Calculus - The product rule for derivatives

[@Fernwald84]

This program (and the associated comments below) clearly demonstrate that most people have problems with math due to bad teaching. Here the presentation is clean, orderly, divided into just the right "chunks" and, to top it off, delivered in a pleasing voice. Great job!

[@jeraldgarner1636]

Feernwald84, well said. You are on point!

[@Ureyeuh]

How can I spend 3-4 hours in lectures and be clueless, then turn around and spend 1 hour on this channel and know everything I didn't understand in the lectures?? Sometimes I feel like I'm wasting my money and that these channels should profit.

[@omg5864]

Ikr. I'm currently in high school taking bc calc so I don't have the same struggle as you with feeling like I'm wasting my money, but I can relate to what you're saying though. I never learned this in a classroom because... well school hasn't started quite yet for me. I watched all his vids on derivatives and parametric equations and now I feel like I could teach them to another student because he just does it that well.

[@lechatduverger7154]

Bro I quit going to class because I can't understand shit, but as soon as I come here everything is much more easier to understand

[@nelsonsema6777]

The understanding of any concept depends largely on the instructor and how you relate personally with the teacher.

[@jamialong8142]

SAME! Ive been confused a whole semester watch a few of these and im good lol

[@DomainAspect]

Everyone here is possessing disillusion

[@g7DT304UB9e]

i literally pay a thousand dollars to my university and still not understand a thing... but i do get it in a 10 minute video?? you sir are the best, you helped me a lot!

[@omg5864]

You make everything so easy to understand. I am going into my first calculus course and thought I would be struggling a ton, but if I just make sure to come and learn stuff from your vids while studying everything seems like it will be a breeze.

[@bwater688]

This video was extremely helpful, thanks! I have an exam tomorrow and I feel a lot more confident about it now

[@Sjb2077]

So clearly explained. No fuss, just , this is how you do it. Thank you for saying it clearly. I have no doubt that in the future we shall come to understand what finding a derivative means in the real world and why it is used but I shall be prepared for that when the time comes. Again a big thank you.

[@oneiraxd3098]

My tuition fees should go to you instead

[@richardjames9406]

This guy is really good in explaining. I now believe I can manage to pass my calculus test. Thanks much.

[@SilentChirps]

Thank you so much! I have my first calculus exam this upcoming Wednesday and you made it so simple!

[@reggidemechko9930]

I can't thank you enough. This whole semester I was so confused and as soon as I found your videos I aced my test. You are an amazing teacher!

[@MySecretMathTutor]

Glad I could help! Keep up the good work. :^D

[@CarlosQuarterman]

Now I got a better understanding of Product Rule instead of using the textbook.

[@aritroc3368]

Thanks. Really helpful for 6th graders like me who can actually relate to it, unlike college lectures.

[@alexachance3979]

Thanks to your videos I could finally understand 18 hours worth of lectures. My only problem is that I get flustered when I see square roots and fractions. Help me overcome this hahahaha thank you again!

[@Mahdul]

I m truly grateful to you for your derivative lessons.... stay blessed.

[@agil-j4n]

I got kinda pissed when you didnt finish the second question

[@igenboi5277]

For real, do you know the answer by any chance

[@ramireztradez3977]

bruh my professors be pulling the same thing and expect us to know what to do in exams

[@PlasticBubbleCosplay]

I kept waiting for him to take care of that radical in the denominator -- 1/(2*sqrt(x)) multiply by sqrt(x)/sqrt(x) yielding sqrt(x)/2x -- plug that in much more easily than that first form ;-)

[@withtheruths]

Wow I wish I would have found your channel before my first calculus exam (which the entire class bombed the professor curved it by 50 points). Thank you so much for making these videos you are saving me rn!!

[@MySecretMathTutor]

That is one crazy curve! Hope the next one goes a bit better. With some hard work I know you can do it. :^D

[@guloguloguy]

WOW!!!!! THANK YOU, VERY MUCH, FOR MAKING THIS SO COMPREHENSIBLE!!!! I'M EAGER TO KEEP GOING!!!! THIS IS GREAT!!!! NOW, ...WHERE CAN WE "APPLY" THIS KIND OF MATH???!!!

[@ajaygupta-nf2bu]

This one is too easy that any not being good at maths can also get it well.thsnks

[@PAVANKUMAR-yi4fw]

I'm actually understanding maths now . xD

[@DylanGuillemette]

Great video man 😃 I like the positive vibe! Thanks for the help.

[@danielamanna7381]

i enjoy maths whenever i watch dis guy.....kudos mhen

[@venkatareddy4641]

I am impressed by seeing your video i everything about calculus now thanks a lot

[@Fleathemighty]

learn math with this one simple channel ! teachers hate him

[@saideepps2920]

You are the best teacher ever, I liked your video and subscribed too, keep up the good work

[@justinkerry7389]

Greetings and thank you for all of the great help. Just wondering (around 5:20) why it is d/dx(x) to the exponent of 1/2? I know that the x is originally under a square root, but I'm not sure why that leads to the power of 1/2. Thanks in advance!

