Surveying Horizontal Curve Compound Curve Prob 1 (PH)

Surveying
Horizontal Curve
1. Simple Curve
2. Compound Curve
3. Reverse Curve
4. Spiral
Credits:
1. Intro Template: • (FREE) 2D Square Intro...
2. Music:
2.1 Driven to Succes by Scott Holmes, Source: www.freemusicar...
2.2 Instrumental (Guitar) by Carl Ernest Tayag, check his channel: / @ninja35ful
Comment your suggestions or questions here.
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God bless! :)

[@cebox]

CORRECTION: L2 = 133.33 meters

[@yukipaisen3626]

Didn't expect that my 3 hour lecture regarding this topic can be explained in a matter of 13 minutes. Thank you so much po sirr all the love from a puyat Ce student from Mapua University!!

[@cebox]

You're vey welcome! Hoping na makatulong kami sa study/review ninyo and also we are hoping na maishare mo ang videos/playlist and even our channel to your friends, classmates, and schoolmates. This can help us reach and help more students/reviewees/professionals like you! Thank you and God bless you po sa review! 😌😇 And best regards sa mga taga-MAPUA! Hope mainvite kami sa school ninyo as guest speaker. 😇

[@yukipaisen3626]

Update: I got a 1.5 on my surveying subject thank you sir!!!

[@rapdeonon9476]

L2 = 133.333 same parin lalabas po for station PT = 3+573.325 :) Hi po! from UE - Caloocan ako. 1st time ko po susubok sa board exam this NOV 2023. pero graduate ako ng 2020. thanks sir sa vids mo. narerefresh talaga ko sa topics. God Bless po!

[@cebox]

Hello po! God bless po sa review! Hoping makatulong kaming lubusan sa pagrereview po ninyo! 😇😇😇 (𝗦𝗼𝗿𝗿𝘆 𝗳𝗼𝗿 𝘁𝗵𝗲 𝗹𝗮𝘁𝗲 𝗿𝗲𝗽𝗹𝘆. 𝗪𝗲'𝗿𝗲 𝗷𝘂𝘀𝘁 𝗯𝘂𝘀𝘆 𝘁𝗵𝗲𝘀𝗲 𝗽𝗮𝘀𝘁 𝗳𝗲𝘄 𝗺𝗼𝗻𝘁𝗵𝘀 𝗶𝗻 𝗼𝘂𝗿 𝗽𝘂𝗯𝗹𝗶𝗰𝗮𝘁𝗶𝗼𝗻 𝘀𝗮 𝗠𝗮𝘀𝘁𝗲𝗿𝗮𝗹, 𝘀𝗮 𝗧𝗵𝗲𝘀𝗶𝘀, 𝘄𝗼𝗿𝗸 𝘀𝘁𝘂𝗳𝗳, 𝗮𝗻𝗱 𝗹𝗶𝗳𝗲. 𝗛𝗼𝗽𝗲 𝗻𝗮 𝗻𝗮𝗸𝗮𝘁𝘂𝗹𝗼𝗻𝗴 𝗮𝗻𝗴 𝗖𝗘 𝗕𝗼𝘅 𝘀𝗮 𝗶𝗻𝘆𝗼𝗻𝗴 𝗽𝗮𝗴𝗮𝗮𝗿𝗮𝗹. 𝗧𝗵𝗮𝗻𝗸 𝘆𝗼𝘂 𝗮𝗻𝗱 𝗚𝗼𝗱 𝗯𝗹𝗲𝘀𝘀!)

[@jhuncliffordhosena4604]

May maisasagot na ako sa Exam mamaya salamat po!

[@cebox]

Woah! God bless engr sa exam! Hoping mataas nakuha mong score, engr! Balitaan mo kami. 🥹

[@pileep]

UNIVERSITY OF THE ASSUMPTION GODBLESS

[@cebox]

Hello po sa lahat ng taga-University of the Assumption! (Sorry for the very late reply. Abala lang sa masteral, work, and life. God bless po!)

