Can you solve the stolen rubies riddle? - Dennis Shasha

Practice more problem-solving at brilliant.org/TedEd/
Solution to Bonus Riddle: brilliant.org/TedEdRuby/
Townspeople are demanding that a corrupt merchant’s collection of 30 rubies be confiscated to reimburse the victims of his schemes. The king announces that the fine will be determined through a game of wits between the merchant and the king’s most clever advisor - you. Can you outfox the merchant and win back the greatest amount of rubies to help his victims? Dennis Shasha shows how.
Lesson by Dennis Shasha, directed by Artrake Studio.
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[@TEDEd]

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[@lancebakker1198]

Already have a subscription on it!

[@Isma-fn6tk]

Why do not they add subtitles in Spanish TED 🤔???

[@Isma-fn6tk]

Add subtitles with translation in Spanish please!!!

[@TEDEd]

Hi Ismi Gómez Laz! Check out our response to your comment, below. Thanks!

[@sanketchiti1]

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[@mistyhusk]

If I’m the kings most clever adviser, there’s a problem somewhere

[@c0smic_eve]

Its medieval times knowing basic maths makes you a witch to them

[@itayraviv2422]

Maybe he's paranoid so he killed all the actually clever ones

[@BeckDawg123]

😂😂😂

[@henryweinschel1357]

If I’m the smartest person in the room, I’m in the wrong room.

[@thezombiekat7506]

Seventh commet

[@coin2039]

"The king's most clever adviser : you" Lol what? You guys are screwt

[@hanxu7529]

*s c r o o t*

[@chrispychip3905]

y'all are *s c r e u t t e*

[@seanwilson613]

No the king is smarter he made the rules so you would win the most

[@mdavis621]

Yes

[@user-dm2qi9vq4d]

o o f lmao

[@sev1011]

"The king's most clever advisor, you" Weird they have a guy named 'Yu' in the middle of-ohhhhhh

[@gsftb]

😂 That is some advanced humor. Thanks

[@itayraviv2422]

I actually have a friend called "Yu" so I got really confused there xD

[@cozyflurry]

Dis underrated! :D

[@ashuto2025]

It's all fun and games until the advisor crushes a tarot card to summon a god

[@xndybxyo]

@@ashuto2025 or the tarot card represents a manifestation of their fighting abilities

[@m.magarwal5287]

You can acquire “more than half” of his treasure Me: OOOOOH Reality: 1 extra gem.

[@R.F.9847]

Half of 30 is 15. If you write 8 for each box, you get 24 and the kings keeps only 6.

[@R.F.9847]

@@amirul3233 15+1=16, not 24.

[@amirul3233]

@@R.F.9847 no, you can only get from 2 boxes, so it's 16, not 24

[@sebastiangottlieb1527]

@@amirul3233 wtf you can get from all 3 boxes you’re lucky?

[@itayraviv2422]

@@sebastiangottlieb1527 if u are lucky yeah, but think of worst possible case. (11,17,2) U "only" get 16

[@cauilfiower]

"The situation resembles an adversarial game like chess only here you can't see the opponent's position." Sounds a lot like a game of Battleship...

[@georgestafford7843]

Stratigo

[@0mathgaming]

@@georgestafford7843 I was going to say the same thing. Also FYI it's spelled with an e (stratego)

[@kirbycreep]

so basically Kriegspiel?

[@GalexiDude]

I don't how you've been playing battleship

[@walkerfan6341]

Thats not how I play battleship

[@Yippieyiyo]

I never bother to solve these lol. I just find the explanation interesting.

[@adambroderick3410]

Same

[@erikalopez7420]

Yippieyiyo same all might. Same.

[@2winceball]

Me too

[@cyralamen]

yeh same, and then I forget it seven seconds later-

[@ritazhu4786]

I stay for the stories

[@steeledminer616]

For the bonus riddle: 10 The merchant will always take the 2 most valuable piles, only leaving you with the lowest value one. That means you can only get it if you split it into 3 equal piles, 10,10,10. If I take any out of any pile and put it in another the merchant will take that more valuable pile leaving me with one less than 10.

[@melodylai40]

Quite similar to the first one.

[@griffitethehuman5006]

They asked what was the most one can keep. The most you can keep is 28, assuming that you can place a minimum of one ruby per pile. This gives you a perfect 1/3 chance that you will keep 28 rubies.

[@steeledminer616]

@@griffitethehuman5006 Except the Merchant always gets to choose which one and knows which piles to take. Your argument would only work if it was blind luck, but that's not the case.

