Calculate LCM Of Two Numbers in Python | Python Program For Finding LCM of 2 Numbers

[@BCS_MohdMaaz-bm8vu]

LCM to n numbers # LCM of n numbers n = int(input("Enter value of n : ")) li = [] print("Enter the numbers : ") for i in range(n): li.append(int(input())) def LCM(li): max = None for i in range(n): if max is None or max < li[i]: max = li[i] while True: for i in range(n): if(max % li[i] == 0): if( i == n-1): return max else: continue else: break max = max+1 LCM = LCM(li) print(f"LCM of {li} is {LCM}") Thanks Harry bhai you teach it so well that now i can easily find the lcm of n numbers

[@sunilpal5389]

One of the best coding teacher of this era!

[@aditgaur1585]

I think we can simplify our code by :- a = int(input('Enter the First number: ')) b = int(input('Enter the second number: ')) maxNum = max(a, b) while maxNum % a != 0 or maxNum % b != 0: maxNum += 1 print(f"The lcm is {maxNum}")

[@jishnudhar1507]

Thank you Very much!

[@DiptabrataMukherjee]

Please make a series on React JS...

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Ha bhai hmko bhi sikhna h

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Bhaiya aap jaise teacher hona chaiye bas... India sbse aage chla jyega

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Harry Praji. Bas isika intazaar tha. Wo bhi Apne puri Kar Di. Thanks Praji . Aise hi maths and CP me video. Banayiye. Apka channel best hai. Aur aap to ho hi best. Aur all rounder. Superb explanation.

[@RinkuDevi-mu6uz]

Sir , using this code I've found out both HCF and LCM of two numbers (I've not used math module) : def hcf(a,b): if a < b: c = a + 1 else: c = b + 1 for i in range(2,c): if ((a%i == 0) and (b%i == 0)): hcf = i return hcf a = int(input('Enter 1st number : ')) b = int(input('Enter 2nd number : ')) print() print('The HCF of these two numbers is :' , hcf(a,b)) d = (a*b)/hcf(a,b) print('The LCM of these two numbers is :' , int(d)) Hope you like it .

[@durgaprasadkanda1676]

For 3,5 what will hcf function return? It should be 1.

[@ishansrivastava674]

hello sir i am currently watching your python full playlist and I am on the 36th video of that playlist and I just wanted to say thank you sir for creating such good videos

[@sachini1168]

p=int(input("enter num1:")) j=int(input("enter num2:")) if(p>j): for k in range(1,p+1): if(p%k==0)and(j%k==0): l=k else: for o in range(1,j+1): if(p%o==0)and(j%o==0): l=o print("LCM of the following numbers is",(int((p*j)/l))) Simpler.

[@sunilsah4993]

a = int(input(" Enter first number ")) b = int(input(" Enter second number/n") maxNum = max( a, b ) while( True ): If( maxNum%a==0 and maxNum%b==0): Break maxNum = maxNum + 1 Print(f"The LCM of {a} and {b} is {maxNum}")

[@RaviRanjan-yi5rq]

maxnum=maxnum+1 why

[@Shauryaaaaaaaa]

Java = System.out.println("Harry is the best teacher"); JavaScript = Console.log("Harry is the best teacher"); Python = print ("Harry is the best teacher") .... .... .... You take as many languages but the output will be same that Harry is the best teacher

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[@vimalkumarchaudhary1913]

Pura pasand aaya hai nd best incredible teach

[@focusonmyaim8980]

a= int(input(“enter a no”) ) b=int(input (“enter second no”)) i=1 while ((a*i)%b !=0): i+=1 LCM= a*i; print(“LCM of” , a “and”, b , “is” , LCM)

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Congratulations sir on 6 lakh subscribers

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i have watched your machine learning playlist and it helped me a lot. Thank you.

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Harry bhai kyo na aap programming ke liye maths be sikhane🤩🔥

[@tasin487]

Thanks a lot Harry vai. It helped me a lot.

[@rudrashiva]

Programming is the best way to increase your thinking capabilities. Let's build a strong Bharat coding force.

[@rajnishpal2460]

One of the simpliest explanations by harry bhai

[@introvertgamer6850]

hi i got this question in an interview i used same method but for large input time limit get exceeded is there any optimal way to solve it

[@ganeshjaggineni4097]

NICE SUPER EXCELLENT MOTIVATED

[@MananGandhi]

East or West, Harry Bhai is the best

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sir please make hangman game with python please.