[@patricialainegonzales8692]

Hello, Sir. Thanks for your lectures. Suggestion ko lang po, please place your lighting sa left since your right-handed. Mahirap po kasi basahin yung sinusulat dahil natatakpan ng anino. Thank you!

[@cebox]

Ah, yes po. Hindi na po kami nakawhite board ngayon. Nakalaptop na po kami and using screen recording. Thanks for the suggestion! 😇 (𝗦𝗼𝗿𝗿𝘆 𝗳𝗼𝗿 𝘁𝗵𝗲 𝘃𝗲𝗿𝘆 𝗹𝗮𝘁𝗲 𝗿𝗲𝗽𝗹𝘆. 𝗪𝗲'𝗿𝗲 𝗷𝘂𝘀𝘁 𝗯𝘂𝘀𝘆 𝘁𝗵𝗲𝘀𝗲 𝗽𝗮𝘀𝘁 𝗳𝗲𝘄 𝗺𝗼𝗻𝘁𝗵𝘀 𝗶𝗻 𝗼𝘂𝗿 𝗽𝘂𝗯𝗹𝗶𝗰𝗮𝘁𝗶𝗼𝗻 𝘀𝗮 𝗠𝗮𝘀𝘁𝗲𝗿𝗮𝗹, 𝘀𝗮 𝗧𝗵𝗲𝘀𝗶𝘀, 𝘄𝗼𝗿𝗸 𝘀𝘁𝘂𝗳𝗳, 𝗮𝗻𝗱 𝗹𝗶𝗳𝗲. 𝗛𝗼𝗽𝗲 𝗻𝗮 𝗻𝗮𝗸𝗮𝘁𝘂𝗹𝗼𝗻𝗴 𝗮𝗻𝗴 𝗖𝗘 𝗕𝗼𝘅 𝘀𝗮 𝗶𝗻𝘆𝗼𝗻𝗴 𝗽𝗮𝗴𝗮𝗮𝗿𝗮𝗹. 𝗧𝗵𝗮𝗻𝗸 𝘆𝗼𝘂 𝗮𝗻𝗱 𝗚𝗼𝗱 𝗯𝗹𝗲𝘀𝘀!)

[@patrixemary2187]

Nakasabay ako sa discussion for the first time. HAHAHAHHAHA. Thank u beri mats sir!

[@cebox]

Ah, hahahah mabuti naman kung ganun. :) You're welcome! :)

[@aasports8924]

Tanong Lang po. BAkit po curve length Yung gingamit niyo SA pagkuha Ng station Ng PT? Bat Di Ka nalang nag base SA station Ng vertex at Yung tangent distance to PT Yung ginamit? Parang appropriate po Kasi Yung curve length eh. Salamat po

[@cebox]

in actual, yang tangent line na yan ay imaginary. sa daan ka po magsusukat ng stationing. yung daan na yun, yun yung curve po. (Sorry for the very late reply. Naging abalansa life, study, and work stuff. God bless po!)

[@fighterbuild9288]

Sir, sa pagkuha po ng PT, bakit hindi po pwede kunin nalang yung side b tas t2 tapos iminus agad sa station ng vertex?

[@cebox]

Hindi po ganun ang pagsusukat sa daan. Since curve po ang dinedesign dito, dapat nakabase sa curve yung sukat para sa daan. (Sorry for the very, very late reply as CE Box is very busy with his Master's Degree, Accreditation, Work Stuff, and Life. Thank you for understanding. Keep in touch with CE Box as we plan to do more video tutorials.)

[@Adoreefly.]

exam na namin bukassssssss

[@cebox]

Hoping mataas nakuha niyong score, engr! 🥹

[@chesterdbst6438]

pwede ba Longchord gamitin instead of Length of Curve to find PT??