[@griffitethehuman5006]

@@steeledminer616 I was thinking he couldn't see the piles, like they had been in chests and he had to pick randomly, but I guess the video never mentions that

[@steeledminer616]

@@griffitethehuman5006 Yeah at no point does the video ever mention the merchant not getting to see the piles, it just says "make 3 piles"

[@ratoim]

Guard: *guards king* Also guard: *completely fails to detect group of people rushing up to king*

[@Dexaan]

Failed his perception check

[@lamantinelsarchives9616]

I don't even know which way should I plug the USB

[@heliusuniverse7460]

sideways

[@edfreak9001]

Just look for that little icon on top of it, also the side of the metal prong with a line through it goes down

[@t_kon]

Just look which one is able to fit in....

[@abdulsamadansari222]

Just smash it in ur cpu with hammer or smthing like a brick

[@satviksharma23]

@@abdulsamadansari222 isn't that how you do it?

[@quahntasy]

I solved it ! I solved it Someone give me a cookie or something. And why does king face looks like a seal

[@theshoulderofgiants]

🍪...There you go ....A cookie..

[@tsya]

Walrus, not seal

[@LePezzy66]

Looks like you already found a new riddle to solve

[@TheHipPro]

yoink my cookie now

[@timjack129]

🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪

[@NoobsailerRBH]

"You have to divide 30 rubies into 3 piles. The scoundrel will then choose and keep 2 of those piles." Me: **Makes piles of 28, 1 and 1, then pees on the 28 rubies.** Scoundrel: Bugger.

[@aashiyanaashfaqueiv-aroll-4131]

😂

[@ReinisDoesMinecraft]

let's just hope the scoundrel isnt into urination

[@NoobsailerRBH]

@@ReinisDoesMinecraft Then we'd have him charged for indecency or something.

[@geanbenicio1338]

Every box may have more than 2 rubies

[@NoobsailerRBH]

@@geanbenicio1338 This is referring to the "bonus riddle" - which has no such constraints.

[@adrianwoodruff1885]

Bonus riddle Put them in groups of 10 He'll take 2 groups and leave you with the last one. If you put them in any other way, he'll take the two biggest group, leaving you with less then ten.

[@davidcopca7336]

At first I thought it was too simple to be that answer compared with the previous one, but I stand corrected, too simple

[@marlinbundo2409]

This is eaither the correct answer or else the question was worded poorly and there was supposed to be more conditions. If the original question was worded coreectly, this is the only answer that makes sense

[@guytanlol]

Yes. The thing is that they say that the scoundrel CHOOSES and KEEP, so i guess he can see the piles... Btw, the first problem says that you want to guarantee the maximum number of rubies, but maybe other combinations could have a better risk/reward overall, i'm lazy about listing everything i should just do a computer program lol

[@locksmack]

You are correct. However, if we assume that the scoundrel can't see the amount in each pile, then the answer is 28. This is because of the wording of the question - what is the MAXIMUM amount you can keep? If the two piles he choose each have just one ruby, then you can keep the pile with 28. Assuming 1 ruby can be called a 'pile'...

[@Wishkeyn]

Technically you could arrange the piles so that a closer packed pile of more rubies would look less than the 2 other piles which are not as densely packed.

[@eagletgriff]

"The game will be played between the merchant and the king's most clever advisor-- you." *We're screwed*

[@Ripurlife]

We're ded

[@ok-xh7dn]

Copied

[@eagletgriff]

@@ok-xh7dn i guess people arent allowed to comment similar stuffs

[@ok-xh7dn]

@@eagletgriff no but this is tha same exact comment. Almost word for word. Also the comment you copied is one of the top coments So?🤷‍♀️

[@keiramcgrath4131]

😂

[@isyoursheepwireless]

I love the art style of this episode. It reminds of those early 2000s children's shows. Where a narrator reads a storybook brought to life with cheap flash animation lol.

[@thebalancer]

So true

[@andrewgreeb916]

"One box must contain exactly 6 more" small details that make or break your guess

[@jdramirez77]

Doesn't it seem that "exact" should have been in the rules...

[@chriswebster24]

@@jdramirez77 The answer would be the same, whether it’s exactly 6, or at least 6, so no, it’s irrelevant.

