Learn how to find the unknown angle in this compound shape created by two overlapping isosceles triangles by using the Exterior Angle Theorem. Step-by-step tutorial by PreMath.com
Пікірлер: 180
@procash19682 жыл бұрын
Superb Teacher Ji🙏 You are altogether a different level.... Coming up with good questions and solving it so that everyone understands
@PreMath2 жыл бұрын
Thank you for your nice feedback! Cheers! You are awesome Pracash😀 Stay blessed! Love and prayers from the USA!
@nitinarora57192 жыл бұрын
Marie Van Camp is perfect. BC, BD and BA are three radii, so that a circle would pass through them with B as the centre. Now angle made by the chord AD at the circumference is half that made at the centre. So 66 divided by 2 = 33 degrees.
@sandanadurair58622 жыл бұрын
Simple solution. Nice
@PreMath2 жыл бұрын
Super job! Great approach Thank you for Sharing! Cheers! You are awesome Nitin😀 Love and prayers from the USA!
@tychophotiou69622 жыл бұрын
Your comment made perfect sense except for the first sentence. Who on Earth is Mary Van Camp?
@mahatmapodge2 жыл бұрын
Yep, same way
@llawliet5767 Жыл бұрын
@@tychophotiou6962 the one who wrote the original solution first, in the comments
@matthewleitch12 жыл бұрын
A, D, and C are points on the circumference of a circle (because BA, BD, and BC are radii). That means the circle theorems come into play. The angle from a chord to the centre is twice that to a point on the circumference in the same segment, so x = 66/2 = 33.
@user-bu2cf1ub2h Жыл бұрын
beautiful answer🎉
@Leivoso7 ай бұрын
Thats a nice approach
@marievancamp5092 жыл бұрын
Plus simplement ... Les points A, D et C sont sur un cercle de centre B. L'angle ABD est un angle au centre de 66° L'angle BCD intercepte le même arc de cercle AD avec son somment sur le cercle. Sa mesure est la moitié ; donc 33°
@dimitrioskatelouzos29472 жыл бұрын
Exactly! No nead for complicated solutions!
@PreMath2 жыл бұрын
Super approche ! Merci pour le partage! Acclamations! Tu es génial Marie😀 Amour et prières des USA !
@guruswamyvishwanath47462 жыл бұрын
A very elegant solution by Marie Van Camp
@Q_from_Star_Trek2 жыл бұрын
Très original, bravo!!!
@jundub_31311 ай бұрын
Un angle au centre mesure le double d'un angle inscrit interceptant le même arc 👍 Mais je crois que vous vouliez dire L'angle ACD (X) intercepte le même arc AD ... et non l'angle BCD Another way BÂC + 66 = X + angle BDC & (angle BDC = X + BÂC) ==> 66 = 2X ==> X = 33
@MathsOnlineVideos2 жыл бұрын
Nicely done! I did it two different methods. METHOD 1: I assumed there is a circle going through points A, D and C. (since AB = BD = BC) Also, point B would be the centre of such a circle.
@PreMath2 жыл бұрын
Super job! Great approach Thank you for Sharing! Cheers! You are awesome Siyanda😀 Love and prayers from the USA!
@ncsarola2 жыл бұрын
If I had teachers line you, I’d of been a mathematician! You’re a great teacher!
