabbey91]

This was helpful

[@tps8470]

Thanks a lot mam

[@SadhanaSharma]

16:20 output is 1

[@needofrightdirectionByGajendra]

Thank you so much ma'am

[@forgedinstudies5853]

Very beautifully explained 👌

[@user-uu6xe5rx5m]

Mam you are looking so beautiful

[@sakibulhuda9440]

as it will get true and true ,ouput will be one and value of b is 6 and if it finds another b then b will be 7

[@PalyamYashwanthsai]

In last you said that b will remain 6,but wrong madam it will be 7 madam

[@kumaravel1301]

Mam, is b+1 is a relational operator?(13:25)

[@venkatsai4865]

It is arithmetic operator

[@kumaravel1301]

@venkat sai ,then y mam told b+1 is relational operator (13:25)

[@aalfaroque]

arithmetic operator

[@satyajitmanna8501]

I think b+1 is a arithmetic operator

[@yashhokte1020]

@@kumaravel1301 By mistakely mam said that thing ...... there is + between two operands so it is an arithmetic operator only don't get confuse

[@vinodgamer4553]

mam Give suggestions to MCA students , scope is fit for software

[@syedalifathimaa9618]

b=6 Even if && is there, it didn't get incremented while executing #include int main() { int a=10,b=6,c; c=a&b&&b+1||0&&b++; printf("%d %d %d",a,b,c); return 0; } output==> 10 6 1

[@syedalifathimaa9618]

Can you tell me why?

[@ja3r]

@@syedalifathimaa9618 because logical && operator precident higher then logic ll operator C = a & b && b+1 || 0 && b++; C = 10 & 6 && 6+1 || 0 && b++; C = 10 & 6 && 7 || 0 && b++; C = 10 & 6 = 2 && 7 || 0 && b++; C = 2 && 7 = 1 || 0 && b++; C = 1 || 0 && b++;(logical && operator incounter 0, it will not move on b++ , it give ans 0 and b++ will not exicuted. C = 1 || 0 = 1 I hope my explanation you will understand 😊

[@creatorpanel3230]

@@ja3r thnx bro keep it up

[@pavanmurthya9482]

Mam do one more video on bitwise operator with more examples

[@falconixop6994]

All the best for your Exam 👍

[@blackdog365]

Ans for three Q 2 14 12

[@ramrayapati]

@jenny's lectures.Mam please explain detailed programme like that programme

[@mrakashsaha]

Main Video started from 2:22

[@lokesh6828]

I didn't understood that why the output of b would be 6 and not 7, as precedence of increment operator is more than other operators, so logically the increment operator should be executed first and the value of b must be 7 in both && case and || case.

[@vrajalingam3487]

i also same doubt!

[@lokesh6828]

@@vrajalingam3487 I got my answer. See precedence is checked only when a operant(or any number) has more than one operator, and not checked at first for whole statement. And in case of || only first part is checked and if that part returns true then other part is not check., same in case of &&, if first part returns false, other part is not checked.

[@Helly04]

​@@lokesh6828bro l also know that even everyone but here the main problem is when we r doin b+1 i.e 6+1=7, then value of b is updated here only & in b++ we have to consider 7 & not 6 (coz the value of b is updated in the memory after doing b+1 ) i.e why when we'll print 'b' we should get 7 but still we r getting 6 . How's that possible, l can't understand

[@daydreamer_megh]

​​@@Helly04 Because b++ and b+1 is not the same thing, in case of b+1 the value doesn't change in the memory it just changes where it is assigned to. So if b=6, c=b+1 then c will become 7 but b will remain 6 in the question, && has higher precedence so, after initial solving the question comes to this, 1 || 0 && 6, here && will be evaluated first due to higher precedence, in logical and if first operand is 0, second one isn't evaluated final output becomes 0. So now it is 1||0, in logical or if first operand is 1, final output becomes 1, second operand isn't evaluated, so the second operand b++ was never checked in any of the steps, that's why the value of b remains 6 and the final result is 1

[@SagarTadasaloor]

Mam last printf statement you said that b value will be 6 it will not be 7 but if i run that program and printf("%d",b); the output is 7 not 6

[@jaijaijaijai123]

bitwise operators can be applied on -ve numbers

[@MECH-to-IT]

1 and b = 6... bcoz 0 && b++ then first false then second not checked in and op.

[@shwethanagaroor8949]

At 16:23... U said to use apparends in the place of logical OR... I applied and I got ans =1. Am I right mam

[@farzanaashraf8136]

Yes you are right but the value of b will not be updated, it will remain 6.

[@chittuluribhuvaneswari2914]

13:32 it's arithmetic not relational 🤔

[@sreevidyam8963]

Output:1 b=6

[@starkendeavours7072]

What mam told at the end, if we use logical AND then also the output will be 1 as 1 && 6 is 1 and since the first operand is true which is 1. so will b = 6 or 7? in next printf statement. Can u please explain?

[@vaibhavsinhbihola1]

b is 7 bcz in and operator first is 1 then second expression will be evaluated so in this question b is evaluated therefore b is 7

[@jitendratiwari4292]

Dress++ 😎, *+beauty 🥰

[@dhananjayjadhav7064]

Yahh😂❤️

[@Mukesh-cw3tz]

Output of three statement are:- O 7 7

[@aravindraj913]

A&B = 2 A|B = 14 A^B = 12

[@4zp207]

2,14,12 is answer for what u told to answer in comment section..

[@kpandeeswari6037]

First comment😍

[@vikashjha6628]

very helpful

[@jaijaijaijai123]

NOTE: Precedence will come into picture only if expressions will be evaluated. In case of && or || its possible that some expressions may not be evaluated at all because we obtain 0 or 1 respectively. Hence, no matter how much higher precedence operators are there in those expressions, those expressions would never be evaluated