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Class 11 chapter 7 | Systems Of Particles and Rotational Motion | Rotational Motion 01: Introduction
• Class 11 chapter 7 | S...
Class 11 chapter 7 | Rotatational Motion 02 || Torque - Moment Of Force - Turning Effect Of Force |
• Class 11 chapter 7 | R...
Class 11 chapter 7 | Rotational Motion 03 | Rotational Equilibrium IIT JEE / NEET | Torque Problem |
• Class 11 chapter 7 | R...
Rotational Motion 05 | Moment Of Inertia Of Continous Bodies - Rod , Ring ,Disc, Cylinder,Triangle
• Rotational Motion 05 |...
Rotational Motion 06 || Moment Of Inertia Of Sphere and Cone || MOI of solid Sphere JEE MAINS /NEET
• Rotational Motion 06 |...
Rotational Motion 07 || Perpendicular and Parallel Axis Theorem Moment Of Inertia JEE MAINS / NEET
• Rotational Motion 07 |...
Rotational Motion 08 | Best Numericals of Rotational Motion and Rigid Body Dynamics JEE MAINS /NEET
• Rotational Motion 08 |...
Rotational Motion 09 | Hinge Forces | Rigid Body Dynamics JEE MAINS / NEET | Rotational Numericals
• Rotational Motion 09 |...
Rotational Motion 10 || Kinetic Energy of a Rotating Body | Work Done By Torque IIT JEE MAINS / NEET
• Rotational Motion 10 |...
Rotational Motion 11 || Angular Momentum IIT JEE MAINS / NEET || Angular Momentum of Rotating Body
• Rotational Motion 11 |...
Rotational Motion 12 || Conservation Of Angular Momentum || Angular Momentum IIT JEE MAINS / NEET
• Rotational Motion 12 |...
Rotational Motion 13 | Rolling Series 01 | Combined Translation + Rotational Motion |IIT JEE / NEET
• Rotational Motion 13 |...
Rotational Motion 14 | Rolling Series 2 |MOI , KE and L expression for Translation + Rotation Motion
• Rotational Motion 14 |...
Rotational Motion 15 | Rolling Series 3 | PURE ROLLING JEE MAINS / NEET | Uniform PURE ROLLING
• Rotational Motion 15 |...
Rotational Motion 16 | Rolling Series 4 | Forces in PURE Rolling | Pure Rolling IIT JEE MAINS / NEET
• Rotational Motion 16 |...
Rotational Motion 17 | Pure Rolling on Inclined Plane IIT JEE MAINS / NEET | Rolling Series 5
• Rotational Motion 17 |...