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Excellent video

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Harry bhai , I wish aapke 1 million ho jaye

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Bhai Ruby and shwift par banao series🤗

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[@thatcoolkid370]

He had already made a video on it

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[@jitendradashora8956]

def is_smaller(num1, num2): if num1 < num2: return num1 else: return num2 def is_greater(num1, num2): if num1 > num2: return num1 else: return num2 def hcf(a, b): divisor = is_smaller(a, b) dividend = is_greater(a, b) while True: remainder = dividend % divisor dividend = divisor if remainder == 0: return divisor else: divisor = remainder def lcm(a, b): return (a * b) // hcf(a, b) while True: print(lcm(int(input("Enter your first number:- ")), int(input("Enter your second number:- "))))

[@sudarshanmhaisdhune1039]

Good one!

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Great video

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[@nilanshpathakk760]

thanks bro!

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Thank you sir..Thank u for making Python an easy programme that I can understand..

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[@AshishTiwari-zj7yq]

MaxNum=MaxNum+MaxNum

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Amazing

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bhaiya mai bhi programming ke line pe jaunnga .

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[@AdarshSingh-cb5yf]

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[@chaitanyabansal292]

should not we write maxnum= maxnum+ max(a,b). Since LCM will always increase in the multiples.

[@PranavBhattad]

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You will also need REACT AND NODE too

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Yes I have make with pure html , css , js and no other libary or framework used

[@harsh_miglani99]

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Please tutorial on Oracle

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Plz make a jarvis because my brother was telling that u can not make jrlarvis by using java

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Bhaiya class 10th se aadhe aadhe ghante me kya ham programming sikh sakte hai ??? Agar ha to hame start kya chiz se karna chahiye jo next 2-3 years me beneficial ho.....please like and comment !!!

[@Shauryaaaaaaaa]

I think you should start from c++

[@g4j3ndr4]

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[@laxmikanth8076]

sir how to get out while loop without using break . for this to happen what condition should we give to while loop for the same program

[@prashantthakur113]

Sir apney toh "python for absolute beginner" waley playlist mai toh Python key liye hammey pycharm recommend kiya tha..Toh ye (v.s code) mey kyu kar rahey Ho?

[@rajputjay9856]

You can use VSCODE THATS BETTER .... Pycharm is complicated a little bit with libraries ... So use VSCODE that's the best

[@prashantthakur113]

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[@mohitgupta2699]

I use submile text 3 , it is a light weight editor and easy to install

[@prashantthakur113]

@@mohitgupta2699 Me too

[@shivamchaudhary2714]

Sir more than 2 numbers ka LCM nikalne ke lia kya kare Please bata do 🙏🙏

[@crazyduniya128]

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[@pratik6089]

Why max incremented by 1???

[@nitinverma1359]

bhai ye bta do ki tensorflow install kese krna hai Install krne pe error aa rha hai (pip install tensorflow ) se bhi error aa rha

[@MohitKumar-dk2tt]

Machine learning pa aur videos kab aaye gi

[@AkashSharma-mv2yx]

Bhai m ne ek software banaya h aap ke video dekh ker or m us ko play store per upload ker ru ga per kya m ker m update dal pau ga kya

[@ameygujre7674]

instead of incrementing 1 in every iteration, why don't we increment the maxNum as it's table. since it is pointless to check every single number with the increment of 1. We can simply iterate the table of max num till it is divisible by the least number..

[@ScholarStream_25]

Bro check that calculator of cbse students asap🙌

[@neontuts5637]

Harry bahi HCF aur GCM same hai kya?

[@arnavjha7375]

HCF aur GCD same hota hai Agar GCM chiye to dono number ko multiply kar do

[@java2308]

Can you make a video on how to find LCM of two numbers is JAVA

[@thelocaldev]

Sir I think it is not working fine its not able to calculate the LCM of 3 and 5 , its giving a result of 5 where the original result must be 15

[@DreamPixelStoryOfiicial]

sir, use for loop video give me

[@shantanulamba3599]

Unity tutorial

[@urm1n]

a = int(input("Enter Fist Number ")) b = int(input("Enter Second Number ")) maxNum = max(a, b) c = maxNum while(True): if (maxNum%a == 0 and maxNum%b ==0): break maxNum = maxNum + c print(f"The LCM of {a} and {b} is {maxNum}")

[@PreetRaj235]

What is f here

[@urm1n]

@@PreetRaj235 it's python code (f string)

[@Opinionmatrix1]

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[@jeenu123]

Please make unreal engine tutorials

[@rsatishkumar1682]

Hi sir Can anyone explain maxNum=maxNum+1

[@AshutoshKumar-ij5hw]

Python code me while ke ander true likhne ke baad name true is not define esa error q aa ra h

[@aayushgupta2048]

❤ please

[@sumansingla9644]

Sir basic tutorial session ki series m comment kiya h mne please ta do

[@vaibhav3852]

bhai mujhe isiki talash thi

[@rudrapatel2234]

I found mistek in programme that we can't find LCM of numbers like 3,7,11,13,17,19,29,23

[@danishmakrani8991]

Sir 45 aur 60 ka lcm galat a raha hai yeh program se