C Practical and Assignment Programs-Pattern Printing 9

[@ZaiiZ3ro]

dude you're a life saver !!!

[@yuvrajadkar]

Shortest and Smart code for diamond pattern in just 2 FOR loops.. #include #include #include void main() { int n,row,col,flag=0; printf("Enter Number"); scanf("%d",&n); for(row=1; row>=1; row++) { for(col=1; col=row) printf("*"); else printf(" "); } printf(" "); if(row==n) flag=1; if(flag==1) row = row-2; } }

[@wethecomputerguys9903]

@V Lak Here is the link to the diamond pattern. wethecomputerguys.com/2014/09/08/pattern-printing-28/

[@SmartProgramming]

awesome work sir, keep going, best wishes for future 👍👍

[@nikhilgoyal8340]

Here for printing spaces in the second case we can use the same for loop as used above that is ::: for(colSpace = totalRows-row ; colSpace >=1 ; colSpace--) In the second for loop since we have started counting rows from 4 the same logic for printing spaces will work.

[@yuvrajadkar]

Shortest and Smart code for diamond pattern in just 2 FOR loops.. #include #include #include void main() { int n,row,col,flag=0; printf("Enter Number"); scanf("%d",&n); for(row=1; row>=1; row++) { for(col=1; col=row) printf("*"); else printf(" "); } printf(" "); if(row==n) flag=1; if(flag==1) row = row-2; } }

[@SaumyaSharma007]

Thanks man 👍 for the concept....

[@arilee5450]

Thank you so much for your detailed explanation. it was extremly helpful!

[@ItTimetotravel]

kzbin.info/www/bejne/moisloemh5eBrdU for reverse pattern for beginner

[@yuvrajadkar]

Shortest and Smart code for diamond pattern in just 2 FOR loops.. #include #include #include void main() { int n,row,col,flag=0; printf("Enter Number"); scanf("%d",&n); for(row=1; row>=1; row++) { for(col=1; col=row) printf("*"); else printf(" "); } printf(" "); if(row==n) flag=1; if(flag==1) row = row-2; } }

[@DannyKnot]

What if instead of using white spaces I wanted to use "+" ?

[@deepaagrawal8653]

thanks for making me to take intrest in learning in pattern only becoz of ur awesome video

[@deepaksuri8423]

I looking for help with the pattern of : Seven lines of output as follows: The first consists of 3 spaces followed by a star. The second line consists of 2 spaces followed by a 3 stars. The third consists of one space followed by 5 stars, and the fourth consists just of 7 stars. The fifth line is identical to third, th sixth to the second and the seventh to the first.

[@yuvrajadkar]

Shortest and Smart code for diamond pattern in just 2 FOR loops.. #include #include #include void main() { int n,row,col,flag=0; printf("Enter Number"); scanf("%d",&n); for(row=1; row>=1; row++) { for(col=1; col=row) printf("*"); else printf(" "); } printf(" "); if(row==n) flag=1; if(flag==1) row = row-2; } }

[@abhitasan]

Can you provide me a code whose pattern resembles to a diamond and in between that i have to write AMU ,means in the middle line ..

[@serajhassan545]

can u write code only using 3 loops that will print at a time instead of writing two times for each parts because its not look good.

[@cafafans]

I saw so many comments complaining; I decided to help you guys; for anyone that care, here is a link to my Github Repo. You can download all source codes. If you have any question; feel free to ask. github.com/ElectronicMoney/PatternPrinterCProgramming

[@yuvrajadkar]

Shortest and Smart code for diamond pattern in just 2 FOR loops.. #include #include #include void main() { int n,row,col,flag=0; printf("Enter Number"); scanf("%d",&n); for(row=1; row>=1; row++) { for(col=1; col=row) printf("*"); else printf(" "); } printf(" "); if(row==n) flag=1; if(flag==1) row = row-2; } }

[@justarandompersonontheinte9818]

Does this code uses recursion?

