Calculating the Magnetic Flux for a Non-Uniform Magnetic Field

Explains how to calculate the magnetic flux for a non-uniform magnetic field. This is at the AP Physics level.
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[@ousooners5193]

It's shocking to me that AP Physics is apparently a lot more comprehensive than university physics, thanks for the explanation.

[@adonis1168]

thats university physics for most

[@shenanigans4177]

@@adonis1168 We learn that at highschool in India. So not University physics for me.🎓🎓🎓

[@baraaahmad7738]

@@shenanigans4177 no one cares

[@ankushghosh7485]

@@baraaahmad7738 you will repent when you realise that what you should have cared

[@isaacjoseph7865]

this guy is the goat. on a real note what kind of highschool AP physics is teaching this?? feel bad for those kids man lmao

[@cuteypetz]

thanks, you explained this slowly and understandably! I didn't get what my textbook was trying to say at first, but having watched this, I get it now.

[@bryanseare2704]

You Helped me understand how to divide the area up into little changing pieces! thank you!

[@laurasmith182]

literally just what i was looking for! been searching for ages, your videos are really useful!

[@Konchok_Dawa]

You draw really good pictures! A rare thing among physics teachers

[@Dark69bladeAE]

You haven't seen Sal (Khan Academy) it seems lol

[@26jdom]

you can explain this so easily compared to my professor, thanks!

[@adonis1168]

Nailed this one. Congrats sir

[@surendrakverma555]

Excellent lecture Sir. Thanks 🙏🙏🙏

[@msuman4289]

Thanks a lot. I was looking for this explanation 👌

[@egyptiangirlxt]

You should start putting ads in you vids, you could make some money. You deserve it.

[@jspianoman07]

Nice video. I missed my lecture on Friday and this really helped out. In response to shazaduh4ever, if current is a function of time, it is independent of the dr, so pull it out of the integral anyway and just use the current at the specific point in time you want to observe. Your equation would look something like Flux(t) = uI(t)h/(2pi)*Integral(1/r dr) from r=a to r=a+L. In english: [(mu_not*current as a function of time * h)/(2*pi)] * integral of (1/r) dr from radius = d to radius = d+L

[@GrantOakley]

This video makes me feel silly for paying a professor so much. Thank you.

[@hardikarora7681]

hi grant replied 2 ur comm, 8 years after

[@ThatLooksLikeARake]

@@hardikarora7681 replied to yours 2 years later so we’re even?

[@hardikarora7681]

@@ThatLooksLikeARake nah do it after 6 years then we are

[@ahmedelwakeel225]

So informative. Keep going, sir.

[@user-lu1pd1ig7x]

thank you so much i hope you re doing great

[@eaglejoshi410]

Thank you very much.... It is exactly what I wanted ☺️

[@anuj8565]

I can't believe it was posted 10 years ago

[@Rockyzach88]

So how do you find the EMF from that flux? I'm confused on the math for the time derivative of the flux you have found and the flux I have found in my problem. I have a similar problem except that instead of using Amphere's law, they just gave us a function for the B field.

[@shenanigans4177]

Just differentiate the flux w.r.t t( time)

[@twintipnation2758]

thank you

[@imjustacritic]

I'm not sure if you made a mistake in the commentary but at 3:30ish you say B is perpendicular to dA, but later on you say parallel. This had me a bit confused, but looking back on it I think you mean to say parallel because I don't think dot product cancels out for it being perpendicular

[@justinsantos5751]

I thought that the magnetic flux is always equal to 0. So why is there an expression that we get? Is that expression equal to?

[@lasseviren1]

Sorry, the magnetic flux through a CLOSED surface must equal zero. An example of a closed surface is a sphere or a cube. But a surface that is not closed can have magnetic flux through it. An example of one of these surfaces might be one side of a piece of paper.

[@allphones9817]

٨٧ امتحان كان هذا السوال اخذت درجه كامله فيه موجود بكتاب سير sires

[@numbo655]

Thank you.

[@betulguncaldi4676]

You're great !

[@syuhada9627]

hi! is it possible for you to explain how to calculate the power dissipated in the loop?

[@TheJoker-rf5iv]

Find out emf Then use this (Vsquare/R)*t

[@blakeangel8355]

What if I wanted to find the induced EMF after the magnetic flux?

[@lasseviren1]

So you only have an emf if the magnetic flux is changing with time. To find it, use EMF = -d(flux)/dt or EMF(ave)=delta(flux)/delta(t).

[@blakeangel8355]

@@lasseviren1 yeah I have a similar problem to this one where I integrate from r=H to H+W but there is also a velocity on the loop going towards the current carrying wire. So if I am not mistaken I can use minus d fee over dt.

[@TheHotOnes0]

Beautiful explanation!!!

[@tarek2998]

You are the best

[@thePhysicist1]

this Q was in my physics test last week en i only saw it now

[@Shooterrg]

The square loop rotate 180 degree angle then change of flux???

[@gayathrikumbalathara2054]

Cos 180= -1

[@saifulphysicscenter9551]

wow BOSS

[@johanponin1360]

appreciated

[@Kashif_Javaid]

what if the current is not constant?

[@frenchy641]

then I is an equation

[@kaiyan9049]

thx

[@hardikarora7681]

anyonw atching in 2020 lockdown

[@hardikarora7681]

@@kms7616 hi

[@simlol12]

is it me or is he saying *hoop* instead of loop ?!

[@Dan-bg5fm]

he says hoop instead of loop for some reason lol

[@TheJoker-rf5iv]

In india every 12th student knows this