[@amirul3233]

@@chriswebster24 It's actually relevant. Had the word "exactly 6" not been there, the merchant could put 2, 2 and 26 into those 3 boxes (26-2 = more than 6). So if we write 8 on each paper, we will only get 8 in total. But since the difference must be exactly 6, the merchant now has very limited options. Whether it's (2,8,20), (3,9,18), (4,10,16), (5,11,14), (6,12,12), (7,13,10), (2,11,17), (6,9,15) or (8,8,14), if we write 8 on each paper we will get at least 16 rubies instead of only 8. Best case scenario, we would get 24 because if the merchant sorted the rubies as 8,8,14, it will guarantee us 8 rubies from each boxes

[@mongoliacomix]

The wording " exactly 6" changes the problem completely. As suggested, and that was my line of thinking, 2,2, 26 would be the merchant safest bet

[@nickryan4619]

It doesn't even need to say exactly 6. The rules say that one box has to have 6 more than one other box. That means only one box has to have 6 more than only one other box. Therefore the other two can be the same. 2, 2, and 26 is the answer I came up with.

[@aidanmcwenie9936]

I really enjoy these TED-Ed riddle videos. I’ve watched a bunch of them and this was the first one I was able to solve on my own.

[@Sourpatchchild]

Same!

[@john_cena_cheeseburger]

this one, THIS one, NOT the REBEL one

[@john_cena_cheeseburger]

this one, THIS one, NOT the REBEL one

[@john_cena_cheeseburger]

this one, THIS one, NOT the REBEL one

[@dryzalizer]

Props to the king for designing a game that allows his clever adviser to win more than half the rubies in every scenario!

[@globin3477]

If he'd required that each box contained at least 3 rubies, we could have guaranteed 18 of them.

[@dervakommtvonhinten517]

but what if the guy guesses what you are gonna do and puts 2 2 26 into the boxes. he would get 22 rubys back cause he KNOWS that you cannot know which box he put the majority in and to be on the safe side you could only get 6 rubies....

[@globin3477]

@@dervakommtvonhinten517 He can't do that. One of the boxes must contain 6 more than the content of another box. and 26-2 =/= 6.

[@hautakleightontam771]

That's only if you're smart, or lucky. Betting on 8 is the ONLY scenario that allows you to consistently win more than half of the rubies without the risk of getting less.

[@BudiTabootie]

2 8 20 combination?

[@bigbakerboi3872]

Bonus riddle: The maximum amount of rubies you can have is 10, as putting any more in a pile will result in the opponent taking it

[@111moonk]

I thought so too but it seems too simple to just divide it by three.. Oi

[@fxllenrain14]

Parth Sankhe I got same dude👍

[@bagel8284]

Clara Kapustka I guess they’re expecting us to overthink it

[@yanivshemtov9430]

These questions get dumber every time, I guess they ran out of ideas and are doing quantity over quality for their patrons and sponsorships

[@caiomiguel7152]

@@111moonk I thought the same, i was like no it just CANNOT be that easy. Goddamn it even when i'm right, i'm wrong😂😂😂😂😂😂😂

[@Paul.V.24]

The way I solved it was thinking of 3 scenarios(using the same number on all 3 cards seems pretty straight forward): 1. A box with minimum amount of rubies, so 2. The other two boxes bound by the +6 relation so 11 & 17. (2,11,17) 2. A box with minimum amount of rubies, so 2. One other boxes bound to this one by the +6 relation so 8, and then 3rd box with what's left 14. (2,8,20). 3. Starting with 11 in each box, satisfying the +6 relation while keeping rubies as evenly spread as possible: (8,8,14). While looking at these numbers in the last two cases, picking anything above 8 will yield just 1 box of stolen rubies with this number. In order for this to be better than 2x8 the number must be 17. But in the 3rd case this would give no rubies at all. Therefore picking 8 is the only logical solution.

[@ABHISHEKAGGARWAL-qt2yk]

I also thought the same

[@finnvaneekelen7740]

Step one: confirm the Ruby theif has green eyes. Step 2: ask them to leave

[@Bloobinton]

I don't get it

[@todd3143]

@@Bloobinton it's a meme

[@H8NN9H758]

@@Bloobinton it was a reference to the green eyes riddle

[@Bloobinton]

@@H8NN9H758 OOOOO that makes more sense

[@kadreath]

@@Bloobinton we say these people are 'madlads'

[@bluesbreaker6657]

For a second I thought the solution was wrong because in the merchant’s shoes, I’d have done 2-8-20, except that combo still gives you 16 gems by the proposed 8-8-8 method. And if you got lucky enough to hit the 8-8-14 scenario, that’s 24 gems for you. So good riddle, but perhaps the logic behind the solution could be explained better by showing more distribution patterns going through 8-8-8?