[@MS-rl7rh]

Thank you sir, it's very helpful

[@bipros7]

Sir,after coding the above statements when i run this program,stars of upper half of the triangle from row 1 to row 5....but the lower half of the triangle is not executed...I'm using turbo C++ compiler fr windows7...why is this happening?

[@vijayKumar-pf8ol]

beta ye work ni kregaa

[@Kris-ui1wv]

#include int main() { int n, m, k, i= 1; printf("Vendosni numrat e rreshtave ");//n-nr rreshtash scanf("%d", &n); i = n - 1;//i hapesira for (k = 1; k

[@vignesh8507]

@@Kris-ui1wv appreciate you

[@yuvrajadkar]

Shortest and Smart code for diamond pattern in just 2 FOR loops.. #include #include #include void main() { int n,row,col,flag=0; printf("Enter Number"); scanf("%d",&n); for(row=1; row>=1; row++) { for(col=1; col=row) printf("*"); else printf(" "); } printf(" "); if(row==n) flag=1; if(flag==1) row = row-2; } }

[@esomcmuffin8989]

Would you be able to write this code, except take in user input for the middle row and have a minimum of 2 stars in each row? Im having a lot of trouble in doing so. Thanks

[@wethecomputerguys9903]

Eso McMuffin I dint get your doubt. can u send me a sample input / output for your question?

[@esomcmuffin8989]

So I would like the program to accept user input for the middle row and how many rows on top and below the middle as well. so if user enter 6 for middle row and 4 on top: ** **** ****** **** ** also, there cannot be less than 2 asterisks per row

[@muhammadsheharyar4105]

you are awsome bro ......realy a helpfull video for my assgnment..keep it up

[@yuvrajadkar]

Shortest and Smart code for diamond pattern in just 2 FOR loops.. #include #include #include void main() { int n,row,col,flag=0; printf("Enter Number"); scanf("%d",&n); for(row=1; row>=1; row++) { for(col=1; col=row) printf("*"); else printf(" "); } printf(" "); if(row==n) flag=1; if(flag==1) row = row-2; } }

[@sunilsharma9611]

Very very thanks for helping .

[@muwangasulaiman9246]

hey write for me a program which prints 6 stars in the first column,4 in the second,3 in the third,2 in the forth.remember there are 8 columns and 6 rows.but the forth row is printed throughout.am waiting thanks

[@speakingwordsindia5631]

not a correct code i think. The program is not running correctly plz help

[@olsonjames2614]

how to get the out of 9 stars shape by using c++ program

[@shristisinha7264]

how we will write the code for N pattern

[@lakhdeepsingh5883]

sir pls tell, which platform you use to write codes, i use turbo c

[@YashYadav-dd7is]

Lakhdeep singh It is dev-c

[@seeknithyashri6591]

sir why u r naming the lower half as 4 3 2 1...can we name it as 1 2 3 4....

[@baljotsingh4013]

Because the loop is working in reverse, so the rows will be 4 3 2 1, 1 2 3 4 is when you're iterating a normal loop

[@skylar6268]

Sir , in the first nested loop to print * - last video u told the logic is.. for(colstar=1;colstar

[@skylar6268]

i got it :P tq !

[@yuvrajadkar]

Shortest and Smart code for diamond pattern in just 2 FOR loops.. #include #include #include void main() { int n,row,col,flag=0; printf("Enter Number"); scanf("%d",&n); for(row=1; row>=1; row++) { for(col=1; col=row) printf("*"); else printf(" "); } printf(" "); if(row==n) flag=1; if(flag==1) row = row-2; } }

[@khanzadaasad4127]

how to make program for this output?? * * * * * * * * * * * *

[@Junaidkhan-ti8qd]

+khanzada Asad hahahahahaha hpala e jora wa kana

[@tryingtocorrect]

+khanzada Asad This is just a quick one, surely can be done in a better way, but it works (size is the size of the figure): #include using namespace std; int main() { int size = 4; int halfHeight = 2 * size; for (int i = 0; i < halfHeight; ++i) { for (int j = 0; j < halfHeight - i; ++j) cout

[@krishnadevanp3820]

Which compiler is this??...can you help.Me to install that on windows10

[@satarabanolur9284]

Krishnadevan P devC++ dude

[@martialolipiano9803]

please can you do it in Visual Logic?

