Operational Amplifiers - Inverting & Non Inverting Op-Amps

[@TheOrganicChemistryTutor]

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is there any way to invert ac signal without using feedback ?

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How did your test on op-amps go?

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Thank you Sir😊 In the inverting amplifier circuit, the method to eliminate the output error voltage caused by the bias current is to connect an R to the ground at the non-inverting input terminal. The value of this R is: R=Rin//Rf

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This helped me with the resistor reference portion. Now I need help with an open loop and cap ref op amps

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[@gammarayflash1170]

nice video. But one remark: @11:53 (continued), the output should be between -200mV and +200mV because it is an opamp in inverting mode. :)

[@PunmasterSTP]

I would think it's still correct and reasonable to give the range as +200 to -200 mV if you usually specify the maximum voltage before the minimum voltage. Is there a convention related to op amps where you would specify the minimum voltage first if you're working with an op amp in inverting mode?

[@sanathkumar3052]

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[@PunmasterSTP]

@@sanathkumar3052 I think so, since 0.2 V should just be 200 mV unless I'm missing something.

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You use them as gain amps, mux, rectifiers, diff amps, buffer, regulated supplies, balanced drivers, instrumentation amps, dc servos, and many more applications.

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[@adipati9161]

8:25 the non inverting input terminal doesn't need some resistor?

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You should include ideal cases and how to solve with missing variables using node voltage method in another video!

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Thank you! I have an exam on this in a week

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How did your exam go?

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@@ihtemad How did it go?

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[@Festus2022]

@11:40 you failed to explain the relationship if any between the Vout and the power supply voltages +/-18V. How does the power supply voltage affect the Vout? In your example Vout seems to be independent of the power supply voltage.

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[@adipati9161]

6:34 can I power the op amp with +18v and 0v instead of +9v and -9v?

[@PunmasterSTP]

I think it depends what voltage you are taking to be your reference. If I understand things correctly, the main idea is that you want to feed the op amp with supply voltages both above and below some reference value (such as +18 V and -18 V compared to ground where the voltage is taken to be 0). So ultimately I think you could label things a different way, but if you are powering an op amp with +18 V and 0 V, then the input signal should be around +9 V.

[@shaneburns317]

He showed how to connect the batteries and the circuit diagram, but it would be nice if that was immediately followed by a hypothetical output. I mean, what good is it to see the circuit if we don't know what it actually does? He gives an example at the end, but it would be nice to have it after each diagram.

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[@WistrelChianti]

Potentially daft question... but if you didn't have access to the "middle" of the 2 batteries to use that as a ground for the op amp, could you put in an equal resistor voltage divider in parallel to the battery, then use the point in between the resistors as the ground for the op amp instead? Sorry if that's a dumb question.

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I have a question guys, how pin 8 which is a not connected pin is used in mobile phone detector ? (CA3130)

[@williamzinser2378]

So, in your first inverted example, why is the value of "R" what it is. How is the circuit affected if "R" is increased or if it is removed and the "+" pin tied to gnd?

[@Mr_Wh1]

Is there a best practice way of making a non-inverting uni-gain setup?

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Please anyone explain what is the use of inverting output and non inverting output and when we need it ?

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[@gabvelasquez1489]

8:31 you said gain=(Rf/Rin)+1 but when you calculate the sample problem it became -Rf/Rin. i just need to know why because im a student haha and taking my online clss right now.

[@gabvelasquez1489]

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[@zeusnegron6586]

In the example, is the gain 20 or 20k? Should the output voltage not be 200V instead of 200mV? Thanks

[@fatimashoaib3010]

so the feedback resistor is always connected to the inverting input ?

[@PunmasterSTP]

I think that must usually be the case, because I think if you were to connect it to the non-inverting input, then you would get *positive* feedback and the signal would grow without limit (until it reached the supply voltages).