[@alejrandom6592]

They are only 10 possible scenarios and knowing them you easily solve the riddle: If the 3 numbers are a b and c then A+6=B C=30-A-B A>1 B>1 C>1 Resulting scenarios are: 2 8 20 3 8 18 4 10 16 5 11 14 6 12 12 7 13 10 8 14 8 9 15 6 10 16 4 11 17 2 Choosing 8 8 8 (all of them have at least 2 numbers greater than 7) guarantees 16 rubies at least Best case would be 8 14 8, getting 24 rubies, any other case you get 16

[@martinguerre8220]

Kenny Arias, now that's clarity.

[@exantiuse497]

The problem included the assumption that the merchant knew the rules and assigned the rubies to maximise his gain, so he would never assign them in a way that gives you more than 16

[@zclin84]

@@alejrandom6592 there are only 9 scenarios. 4 10 16 and 10 16 4 are the same. Also, it shld be 3 9 18 and not 3 8 18.

[@spiceyknodel6950]

@@zclin84 then its 8 possible scenarios

[@trollonainternet3269]

I’ll feel really smart whenever I solve a riddle but realise its not that big of a deal

[@TEDEd]

We think you're smart!

[@hannajiang4929]

Haha 🤠

[@kalakar576]

r/IamVerySmart. See you there.

[@trollonainternet3269]

TED-Ed umm. Thanks...?

[@trollonainternet3269]

akshay barve wut

[@michaelsmith2619]

The answer to the riddle at the end is 10. Because obviously he's going to take the two biggest piles. So your best bet is to split those 30 rubies evenly 10 in each pile

[@DLAppleGamez]

He doesn’t know how many rubies are in each pile

[@elisanateri4390]

@@DLAppleGamez but he could be lucky and pick the two biggest piles anyways. With ten rubies for each pile you will always keep ten rubies

[@DLAppleGamez]

@@elisanateri4390 but can’t you just split them 28/1/1 and hope he gets unlucky?

[@elisanateri4390]

@@DLAppleGamez yeah but I'm unlucky too

[@kevenbouchard7973]

Since he pick 2 out of 3, you have 2/3 to get 1, 1/3 to get 28. I think you improve your chances by doing 2 piles of 14. But in the end, would you rather have 100% to get 10 or 66.6% to get 14 or 33.3% to get 28

[@hamblance5938]

The King: Everyone else in the kingdom: Everyone in this comment section: hOw aM i ThE cLeVEreSt ThE KiNgDoMs ScReWeD

[@ghatiyapictures7824]

Very true...

[@isha-]

I dont understand why people think making the same "hOw aM I tHe SmArTeSt" joke is funny

[@Bloobinton]

@@isha- its fun to see a verity of a same joke lol

[@CrypticCobra]

@@isha- Because they are not very smart....hence why it's funny to them.

[@notjustastopmotion6493]

“The king’s most clever advisor... you.” If you need me, I’ll probably be getting executed for my terrible service as the most clever advisor

[@NoriMori1992]

I did it! I did some math and saw that one of the boxes had to contain between 2 and 11 rubies. From there I calculated how many rubies each box would have in each scenario, and noticed that in every case, at least two of the boxes contained 8 or more rubies. I did it!

[@sidhharthmoghe7247]

"The King's most clever adviser: you" The kingdom is doomed

[@dogeloaf2821]

Stolen comment

[@TheThunderBat]

I’m sorry but this joke never gets old lmao, I’ve seen it so many times but I always laugh

[@RayBlendertube]

I literally said "8" because it's the minimum there can be in one box. I was accidentally correct

[@michaellyndon6982]

That's actually related to it, because for two of the chests, there can never be less than 8, so yeah, not so much of an accident, just a different way of looking at it.

[@sen7826]

2 is the minimum that there can be in one box.

[@thichinhphan4010]

Why not just put 2 for all the chests since you the advisor is not restricted by rules like the merchant ? I think in this case 2 is actually the easy answer.

[@sen7826]

@@thichinhphan4010 ...in the second riddle? Because you have to distribute all the rubies, not just six of them. And in the first riddle, you're not the one putting them in the box.

[@michaellyndon6982]

@@thichinhphan4010 Because you want the number to be as high as possible. Remember, you have to guess a high number correct, so that you can take more rubies.