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Live Classes, Video Lectures, Test Series, Lecturewise notes, topicwise DPP, dynamic Exercise and much more on Physicswallah App. Download the App from Google Playstore ( bit.ly/2SHIPW6 ) Physicswallah Instagram Handle : instagram.com/physicswallah/ Physicswallah Facebook Page: facebook.com/physicswallah Physicswallah Twitter Account : twitter.com/PhysicswallahAP?s=20 Physicswallah App on Google Play Store : bit.ly/2SHIPW6 Physicswallah Website: physicswallahalakhpandey.com/ LAKSHYA Batch(2020-21) Join the Batch on Physicswallah App bit.ly/2SHIPW6 Registration Open!!!! What will you get in the Lakshya Batch? 1) Complete Class 12th + JEE Mains/ NEET syllabus - Targeting 95% in Board Exams and Selection in JEE MAINS / NEET with a Strong Score under Direct Guidance of Alakh Pandey. 2)Live Classes and recorded Video Lectures (New, different from those on KZbin) 3)PDF Notes of each class. 4)DPP: Daily Practice Problems with each class having 10 questions based on the class of JEE Mains/NEET level. 5)Syllabus Completion by end of January, 2021 with topicwise discussion of Last 10 Years Problems in Boards, JEE Mains/NEET within Lecture. 6)The Complete Course (Video Lectures, PDF Notes, any other Study Material) will be accessible to all the students untill JEE Mains & NEET 2021 (nearly May 2021) 7)In case you missed a live class, you can see its recording. 8)You can view the videos any number of times. 9)Each chapter will be discussed in detail with all concepts and numericals 10)Chapterwise Approach towards JEE Mains/ NEET & Board Exams. ****Test Series for XI & XII**** We provide you the best test series for Class XI,XII, JEE, NEET chapterwise, which will be scheduled for whole year. The test series follows very logical sequence of Basic to Advance questions.& Evaluation of Test and Solution to all the questions at the end of the test. Class 11 chapter 7 | Systems Of Particles and Rotational Motion | Rotational Motion 01: Introduction kzbin.info/www/bejne/rIStZ2l3ea-XaNE Class 11 chapter 7 | Rotatational Motion 02 || Torque - Moment Of Force - Turning Effect Of Force | kzbin.info/www/bejne/jF7YkIWAjplqosU Class 11 chapter 7 | Rotational Motion 03 | Rotational Equilibrium IIT JEE / NEET | Torque Problem | kzbin.info/www/bejne/qXOZi2adp7CrgLM Class 11 chapter 7 || Rotational Motion 04 || Moment Of Inertia - Introduction || kzbin.info/www/bejne/fpSxmHiOqr6Hac0 Rotational Motion 05 | Moment Of Inertia Of Continous Bodies - Rod , Ring ,Disc, Cylinder,Triangle kzbin.info/www/bejne/aJfaYqVqj5uZZtU Rotational Motion 06 || Moment Of Inertia Of Sphere and Cone || MOI of solid Sphere JEE MAINS /NEET kzbin.info/www/bejne/fHLNgn-YoquAgbc Rotational Motion 07 || Perpendicular and Parallel Axis Theorem Moment Of Inertia JEE MAINS / NEET kzbin.info/www/bejne/q4bbfGCOZdijrdE Rotational Motion 08 | Best Numericals of Rotational Motion and Rigid Body Dynamics JEE MAINS /NEET kzbin.info/www/bejne/nYGqgJSBrpybaNE Rotational Motion 09 | Hinge Forces | Rigid Body Dynamics JEE MAINS / NEET | Rotational Numericals kzbin.info/www/bejne/a3POYqSEftlgZ8k Rotational Motion 10 || Kinetic Energy of a Rotating Body | Work Done By Torque IIT JEE MAINS / NEET kzbin.info/www/bejne/n2HLZnpsqMmSq6s Rotational Motion 11 || Angular Momentum IIT JEE MAINS / NEET || Angular Momentum of Rotating Body kzbin.info/www/bejne/qF7PYYVmeNamqpo Rotational Motion 12 || Conservation Of Angular Momentum || Angular Momentum IIT JEE MAINS / NEET kzbin.info/www/bejne/bqbXhnmgg8aleqs Rotational Motion 13 | Rolling Series 01 | Combined Translation + Rotational Motion |IIT JEE / NEET kzbin.info/www/bejne/gKfVcqWcmcSSepI Rotational Motion 14 | Rolling Series 2 |MOI , KE and L expression for Translation + Rotation Motion kzbin.info/www/bejne/iqjOY5qKn62JfKc Rotational Motion 15 | Rolling Series 3 | PURE ROLLING JEE MAINS / NEET | Uniform PURE ROLLING kzbin.info/www/bejne/n4WrYZ1-ltWtqpY Rotational Motion 16 | Rolling Series 4 | Forces in PURE Rolling | Pure Rolling IIT JEE MAINS / NEET kzbin.info/www/bejne/aGSkXmhqn898fbc Rotational Motion 17 | Pure Rolling on Inclined Plane IIT JEE MAINS / NEET | Rolling Series 5 kzbin.info/www/bejne/gqqcgKyDZbSHbtU

[@hemantupadhayay954]

3/4ML^2 is the last answer sir ji

[@taiba7139]

D

[@sapnakumari4943]

Option (d) is correct

[@rushaangandhi2646]

Thanks for explaining me moment of i ertia and torque

[@rishabhranjan252]

Sir maine isko simple method se solve kiya hai to iska answer 1036 aa rha hai 1(1×1)+2(2×2)+3(3×3)+10(10×10)= 1036 Maine simple .Method se kiya hai submission nhi use kiya

[@PhysicsWallah]

UP NEXT : Moment of inertia of Continous Bodies : Published on or before 9 pm

[@GauravKartikey]

Physics Wallah - Alakh Pandey tqq so much sir for it

[@sneha7711]

Sir +1 ki phy aur chem ka syllabus kb tk khtm hoga. ?

[@sujaykumar7040]

Sir oblique collision kab karoege?

[@Amongusgal]

Physics Wallah - Alakh Pandey Thank you sir !! Bahut interesting h aapke lectures

[@markandeytripathi2820]

Sirjii gravitation pe plzzzzzzzz

[@nehaamin8841]

I am giving you the easiest solution for the last Q ( you might feel discouraged to read such a long solution but trust me its damn simple I have written it in many steps for clarity.) :D answer = option D method: we should first know the formula { I = m (r)^2 } step 1: in the question, I of A and I of B will anyhow equal 0 because r = 0 step 2: now the problem is very simple because we have to find I only for C step 3: turn the triangle making side with masses A, B as the base then C will be at the top step 4: we know that a perpendicular line from C will divide the base (AB) into 2 equal halves i.e L/2 (mathematical property of triangles) step 5: now using the basic Pythagoras theorem we can solve for perpendicular distance assuming it as x step 6 : L^2 = (L/2)^2 + x^2 step 7 : from here you will get x^2 = 3/4L^2 substitute this back in the formula and you will get 3/4 ML^2 as the answer

[@moonwalkers2005]

Thank you very very very much bro

[@kajal.sambyal.1.530]

Tysm

[@nishashaw5979]

Thank u very very much. 😊😊😊

[@omkesharwani8735]

Tysm di😊

[@nehaamin8841]

@@moonwalkers2005 happy to help!