@PreMath2 жыл бұрын
Wow, thanks Nick! You are awesome. Stay blessed😀
@HassanLakiss2 жыл бұрын
Nice question and nicely done. I did it your way as well as using circle theorem(angle at the centre =2xangle @ circumference. B being the centre, radii BC=BD=BA. Angle x=66/2=33°. Thank you. God Bless
@Q_from_Star_Trek2 жыл бұрын
very nice, PreMath!!! i did it in a simpler way: AB=BC=>
@PreMath2 жыл бұрын
Super job! Great approach Thank you for Sharing! Cheers! You are awesome Q😀
@yamunadegamboda8485 Жыл бұрын
Marie absolutely correct 👍
@sumithpeiris8440 Жыл бұрын
Simple Solution Consider Triangle ADC. Since AB = DB = CB, B is the Centre of the Circumcircle of Triangle ADC. Since the angle subtended at the Circumference is half of the angle subtended at the Centre it follows that x = 1/2 of 66 = 33 Sumith Peiris Moratuwa Sri Lanka
@SteveDorsett2 жыл бұрын
I did it slightly differently, I made an additional triangle APD. This gave angle BAD as 57 and angle ADB as 57, due to being an Isoceles. Then I looked at New Triangle ACD, and the angles made the following: 57 + x + a + x + 57 - a = 180 114 + 2x = 180 2x = 66 x = 33
@mohanramachandran45502 жыл бұрын
Simply solved by different way. Very interesting solution. Have a nice day.
@OrenLikes2 жыл бұрын
a?
@johnbrennan33722 жыл бұрын
Realising that a circle with centre B passes thr' puts A,D andC is by far the best way to solve it.It is short and simple and you don't have to draw the circle to see that angleABD is twice measure of angle ACD.
@PreMath2 жыл бұрын
Great approach! Thank you for Sharing! Cheers! You are awesome Steve😀
@SteveDorsett2 жыл бұрын
@@OrenLikes alpha
@zackhemsey6003 Жыл бұрын
Nice video . Love from Spain !!!
@PreMath Жыл бұрын
Thanks for watching! Glad you think so! You are awesome, Zack. Keep it up 👍 Love and prayers from the USA! 😀 Stay blessed 😀
@MatchupFashion2 жыл бұрын
very well explained, thanks for sharing
@George-qb8hf Жыл бұрын
Man, at first I thought this task has an infinite number of solutions. Then I saw your solution and surprized. I drew this task in AutoCad for check. I rotated BC line. So, yes. Angle X is 33 degrees no matter the BC line position. Bravo!
@govindashit65242 жыл бұрын
Simple problem, but your method is very so exciting.
@PreMath2 жыл бұрын
Glad you think so! Thank you for your feedback! Cheers! You are awesome Govinda😀
@phungpham17252 жыл бұрын
Because BA=BD=BC so we can draw a circle of which point B is the center, and the radius BA, BD, BC. In this circle the angleABD is the angle at the center, and the angle x = angle ACD is the angle at the circumference so x= 1/2X 66 == 33 degrees.
@user-ly5bc4xd2s Жыл бұрын
تمرين جميل جيد . رسم واضح مرتب . شرح واضح مرتب . شكرا جزيلا لكم والله يحفظكم ويرعاكم ويحميكم. تحياتنا لكم من غزة فلسطين .
@George-qb8hf Жыл бұрын
The time of arabian mathematicians has gone more than 10 centuries already
@satyanarayanmohanty34152 жыл бұрын
Great upload as always.
@PreMath2 жыл бұрын
Thanks for the visit Thank you for your feedback! Cheers! You are awesome Mohanty😀 Love and prayers from the USA!
@Gargaroolala2 жыл бұрын
I have a simpler method! I labeled angle PBC = y. So, in triangle BDC, y+2a+2x = 180 deg. In triangle ABC, y+2a+66 = 180 deg. Equate both equations together, 2x = 66. x = 33. Good qns!
@binadasenovin95942 жыл бұрын
yes I am too
@PreMath2 жыл бұрын
Great approach Thank you for Sharing! Cheers! You are awesome Garrick😀
@mitulsamajik32446 ай бұрын
Very good Dada 👍👍👍👍❤️
@sameerqureshi-kh7cc2 жыл бұрын
Sir your tremendous efforts are really appreciable, love from Pakistan 😊👍🌹
@PreMath2 жыл бұрын
So nice of you Sameer! Thank you for your nice feedback! Cheers! You are awesome😀 Love and prayers from Arizona, USA!