[@thespicyspicey]

Check out this video, you'll understand kzbin.info/www/bejne/lYmxhJpsdt9mgKc

[@bonifacemusembi9459]

how can i form this pattern * * * * * * * * * * * please help

[@ThePheonix123]

The code source link is not working for me, can u pls post a working link?

[@Ghandimw2]

+ThePheonix123 This is the same code but uses an input from the user in order to make the triangle. Use the online c++ compiler c++ shell and it'll run. #include using namespace std; int main() { int n; cout > n; for (int row=1; row=1; col--){ cout

[@yuvrajadkar]

Shortest and Smart code for diamond pattern in just 2 FOR loops.. #include #include #include void main() { int n,row,col,flag=0; printf("Enter Number"); scanf("%d",&n); for(row=1; row>=1; row++) { for(col=1; col=row) printf("*"); else printf(" "); } printf(" "); if(row==n) flag=1; if(flag==1) row = row-2; } }

[@zekosalemeh4135]

hey i saw all the video you install and i liked i want to know what to do if my dev c++ make cmd run then close without show me the solution

[@ashishmane1343]

"9 7 C:\Users\Ashish\Desktop\porgrams\pattern print 2.cpp [Error] 'colstar' was not declared in this scope" what does that mean pleas tell me the solution on this error........

[@wethecomputerguys9903]

Ashish Mane Post your source code.

[@ashishmane1343]

#include main(){ int totalrows=5; int row,colspace,rowstar; for(row=1;row=1;colspace--){ printf(" "); } for(colstar=1;colstar=1;row--){ for(colspace=1;colspace

[@bipros7]

Ashish Mane while declaring you mentioned rowstar instead of colstar,thatswhy this error is coming...

[@Junaidkhan-ti8qd]

+Biprodip Sanyashi how this error can be removed plz tell me as they say "undefine colstar"in the upper written program

[@skylar6268]

+Junaid khan error can be removed by changing the name of the variable rowstar into colstar (or) instead of colstar use rowstar itself !

[@lynetsvotwa3704]

please make the programs simple and i need a program to accept m*n matrix and generate a (m+1)(n+1)

[@justinkujur4618]

How can i solve this program using a single loop

[@yuvrajadkar]

Shortest and Smart code for diamond pattern in just 2 FOR loops.. #include #include #include void main() { int n,row,col,flag=0; printf("Enter Number"); scanf("%d",&n); for(row=1; row>=1; row++) { for(col=1; col=row) printf("*"); else printf(" "); } printf(" "); if(row==n) flag=1; if(flag==1) row = row-2; } }

[@Pachojuanck]

Ojala hubiera gente que explicara como tu, pero en español :/

[@malkeetsingh8849]

Marvellous guys.

[@shitizgupta3557]

can you plz tell me how to print this &&&&&&& &&&&& &&& &

[@Elporqué-m6w]

I need to make 64 combinations wiht + and - heelp me please in this

[@IbnHussain12]

Great work ..

[@dilhanidesilva548]

thank you sir

[@aiazasheikh8224]

Kindly provide this using do while loop

[@shaleen9434]

sir please make a video on i in Ind Indi india

[@SUNNYPATILkolhapurkar]

char word[ ]={'i','n','d','i','a'}; for(int i=0;i

[@pratyushsrivastava4476]

Printf(" - %5.*",(arrayname), (width)) ; ... Look for it in you book

[@zareensayed6922]

Thanks 😊

[@profstat1970]

guys pls tell me how to find this output without using any spaces * ** * ** *

[@tryingtocorrect]

+Prof Stat hmm, how can that be done without spaces becouse it clearly ahs spaces..

