C++ Polymorphism and Virtual Member Functions [6]

In object-oriented programming, polymorphism enables object reference variables or pointers to reference objects of different types, and to invoke the appropriate member functions based on the type of object being referenced.
Learn how through writing sample classes in this C++ tutorial for beginners written with Visual Studio 2022 C++ .
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The Inheritance, Polymorphism,and Virtual Functions play list:
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[@orionpluto1214]

The best explanation I've found on this subject, thank you very much !

[@saramomen2161]

You explained too well. Tomorrow is my exam and I understood the topic completely. Thank you.

[@ProfessorHankStalica]

Glad it helped!

[@dwivedys]

Absolutely wonderful!

[@Johannes-vr3vc]

Some time ago, when I used g++, I could type something like this: Square *s = (class Square*)&r; I think this will probably still work and maybe it explains things better.

[@lg7t]

so why did we make all the destrcutors virtual should not that be just for the base class or we did it for readbilty of the code ?

[@menachemlevi]

amazing keep going

[@ProfessorHankStalica]

Thank you, I will

[@AlexTrouman-oi1yp]

Mr.Hank please what is the difference betwen ~square(){}; and virtuel ~square(){}; .Thanks for your explanation

[@ProfessorHankStalica]

It's the difference between using static binding and dynamic binding. If you want C++ to decide which method to use at runtime, you use dynamic binding (virtual), otherwise you use static binding. Sometimes C++ has to decide which destructor to use at run time. Basically, if you expect your class will ever be inherited from, you should make the destructor virtual.

[@user-hq2pc5yz6p]

what if we did r.print()

[@bashiraddean-mufarreh]

im first watching 🤓first like 👍🏻

[@manedurphy]

class Foo { void print() const { cout

[@ProfessorHankStalica]

It means that the print() function can not contain any code that modifies class member variables. If print were to try, the compiler will give you an error at compile time. For example, class Foo { int x; void print() const { x = 0; cout

[@manedurphy]

@@ProfessorHankStalica thank you for explaining. new subscriber 🤝

[@egetan9247]

Sir , I did not understand something , which is ; Why we put virtual for all destructors meanwhile put virtual for only base class's print function . Thank you for considering :)

[@ProfessorHankStalica]

You use virtual on methods that you expect will be overridden in child classes. If there is a chance your class gets inherited from, then it's a good practice to make destructors virtual. That way, if the classes get used in a polymorphic context, you ensure the correct destructor is executed for each object.

[@egetan9247]

@@ProfessorHankStalica thank you so much.. :)

[@massimoazzano]

I like you use a geometric example, people like me can visualize the proposed problem, meaning and scope!

[@jesuschrist1501]

yea but why the hell would you ever need to use all this shyt, keep it simple and readable.