LMTD(Logarithmic Mean Temperature Difference) for Heat Exchanger area calculation

[@suniltiwari3824]

Nice lecture....pls derive such more videos which directly link to industrial applications....

[@hemantasmar6970]

Very good

[@uniquemomentum1742]

Very easy....

[@thisisarpitjain9608]

Sir please upload the lecture about shoval dryer working principle and its parts

[@maheshdugane1422]

Sir please make an video Agar mere reactor me batch dalni uske se pahle reactor ke check points kya hai ?

[@ChemicalMahi]

Dear sure soon....

[@deeppatidar8103]

Sir secondry condenser me vaccum Dene se vapour lose jyada nai ho skta instand of reciver

[@ChemicalMahi]

Dear no it depends on vapour load and size of condenser.

[@Chemwarrior319]

For a given heat exchanger, the hot fluid flow rate is 5 kg/s, and its specific heat capacity is 4 kJ/kg°C. The cold fluid flow rate is 3 kg/s, and its specific heat capacity is 3 kJ/kg°C. If the logarithmic mean temperature difference (LMTD) for this heat exchanger is 40°C, what is the heat transfer rate (Q) in kW? Sir, is problem kaise solve kare?

[@ChemicalMahi]

Dear will prepare seperate lecture on same....