Can you Solve Stanford University Admission Test ?✍️🖋️📘💙

  Рет қаралды 4,097

Super Academy

Super Academy

Күн бұрын

Пікірлер: 13
@wes9627
@wes9627 3 күн бұрын
49-9=40
@alfastur6833
@alfastur6833 3 күн бұрын
5:44 (x+y) (x-y)=20x2 has integer solutions, 11 and 9.
@gabrielng9799
@gabrielng9799 2 күн бұрын
but when x and y got substituted, u is not an integer
@MorgKev
@MorgKev 2 күн бұрын
1) You didn’t say integer solutions only. 2) because m is an integer doesn’t force sqrt(m) to be an integer and hence u didn’t have to be an integer. I sure you started with your solution and worked back to create your question… you should ask your question with all your little bits of extra information required to get to the solution you want.
@justekiara1953
@justekiara1953 Күн бұрын
Happy New year 2025 to you, dear teacher. I thank you for all your efforts to prepare beautiful math problems welcomed by most of your followers.
@superacademy247
@superacademy247 Күн бұрын
Thanks for the kind words, Happy New Year 2025! 🥂🎉🥳
@doowadiwadi
@doowadiwadi 2 күн бұрын
No such thing as a Stanford university admission test. And if there was, this question would never qualify as it is way too easy.
@nuhumaishanu6944
@nuhumaishanu6944 2 күн бұрын
To verify, you don't equate the LHS to 40 ,you just world out what the LHS is and if it comes to 40 the solution(s) are verified
@Behera18
@Behera18 2 күн бұрын
Square root of m can be written m^1/2 not m/2.
@prollysine
@prollysine 2 күн бұрын
let u^2=(V7)^(Vm) , & v^2=(V3)^(Vm) , I count on one occasion , u^2-v^2=10*4 , (u+v)(u-v)=10*4 , let u+v=10 & u-v=4 , u+v+u-v=14 , 2u=14 , u=7 , u^2=49 , (V7)^(Vm)=49 , Vm=2*log7/((log7)/2) , Vm=4 , m=16 , test , (V7)^(V16)-(V3)^(V16)=(V7)^4-(V3)^4 , 49-9=40 , OK , solu , m=16 ,
@TheNizzer
@TheNizzer 2 күн бұрын
m=16 by inspection. No algebra needed. At this level, should it even exist, it’s obvious 49-9 is required.
@pashmina858
@pashmina858 Күн бұрын
This can be proven in 30 seconds so why take 11 minutes
@hamvtom
@hamvtom 2 күн бұрын
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