@mohanramachandran45502 жыл бұрын
Very interesting question, fine solution finding result . Thank you so much.
@PreMath2 жыл бұрын
Glad to hear that! Thank you for your feedback! Cheers! You are awesome Mohan😀 Love and prayers from the USA!
@thunder25692 жыл бұрын
Angle at center twice angle at circumference, 1step work
@PreMath2 жыл бұрын
Great approach Thank you for Sharing! Cheers! You are awesome Charlie😀
@user-xk7qx7zc6p2 жыл бұрын
Simply the best
@paulgreen9059 Жыл бұрын
Inscribed angle theorem. B is the center of a circle passing through A. C and D. ACD is an inscribed angle and thus half the intersected arc AD. AD is 66 and ACD is 33.
@mahalakshmiganapathy64552 жыл бұрын
Great explanation nice to watch
@PreMath2 жыл бұрын
Glad you think so! Thank you for your feedback! Cheers! You are awesome Mahalakshmi😀
@darkomarkovic33732 жыл бұрын
The angle BAC and BCD=57° From triangle BCD we have the angle CDB and angle BDC are equal 57+x. Then angle CBD= 66-2x. From triangle ABC we have 132-2x+114=180° That means x= 33° Best regards from Belgrade Serbia sir 🇷🇸👍😉
@phungcanhngo2 жыл бұрын
BA=BD=BC :A,D,C on the circle of Center B.Angle X=angle ACD=1/2 angle ABD(angle at center of circle)=1/2 66=33.
@williambunter33112 жыл бұрын
Brilliant! Another solution by the Sherlock Holmes of maths!
@PreMath2 жыл бұрын
So nice of you William! Thank you for your feedback! Cheers! You are awesome😀 Love and prayers from Arizona, USA!
@DB-lg5sq Жыл бұрын
شكرا على المجهودات نستعمل الداءرة ذات المركز Bوالشعاع BC نجد x=66/2أيx=33
@xingsu3489 Жыл бұрын
A simple way is assume A, B, C are in one line, that means P and B are the same point. Due to BC = BD, angle BCD = angle BDC = 66/2 = 33.
@sumithpeiris84409 ай бұрын
Simple solution, 2 steps BA = BC = BD so B is the centre of circle ACD Hence = 66/2 = 33 (angle subtended at centre is double the angle subtended at the circumference) Sumith Peiris Moratuwa Sri Lanka
@OrenLikes2 жыл бұрын
I've marked ∠BAC as b, ∠DBC as c. 2b+c+66=180 → c=114-2b 2(b+x)+c=180 → c=180-2x-2b 114-2b=180-2x-2b → x=33
@PreMath2 жыл бұрын
Super job! Great approach Thank you for Sharing! Cheers! You are awesome Oren😀
@OrenLikes2 жыл бұрын
@@PreMath Thank you! You are awesome too!
@ludmillamerdian90892 жыл бұрын
180 - 66 = 114
@OrenLikes2 жыл бұрын
@@ludmillamerdian9089 Thank you! typo... fixed!
@ch0129 ай бұрын
Very quick stuff on this...Connect A with D. Now Angle X will be half of 66, as ADC arc is a circle with point B as center, AD is a chord of the circle. Hope this is useful.
@aiboljusupov9116 Жыл бұрын
Great!
@biaohan435811 ай бұрын
There is actually a very easy way to solve this question although it might be very difficult to find out. Basically if you draw a line from B to segment AP that meets AP at Q, such that angle ABQ equals x, then you can easily find that triangle QBP and triangle DCP are similar due to that they have one angle facing each other, and angle BQP=angle A+x=angle BCA+x=angle BCD=angle PDC. So two angles equal the triangles are similar so angle QBP=x, and since angle QBA=x as well 2x=66degree.
