Calculate the pH of a Strong Acid and pOH, [H+] & [OH-]

[@salmaaosman2829]

I haven't seen anyone explain this as simply as you have so THANK YOU

[@AnneSchmidt]

Thanks! Glad the video helped you 👍🏻

[@soniahshankoti6245]

Simple and straightforward Easy to understand

[@AnneSchmidt]

Thank you 😊

[@KumoGhum]

Thank you so much, your so good at explaining i wish my teacher was as good as u

[@AnneSchmidt]

Awww 🥰 thank you! Glad you are finding my videos helpful.

[@lallal7528]

Leaving a comment to appreciate the work and the creativity. Helped out

[@AnneSchmidt]

Much appreciated!

[@asifulalamc]

Great video! Merry Christmas and Happy Holidays!

[@AnneSchmidt]

Thanks! Have a wonderful holiday season.

[@angeleerivera1690]

Super helpful! Loved the visuals, thank you so much!

[@AnneSchmidt]

Thanks 😊 Great to hear the video was helpful

[@Dodo-ym8cc]

I have a question for Anne Schmidt: What happens to the Kw water equilibrium when a strong acid fully dissociates and you get loads of H+, does it disturb the water Kw equilibrium, if so in what way? Thank you for your time.

[@AnneSchmidt]

Typically only a change in temperature alters the Kw value.

[@Dodo-ym8cc]

@@AnneSchmidt Could there perhaps be an implicit heat component in the Kw equilibrium like for example Kw= [H+] [OH-] / Heat? If you get an abundance of H+ which depletes OH- to the extent that there is "practically" no more OH- left for the abundant H+ to react with, could that increase the heat component thus increase the temperature thus change the Kw constant itself? I never took chemistry that is why i am asking. Thank you Anne for your reply.

[@lightdi-gw6gn]

You're so talented! Thx for this video :) 🥰

[@AnneSchmidt]

Aww ☺️ thank you for that!

[@ltac8194]

Your videos are a god send. Thank you so much. My question is for # 2 . I got log(2.51) = .399673721 and doesn't the ph=-.400 because 3 sig fig and the 9 rounds up?

[@AnneSchmidt]

Thanks! Log calcs have different sig fig rules I discuss in the video.

[@martinakubuo3398]

Thanks a bunch.

[@AnneSchmidt]

You're welcome! ☺️

[@m.veyselakin]

thank you very much ! i liked the video

[@AnneSchmidt]

Glad you liked the video!

[@selwyntiongson70]

How about pkw pka ma'am and the general formula, how to derive it

[@AnneSchmidt]

pKa = - log Ka 10^-pKa = Ka pKw = - log Kw 10^-pKw = Kw

[@dnyyyyyx1036]

thankkk u so much!!

[@AnneSchmidt]

Great to hear the video was helpful ☺️

[@EmmettMarcet]

Thanks anne

[@AnneSchmidt]

Thank you for the comment. Happy to hear the video helped!

[@charlieropesocks5793]

mister green

[@selwyntiongson70]

Pink calcu

[@shikamarunara2034]

?