17.5 Common Ion Effect and Precipitation | General Chemistry

[@taurusequus891]

I used to be so stressed out about my chemistry exam, but now with your videos I understand so much more and feel much better. I can't even express how thankful I am! Your goal of taking away the stress has definitely been reached!!

[@ChadsPrep]

Great to hear!

[@ShaliniSingh-vj1lh]

In which grade u r??

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You are SAVING my life with this chem exam tomorrow. Thank youuu!!

[@ChadsPrep]

You're welcome - I hope you do well.

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[@ChadsPrep]

Glad to hear it - You're welcome!

[@skylardean4540]

These videos have helped me get the highest score on midterm 1 and 2 in chem 1-b. Thank you.

[@ChadsPrep]

Excellent - way to go!

[@AbhiramKarthik-qt1xp]

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[@ChadsPrep]

Glad you found us - Happy Studying!

[@AbhiramKarthik-qt1xp]

@ChadsPrep ❤️

[@navdeeppoonia3747]

Chad I gotta tell ya....you're bloody good ...in fact there are only 2 things that I would do in addition : 1) slow down 2) use a mind map at the beginning of each lesson to put into perspective a summary of what you are about to teach

[@ChadsPrep]

Thanks for the feedback :) You can always slow down the video speed in your KZbin settings

[@AlizaNissanoff]

23:12 Hi, thank you so much for these videos. I was wondering why the Hydroxide concentration is not doubled. I understand why it's squared but shouldn't it also be doubled? If we did an ice chart for this, the Mg2+ would be +x and the OH- would be +2x. So why aren't we multiplying the hydroxide concentration by 2?

[@ChadsPrep]

Hey Aliza, the 1 Mg2+ : 2 OH- ratio from the chemical equation tells us the ratio that Mg2+ and OH- are formed when we start with one molcule of Mg(OH)2. But here our source of OH- is from NaOH so we use the concentration of NaOH only... each NaOH gives us only one OH- so we do not double it

[@simplekanal4339]

@@ChadsPrep Hi , but why we square it then? it means we should use just concentration of OH multiplied by concentration of Mg ? Thank you for videos

[@medicemmanuel]

I so much love the way you break down your teaching to the barest minimum unit❤❤❤ and makes it easier for one to grasp easily😊😊 You're so good sir... Bravo🎉🎉 🇳🇬🇳🇬🇳🇬 #UniPort #Nigeria.

[@ChadsPrep]

Kind words - thank you.

[@kceesimon1112]

I literally stayed up all night watching this so nice and explanatory,thank u very much sir

[@ChadsPrep]

You are welcome!

[@nazninsaleel6006]

Gosh I legit cannot thank you enough, I finally get equilibrium.

[@ChadsPrep]

Excellent!

[@ankanbiswas1527]

You are not chad , You are a Real Gigachad sir , actually I'm from INDIA , i didn't get any vid for precipitation in youtube , i was scrolling down and down , then I saw your video... Excellent man ❤️🎉

[@ChadsPrep]

Thank You!

[@gulrukhhamd7732]

Thank you so much. I was able to get an A in my Gen Chem 2 because of your lectures.

[@ChadsPrep]

EXCELLENT - way to go!!!

[@alison3356]

at 19:32 when you're writing out the equation why did you ignore the nitrate given in the problem? How did you know to replace it with OH?

[@tbji]

Common Ion effect we ignore nitrate since its not on the dissociation reaction while we use Mg and OH since they are the common ions

[@awesomeboise5732]

Thank you so much that was great! Keep making these videos please.

[@ChadsPrep]

You're welcome and Thank You.

[@jojoo_aah8072]

Thank you , you saved me !!

[@ChadsPrep]

That's great!

[@Clipaholick]

Such a good video, thanks so much!!

[@ChadsPrep]

You're welcome!

[@Priyanshu.G]

22:40 hey chad, why is the OH concentration not doubled, like according to the balanced equation

[@ChadsPrep]

Hey Priyanshu, the OH- concentration is formed from the NaOH where we have the following dissociation NaOH > Na+ + OH- so [OH-] and [NaOH] are in a 1:1 ratio

[@treetrunkexpress8684]

Thank you bald man 🙏🙏🙏🙏🙏🙏🙏🙏

[@ChadsPrep]

Very welcome, person of undetermined hair quantity!

[@alessandrac1940]

This vid is just what I needed

[@ChadsPrep]

Excellent!

[@thomashalm8585]

yo ur examples are dope.

