Circuits 1 - Ideal Op-amp Example

Adam with UConn HKN presents a simple ideal Operational amplifier (OP-amp) example problem. Adam explains the most important principles of the OP-amp and then goes to solve for the output voltage and all other circuit parameters. The methods taught in this video can be used on any op-amp problem.

[@UConnHKN]

Howdy All! Some corrections for you! Vo = -3V is correct, however when we calculated i_3, we forgot our negative sign! i_3 = -0.12mA is the correct answer, meaning that our answer for io is: io = i_2-i_3 = 0.075mA - (-0.12mA) = 0.195mA (into the OpAmp) Sorry for the sign error! ~Andrew

[@joanitarzzalwango6392]

Some are still incorrect

[@multivideos086]

bro u realized after 6 years mannnnn

[@bakugan366]

There is a mistake at the end of your calculations. You forgot the negative sign on i3 which would have made i2 positive meaning that there was current entering the op amp from the output side. Please add an annotation or add it to the description to clarify.

[@joanitarzzalwango6392]

i3 doesn't have a negative

[@michaelaono5535]

loudest intro i have ever heard

[@kimedwardoclida2137]

Io is wrong since Vo =-3v if you KCL on that node it must be 75uA=Io+((-3-0)/25K) = Io-120uA then Io = 195uA

[@mfanelovehealthfitness4204]

The formula that you used to calculate the output voltage(Vout) which is 0v+3v+Vout=0 is incorrect, the right one is 0v-3v-Vout=0. Try it, you won't get stuck again. Everything else is superb. Thank you.

[@Jay-fp8iy]

Thank you white man. Very helpful

[@SunilKumar-jl7or]

Good illustration...transparency

[@nickseurynck7416]

Thanks that was very helpful!

[@nicholasneto8797]

Great video, very educational

[@VeritasEtAequitas]

Sorry, this video should have been redone. It's confusing and has errors. Passive sign convention!

[@rickbronx8528]

Very helpful thank you

[@minhdiep1892]

why -3V/25K=0.12mA???? I think it is opposite

[@clarkken2148]

perfectly lecture !

[@keynaanmedia5329]

Shouldn’t Vo= 3V instead of -3V

[@sibilakshman9575]

Cool video

[@anisurrahman3941]

wow excelent video....

[@davidglendaleardenaso8735]

shouldn't V2 be negative?

[@joanitarzzalwango6392]

The negative on vo is not there supposed to be there

[@singlefather01]

I don’t understand why it is not -0.12mA…. Didn’t see the correction. Oops

[@ampudiauribemagdalena9023]

Merci beaucoup

[@mdhossain3526]

Plz suggest me a book for critical problem on op amp

[@goofypettiger]

Just a general question here, what purpose does the 25k Ohm resistor from the amplifier's output to ground serve? I've seen circuits that have similar and the purpose escapes me. Thank you.

[@VeritasEtAequitas]

That represents the resistance of whatever the circuit is driving. IRL it could be a simple resistance like a light bulb or a complex impedance of a speaker.

[@tahancan]

Thank you.

[@aliakbar4068]

please correction require Io = I3 +I2

[@quantummandavid]

Thanks bro.

[@srikrishna6122]

What is it your are writting on? What's the name of that device?

[@binaryparrot3352]

I believe its called a glass pane :3

[@christinaminnigh5748]

Would you be able to help me solve a problem?

[@Andalfulfulde]

❤❤

[@senanurkok2232]

there is a mistake. i3 is minus 0.12 and i0 is 0.195 mA

[@joelhall649]

Thank you very much

[@philosofsky123]

Volume warning: the first 5 seconds or so are super loud 🔊🔊🔊

[@philsey2783]

bro the sounds from writing on that glass board or whatever makes me feel weird💀

[@parsa2007]

very helpful. you look like a very nice guy i want you hug you brother

[@BenjaminProdAyoJB]

The intro music is so loud

[@joanitarzzalwango6392]

Vo is 3v not -3v

[@aybuke2534]

Please can you tell me why "0V+ V40Kohm+V0=0" ?

[@killersiggy]

Aybüke Gökmen KVL

[@HasanVurucu]

Lmao we lost about 5 minutes because of dancing with your intro.

[@Puogks]

Pen sound 😢

[@arthurc.3747]

How to calculate the currents easily, just apply the the Kirchhoff's rule of knots: i2 + i0 + i3 = 0 // i2 flows into the knot, so it's positive, i0 and i3 flows out of the knot, so they are negative 0.075mA +(-0.12mA)+(-i3)=0 // convert to i3 i3 = 0.075mA-0.12mA *i3 = - 0.045mA*

[@dael1438]

why the dislikes lol

[@ABHINAVSHARMA-rn4td]

hello friends...chai peelo

[@Yoaedn]

its a good video I just don't like the fact that I have to see his face through the calculations. :/

[@UConnHKN]

We happen to think Adam has a wonderful face and makes the calculations even better!

[@laughy38247357075834]

That’s so rude. Your mother should be ashamed.