C Program to Check a Number is Armstrong or Not | Learn Coding

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writer ✍: ankush
voice 🔊: akhilesh
Thank You 👌👌👌

[@DhruvGadara]

aapki technic se muje sab samaj aa jata he 🙏🙏👍👍❤❤ THANK YOU Learn Coding

[@samratmandal2523]

Great explanation ever! Respect... Thank you so much sir 💝

[@janhvinarayan1633]

sir aap pehle hi itne ache se samjha dete hain ki dry run ki zarurat hi nahi padti hain par sir aapne bus 3 digit armstrong no.s ke liye bataya hain, agar aap general program batate any no. of digit no.s ke liye too aur acha hota bhale hi vo zyada lamba aur complex ho jata

[@nilanjandey9604]

Sir, thank you so much. 🙏 your explanation is really awesome. 🙏🙏

[@adnanbinalam2539]

Thank you so much sir for your awesome and simplicity example. when there are some question which I can't solve or hard to understand I just come to you. Now I am a regular viewer and fan of you.

[@surtasingh6480]

This is very helpful.... Mujhe ye Armstrong name sun ne m hi bdaa hard lagta thaa..... Lekin aapke itne acche se samjhaane pr ek baar m hii samjh m aa gya wo bhii bina Dry run k..... Thank you ❤so much.... Aap bahut hi acche se samjhaate h..

[@digvijaychaudhari2892]

Best Explanation Thank you Sir🙏🙏👍

[@bhagyashri5114]

Easy to understand concept... Thank you sir..

[@pawansahu5175]

Very good video for this question

[@sandiponghanty9925]

4:44 bro got connected with another planet

[@harshitbisht6419]

😂👍

[@drgamer84]

Bahut acha video hai

[@vivekdighe4117]

Excellent explanation 👏😀❤

[@shaiktanjuna8626]

Great explanation thank you 👏

[@drniketu]

Mauj kar di sir. Aapne jitna pressure pen pe dala hai likhne mai, utna hi pressure hamare dimag se kum ho gaya :-)

[@arpan9585]

best explanation thank you sir

[@BabyWorld-f8m]

very very nice explanation i am ur regular viewer thanks for sharing that kind of videos to understand our concepts 🤩😇👌

[@vaibhavgupta777]

Thank You Sir So So Much🙏🙏🙏🙏

[@yashmakwana956]

Your methad is so good 😊😊

[@madhurithoke3480]

Thank u sir🙏 and ur videos always help me a lot and ur teaching is commendable sir😊

[@MiniMarvelsStudio-o9s]

what about if any number having more than 3 digit, Then how can program multiply them? for example if user input 1634 then all digit need to multiply 4 times of itself.

[@raghasreekosigi4443]

armstrong number means sum of cubes of digits in a number...it doesnt matter how many digits..if the answer is same as the number.Then it is a armstrong number

[@bhuvxn]

Use another while loop

[@lipakshishaw9471]

Sir your videos are very helpful....ur explanations are awesome....

[@sumantsaieskaspa]

bhaiya dhanyavad mai aap video half bhi nahi dheka lekin pura samajh gaya logic mujhey jaha doubt tha na exactlyvo pointvery clear tha aur aap code bahuta acha say smajha rahey hai. Maza aa gaya and akpo subscribe karna banta hai and once again dhanyavad

[@ig.devil_21]

Simplest explanation sir 🔥🔥🔥

[@prernakumari1431]

Thank you sir It was helpful

[@Shivakumar-vg4hx]

Super sir u are good sir you are excellent

[@NehaSharma_nsds]

Great explanation sir 😊😊💜

[@Alphx_pvt]

Sir you're awesome 🎉

[@archnajekku8255]

Good explanation 👍 Thank you so much 🤗

[@animaqaar]

aapka explanation bhut achha hota h ❤❤❤

[@gaziogamer]

very nice explanation sir

[@user222-i7q]

Yes it work for four digit number try it with 1634 and do (r*r*r*r)+arm

[@ankitmji786]

Thank you so much Sir 😊

[@fax_tech]

Very useful thanks 😊

[@hpk.3617]

thanks sir mujhe bahut der se sahi video nahi mil arhi thi

[@ShubhamKumar-qo6qs]

well explained sir Thank you

[@MondalSuvankar]

The best c education hub in KZbin What a explain sir❤ Mind blowing Superb sir I see your video for my doubt only your video clear my doubt❤❤❤❤ Sir one more thing sir give some video for BCA course

[@arshshaikh9442]

Thank you so much sir your videos helps us alot 💓

[@xyzcontent5599]

kzbin.info/door/jEOyfxpWMY7tJO9D2rt5JQ

[@maxgamingyt100k]

Thank you sir ❤ Nice 👍,

[@delllaptop2605]

Very big congratulations for 1M and salute to your efforts... 🔥🎉🎊

[@RoyalKingharshpandit]

Mst sir g good 👍 u

[@viane123456]

Very good program thank you

[@xyzcontent5599]

kzbin.info/door/jEOyfxpWMY7tJO9D2rt5JQ

[@Alwayspositive-pf1yf]

Thank you Bhai nice explanation

[@savagestuff4334]

King of coding♥️♥️♥️

[@Akashkumar-vu9bu]

Thnks sir Isska program mere sar ke uper se jaa rha tha par abb clear hai

[@arshuarshad1551]

your dry run is fantastic sir

[@radhikaparaja1369]

Very well explained sir but how will you very much talent 😮😮😮

[@bhupendra382]

Bhai you taught excellent

[@Kaifgaming-w3d]

GREAT EXPLANATION sir In dry run

[@famousjedits_143]

Really very helpful

[@rohit_lomga]

Thank you sir

[@jatinjasrotia31]

thanks buddy and well explained keep bringing these vedios.