@isaiahkruz8544 Жыл бұрын
Another way
@user-bb7iq3ft8m2 жыл бұрын
We can use circle, wihf center in point B. 66 is a center angle, and x = 66/2. With together AD
@PreMath2 жыл бұрын
Great Thank you for your feedback! Cheers! You are awesome😀
@user-ng6np2uk5ysimpei Жыл бұрын
The chord AD subtend the arc ADC. B is the center. So, the angle of ABD is the central angle of the chord AD. and the angle of ACD(x) is angle of the circumference of the chord A D. X =66÷2=33
@abhishekpatil10632 жыл бұрын
Taking B as radius we can draw circle going through points A, D, C. So Angle ACD= 1/2 central angleABD by circles thm that any circumferential angle is half measure of central angle .So is 1/2(66)= 33 degrees.
@user-xs4qx6rm8x9 ай бұрын
Draw circle with centre B radius AD. Therefore X is half the angle that cord AD subtends at centre. X=66/2=33
@jundub_31311 ай бұрын
The inscribed angle theorem states that an angle θ inscribed in a circle is half of the central angle 2θ that subtends the same arc on the circle & central angle ABD = 66° therefore angle ACD (X) = 33° _ both are subtending the same arc AD Another way _ we have angle APB = angle CPD & triangle sum = 180° Therefore BÂC + 66 = X + angle BDC & (angle BDC = X + BÂC) ==> 66 = 2X ==> X = 33
@sin_x Жыл бұрын
B is center of circle. A, D, C is point on the circumference. angle ABD is 66°. so, angle ACD is 33°. *Q.E.D.*
@AbdelkaderLAHLALI-ng5mg Жыл бұрын
Bonjour, merci pour vos intelligents exercices de la géométrie pour les jeunes mathématiciens. Cette solution est très générale pour un exercice du genre, sauf pour celui là je propose une solution d'une seule ligne, il suffit de remarquer que le point B est le centre du cercle de rayon BA, BC et BD donc il suffit aussi de remarquer les angles x et 66° intercepte le même arc dont x =66/2 = 33° Merci pour l'effort que vous déployer pour nos jeunes.
@phungcanhngo2 жыл бұрын
A,D,C on the circle(B,BA) Inscribed angle X(Angle ACD)equals half of central angle ABD:66/2=33.
@lachezarbonev5 ай бұрын
I figured out 35° in 5 seconds according to what is given, so this is good enough for me.
@kadirkusmez7724 Жыл бұрын
Since BA=BD=BC, one can draw a circle centered at B, with radius BA=BD=BC. Then, by inspection, since the 66 degree angle, ABD, is the central angle corresponding to the arc AD, it is twice the angle ACD, corresponding to the same arc. Hence the angle ACD is one half of angle ABD,i.e., 33 degrees.
@millipro14352 жыл бұрын
it was a good question !!!!!! 👌❤️
@hadjnabil4811 Жыл бұрын
thank you lot's
@heliumsingh2 жыл бұрын
How to calculate the value of Alpha in this ?
@skumarikannangara7397 Жыл бұрын
Can you do a video about differentiation dy/dx
@padraiggluck2980 Жыл бұрын
In MVC’s solution x = angle ACD, not BCD, intercepts the chord AD. But the conclusion is correct.
@dakshgiriraj4468 Жыл бұрын
i did this by myself...happy..
@sumanduwal4080 Жыл бұрын
B is center of circle circumferencing A D and C so x is half of 66 … relation of central angle and circumference angle at same arc… so x is equal to 33….
@dogwelder Жыл бұрын
If AC and BD are both segments of straight lines and this is a plane, how is this possible? AB, BP, and BC are all the same length, which should make B the center of a circle with AB, BP, and BC as radii, right?
@edeltax67222 жыл бұрын
Point B is center of circle and points C, D, A are on this circle... Angle ABD is twice larger than angle ACD. ;)
@JSSTyger2 жыл бұрын
66+M+2N = 180 M+2(X+N) = 180 and M+2N = 180-2X 66+(180-2X) = 180 X = 33° The main key is recognizing the two isosceles triangles.
