Im not exaggerating when I say my chemistry teacher won't teach me, so thanks for the video.
@hunterelsarelli26865 жыл бұрын
That’s most teachers these days
@dogestep643 жыл бұрын
American education system be like
@daniellecarbajal37329 жыл бұрын
Your videos just get better and better! I am your biggest fan! Thank you Chem Academy!!! :)
@rmsarchive7 жыл бұрын
THANK THANK YOU SO MUCH FOR CREATING THIS VIDEO!!!!!!!
@stb965737 жыл бұрын
Thanks so much, so much better than my teacher
@brendaelizondo47826 жыл бұрын
Thank you!! I wish you were my teacher. My teacher goes super fast, you made this so easy!
@katherinedemetroulis97814 жыл бұрын
FREAKING LEGEND YESSS NOW I CAN WRITE THE HONORS PART FOR MY TEST THANK YOU SO MUCH :)
@Djsjnsnsnsns6 ай бұрын
This helped me pass my chemistry test. Thanks for the help.
@ChemAcademy5 ай бұрын
Glad it helped!
@romeledeinbarboza4-3 Жыл бұрын
Very Helpful. Thanks for the Video
@Moonokami_KR4 жыл бұрын
CORONAVIRUS BRING ME HERE!!! ANYONE 2020😂😂😂???
@kyleroby97494 жыл бұрын
same
@nunyaaa1bidness2334 жыл бұрын
Moon Wolf same🤣
@danismom71824 жыл бұрын
same moon wolf same
@keypo790 Жыл бұрын
It's been 2 years already d4mn :(
@zackt14805 жыл бұрын
thank you too much i have a test today
@sethsteiner13 жыл бұрын
Same
@andrewteh85942 жыл бұрын
U are the greatest man to live
@silindokuhlenogaga14948 жыл бұрын
This video is very helpful.Thank you guys
@azourisuarez4040 Жыл бұрын
Thank u sooooooooo much cause I was not understanding how the saturated, unsaturated n supersaturated work
@naghamlvly63066 жыл бұрын
wow, well understood thank you very much for the super chem teacher well done.
@alyssaelmore52467 жыл бұрын
This helped a lot! Thanks!! Happy Thanksgiving 🦃🍁
@meatsandwitch31418 жыл бұрын
Learnt a lot thx
@baileywallman15473 жыл бұрын
You should watch some grammar videos next 🤡
@ayoshawty25992 жыл бұрын
Thank you for this video I have a test Tomorrow and this really help sense i was confused on this topic!
@ComandaKronikk7 жыл бұрын
Thanks man u are a legend!
@kachicelestine96592 жыл бұрын
Cool, Thank you sir for such a comprehensive explanation.
@ChemAcademy9 жыл бұрын
New video on Solubility Curves. SUBSCRIBE to my KZbin channel if you like it.
@markwalusimbi22783 жыл бұрын
This video was amazing! Thanks for the help!
@dechendorji77553 жыл бұрын
This really really helped me do my assignment. Thankyou for the video sir
@raylynbarnes70136 жыл бұрын
Thank you SO MUCH!!!!!!!!!!
@skullesports8053 жыл бұрын
Thanks alot sir helped alot 😍😇
@jharyncraig48566 жыл бұрын
THANK YOU SO MUCH!!
@SaraAli-dx8kd5 жыл бұрын
Thank you!!
@DMRVR6 жыл бұрын
So let's say the solution is over saturated by 22 grams. Could you also add 22 mL of water to make it saturated?
@niayamcintosh54166 жыл бұрын
Life saver
@davidgamble48933 жыл бұрын
The symbol for cesium is Cs not Ce. The compound containig cerium is cerium (III) sulfate.
@98850403708 жыл бұрын
why cerium sulphate solubility decreases with increase in temperature
@baileywallman15473 жыл бұрын
It is a gas-liquid not a liquid-liquid or solid-liquid so it has to have a decrease in temp to increase solubility 😊
@8-theotokoscholomigueldelr2873 жыл бұрын
Thank you
@himanshupatel54587 жыл бұрын
wonderful
@JJ-cc8cf3 жыл бұрын
Thank u so much : )
@archaicStargazer9 жыл бұрын
I am still having trouble on solubility in 50g. Could you please elaborate on that?
@archaicStargazer9 жыл бұрын
*mL
@ChemAcademy9 жыл бұрын
jake jensen If you only have 50mL of water which is half of the 100mL of water that is on the Y axis then you will need to cut the solubility at 100mL in half. For example if 30 grams of a salt are soluble per 100 mL of water at a given temp. then 15 grams of that salt will be soluble in 50mL of water. If you had 200mL of water then 60 grams of the salt would be soluble. Does that make sense?
@archaicStargazer9 жыл бұрын
Yes. Thank you.
@IceCream-uw5ts4 жыл бұрын
Thank you 💖
@markomarosevic52404 жыл бұрын
Thank you sir :D
@sk8terwang8314 жыл бұрын
corona :(
@zacharyjones-lehfaculty88063 жыл бұрын
It is not true that gram amounts above the curve are supersaturated. They are simply saturated. The more solid that is dissolved beyond the saturation point DOES NOT change the concentration of the solution and therefore, despite more solids on the bottom, the concentration of the solution is still simply - saturated. A supersaturated solution is a rare circumstance where a heated solution is saturated and allowed to cool so that more solids are dissolved than would normally remain in solution at that cooler temp. So in fact, a supersaturated solution will appear to be completely dissolved with no cloudiness or solids visible. But any agitation will quickly precipitate those solids out. Please stop teaching people that gram amounts above the line are supersaturated. They are not.
@lttrunks78663 жыл бұрын
I have a test right now
@alishan-cb1vk4 жыл бұрын
video se pehlay add bhoot boring......
@heatherross91264 жыл бұрын
Is it just me or does this guy sound a bit like technoblade??