[@talibhussain7050]

thankuu soo much

[@Abhay0498]

Jai ho

[@abhitapaniya9276]

thank you sir you're great

[@26_rajashrikhetmalis34]

Thanks sir

[@RoyalKingharshpandit]

Thanku sir g

[@Fact_Frenzy11]

guru jii

[@Ayush_shukla0143]

Bhott sahiii guruuu Maja aa gya

[@user-meeSS]

Awesome explanation

[@niteshnayak940]

Great❤❤❤

[@alameen6329]

Very helpful , thank u❤

[@abhinavsingh9315]

nice explanation

[@ankushdangi3154]

Ese hi vidio bnate rho

[@PrasantaDas-cj4xe]

Thank you so much 🙏🙏

[@sambitbhattacharya2413]

sir but this is only for a 3 digit number what if user input a four digit number . then it would be 1^4 + 2^4 +3^4+4^4 just like that .. this program is only applicable for 3 digit numbers .... it cannot check 4 digit number

[@RamDas-lq4ld]

yes i also face this problem

[@nckcyc191]

No this is not

[@nckcyc191]

Only

[@nckcyc191]

Digits se matlab nahi hai

[@nckcyc191]

Arm no. is a no whose sum of cube of no. is equal to the same no

[@shubhamkumarjha9192]

Superb..👍❤️

[@pradeeppradeepkanaujiya8990]

Great explain sir 😊😁😁😁

[@crAzy.346]

it is not the general solution for all armstrong number as when the input is 1634,it shows not armstrong number....it is obvious because in this code we are doing the cube of the digits...but in the original logic of armstrong number we are multiplying n times where n is the length of the number...in case of 153 n will be 3 and in case of 1634 n will be 4...so 1^4+6^4+3^4+4^4=1634......

[@yashmakwana956]

Super

[@thathaseyyalubogadi5864]

Thank you sir 😊😀😃🙂😉

[@dhanuu1062]

Thank you sir🙏

[@RohitKumar-zp1ru]

Sar computer graphic ki video bhi send kar dijiye important

[@theproplus7061]

Sir apke chalte mai programming sikha mujhe pahle nahi samaj aata tha thanku so much sir...Sir interview ka question ka video banaiye sir plzz

[@prashantbhujbal9880]

Thanks a lot bhai❤😌

[@beastboy7327]

Thanks 👍

[@romanbirla5410]

Great Sir...💯❤️

[@rhythmmissen3130]

thanku sir : )

[@ashishmemariya1204]

There is small mistake in your concept....An Armstrong number is a number that is equal to the sum of its digits each raised to the power of the number of digits. In other words, if you take each digit in the number, raise it to the power of the total count of digits in the number, and then sum them all together, the result is the original number itself.... and you said about the cubes which is wrong.. Hope it will helpfull...

[@sheetalsharma1675]

bhot acha padthe ho aap..

[@mahekjoshi9959]

dry run badhiya kiya

[@ankushdangi3154]

Super sir ji

[@pariagarwal1284]

Nice explanation 😀

[@status_beatz_1]

Next level explanation 😁😁

[@sanjibpaudel6921]

only applicable for 3 digit numbers

[@swapnilchate2412]

Great Explain 👍

[@Gattiks_edit_OFFICIAL]

🙌

[@miraclebeats7542]

Thanks sir 💯🥳

[@surendradahare704]

This is too good 😊😊😊

[@wonderchemistry76]

Programming galat hai Agar 4 ya 2 ya kitne bhi digit ka number ho to kya karenge

[@gulabchandgupta5486]

Nice ❤️❤️ concept and explained 🙏🙏

[@xyzcontent5599]

kzbin.info/door/jEOyfxpWMY7tJO9D2rt5JQ

[@arbaazahmed1603]

nice explain sir👍

[@tanupriya2571]

Wah sir

[@gauravthakur6634]

❤❤❤

[@aviralmishra785]

Thankyou 🙂

[@shivamkadve9938]

Thank you sir 😌

[@kartickchandramanna267]

Good explanation. Thanks 🙏

[@xyzcontent5599]

kzbin.info/door/jEOyfxpWMY7tJO9D2rt5JQ

[@upashna397]

Thankyou

[@RupakDash]

Agar 1634 likhe to code run karega?

[@satisfy146]

Thanku sir

[@rishavsingh1849]

Thanks