[@cebox]

Ang alin po? yung Station ng PT? (𝗦𝗼𝗿𝗿𝘆 𝗳𝗼𝗿 𝘁𝗵𝗲 𝘃𝗲𝗿𝘆 𝗹𝗮𝘁𝗲 𝗿𝗲𝗽𝗹𝘆. 𝗪𝗲'𝗿𝗲 𝗷𝘂𝘀𝘁 𝗯𝘂𝘀𝘆 𝘁𝗵𝗲𝘀𝗲 𝗽𝗮𝘀𝘁 𝗳𝗲𝘄 𝗺𝗼𝗻𝘁𝗵𝘀 𝗶𝗻 𝗼𝘂𝗿 𝗽𝘂𝗯𝗹𝗶𝗰𝗮𝘁𝗶𝗼𝗻 𝘀𝗮 𝗠𝗮𝘀𝘁𝗲𝗿𝗮𝗹, 𝘀𝗮 𝗧𝗵𝗲𝘀𝗶𝘀, 𝘄𝗼𝗿𝗸 𝘀𝘁𝘂𝗳𝗳, 𝗮𝗻𝗱 𝗹𝗶𝗳𝗲. 𝗛𝗼𝗽𝗲 𝗻𝗮 𝗻𝗮𝗸𝗮𝘁𝘂𝗹𝗼𝗻𝗴 𝗮𝗻𝗴 𝗖𝗘 𝗕𝗼𝘅 𝘀𝗮 𝗶𝗻𝘆𝗼𝗻𝗴 𝗽𝗮𝗴𝗮𝗮𝗿𝗮𝗹. 𝗧𝗵𝗮𝗻𝗸 𝘆𝗼𝘂 𝗮𝗻𝗱 𝗚𝗼𝗱 𝗯𝗹𝗲𝘀𝘀!)

[@vincelorenzang664]

hello po di po ba pwedeng kunin na lang ang length of the curve ng 2nd simple curve tapos i add sa station ng vertex para makuha ang station na P.T.?

[@cebox]

No. HIndi po pwede. How can you add the length of the 2nd curve sa vertex e hindi naman po nakadugtong ang L2 sa Vertex. So hindi po pwede.

[@ashleygarcia9155]

hello po, sir. may tanong po ako related po sa problem. paano naman po ang gagawin if PT was moved out po ng ilang meters and yung PCC po is nasa same point pa rin. ano na pong mangyayari sa PT?

[@roldanouano2917]

Constant napo ba yang 1145.916 sa pagkuha nang R ?

[@imolodi4351]

Good pm po sir, sir pwede din po ba ung way ng pag solve sa PC pwede din ba gamitin sa pag solve sa PT? thank you po sa reply sir,

[@cebox]

Yes po. 😇 (Sorry for the very late reply. Naging abala po sa pagpapaorder ng aming CE Box Merch tinyurl.com/4mvnu6yu and work stuff).

[@Theguywithephonyname]

Sir d po ba pwede yung sta. Vertex minus b minus t2? Para makuha ang P.T.

[@cebox]

No. Hindi po pwede. Imagine, nasa actual po kayo, hindi naman po natin kukunin ang Sta. natin sa PT from Vertex, hindi po ba? So magsstart po muna tayo sa PC then get the length of the curve (road) papunta sa PT. Yung curvature ng road po tayo nakabase at dun din magbabase sa pagsukat. (Sorry for the very, very late reply as CE Box is very busy with his Master's Degree, Accreditation, Work Stuff, and Life. Thank you for understanding. Keep in touch with CE Box as we plan to do more video tutorials.)

[@welamaericaplaza7690]

sir pede po bang sa pagkuha ng PT ay iadd yung length ng second curve sa Station ng PCC?hihihi thank youu po sir.

[@charisselayasan5606]

sir baka po pwede sa other side yung lighting next time. Minsan mahirap makita yung given dahil sa shadows sir eh hehe

[@cebox]

Opo. Hehehe pero next time, hindi na po ganyan. Kasi gumagamit na po kami ng Pen Tab. Pero wala pa po kaming updated videos sa mga topic na ito. You may watch our tutorials po sa Steel Design, nakapen tab na po lahat run kaya malinaw lahat. 😇 (Sorry for the very, very late reply as CE Box is very busy with his Master's Degree, Accreditation, Work Stuff, and Life. Thank you for understanding. Keep in touch with CE Box as we plan to do more video tutorials.)