[@christianx1z]

"the kings most clever advisor: you" haha then our budget is going down to the ground

[@psycologo121]

The riddle says that 1 box has to have 6 more rubys that another. It never said it had to be the other 2. So why can't the scaunrel put them as 2 8 and 20?

[@sofiazubkova1143]

still 8 is the answer and you get 16 rubies, that was my solution

[@EdwinGonzalez-vs9el]

@@peacocean but psycologo is right.. is there a rule that does not allowe scunrel to arrange the rubies in 2, 8 and 20 in the boxes? Since we know that only one box has to be 6 more than other.

[@JustKidding_LOL]

you get 8+ 8(not the whole 20 but the number you wrote) =16 *since you're gonna be writing 8 on all boxes

[@seanstratford1121]

Even with that the point is you’ll get 16 rubies which is still more than half of them.

[@chadd990]

No. My brother did this in middle school and had to go home early because of head lice. Don't try this, you've been warned

[@aym9808]

The add placement was just ......... BRILLIANT...

[@avivastudios2311]

I didn't notice just how pretty the background drawings were. They're very lovely.

[@josephw3999]

From an expected value perspective, the answer would actually be 9. Even though there are two instances you would only get 9 rubies ( 8-8-14 or 20-2-8) this is actually outweighed by the fact that the other 8 times you are getting 18. This can be shown as 8*18 + 2*9 = 162 > 160 = 16*10. Note this answer is only true under the assumption that the merchant distributes his rubies at random. The riddle stated after the fact that the merchant would choose the worst case scenario.

[@christianratuschny6533]

Almost, you need to account for the fact that, using 8, there's one scenario(8-8-14) where you score 24. Therefore the expected value would be 16*9 + 24 = 168, thus making 8 optimal also from an expected value standpoint

[@lutherwilliamson]

How is the answer not just 10 for the bonus riddle? Assuming the scoundrel always picks the two larger piles

[@neelparmar6690]

Luther Williamson you could go for 1-1-28 and hope to get lucky

[@erikkmetic3741]

@@neelparmar6690 but you need to win in the average of cases... Either way, 10 seems like the best solution.

[@BankruptGreek]

Actually the answer is probably 26 as the definition of "pile" is 2 or more. Best case scenario is 2-2-26 and he keeps 4. this is assuming he is using the definition of pile that everyone uses. edit: wouldn't making a pile of 1 break the rules as 1 isn't equal to a pile, it must be 2+ and so 2-2-26 and you get to keep 26 is the best case scenario.

[@chaudharycodes]

@@BankruptGreek it's a different riddle altogether...

[@studiousboy644]

@@BankruptGreek It's actually paradoxical to think about a pile , in common sense , two things doesn't actually make a pile,it's just...two. And anyway he didn't mention that he could not count the number of gems in each pile, so the best bet is 10 10 10, (Or maybe I'm wrong)

[@radiantabsurdism4671]

I misheard and thought 1 box must have AT LEAST 6 more, I noticed if we exclude that extra 6 then each box would have 8 rubies (24/3=8) which is how this riddle works. I was assuming there was a game theory method to guess if the merchant would try to spread out his rubies or pile them into 1 chest. very interesting idea though

[@mustafahaykal7742]

YES ME TOO AND I SPEND WHOLE WEEK TRYING TO SOLVE THIS ONE USING THAT METHODS...

[@leovaldez8145]

me be like: **opens all three boxes with an axe and dumps out the rubies and “accidentally” throws the axe at the merchant, instantly killing him then proceeds to give some of the rubies back to the people and keeps some for myself** **i am forcefully escorted out of the kingdom**

[@pyr4625]

Medieval problems require medieval solutions

[@utterqueernightmare]

@@pyr4625 Pfft!

[@anayaj402]

Ted videos: “Can you solve the riddle?” Me: No Me: immediately clicks on video

[@sliveriousthegamer1174]

Every video I watch, it always sponsers something. Wix, brilliant, and squarespace. Wow.

[@galaxy7975]

I’m in a math program that sponsors/ uses brilliant and at first I thought it would be like a normal math program. I’m in love with brilliant for some reason

[@jessicabarnes7261]

This is the first riddle I actually solved I'm so happy. This one was quite easy honestly!

[@mixailkaiopioutouare]

Don't bother you solve it wrong

[@iyunganam3885]

I know, link steal them all

[@thehKB24]

Lol

[@kaitr.8658]

Quick change the boxes to pots and grass!

[@emeraldqueen1994]

Oak synia, nice Legend of Zelda reference!