@PreMath2 жыл бұрын
Super job! Thank you for Sharing! Cheers! You are awesome JSS😀
@IanKendallMagic2 жыл бұрын
That was my method as well.
@nizamuddinahmed2193 Жыл бұрын
Here BC, BD and BA R equal So we can draw a circle passing through point A, D, C. Hence angle ACD= half angle ABD.= 33°{Central angle is twice the angle on remaining part}.
@user-lt7me8sj1m Жыл бұрын
АВ, ВD и ВС - радиусы описанной окружности с центром в точке В. Дуга АВD =66 градусов. Дуга угла АСD в два раза меньше или 33.
@francois8422 Жыл бұрын
circumference C (B) center B, radius AB = BD = BC AD = chord = arc circumference C (B) Angle x with vertex C on circumference C (B) insists on arc AD, with respective angle in the center = 66 ° = 2x Hence x = 33 °
@akramabdou3005 Жыл бұрын
another solution the the 3 point ADC AT perimeter of circle which its center @ B , CENTERAL ANGLE 66 = TWICE circumferential angle x HENCE x=33
@mathtv3982 Жыл бұрын
Since AB=BD=BC, then A,D and C are cyclic and B is the center of the circle. Then x= Angle DCP = 1/2 of the angle ABD=1/2. 66=33.
@cityatlant1238 Жыл бұрын
You are not drawing proportionally. If BA = BP = BC, then APC can not be a straight line, or can it?
@guidosillaste4297 Жыл бұрын
I remeber this in school.
@phungcanhngo2 жыл бұрын
How to draw the quadrilateral ABCD? What is the angle of ABC?
@gam80525 ай бұрын
Dude I thought segment BP is congruent to AB and BC😭 I was a bit confused when using isosceles triangle theorem, and why it does not match up
@xyz92502 жыл бұрын
Assume the angle next to x is y, and the angle next to 66 one is z, as the sum of interior angles of any triangle is 180, 2(x+y) + z = 2y + z + 66 , x= 33
@malcolmmcgrath9344 Жыл бұрын
I had convinced myself that if the angle DBC was less or greater then the angle x would change , so I got out my trusty ruler and protractor and carefully drew a number of different diagrams. x was always 33. Sorry to have doubted you ! ! ! !
@g.p.22032 жыл бұрын
To my mind it is better to replace the value 66° with a parameter from the interval ]0, π[.
@pieggreiner82012 жыл бұрын
les points aA C et D sont sur un cercle de centre B soit E l’extrémité du diamètre DBE, les angles ACD =x et AED sont égaux donc l'angle AED =ABD/2 =66°/2=33° et don c x=33°
@PreMath2 жыл бұрын
Super travail! Excellente approche Merci pour le partage! Acclamations! Tu es génial Pieg😀 Amour et prières des USA !
@kennethkan32522 жыл бұрын
66÷2=33 A,C,D, point is in same cycle, B is cycle center.
@PreMath2 жыл бұрын
Thank you for Sharing! Cheers! You are awesome Kenneth😀
@pranavamali052 жыл бұрын
Very nice question and explanation thnx
@PreMath2 жыл бұрын
Most welcome Pranav Thank you for your feedback! Cheers! You are awesome😀
@Ahuromazda5 ай бұрын
How do uou know that ab=bc=bd???
@abhishekpatil10632 жыл бұрын
Using circles theorom x= 66/2 = 33 degrees.
@pepeluchosykes687411 ай бұрын
Es más fácil usando ángulo inscrito. En Perú es hasta un teorema, le dicen "TEOREMA DE LAS TRES PIERNAS"
@gtoaha2 жыл бұрын
B is the center of the circle make a circle A,D,C On the circumference .....