[@monn4826]

mahirap makakita ang malalabong mata gaya ko..salamat

[@datuabdulraufmacmod7120]

Good day sir, san po nakuha yung 1145.916? I assume it comes from (360*20/2pi), if yes bakit po ganun sir? Curious lang po thank you

[@cebox]

Nasa introduction po yan if pinanuod niyo po yung intro ng Playlist ng Simple Curve. Ito po yung video: kzbin.info/www/bejne/nam5d3mdaZWKi7s (at 16:36). Here's the playlist link: kzbin.info/aero/PL5-rj23AEMNiMeOGlVgNEo2R6xnDACnYU

[@oleopathic]

example problem uses metric system. which language is this?

[@cebox]

Hello. This is Filipino language.

[@meeeerv_8113]

Hi Lods! Ask lang po for clarifications lang. baka namiss ko. Diba po nagsolve ka po sa R_1 or yung radius ng unang curve, Saan po ulit galing yung 1145.916?

[@cebox]

Hi. Meron po akong discussion paano nakuha ito sa intro po ng simple curve. :)

[@meeeerv_8113]

@@cebox ayy okay po. nakalimutan ko agad haha

[@meeeerv_8113]

@@cebox Thank you po!!!

[@cebox]

Hehe ayos lang po yan! ;) Pero at least nacurious ka pa rin saan nanggaling yun. Meaning hindi ka lang basta nagmememorize ng equation. ;) And that is good. :)

[@meeeerv_8113]

Yes po. Mahirap po na imemorize lahat. Kaya lagi ko po inaanalyze yung derivation ng formula para maretain sa utak hahaha

[@kereenpantua9177]

hi sir. new subscriber here. ask ko lang po kung may constant formula po ba sa pagkuha ng stationings? sana po manotice. salamat. God bless po

[@cebox]

No. Kasi sa stationing, nagbabago bago yun e, kaya walang constant equation dun. Concept of Trigonometry lang naman yun.

[@kereenpantua9177]

@@cebox thank you po sa pagnotice. okaay po kasi medyo nalilito lng po ako kung kailan ako mag aadd or magsusubtract.

[@cebox]

Hmm, kapag ganyan, kunin mo muna station ng PC saka ka magadd para sa station along the curve.

[@kereenpantua9177]

@@cebox salamat po. big help.

[@desu5722]

Hello po Sir. Pahelp po hindi ko po makuha ang logic, nag subtract po kayo ng a at t1 from vertex para makuha ang sta PC. Pero bawal po kunin ang sta PT by adding b and t2 from vertex?

[@riapark9050]

nope bawal po. May prof said na need bumalik sa P.C to get the P.T since starting point ang P.C. so P.C + L1 + L2 po to get the stationing sa P.T

[@desu5722]

@@riapark9050 ohhh I see noted noted thank you po

[@cebox]