[@spooky961]

Great choice, links an expert at stealing rupies

[@ryank2465]

The Alpaca Redstoner do you know what a joke is

[@some1209]

Why does the king face looks like a seal lmao

[@zkhdillard]

ARF ARF

[@globin3477]

He's the royal seal.

[@aussieboy4279]

The answer to the bonus riddle is you should divide them up into piles of 10. If you give an unequal amount to each pile then the scoundrel will always take the two biggest piles. So giving each pile 10 is the maximum amount you can get.

[@flamefierce998]

"The king's most clever adviser. You" Everyone probably has single digit IQ at this point

[@redboy3743]

Watching for 4 years now

[@4ltrz555]

Yay another riddle!!! I love these!!

[@preetishmajumdar4476]

This is the first riddle that I was able to solve by myself

[@Cyber_One]

YAAS, I FINALLY SOLVED A TEDED RIDDLE JUST BY THINKING!!!!

[@BobMcCoy]

*TED-Ed gives great animation in exchange for rubies*

[@Milos111Zivkov]

Thank you, I worked hard for that animation :3

[@user-ht1vg5we2p]

The last riddle is easy. He will choose the two largest piles, so you're left with the smallest one. The maximum size for the smallest one is 10. You divide the rubies into 3 piles of 10, you give the king 10, the criminal keeps 20.

[@rylandrc]

There's nothing that says the scoundrel will choose the two largest piles, that is a (reasonable) assumption. But the question is what is the maximum number you "can" keep, which includes the possibility, however unlikely, that the scoundrel decides to take the two smallest piles. So technically, assuming that each pile has to have at least one ruby, the maximum number you "can" keep is 28.

[@markangeloisulat217]

I'm so proud the finally, I answered one riddle from TED-Ed correctly

[@ridheesh4765]

Always love the animated/riddle uploads! This is one of the few which I actually got, I'm sure it was one of the easy ones.

[@glittery_cucumber]

This is less of a riddle and more of a math problem

[@sims3man1]

"The king's most clever advisor: you." Your majesty, your faith in me is appreciated, but it is also *SEVERELY* misplaced.

[@idiosyncraticlawyer3400]

Faith is not a virtue; believing despite any evidence to the contrary will sabotage your capacity for learning.

[@shariganchidori]

i've watched every one of the riddles and i finally solved this one, not the same way they did it, but i got the same answer!!

[@mattyaqin7501]

The king's clever advisor - us :D thank you

[@karankhurana7457]

Plot twist: The trader did not watch Ted-Ed videos! He had put 8 in two and 14 in third. You get 24 gems. That sucka paid for his sins!

[@esqimo6647]

“Can you solve this riddle?” I dont even understand the answer

[@0ostormo0]

solution: confirm u have green eyes then leave

[@thetexc]

ozo

[@0ostormo0]

@@thetexc genius

[@champluvdogz4470]

Can you stop posting the same comment on every vid it’s getting annoying

[@0ostormo0]

@@champluvdogz4470 why read it

[@tracydu8052]

Give 1 gold to Eliza and Charlotte, and keep 98 for yourself

[@ttt5020]

The king should have let his ADVISOR advise on his rules! Change his seemingly arbitrary rules to each box must have at least 2, and at least one but must have exactly 12 more gems than another. This makes the only possible combination 2-14-14, and with three 14s we can give the people 28/30 gems!

[@redx3083]

In this scenario you would only get 14 because of choices such as 3-15-12 or 4-16-10. There is also the tricky 2-8-20 where 20 is 12 above 8.

[@pathington]

Just choose the number 1 for all boxes. The rules said 1

[@ashutoshshugla]

I thought the same, but youll get total 3 gems, as it says you get the number you write down

[@calidadfuriousdestroyer1889]

Props to anyone who’s actually able to solve these

[@santanaoutlaw]

I thought there'd be a solution where you could keep them all.

[@BazookaPig]

Punch the merchant and steal his rubies

[@azlan194]

Also, thats not guarantee the best either. What if the scoundrel just put 2,2 and 26 in the boxes. Then you only get 8 back, and he will get 22.

[@roxolp604]

2 2 and 26 isn't possible, one of the rules is that one of the chests must contanin EXACTLY 6 more. The only legal setups are as follows: 2 8 20 3 9 18 4 10 16 5 11 14 6 12 12 7 13 10 8 14 8 9 15 6 10 16 4 11 17 2

[@sd8098]

The best scenario for corrupt merchant is 20 , 8 , 2 so if we select 8,8,8 we get to keep 16 (minimum for us) and he keeps 14 (maximum for him) , I have explained why in my comment ..

