Cambridge University Entrance Test Tricks ! | Find x=? & y=?

[@ManojkantSamal]

Respected Sir, Good evening... Nicely solved

[@superacademy247]

I'm glad you found it helpful! 💯🙏🤩💕Thanks for watching! 🔥🥰✅💕

[@rlouisw]

You could have factored that.... 😛 Nice solution.

[@superacademy247]

Thanks for pointing that out! 😎I’m glad you found it helpful! 🔥🥰✅💕

[@ManojkantSamal]

X=9, y=4......May be ^=read as to the power *=read as square root 3^(x-4)+3^(y-4)=244 Multiply 3^4 3^4{3^(x-4)+3^(y-4)}=3^4(243+1) 3^x+3^y=3^4(3^5+1) 3^x+3^y=3^9+3^4 X+y=9+4 or 4+9 So, x=9 & y=4 Or Y=9 & x=4

[@НеллиПшено]

Решаем методом устного счета. 244=243+1 243=3^5 Х=5+4 х=9 у=0+4 у=4 9+4=13 Good luck!

[@ChavoMysterio]

3^(x-4)+3^(y-4)=244 x+y=13 -----> y=13-x 3^(x-4)+3^(13-x-4)=244 3^(x-4)+3^(9-x)=244 3^(x-4)+3^(5-x+4)=244 3^(x-4)+3^[5-(x-4)]=244 Let n=x-4 3ⁿ+3^(5-n)=244 3ⁿ+[243/(3ⁿ)]=244 Let h=3ⁿ h+(243/h)=244 h²+243=244h h²-244h+243=0 (h-243)(h-1)=0 Case 1 h-243=0 h=243 3ⁿ=3⁵ n=5 x-4=5 x=9 ❤ y=13-9 y=4 ❤ Case 2 h-1=0 h=1 3ⁿ=3⁰ n=0 x-4=0 x=4 ❤ y=13-4 y=9 ❤