Can You Handle the Math Magic? || Most Likely to Come in IIT-JEE ADVANCE (2023)

[@madhubala2049]

Perfect candidate for advance!

[@krishna-yl6sy]

very nice approach sir...thankyou very much 😇

[@thunderbolt6276]

Very nice method sir.....thanks

[@asimkalim1261]

Already saw your Honolulu video.. so this was piece of cake

[@harshan-r6y]

THANK YOU FOR EXPLAINING THESE TYPE OF QUESTIONS WITH UNIQUE APPROACH FEET GRATEFUL FOR YOUR DEDICATION SIR

[@fasihullisan3066]

Very nice explanation

[@yatharvvv11]

Amazingggg

[@prakashsahu4332]

Amazing session sir

[@yatharth2463]

VERY EASILY CAN BE DONE BY DERRANGEMENT IF LEARNED CORRECTLY: let a1 be the even where UU are together similarly a2 and a3 with KK and TT respectively then TOTAL CASES - a1Ua2Ua3::hence 6!/(2!)³-[3C1(5!/2!²) -3C2(4!/2!) + 3C3(3!)] = 30 Ezpz

[@RocketsNRovers]

extremly easy question because of honolulu concept

[@ritujain8515]

Basically it was, inclusion and Exlcusion only

[@kuAtul]

Thank you sir

[@VedicBhatnagar-IIT-BHU]

Nice 👍🏻

[@hmm.3367]

30?

[@hmm.3367]

Let's go Got it Correct

[@kshitijkumar5629]

Even I got it correct using simple "guna bhag" :)

[@akshatgupta7490]

We can also do it as A- no 2 u are together, but both t may or may not be together. Then B- no 2 u are together and c are together. Now subtract cases of N from cases of B Edit- i didnt realise it also has 2 K's This method is applicalbe for words like SUCCESS or IITJEE were only two set are alike.

[@AmanSingh-bt4yg]

L

[@bhavyashah3674]

Please make more video for jee adv 2023

[@prakashsahu4332]

Sir please try to make videos consistently

[@sangeetaagarwal6328]

It's just principle of inclusion or exclusion or sieve formula

[@RitaSharma-w4s]

48 nhi ara kya??

[@RitaSharma-w4s]

48 nhi ara kya?

[@RitaSharma-w4s]

48 nhi ara kya?

[@RitaSharma-w4s]

48 nhi ara kya?