[@sd8098]

@UC-qh5Ljca3ccH6R3fgMI6oA I mean if you know the numbers then they might be no reason to guess xD I guess you mean if you know the box with maximum rubies ..

[@adamtan4745]

Lol a chest wont cut it. The rubies are gonna reform you need to bubble it and teleport to the temple

[@woodfur00]

This comment is great.

[@Ark_Mark]

steven fan ?

[@troyvictoria6589]

@@Ark_Mark I'm an air conditioner

[@obbyalana6534]

HAHAHAHAHAHA 😂

[@mazkiey1364]

what i dont get it

[@pallepuaruna6970]

Absolutely amazing no words for this problem

[@hadarshrot4350]

Its simpler to look at the graphs of y = x y = x + 6 y = 24 - 2x At x=2, the intersection with the graphs are in 2, 8, 12 So minimum of 8 is certainly in two of the boxes.

[@zat1245]

Interesting approach. This is why logic is fun, as long as you know the rules things can be approached in different ways but always seem to be closely related, just at a different angle. My solution was that the formula for the boxes were: a x x + 6 since there are always 30 gems among them: a + x + (x + 6) = 30 so a + 2x = 24 and I concluded that a has a range of even integers from [2, 20]. a can only be integers because there has to be an integer number of gems in the box that equals a. 2 is the smallest amount a can be because of the rules and 20 is the biggest because the smaller a is, the bigger x has to be so the inverse is true and the smallest x can be is 2 by the rules so in that smallest case, a = 20. a has to be even because the monomial 2x is even and so is 24. If one integer is even in a sum of two integers, the other has to be as well to produce an even number. So, I looked at the 10 cases made by the constraints and found that the two largest boxes are never lower than 8 in each case.

[@primekrunkergamer188]

Thats pretty smart. The graphs can be useful for more complicated questions.

[@wolfVFV]

The riddle after the video: It has to be 10? Like the other guy will always choose the biggest 2 piles so you have to distribute it 10:10:10

[@ReaSeBy]

I mean I don't think he can see the piles, but either way there is a chance that he'll pick the largest 2 piles and you'll be left with 10. I really don't see how this is even a riddle, like it's actually way too easy, there has to be a trick but I can't find one

[@eragon78]

Yes, the answer is 10. Its surprisingly easy, but I guess it wasnt really meant to be hard since it wasnt the main focus of the video.

[@karry2584]

I can think of 2 answer 1 is if the other person can see and choose the pile then the answer would be 10 but if the other person have to choose randomly the answer could be 28 if the other person got the 2 lowest pile and they say maximum so i think that could work

[@chachos9265]

I think I got it!!. Supposing he can't see the piles (which is the only way all this makes any sense) you arrange the following piles of rubies: 15, 14 & 1. Thus you have a 66.7% chance of getting almost half the pile.

[@hantuchblau]

@Jaeden Vaithianathan the expected value doesn't even change no matter how you distribute the stones so it is even less of a riddle than it first appears. www.wolframalpha.com/input/?i=Maximize+1%2F3+*+a+%2B+1%2F3*b+%2B1%2F3+*+%2830-a-b%29%2C+a+in+%5B0%2C30%5D%2Cb++in+%5B0%2C30%5D

[@cup_check_official]

Ted-Ed: Giving us riddles they can't solve since 1990

[@TEDEd]

But we've only been around since 2012... ;)

[@luthfi4164]

@@TEDEd is this Ted original riddle ?

[@mutsuhanma7807]

These riddles get easier the second time you watch'em

[@fireofdoom1441]

Finally this is the first riddle I could figure out myself

[@imayeti.4674]

The king: your my most trusted advisor Me: lol what, I don’t even live in the same time period, also I can only think of overused comments *were screwed*

[@chavishukla1290]

"The king's most clever advisor ...YOU" I'm surprised that half of the kingdom isn't in blazes??

[@bm8985]

This is one of only a few I've managed to solve both riddles on my own

[@24zawisza]

The legend says that the scoundrel is still waiting for his fine.

[@nyanSynxPHOENIX]

Well, I knew from the beginning they were all going to be the same cards. I thought of three 10's, but realized it would be too easy to get stuck with just ten. I thought maybe of trying to find the highest number so I could get one successful batch at both 15 then 12. Then, I thought obviously if you put in for 6 or 8, you'd be sure to get two of them, so I settled with 8. I didn't have a proof, but I at least feel smart, lol. The one box being x + 6 was pretty confusing, but made 8 fairly obvious.