Thank you @Ria Park for clarifying his concern po. Additional inputs na lang po kami, to determine the Sta within the curve, dapat talaga length of curve or any length na nasa curve ang basis. Why? Daan po yang curve na yan e. At ang mga tangent line, hindi mo po makikita sa daan, but the curve itself which is yung nile-layout mo ay makikita in actual construction. Now, if magsusukat po kayo ng station, need mo pa hanapin sa actual yung tangent line which is impossible right? Kaya sa curve dapat po tayo. (𝗦𝗼𝗿𝗿𝘆 𝗳𝗼𝗿 𝘁𝗵𝗲 𝘃𝗲𝗿𝘆 𝗹𝗮𝘁𝗲 𝗿𝗲𝗽𝗹𝘆. 𝗪𝗲'𝗿𝗲 𝗷𝘂𝘀𝘁 𝗯𝘂𝘀𝘆 𝘁𝗵𝗲𝘀𝗲 𝗽𝗮𝘀𝘁 𝗳𝗲𝘄 𝗺𝗼𝗻𝘁𝗵𝘀 𝗶𝗻 𝗼𝘂𝗿 𝗽𝘂𝗯𝗹𝗶𝗰𝗮𝘁𝗶𝗼𝗻 𝘀𝗮 𝗠𝗮𝘀𝘁𝗲𝗿𝗮𝗹, 𝘀𝗮 𝗧𝗵𝗲𝘀𝗶𝘀, 𝘄𝗼𝗿𝗸 𝘀𝘁𝘂𝗳𝗳, 𝗮𝗻𝗱 𝗹𝗶𝗳𝗲. 𝗛𝗼𝗽𝗲 𝗻𝗮 𝗻𝗮𝗸𝗮𝘁𝘂𝗹𝗼𝗻𝗴 𝗮𝗻𝗴 𝗖𝗘 𝗕𝗼𝘅 𝘀𝗮 𝗶𝗻𝘆𝗼𝗻𝗴 𝗽𝗮𝗴𝗮𝗮𝗿𝗮𝗹. 𝗧𝗵𝗮𝗻𝗸 𝘆𝗼𝘂 𝗮𝗻𝗱 𝗚𝗼𝗱 𝗯𝗹𝗲𝘀𝘀!)

[@desu5722]

@@cebox Thank you po sa pag elaborate! Big help po!

[@erickjoshuanebreja6154]

may rules po ba about sa labeling ng value ng each station? for example, [2 + 1013] ganito pa rin po ba kapag lumagpas sa 999 ang value?

[@cebox]

Wala naman rules, pero kapag station kasi pinaguusapan, dapat may "+" sign na, na ginagamit. Exmaple: 1. 500m = 0+500 (wala ng meters) 2. 1500m = 1+500

[@peligrosibz2467]

San po kayo sa Tarlac? Taga Tarlac din po ako 😇😇

[@cebox]

Saan po kayo sa Tarlac?

[@peligrosibz2467]

@@cebox Nacia po. Kayo po?

[@cebox]

@@peligrosibz2467 Malayo po pala kayo. Capas.

[@cebox]

@@peligrosibz2467 Kaibigan ko isa sa kagawad diyan. Si John Darrel Sumaoang.

[@janssenabellera3787]

Sir san mo nakuha yong 1145.916?

[@cebox]

Pakicheck yung introduction ng discussion namin engr: kzbin.info/www/bejne/nam5d3mdaZWKi7s at 16:18 (Sorry for the very late reply as we are too busy finishing our master's degree thesis. Thank you for understanding and God bless you!)

[@jeffreyfortaleza8382]

sir, pano po nakuha yung 1145.916?

[@gomezjamesedward7224]

Hello po, ano po Yung book na gamit nyo po as reference po?

[@cebox]

Nanghiram lang po kami ng notes sa co-faculty po namin sa surveying e... (Sorry for the very late reply. Abala po sa life and work stuff. God bless! 😇)

[@cosmicxistence3428]

sir bakit po mininus yung station sa pc? san po ba dapat unang nagsstation?

[@cebox]

Yes, dun ka po sa PC dapat magstart. Imagine, maglayout ka ng road, of course wala pa diyang road talaga, saan ka po magstart? Of course, sa PC po.

[@jaimemiguelcarlos]

Hi po, Pwede po ba makuha ung PT gamit ung Vertex? Thank you po

[@cebox]

No. Hindi po pwede. Imagine, nasa actual po kayo, hindi naman po natin kukunin ang Sta. natin sa PT from Vertex, hindi po ba? So magsstart po muna tayo sa PC then get the length of the curve (road) papunta sa PT. (Sorry po for the very late reply, abala lang po sa work, masters, and life.)

[@MohammadJrSolaiman]

San po galing yung 1145.916?

[@cebox]

Pakicheck po sa introduction, engr. (Sorry for the very late reply as we are too busy finishing our thesis in master's. Thank you for understanding and God bless you!)

[@kyrinemaeolan-olan8133]

Saan galing yung 1145.916 sa formula ng R1???

