4.2 Gravity, Normal Force, and Friction | Intro to Free Body Diagrams | General Physics

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Chad's Prep

Chad's Prep

Күн бұрын

Пікірлер: 22
@Priyanshu.G
@Priyanshu.G Жыл бұрын
first chem, and now physics. thank you
@ChadsPrep
@ChadsPrep Жыл бұрын
Very welcome.
@K-wv5ki
@K-wv5ki Жыл бұрын
Thank you so much for helping me build a foundational understanding of physics with your detailed explanations. You take the time where other teachers don't to explain elementary things -- it is really making the difference for me.
@ChadsPrep
@ChadsPrep Жыл бұрын
You're welcome and Thank You.
@eddieansumana9109
@eddieansumana9109 18 күн бұрын
My favorite physics tutor ever
@ChadsPrep
@ChadsPrep 17 күн бұрын
Happy Studying!
@DrBMed
@DrBMed Ай бұрын
Thank you so much, Chad!!!! After spending 3 hours in a lecture, I did not understand this concept and you saved the day in one hour.
@ChadsPrep
@ChadsPrep Ай бұрын
You're welcome - Glad the channel helped you!
@TheRooflesstoofless
@TheRooflesstoofless 6 ай бұрын
24:49 So if normal force is 490 N and positive as you annotated, does the weight now become negative?
@JamieAyala-zv8xe
@JamieAyala-zv8xe Ай бұрын
For the last problem, I was wondering why you kept it at 30 degrees instead of plugging in 330 because the angle was under the horizontal? Thank you for the help!
@are2515
@are2515 Жыл бұрын
Thank you for the video! For the last example, why is the sum of forces in the y-direction equal to 0? Since the force pulls 30 degrees below the x-axis, if the force keeps pulling, doesn't it go further and further in the y-direction? So how can we assume that the sum of forces in the y-direction is 0? Thanks in advance for your help!
@ChadsPrep
@ChadsPrep Жыл бұрын
You're thinking of it more as a torque (turning force) whereas this would be for example pulling with a rope from an angle of 30 degrees that stays constant. Unless stated that 30 degrees stays the same
@killab5952
@killab5952 Жыл бұрын
thank you so much Mr.
@ChadsPrep
@ChadsPrep Жыл бұрын
You're welcome
@shaygame1735
@shaygame1735 Ай бұрын
how do we know that 50N is part of the y component? Is it because the question states that it is "below the horizontal"?
@ChadsPrep
@ChadsPrep Ай бұрын
Yes, essentially, it points diagonally downwards, which means of the 50N part of that is in the y direction
@olisano1
@olisano1 10 ай бұрын
Hi Chad! For the question at 31:00 it said she's accelerating 2m/s2 downward isn't it meant to be -2 in the calculations? If not please why ,thanks for your efforts ❤
@ChadsPrep
@ChadsPrep 10 ай бұрын
I talk about this from 30:15 onwards :)
@olisano1
@olisano1 10 ай бұрын
​@@ChadsPrep thank you , totally missed it 😂.
@ChadsPrep
@ChadsPrep 10 ай бұрын
It happens to the best of us...
@ReyGotSumCents
@ReyGotSumCents Ай бұрын
21:23 did we just treat a woman as an object, then? love your videos btw!
@ChadsPrep
@ChadsPrep Ай бұрын
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