[@kailj1796]

A square root is basically a 2 in the b part of the rational function but it’s never acc shown so it would be 1/2

[@billionthcord]

The way it works the square root splits everything in half (except for prime numbers). Figuratively speaking, 1 can be cut in half, but in higher math we stick to reality. Although mathematics doesn’t stop. Meaning we imagine the possibilities, not just reality. That is the power of assumption. For that assumption capacity is the source of our mathematics. As you go beyond this point; mathematics becomes a theory. Although this is my theory.

[@drubergman339]

I love learning about calculus

[@aram5642]

True, the order does not matter in this case, but since the quotient rule (where the order does matter) has f'g as the first term in the numerator, it is best to always start with f'g. Then you'll never run into doubt.

[@randomperson5579]

This is my introduction to this stuff, and it seems pretty straight forward, I was expecting some crazy 26 dimensional physics.

[@sangitasorty130]

Wow...you explained it like a magic...thank you sir!!! :)

[@knsubramanian9837]

Calculus is no longer the bugbear or Mumbo jumbo to me !.For the first time in 60 years I understood it by this video!.Ta!.

[@mubarakusman4634]

Waooooo!!!!!!! This is great,i had fed my brain with something unique today,thanks to myschoolsecret educator.

[@leslymendez1256]

You are the best tutor ever!!! Many thanks! =D

[@Cosmalano]

Hey man, AWESOME video, super helpful. But how do you simplify the expression at 7:14?

[@Cosmalano]

Where does the (x^3+2x^2) go?

[@jhelo6513]

@@Cosmalano highest to lowest variables

[@Cosmalano]

Jhelo Mae Betarmos haha thanks, I haven’t seen this video in ages! I’m doing graduate school mathematics now, hard to believe I still didn’t know the product rule four years ago!!

[@johnngala2536]

you re an excellent Tutor

[@itsdiva1742]

thanks sir for your lovely explanation!!!!so easy to understand.

[@brajendrapandey4931]

What is Antiderivative? And, what is the derivative of Sine, Cosine, Tangent, Cotangent, Cosecant, Secant, and whatever? (Best channel ever for ...)

[@MySecretMathTutor]

You can often "think backwards" to get these. For example the derivative of what would give us sin ? That would have to be - cos. So we can say that the anti-derivative of sine is negative cosine. :^D

[@dilo9897]

this man is a legend

[@Glambert92]

Beautiful explanation. Needed it for PCAT studying and this helped me rememeber stuff that I have taken a while ago thank you so much.

[@jackiemouse3993]

I’m a sophomore and I’m just getting an idea of Calculus and omg I understand this so much now I thought it was going to be complicated damnnnn

[@sudhasureshkumar6035]

Thank you sir for the detailed explanation.great sir🤩

[@okitsme47]

can you share with us how to simplify the equation, please

[@UnderscoreOwens]

You're a god send brother :)

[@faithcorona5604]

thankyou!!!! NEEDED SOME EXPLANATION LIKE THIS

[@Pintexx]

I just realized how easy derivatives are!!

[@Mystenon]

Dude you are carrying me through my entire finals

[@honeyroseesparagoza1432]

Gosh ! Looks like I'll love calculus because of you ❤ .. lol Thank you so much I understand more. 😄

[@dopemuno37]

Thanks man it really helped 👍

[@khuongho4144]

Very straight forward. Thank you!

[@mariamatrawally7377]

Thank you so much sir you helped me alot.

[@GetUp777]

thanks for this video, it's very simple to understand :)

[@shahadatbashar4509]

what an explanation! Salute....

[@Agustina-xx1mg]

thank you so much

[@_Relinquished]

im in 11 class and my chemistry exam is tommorow and im not studying maths currently and this just seems fun

[@sy2pie]

I've just spent a year doing a maths module with the open University and come out unable to remember any of it. I watch this and it's sticking (and has taken an hour).

[@juanferbazo9979]

Cool video! But in the last exercise can i factorise and write 4e^x[√x+1/(2√x)]?

[@VndNvwYvvSvv]

I don't even see how you get that, and I think you want the terms to be distributed. 2e^x( (1/√x) + 2√x ) will work, but that isn't much simpler. To put irrationals on the top of fractions, we can now factor out √x and get 2e^x √x( 1/x + 2).

[@borjbarcena]

Nice work

[@abdullahsameer9743]

Please give description about the basic of Function

[@TopG_m340i]

Wow made it very clear/easy.

[@ivozeleto2014]

You're an mvp.

[@silentwalls6272]

great work,thank you

[@animitasahasaha8738]

do you have a vdo for the power rule?

