Capacitive Voltage Dividers

[@merwynvincent]

Hi good explanation, can u tell how much current can we draw from a capacitive voltage divider? If the source current is 10A between two capacitors of same value,can we draw 5A from one capacitor terminals??

[@walterbunn280]

With regard to measuring high voltage AC, always measure the voltage at the inner most capacitors. That way if you catch an arc, you've at least divided the voltage in half, rather than eating the hole voltage. as far as using this as a voltage divider, I think i might be able to use this in a DC circuit, but i'd need to run a high value resistor in parallel with the top capacitor. That resistor would effectively match the impedance of the bottom half of the circuit, but, which would be kinda nifty to have a way to estimate that in some RF circuits.

[@blockeduser5769]

Yes but at 8:24 once you shorted out the capacitor on the right with the lamp , if given a few seconds wouldn't the other capacitor charge to the full voltage of the supply ?

[@hatschmolo2923]

Yes, thats what nearly happened. A perfect capacitor with no bleeding would probably work

[@cowpens6]

this is exactly what I want to know. thank you!

[@fgbhrl4907]

Great stuff. Although @10:55 it looks like you get a little close to those caps...

[@ludicscience]

😂

[@MrWasim100100]

nice video just one more point in the end " measure voltage across all the capacitors one by one add them and you get total voltage across transformer approximately instead of averaging :)

[@dadaroja2455]

can u implement this to drive led ? instead using resistor as voltage divider ?

[@nigel-matthews]

Excellent video. I'd like to try the voltage divider at the end of the video. What type and rating are those blue caps? Thanks -

[@ludicscience]

They are 6kv 1 nanofarad

[@nigel-matthews]

Thank you!

[@justinholtkamp9972]

VERY USEFUL thank you so much!

[@monh964]

Can i use the same principle to power 110v loads from 220v ac?

[@yucelgul6445]

Merhabalar kutuplu kondansatorde kapesıte yükselmesi o kondansatorun bozulduğu anlamınamı gelir. Normalde devrede kullanılan konfansatorun genelde değeri düşmektedir. Tesekkurler

[@fieroboom]

Did you make the capacitor tester? If so, is there a video of the build? If you didn't build it, then where did you get it?

[@lez7875]

saudações do Brasil a todos. muito interessante. agora só falta os indutores. muito bom. parabéns e sucesso.

[@ludicscience]

Obrigado thanks

[@lez7875]

@@ludicscience . saudações. tu merece. o canal é bom. sucesso.

[@xntumrfo9ivrnwf]

Good video (as always)! Does anyone know where Ludic is from? I'm guessing based on the accent that it's somewhere in South America?

[@128Wojtek]

He comes from Mexico

[@omprakashtiwari9492]

please help to design r c ckt for protection of diode

[@omprakashtiwari9492]

so nicely explained thanks sir

[@Buzzhumma]

Thank you so much. I always learn well from you 👍🙏

[@clems6989]

Confused.. Your using a DC supply voltage, and the "C" divider is working ?

[@granpatriarca3726]

Thank you for the info.

[@akshaydarekar5863]

Hey can I use voltage divider 2 times. Like 1/10 in your case. So 1/10×1/10=1/100. Measure even more higher voltage. May be restricted by capacitor max voltage

[@Andres186000]

You probably could, just factor in the tolerances of the actual capacity

[@snnwstt]

Starting with 2 cap in series, C1 and C2. If you place other caps C3 in series with C4, but both in parallel to, say C1, then you change the equivalent total capacitor: ( C1 // (C3 ^ C4) ) ^ C2 (where ^ meaning being in series and // meaning being in parallel ) = (C1 + C3*C4/(C3+C4) ) // C2 , and so on... Instead, it would be simpler to remember that for two caps in series, the lower capacitance get the higher voltage: Voltage at C1 (in C1 ^C2 ) = V * C2 / (C1+C2), and voltage at C2 = V * C1 / (C1+C2). So, make C1 = 99*C2, and measure the voltage at … C1: V_C1 = V * C2 / ( 99*C2 + C2 ) = 0.01 V Note though that caps have, built in, a parallel resistor, Rpar, (look for Spice models of capacitors, such as at softsolder.com/2009/11/09/spice-crystal-model/) which can be much lower than the resistivity of the cap (at low frequency, such as for DC voltage) and so, the distribution of voltage across the two caps may be more like a division of tension by two resistors than by two caps. And for two resistors, the max voltage appears … at the max resistor, which is the reverse than when looking at the capacitances values! In conclusion, it is a very unsafe technique for DC, or for low frequency. In fact, when you charge ultra-capacitors in series, you SHOULD always add external resistor in parallel to each cap, for safety: va1der.ca/index.php/balance-resistors-for-series-capacitors/

[@akshaydarekar5863]

Guess I would try with my flyback. Thanks for helping. All.

[@mikebarton3218]

Very interesting, thank you. Somehow, I assumed this would only work with AC. Mike

[@towmaterfan2799]

How do you get away with putting capacitors on a AC circuit without a resistor? You would think it would act as a short circuit.

[@walterbunn280]

Capacitors on an AC circuit are resistors. In fact, they're resistors that don't produce heat, so if you're trying to prevent waste heat, capacitors have some advantage. To be honest though, even in DC current, they act as variable resistors according to the voltage levels across the circuit. As a capacitor comes up to charge, it becomes more resistive, all the way up to becoming an open circuit, which allows the capacitor to act as a voltage source at that point.... or explode.

[@sunilbute4012]

Very nice 👍👍👍

[@davidmon7167]

OK I'm impressed.

[@danielmoraes9637]

thanks! awesome

[@_John_Sean_Walker]

Thank you sir.

[@johnanderson9619]

then you have to figure out a way to limit the resistance to the capacitor to charge the capacitor at the right moment with switches..

[@jayeshvashishtha]

Please make rf based charging circuit.

[@YamazakiKaoru]

Great!

[@pauladesitterdesitter5917]

Now you can discharge the other capacitor with the lamp, and so on...

[@ytrew9717]

it probably xplain how multimeter works

[@anshkunwarji987]

Plz make video on homemade radio

[@agathaverma6430]

Sir please make a small amplifier

[@mintudoku9375]

Can this 14000volt tranformer be use in 120volt ac motor...sir

[@l3p3]

How use?!

[@clems6989]

Until they are charged

[@parthasarathimanna8790]

Nice ....