[@cebox]

Have you watch our Introduction/Concept discussion sa topic po na to? If not, then watch po muna: kzbin.info/www/bejne/nam5d3mdaZWKi7s bago po kayo magpunta sa problems. (𝗦𝗼𝗿𝗿𝘆 𝗳𝗼𝗿 𝘁𝗵𝗲 𝘃𝗲𝗿𝘆 𝗹𝗮𝘁𝗲 𝗿𝗲𝗽𝗹𝘆. 𝗪𝗲'𝗿𝗲 𝗷𝘂𝘀𝘁 𝗯𝘂𝘀𝘆 𝘁𝗵𝗲𝘀𝗲 𝗽𝗮𝘀𝘁 𝗳𝗲𝘄 𝗺𝗼𝗻𝘁𝗵𝘀 𝗶𝗻 𝗼𝘂𝗿 𝗽𝘂𝗯𝗹𝗶𝗰𝗮𝘁𝗶𝗼𝗻 𝘀𝗮 𝗠𝗮𝘀𝘁𝗲𝗿𝗮𝗹, 𝘀𝗮 𝗧𝗵𝗲𝘀𝗶𝘀, 𝘄𝗼𝗿𝗸 𝘀𝘁𝘂𝗳𝗳, 𝗮𝗻𝗱 𝗹𝗶𝗳𝗲. 𝗛𝗼𝗽𝗲 𝗻𝗮 𝗻𝗮𝗸𝗮𝘁𝘂𝗹𝗼𝗻𝗴 𝗮𝗻𝗴 𝗖𝗘 𝗕𝗼𝘅 𝘀𝗮 𝗶𝗻𝘆𝗼𝗻𝗴 𝗽𝗮𝗴𝗮𝗮𝗿𝗮𝗹. 𝗧𝗵𝗮𝗻𝗸 𝘆𝗼𝘂 𝗮𝗻𝗱 𝗚𝗼𝗱 𝗯𝗹𝗲𝘀𝘀!)

[@ToonDereAnimation]

sir sa L po nitry ko yung 20(I)/D hindi po parehas lumalabas kapag ang ginamit ko e yung ( I )(pi/180deg) (R). may kaunti pong discrepancy sa sagot. ayos lang po ba kahit ano diyan ang gamitin ?

[@alexanderigasan8740]

Per station po yan sir, ito yung ginamit ni sir na formula Lc= pi(R)(I)/180

[@ToonDereAnimation]

@@alexanderigasan8740 salamat po

[@cebox]

@@ToonDereAnimation Hi, Kakacheck ko lang po gamit ang (L/I) = (20/D), same lang naman po ang lumabas. Kung hindi man po same ang lalabas, maliit lang po dapat ang discrepancy like 0.0 something lang. :)

[@ToonDereAnimation]

@@cebox salamat po sir!

[@cebox]

@@ToonDereAnimation You're welcome! :)

[@charmbautista8594]

Hello po ask ko lang po if yung stationing ng PC at PCC ay magkaiba? tska po yung sa total length of the curve if ayun na din po yung total non sa PC?

[@cebox]

Magkaiba po. PC is yung start ng Curve, ang PCC ay point of compound curve, that is the point kung saan nagmeet ang dalawang curve.

[@mosessydneyruiz87]

Sir yung sa R1 and R2 mali po ata. :)

[@peligrosibz2467]

Sabi na eh 133.333 meters po yun. Kala ko mali ako 😂😂

[@AuS__Tin]

sir 183 po ba ang c2 or 133?

[@cebox]

133 po. :) Nagkamali lang po ako ng sulat. :)

[@AuS__Tin]

@@cebox padayon si pag uswag sir more powers

[@cebox]

@@AuS__Tin Ano po yung padayon si pag uswag? :)

[@jonbovi-69]

@@cebox "patuloy sa pag progreso" po

[@KUYAKENVLOGS]

Saan nakuha po yung 1145.916

[@cebox]

Check niyo po sa introduction ng topic na ito, diniscuss po namin run, engr.

[@richardsaromines3281]

Thank you sir for this video❤️. Sir ano reference book nyo sir sa surveying?