[@ball4lifemixtapes493]

mate your deadset legend

[@EngrJigs]

Very helpful 👍🏼

[@tabrezahmed1000]

From where does product rule forumulae and quotient rule come from?

[@aaronvences2452]

I can't seem to figure out how to solve (x+7) to the 4th power over (x+7)^2 square root(x + 7)

[@samrasamra5363]

From where l can have these markers they are so amazing

[@MySecretMathTutor]

I use Vis-a-vis markers. They are nice and dark, and I can erase them when I'm done. :^D

[@samrasamra5363]

@@MySecretMathTutor l don't know whether l would get them or not....but I am really crazy for the way you write....its amazing beyond limits

[@slingshotninja6970]

Isnt The First Question factorised? Why cant we simply expand it and find The Derivative?

[@cheezie9710]

Is this applicable in this problem? f(x) = 2x^4+3x^3-2x+7; f' (0). If so how?

[@uiticus]

on the very last equation couldn't you have factored the 2e*x

[@artedsonpascual9339]

u should finish simplifying especially in some hard examples

[@Pun_sangam]

Thank u sooo much 😁

[@jayanthisenthilkumar8990]

what will be the answer for n√x log √x, x >o

[@WelshGuitarDude]

Why not just expand the brackets by the factor of the function then get the derivative of those terms, instead of finding two different functions of the rule separately then combining them with the primes and normal functions at the end which seems like extra complexity to remember.

[@cloud_c5222]

??

[@VndNvwYvvSvv]

You mean to recombine the factors into 3x⁴ + x² and then differentiate it to 12x³ + 2x? Yes, but I suppose we ignore that here in order to teach the rule. The only difference is choosing an expression you couldn't recombine to make it simpler That would require a more complicated outer function that might complicate the teaching process?

[@deborahijeamaka9212]

Thanks very much

[@venkatareddy4641]

Please explain rules also 😫

[@ShivaPeace]

this rocks 👍

[@jayveeflores7757]

can someone furthermore explain or simplify the 2nd problem for me ? I kinda want to know what its outcome is

[@asecondaday1138]

As he said, distribute the square root x So, it would be (3x^2 sqr x + 4x sqr x) And then, you'd place the x^3 +2x^2 on top of the fraction that is beside it, so it would be X^3 + 2x^2 ---------------- 2 sqr x You can, then, factor out a x^2 X^2 (x + 2) ---------------- 2 sqr x

[@rahulkumar-ou4qi]

Y= Sin38[cos23-sin 34]

[@mnm645]

in the last equation isnt the derivative of 4 =0 ?

[@sarahomer7852]

fr tho

[@VndNvwYvvSvv]

If it was 4 + e^x, but it's 4•e^x instead.

[@IM5NFF]

thanks good

[@necktiekakmalith8036]

I wanna help in Leibniz theorem

[@AyAhmed]

This is my first liked video on KZbin.

[@drubergman339]

And I love you videos

[@PreetiSharma-zz8np]

there is a mistake in the first example

[@InJamesWeTrust_]

can you compute the deriative of G(x)=-3x^5 X (-9x^3). I know the answer is 216x^7 but im stumped when it comes to using the product rule formula. I have half of the equation solved. g'(x)= (-3x^5) X (-27x^2) +(_______) X (______) =216x^7. PLEASEEEE HELPPPP THANK YOU IN ADVANCEEEEEEE

[@aucourant9998]

So simple.

[@priyamehta8064]

thankyou

[@Toxicstriker55]

just one thing about the power rule can't understand why 3x^2 is equal to 6x?

[@itsuzairrajpoot6710]

it's because the power of x will multiply with the constant and 1 will minus from the power. Like 3x^2 =3*2x^2-1 =6x^1 =6x.

[@VndNvwYvvSvv]

It is not EQUAL, but one is the derivative of the other, yes. It would be equal for x=2 but not x=10 for example.

[@jayanthisenthilkumar8990]

n another sum (3sec x -4cosec x) (2sinx+5cosx)

[@animitasahasaha8738]

I could not understand the 2nd last example

[@duaafatima-nk3bo]

nice

[@prititiwari7118]

In first example f'(x) by power rule =2x but can we further take its derivative d(2x)/dx =2*dx/dx=2??? Can't we do this??

[@VndNvwYvvSvv]

What?

[@MaricelAraneda]

ur hand in marriage?

[@drubergman339]

I’m 5+5-2+3-2+1

[@hugheschetpet1780]

if it is happening it is really happening much true believe it or not sugunakar

[@ricodiaz8099]

Freebird!!

[@alipoetry1626]

my college fees should go you

[@jcronin3155]

I don't understand why this guy complicates everything by using f and g when the formula clearly uses u and v.

[@toothpick526]

You can just multiply those then take the derivative. You're doing too much work for nothing

[@nielpatrickcondino7950]

All those years in college smh