[@64lundyco]

Wow I got this one and the last one. I'm on a roll!

[@daisyowlgacha9894]

sometimes I can't understand the math in videos like these, but it feels good that I can understand the math in this one

[@mannyfernandez2983]

this is literally the only riddle from this channel that i actually got right

[@beanerman9111991]

"The Kingdom's most clever advisor: you". Well, looks like my time to shine is now. Gets pissed drunk.

[@plvuii]

everyone: I GUESSED 8 AND IT WAS RIGHT me: wait, if it's his rubies why does he have to give it away??

[@mattlovesmovies]

This is third video I’ve solved!...out of, well every single riddle on this channel

[@roronoazoro2496]

I used another method and i also concluded that the safest way to secure the highest ruby was to write 8 in all cards since it will assure to get in two boxes.

[@Vardaris]

Damn I felt so responsible the moment I heard I have to find the answer to save the kingdom that I spent 90 min calculating the possible combinations. At least I found the answer and didn't let the people down.

[@victoriam6569]

Good job!

[@anthonymorgan5822]

Wow. This is the first one I’ve actually been able to solve! 😃

[@theumbrellaofdoom]

I thought so too... but I do not know why the 6, 12, 12 does not work..? I thought that was also possible and I would aim for 12 on all 3 cards...

[@KimThor]

@@theumbrellaofdoom 6, 12, 12 works, and if you would have put 12 on all boxes, you would be rich, but what if he put them in a order of 2, 8, 20? then you would just get 12. or 5, 11, 14, you would again only get 12 rubies. in all of those cases you would get 16 rubies if you said 8 on all boxes which is better than getting 12 rubies unless he divides them like you said.

[@vnkkalninsh]

The video doesn't stipulate that the box that has +6 cannot have more that 6 added to it. So with the 8-8-8 solution, you could end up only getting 8 if the solutions is 2-2-26.

[@GaryLuKOTH]

You did not listen to the rules. The scoundrel is not allowed to do that.

[@yaimelishernandez2755]

Easy to solve! Please harder puzzles!!

[@andrewditton7226]

I was trying to figure this out for hours. I misheard the "exactly" for the 6 more rule. Figured it out in less than 1 min aftet that.

[@chloeknox9102]

What was it

[@nathanwise1608]

This one actually becomes pretty easy once you turn it into a math problem. As seen starting at 1:43, the normal amount of rubies in two of the boxes is x, and the number in one of the boxes is x +6. So, the problem can be written like this: 3x + 6= 30 3x=24 x=8 So, your best guess for each box is 8, just as the video concluded.

[@ranchochaiwala1310]

The best possible answer of the last riddle is 10 ,10 ,10

[@nicolepenagarcia]

The only TED-Ed riddle I've gotten right so far lol.

[@aoyama0022]

King : *chooses you* You : Goddamnit the scraudel's gonna get the ruby.

[@malishah4940]

#TheEarlySquad 😆😆😆 I ❤️ Ted-Ed!!!

[@bloxworld2847]

“You’re the king’s mote clever advisor” Sir, there may be a bigger problem than some stolen rubies.

[@ebonyhippo]

Woot! I got this one, but I didn't understand the explanation at all. I just made a list of all the possible scenarios and plugged in different numbers until I realized 8 was the best any extreme scenario.

[@TUNA-muna]

Seems like a legend of Zelda

[@AaronShenghao]

Rubies missing? Zel... I mean LINK!!!!!

[@magicmaster9769]

There's a flaw in this riddle, the king never said that the merchant had to put all of the rubies in the collection of chests, he can at minimum put 12 up for grabs (2-8-2) and thus the answer isn't perfect (it is assuming he did put all 30 in the boxes)

[@Jedimeister17]

0:57 He needs to devide his rubys between the boxes

[@ObsidianBehemoth]

I just wrote out all iterations... There are 9 unique ways to divide the rubies (x, x+6, 24-2x) where x is between 2 and 11, inclusive. values 4 and 10 give you the same 3 numbers. 4, 10, 16. Then I wrote out the values I could get with each guess from 2 to 20... The most you could get with 1 number is 24 by picking 8 in the (8, 14, 8) division. Or by picking 12 in the (6, 12, 12) division.

[@derdavis6038]

"the kings most clever advisor" guys i dont think the king built schools