Charles's Law - Solving for Final Temperature

A worked Charles's Law problem that shows step by step how to solve for final temperature.

[@invy2017]

Exactly what I was looking for. Thank you so much!

[@l0m1]

Why did you divide it into two? Pls help

[@stitch2908]

Can you help me out with this one a ballon has a vol 325 mL at 17 degree Celsius. What is temp if volume increases to 392 ml? I got 69.55 degree Celsius?

[@judydarwish5310]

I LOVE YOU SO MUCH YOUR LITERALLY A LIFE SAVER

[@sarahenglish8928]

Glad I could help you out!

[@sherynmagallanes4882]

Thankyouu..it helps a lot.🥰

[@RedIsACrepe]

Thank you

[@antonettee_xx]

Thankyou, you're a life saver!!

[@sarahenglish8928]

Glad it helped. Feel free to pass on my channel to anyone else that can benefit!

[@reycuadra6720]

THANK YOU!!!!!!!!!!!!!!!!

[@sarahenglish8928]

You are very welcome. I am glad the video helped you.

[@camilapablo390]

Thank you so much!! you’re better than my teachers

[@sarahenglish8928]

Glad the video helped! Hope my other videos help you too. It’s always good to see a concept explained from a different perspective.

[@AishahTolentino]

Thank you! This helped a lot! Would you follow the same steps when solving for the initial temperature?

[@sarahenglish8928]

Yup. Absolutely. Just think of Temp initial as your X and solve the same way. Hope that helps!

[@AishahTolentino]

Sarah English Thank you!

[@AishahTolentino]

Sarah English do you divide by 2 because that is the initial volume, or is that just a rule you have to do?

[@sarahenglish8928]

Hi Aishah - sorry for the delay! In order to isolate the variable T2 after cross multiplying, you need to divide both sides by 2 liters. When you do that, the liters unit from the .25 and the liters unit from the 2 will cancel each other out leaving only the unit for temperature. So when you solve for T2 you have calculated the final temperature! Hope this helps.

[@salmansedic6431]

@@AishahTolentino Mag-aral ka ng mabuti😂😂

[@user-sb9kp9qr9f]

Where did you get a 273?

[@evelin2cutee]

in order to convert degrees Celsius to Kelvin you need to add 273 Degrees Celsius + 273= Degrees Kelvin

[@erickparungao1858]

Kelvin Temperature cannot be negative... it ' s must be 37.25 + 273.15 = 310.4

[@_lemarin_5255]

erick parungao who said kelvin can’t be negative? What?

[@anthonycorral329]

@@_lemarin_5255 0 kelvin means absolute freezing so it cant get any colder

[@bakedbeluga89]

You're right except 37.25 is already in Kelvins, she stated she's solving for celsius thats why its negative

[@professionalcatgirl8592]

where was there a negative kelvin

[@lilferff9572]

It's not negative in the video. She just convert 37.75 Kelvin to °C. That's why she subtracted 273 Conversely, if you add 273.15 [the exact value] and -235.25, you will get 37.10° C. You just got confused, I guess.🤔

[@zoemcilwain9366]

how does 298k times .75 = 74.5 please help that makes no sense

[@scottwilling9952]

I'm sure you've figured this out by now, but it was 298K * 0.25, not *0.75

[@scottwilling9952]

There's nothing wrong with the result or the method, but it's such a foreign concept to me not to derive the expression for the unknown from the original formula first, and then plug in the numbers. That is, first rearrange the formula to arrive at T2 = T1*V2/V1, then punch the numbers into a calculator in one go. This also eliminates accumulating rounding errors from intermediate results (which isn't an issue in this case, but in general it can be). Just sayin'.

[@MarkOdia-ie6qx]

I agree with u

[@raeka-cn6mg]

i know I'm like 2 years late, but can you explain how or why they divided it into 2?? is it because of the (T²) (2)??

[@bosskenshin7379]

I thought kelvin was 273.15