[@ChadsPrep]

Thanks

[@MalxR]

Hey Chad, why do you only find the mg's new molarity and ignore the oh's new molarity? Am I missing something basic?

[@TalumbaGondwe]

I think its cz of the one to one ratio 😅

[@SijanRai-u6r]

Wow it feels way easier than when I listened my teacher's lecture...

[@ChadsPrep]

Glad you found us.

[@TalumbaGondwe]

I have a question why are wee not usin the formul of molarity overr volume to find the concentrations ??

[@ChadsPrep]

Hey Talumba, are you referring to the dilution calculation at the 25 minute mark? Here we use M1V1 = M2V2 which is derived from the Molarity = moles/Volume formula, just a quicker method and very useful to learn :)

[@TalumbaGondwe]

@@ChadsPrep ooooooh ok thank youu

[@ChadsPrep]

@@TalumbaGondwe You're welcome!

[@kceesimon1112]

I still don't understand why we used 1×10^-4 as the M of the mixture

[@RelaxRailRide]

Life is good sir!

[@ChadsPrep]

Great!

[@الأستاذنبيلالراوي]

Could you solve this problem please if BaSo4 was precipitated in solution contain 0.012 M NaCl and 0.002 M BaCl2 .calculate the sulfate concentration which is sufficient for saturate the solution with BaSo4 , if you now that the Ksp for BaSo4 equal to 1*10^-10 .

[@NdeyTaal]

Great life saver

[@ChadsPrep]

Wow!

[@colossalepic7125]

I do not get what is the difference between last two questions? Like at the end of the day we are adding NaOH to Mg(NO3)2

[@ChadsPrep]

The second to last question just has a solution of Mg(OH)2 and we are finding out how much OH- is present based on the dissociation constant. The last question is taking two different solutions - Mg(NO3)2 and NaOH and mixing them together to see if a precipitate of Mg(OH)2 forms

[@aayushshah4389]

Also thanks these videos are really helpful!

[@ChadsPrep]

Glad you think so!

[@WafaaMohammad-iq7hv]

شكرا ❤

[@ChadsPrep]

You're welcome

[@thomashalm8585]

last question was tough. Saving the best for the last?

[@otsi.l]

thanks Chad.

[@ChadsPrep]

You're welcome

[@otsi.l]

@@ChadsPrep I'm here 2 weeks later to tell you that I passed my chem test. Wish I had found you earlier.

[@ChadsPrep]

@@otsi.l Glad you did!

[@henokmoges8519]

Thank you so much!!

[@ChadsPrep]

You're welcome :)

[@lauraweynants8224]

thank you SO MUCH

[@ChadsPrep]

You're welcome and Thank You!

[@SakeenaManzoor-u4y]

Sir you are saying that we have no evidence whether our reactant is present or not then how could we calculate ksp

[@ChadsPrep]

what time in the video is this?

[@SakeenaManzoor-u4y]

Sir I extremely sorry about my attitude l never ask any sort of question again l don't what happens to me

[@SakeenaManzoor-u4y]

Sir sorry, sorry sorry sorry sorry

[@ChadsPrep]

no problem if you have a question about the video just let me know what time it is and I can help

[@SakeenaManzoor-u4y]

Sir 1 year ago you have released the video but I don't know whether it is of 2021 or 2022 it is about common ion effect and precipitation

[@anasophiacooper5478]

how are you going to define simple ionic effect in words

[@SiyoungYOO-zo4dl]

Thank you so muchhhhhhhh

[@ChadsPrep]

You are very weeeeeeelcome!

[@jjang5802]

Hi Chad! Why is it that we don't include the coefficient of OH of 2? Question under ''Introduction to Precipitation''

[@ChadsPrep]

Hey JJang! The 2xOH- are accounted for in the Ksp [OH-]^2

[@animeworld12]

24:19

[@ChadsPrep]

Hey animeworld! Do you have a question for this part of the video? :)

[@yussele]

❤

[@ChadsPrep]

Great!

[@DallinHardy]

bless you and your bald head

[@ChadsPrep]

Thank you to you with your unclear amount of folicle quantity. Happy Studying!

[@AbhiramKarthik-qt1xp]

​@@ChadsPrep😂 well that's a very professional comment right there

[@ChadsPrep]

@@AbhiramKarthik-qt1xp 😁😁😁

[@davidsandell679]

Hero

[@ChadsPrep]

Happy Studying!

[@ataamelizabeth2429]

❤

[@ChadsPrep]

👍👍👍