[@cebox]

You're welcome! Ahm, nakikihiram lang po ako ng module sa cofaculty ko e. Kaya hindi ko alam ang reference niya. :)

[@shenci9767]

@@cebox siri san po kayo nag tuturo?

[@cebox]

@@shenci9767 Hi. Sa Tarlac po.

[@victorani4459]

Try to produce a complete English versions

[@cebox]

Hello. Yes, we are trying our best to add subtitles in our videos. Thank you for the suggestion! (Sorry for the very, very late reply as CE Box is very busy with his Master's Degree, Accreditation, Work Stuff, and Life. Thank you for understanding. Keep in touch with CE Box as we plan to do more video tutorials.)

[@filthamkrisrobemtolentino1393]

Sir papano makakuha ang D1 and D2 if hindi given?

[@cebox]

Ahmm malawak yung tanong mo. Hindi specific. Depende yan e. Kasi may equation tayo na R = 1145.916 / D, so kung hindi given ang D, possible naman na given ang R, or something na given like L, or T, papunta kay R, then makukuha mo na yung D nun.

[@aldrinmallari2440]

133.33 mts po sir Incase na may ma confuse

[@cebox]

Yes po. Nasa correction na po siya sa pinned comment, actually. Thank you po! (Sorry for the very late reply as CE Box is very busy with his Master's Degree, Accreditation, Work Stuff, and Life. Thank you for understanding. Keep in touch with CE Box as we plan to do more video tutorials.)

[@SittieHanifaCIbra]

paano po makuha Sir yung PCC? BTW, Thank you for this po.

[@cebox]

Add mo lang po yung L1 sa Sta. at PC.

[@andreadianneatudmontebon6993]

SAN PO NAKUHA ANG 1145.916???????

[@jeanpepito2715]

Thank you, Sirrrr!!

[@cebox]

You're welcome! :)

[@louisesion1982]

Hi sir! baka po nagtututor kayo :)

[@cebox]

Hi. Yes. Nagtututor din ako. :)

[@louisesion1982]

@@cebox baka may fb page kayo sir pm ko po kayo :)

[@cebox]

You can search me at CE Box personal account at fb. :)

[@louisesion1982]

@@cebox na pm ko na sir :)

[@cebox]

Huwag sa page. Mahirap sumagot dun. Dun mismo sa personal account ko na CE Box. :)

[@comradejoelocholiakowe5646]

How do you get 1145.916

[@RENZ-cq6og]

constant po siya nasa formual po mismo

[@nicholassubere457]

san galing yung 1145,815

[@cebox]

Punta po muna kayo sa introduction ng Horizontal Curve, dun po kasi namin dinidiscuss yung concept and equation derivation. Anyway, ito po yung video: kzbin.info/www/bejne/nam5d3mdaZWKi7s You may watch the whole video, or you may skip at 16:34 po. Andun po yung question ninyo. (Sorry for the very, very late reply as CE Box is very busy with his Master's Degree, Accreditation, Work Stuff, and Life. Thank you for understanding. Keep in touch with CE Box as we plan to do more video tutorials.)

[@ofemiagutierrez581]

bat ganon sinolve ko ung R1 gamit ang T over tan tas I1 jusme ang layo hahah

[@cebox]

Hmmm? Simple substitution na lang po gagawin ninyo para makuha ang T1 and T2, since nakuha na natin ang R1 and R2, how come na hindi niyo po nakuha ang same answer and sobrang layo pa po? Baka po nakaradian ang calculator ninyo and hindi degree?

[@cebox]

Then ibabaliktad mo lang ang unknown kung gusto mo makuha ang R1 and R2, bale simple and direct substitution na lang po yun. How come po sobrang layo ng answer ninyo?

[@roembonyulo386]

try mo mag drawing ng triangle, basic geometry ang trig lng yan.

[@ofemiagutierrez581]

bakit po ganon di ko po nagets vid nyo

[@cebox]

Ahmmm, hmm first time, na may nagcomment na ganito... Hmmm have you tried to watch the introduction of this topic?