Cascode Amplifier using MOSFET Explained (Cascode Amplifier with Cascode Current Source)

[@ALLABOUTELECTRONICS]

The link for the notes: www.allaboutelectronics.org/cascode-amplifier-using-mosfet-explained/ Timestamps : 0:00 What is Cascode Amplifier? 1:22 Why Cascode Amplifier is used in integrated circuits? 2:36 Output Impedance of Cascode Amplifier (Small signal analysis) 8:00 Intrinsic Gain of Cascode Amplifier (Small signal analysis) 16:02 Effect of various load on the voltage gain of the cascode amplifier 19:49 Cascode amplifier with Cascode current source as a load

[@diptishah3232]

Very nicely explained easy to understand 👌👍👋

[@chrisbankers2728]

At time 6:11 in the video, I thought the equation should be Vx=[ i_x - g_m2 * (-i_x * r_o1 ) ]* r_o2 + i_x * r_o1 it seems to me that in your top most equation at timestamp 6:11 you have a plus sign instead of a minus sign before g_m2. Is this an error?

[@dhruvkawlra9207]

When performing small signal analysis, shouldnt Vgs2 = 0 so Id2 is zero (because Vgs2 is a DC voltage source)?

[@ihiteshkumar]

at 11:56 ,sir while doing nodal analysis ,why we have written vds2/ro2 it should be (vds2-vgs1)/ro2, because source of 2nd mosfet is not at ground at all.

[@ALLABOUTELECTRONICS]

It is actually io = gm2*vgs2 + (vds2 / ro2). But here Vds2 = Vgs2. (you can see it 11:56). Thats why Vgs2 / ro2 is written. Basically a current through ro2 is the voltage drop across it (Vds2) divided by ro2. And here since Vds2 = Vgs2, so its been written as Vgs2/ro2. I hope, it will clear your doubt.

[@ihiteshkumar]

@@ALLABOUTELECTRONICS ok got it sir, thanks.

[@poojashah6183]

Best👍🏻 thank you for sharing 👌🏻👌🏻

[@muhammadnawazawan5526]

well explained! Kindly make more videos on practice questions also!

[@vinaykumarkv5830]

Very good explaination 🔥🔥

[@utkarshkathuria2931]

If ac source is at the bottom transistor, what will happen if you keep Vgs2=0 and do the small-signal analysis?

[@ALLABOUTELECTRONICS]

I think you are talking about small-signal analysis right ?? If vgs2 = 0 then the second MOSFET can be replaced by its output impedance. Ro2 and Ro1 will be in parallel.

[@ravichanderb608]

Very good explanation

[@mayurshah9131]

Excellent as usual 👍👍

[@harshit8957]

very nice explaination

[@225fabry]

"in thit todait bidìo" YOU'RE THE BEST! love you so much hahahaha

[@user-saint]

Very thankful.

[@oneman7039]

Hi great content, What video should I watch for the higher bandwidth discussion?

[@ALLABOUTELECTRONICS]

I haven't discussed about yet. I am going to cover it soon. (The high frequency response).

[@oneman7039]

@@ALLABOUTELECTRONICS great thanks! really good channel BTW.

[@only4music725]

Shouldn't there be minus sign in the intrinsic gain of the cascode amplifier ?

[@ALLABOUTELECTRONICS]

Yes, there will be a minus sign. But in the video if you observe, then only magnitude of intrinsic gain |Ao| is represented. That's why there is no negative sign.

[@only4music725]

@@ALLABOUTELECTRONICS excellent, thanks for the fast and analytic reply

[@noodlenado7827]

THANK. YOU. !!!

[@anshumanpanigrahi7323]

Why we have to ground the output voltage to find eqivalent Gm?

[@ALLABOUTELECTRONICS]

Just consider the entire circuit as a two-port network. The transconductance Gm is the ratio of output current to the input voltage. If you recall the two-port network lectures then it is Y-parameter. I2/V1 when V2 = 0. That's why while finding Gm, output was grounded. I hope, it will clear your doubt.

[@anshumanpanigrahi7323]

❤️❤️love you bro

[@mazinakhtar2958]

Please provide the notes in pdf form .so that easy to revise these topic..

[@ALLABOUTELECTRONICS]

The notes for the same is already updated on the website. Check this link : www.allaboutelectronics.org/cascode-amplifier-using-mosfet-explained/

[@prajjwalpandey253]

Nice 👍👍👍👍

[@hajiclub]

Great!

[@Himanshutiwari590]

love it ❤❤

[@jimbenington2144]

Yeah but how does it work in a few sentences without all the math?

[@chillmatoes7125]

i need subtitle :(

[@kunnu_4]

12:11