[@jasluvdeepsingh8491]

The number of * printed is same as the row we are in. Row 1 has 1 * and 2 has 2 *. No need for spaces. Just write the loop for star with for(row=1; row

[@zoufisha6376]

awesome and fully usefull

[@benjidabull]

THANK YOU SO MUCH

[@munazamalik7427]

Isi ko C++ me kese bnaty hn plz tell me 😑

[@priyachaudhary1210]

If(j>=5-i&&j

[@apsietese8718]

Thank you

[@suprajaprabakaran2159]

I need a mentor to write a c programming... I wanna know about the c programming from beginning... can u please guide me...can u give me ur email Id pls...

[@shreyapaul358]

With my like u complete 1k like🙂

[@nagapurisaivishal1667]

Please i need Code make video for below pattern 1 1 33 33 555555 33 33 1 1

[@Abdu_401]

Thanks

[@mohammedk.k6472]

thanks Sir

[@Usgshshs]

kardeşim teşekkür ederim

[@jhay-araguilar5462]

if n = 4 4 3 2 1 3 2 1 2 1 1 Can you help me please?

[@wethecomputerguys9903]

Hope this would be helpful : wethecomputerguys.com/2014/08/23/pattern-printing-23/

[@jhay-araguilar5462]

//print spaces for(j=0;j0;j-) printf(“%d “,j); This part is incorrect and I try to rearrange this but it's still no good.

[@wethecomputerguys9903]

Jhay-ar Aguilar We are extremely sorry for our mistake ... Thanx for pointing it out.. I have updated the code .. Now it works fine..

[@jhay-araguilar5462]

We The Computer Guys It works. Thanks. :)

[@andargachewmekonnen7164]

It is awesome

[@diamondabbasi284]

thank u sir

[@aruna4760]

Sir please explain the below pattern 1 1 * 2 1 * 2 * 3 1 * 2 * 3 * 4 1 * 2 * 3 * 4 * 5

[@arjaypaglinawan1996]

if n = 4 4 3 2 1 4 3 2 4 3 4 need help :(

[@rithikroosen2416]

If n=4 for(i=1;i=i;j--) { cout

[@serdarkarakas996]

lan bu ne biçim ingilizce 12 dakika 43 saniye boyunca işkence ettin be bilader. thanks for video, great india namaste

[@sachinkumar5879]

THANKSSSSSSSSSS SIRRRRRRRRRR

[@vivekkumarsoni3860]

Nyc...

[@vigneshseralathan9884]

bro print this pattern. P M R A O R G O R R A P M Please help me out with this in C nd JAVA

[@thespicyspicey]

Hello, it's been 4 years.. hope you had cleared this problem. If you still haven't, reply here, I'll send you the code and explain it to you.

[@moixcodez1585]

omg your english ankcent.........

[@xsquall19x]

VASH HAMANYAK

[@juanrodriguezluis4811]

good idea... sad that his accent is too strong... i can not understand, what he says.

[@ashissahoo4158]

how to draw pattern sssss s s s s s s sssss

[@SUNNYPATILkolhapurkar]

for(int i=0;i

[@DeepakYadav-gz9ei]

Quality bahoot kharab hai

[@sawakokuronuma8689]

bhai ya urdu ma ya hindi ma hi bol lety..

[@TheZekf]

omg your accent dude :(

[@atreyeesardar6100]

******* ***** *** * *** ***** *******

[@dubbingertugalseries5155]

Q English ko chod rha hai.Hindi ma baat ker kuch samj v aa jaye..ya English seekh k bol.

[@venkat2830]

c is difficult aaaaaaaaaaaaaa

[@monukumar5618]

Need to improve

[@soustavnandy3043]

Bad

[@piyushsingh2719]

thank you sir

[@muhammadsheharyar4105]

* * * * * * * * * *******