@ahmedmagbambus10932 жыл бұрын
👍👍👍👍👍
@snekadurga85472 жыл бұрын
Super very nice explanation thank you sir
@PreMath2 жыл бұрын
Welcome Sneka dear Thank you for your feedback! Cheers! You are awesome 😀
@predator17022 жыл бұрын
Thank you teacher 🙏
@PreMath2 жыл бұрын
You are welcome dear You are awesome.😀 Love and prayers from the USA!
@user-yb2qx7mm9l2 жыл бұрын
Inscribed angles 66 / 2 = 33
@supermatecumih92112 жыл бұрын
That's how I solved it, too! 😉
@PreMath2 жыл бұрын
Great approach! Thank you for Sharing! Cheers! You are awesome😀 Love and prayers from the USA!
@robertpic267 Жыл бұрын
A quoi sert le theoreme de l'angle inscrit? Qui est la moitié de l'1ngle au centre . Les trois points A,C et D sont sur le même cer le de centre . L'arc AD de ce cercle est intercepté par l'angle ACD qui est la moitié de l'angle au centre ABD interceptant le meme arc AD du cercle....
@vidushijoshi39212 жыл бұрын
Hi sir i am your big fan as millions.
@PreMath2 жыл бұрын
Thank you so much 😀 You are awesome Anita dear😀 Love and prayers from the USA!
@bahijsarhan800211 ай бұрын
يمكن رسم دائرة مركزها b تمر من النقاطaوcوdيكون قياسxالمحيطية =نصف قياسالمركزية66المشتركةمعها بالقوس و=٣٣ اعلم انكم تعلمون بهذه الطريقة ولكني احببت ان اشارك وشكرا لكم
@jakkima10672 жыл бұрын
Я немного по другому решал. Дольше, чем Вы, но ответ такой же. Я просто пересчитывал все углы. Спасибо за краткость)
@PreMath2 жыл бұрын
Супер работа! Спасибо, что поделились! Ваше здоровье! Ты классная Джакима.😀 Любовь и молитвы из США!
@dathyr1 Жыл бұрын
Hmmmm! This one is a little tougher. Ah!!! I found angle X - It is right on the Drawing in RED. Next question.
@bruhO7O Жыл бұрын
I solved it
@user-wi8iq3hn3k11 ай бұрын
Окружность и вписанный угол- половина центрального.
I don't think triangle PBC is possible with those dimentions
@manualrepair2 жыл бұрын
👍
@PreMath2 жыл бұрын
Thank you dear You are awesome😀
@g.p.22032 жыл бұрын
What if ∠ABD=179°59'59.99...9''?
@giovannidepasquale62602 жыл бұрын
AB=BD=BC , raggi uguali di una stessa circonferenza con centro in B, angolo X = angolo alla circonferenza dell'arco AD. Angolo ABD = 66° quale angolo al centro dello stesso arco AD quindi X = 1/2 di 66 = 33°
@GenZRuinedTheWorld5 ай бұрын
I was off by 3 degrees I just did 45-15 and got 30, so it's 48- 15 = 33
@user-rq7xv9qb4k Жыл бұрын
Проведемо через точки А, D, C дугу кола з центром у точці В. Кутова величина дуги AD становить 66 градусів, отже кут АСD = 66/2 = 33 градуси
@Teamstudy45952 жыл бұрын
Super duper bumper easy question!
@PreMath2 жыл бұрын
Excellent You are awesome Jayant😀
@restablex2 жыл бұрын
Since BD, BC, BA are equal.... Points A, D , C are in the circumference with center B. Central angle ABD determines an arc AD = 66. Then angle ACD is half the arc AD... Done.
@PreMath2 жыл бұрын
Super job! Great approach Thank you for Sharing! Cheers! You are awesome😀
@AbhishekSingh-qn4bz2 жыл бұрын
CLEVER ...😏😏
@PreMath2 жыл бұрын
Thank you for your feedback! Cheers! You are awesome Abhishek😀
@rrr2101002 жыл бұрын
2x = 66: x = 33
@PreMath2 жыл бұрын
Thank you for Sharing! Cheers! You are awesome Ranga😀