[@kalyanprasadsharma6223]

The two masses I will be 0 remaining mass I will be m × perpendicular distance. That is height of triangle and it's √3 L/2. I = 0+0+m×(√3 L/2)^2=3/4mL^2 So I = 3/4(mL^2)

[@mohithm7130]

Can u plz send it clearly

[@geetanjali6484]

@@mohithm7130 what he means to say is the for masses on axis its would be = 0 now ONLY one mass would be left for that we need to find the perpendicular Distance from the axis which if you see if the height of the equilateral triangle=√3/2L so Moment of Inertia = M(√3/2L)² which becomes 3ML²/4

[@geetanjali6484]

@@mohithm7130 And if that isn't understandable then if you would see the perpendicular Distance would be equal to Lcos30° which is also equal to √3/2L 30° because it's a equilateral triangle thus angle = 60° half of which is 30° Hope you understood it

[@kiranneyol2150]

Please send me this clear

[@i_mabd5837]

3/4mL Square

[@santoshlavhare7732]

5 years old lecture is still helping me with my doubts 😊😊😊 all thanks to you sir❤❤

[@dhruvratheee-r8b]

☺☺☺🙂🙃😊😊😊😊🤑🤑🤑🤑🤑🤑🤑🤑😇

[@Shivaydhole2016]

It is much better than new lectures ❤

[@Reshu_J]

Same bro

[@MEENAKUMARI-zm7wu]

Yeah

[@MEENAKUMARI-zm7wu]

​@@Reshu_J yeah,

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Physicswallah is like a drugs Once u Start watching u can not stop it afterward But physics wallah is a healthy drug

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[@MohitKumar-nn6rs]

Thanks 🥰

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Please don't compare sir with drugs 🙏 😢 He is like blinking star 🌟 ✨ it attracts our eyes.

[@priteebhandare2237]

Please don't compare sir with drugs 🙏 😢 He is like blinking star 🌟 ✨ it attracts our eyes.

[@nidhireddy2978]

Alakh sir is LEGEND of physics

[@aneeshsheesh5843]

22:46 d 3/4ML² . Make perpendicular from c and cut at AB axis name OC . Draw a line at C parallel to line passing from axis AB and take angle OCA 30° ( ½ of 60° ) and angle of imaginary line also 30° ( alt. int. angle ) . Then find components - Lcos30° = L√3/2 and this is equal to OC. So r of OC is L√3/2 and MOI = mr² = M(L√3/2)² . Final answer = ML²3/4

[@ranomalranomal5999]

ml^2 3/4 hoga sir

[@subratamukhopadhyay9865]

ha aapne itne kuch sahi calculation karke 2 ka square hi nhi kia🥲

[@rashmigita7921]

Thnks 👍 but you forgot to square it

[@aneeshsheesh5843]

@@subratamukhopadhyay9865 o sorry yes

[@aneeshsheesh5843]

@@rashmigita7921 ya ya

[@shalinisharma5901]

Best explanation of rotational motion. Our india will remember him always and appreciate the work. Students hope is only alakh sir and i feel very proud that we have such top educators like him

[@debjitgangopadhyay7713]

How are u shalini ?

[@shyantanroychowdhury8899]

Bhai parai karo .. yaha halchal puchne ate ho kya

[@debjitgangopadhyay7713]

@@shyantanroychowdhury8899 acha hoga ki tum chup raho

[@shyantanroychowdhury8899]

Kyu sirf tum hi bakwas karoge?

[@debjitgangopadhyay7713]

@@shyantanroychowdhury8899 chup be

[@arushagrawaldrawings19]

22:44 option D

[@neilMalhotraO]

Option d is correct. Like who got that and support Alakh Sirrr.😃

[@anjali3106]

Are you from class 12

[@sudarshanp3021]

Yes , opt d is correct

[@mathfun9923]

D is correct!!!

[@betopper7861]

Yes option d is correct

[@_CHANDRAKANTSAHU]

Yes you're right

[@bhaveshlohani6161]

Sir d is correct answer and thank you for teaching us moment of inertia

[@gaganmeher9179]

Bro aj me padhne ayi hu

[@lakhangharami934]

@@gaganmeher9179 toh hum kya pawri karne ke liye aye hain 😂😂😜😜 don't get offend😑😑

[@nuzlock4481]

@@lakhangharami934 ye ham hai, ye hamari book hai, aur yaha year le ant me padhaai ho rhi he😂

[@tusharsinghal7862]

Aaj mai padhne aaya hu

[@369cosmiclogic9]

Aaj Mai "D" answer dene aayaa hoon

[@abhiscreative]

Alakh Sir: "Dilbar mere kab tak mujhe yun tadpaoge, Sawal maine de diya jawab tum kab bataoge 😂" sir ji aapke gaane hit hai .......🙌🙌😘

[@harshbalwally1250]

@SID -Rahul correct bro u r right

[@aakanshasingh1865]

Yep components are not correct 😯

[@ramkishorsingh5903]

3/4 ML^2

[@aliyawahab-9595]

3/4 ml^2

[@santosh1750]

😂😂😂🤣🤣🤣

[@free.fire.india009]

Sir ki sari videos amer hai hamesha hi no one pe 🥰🥰🥰🥰

[@sushantfuse4650]

Option D is correct answer

[@yashbihany7074]

@@aishwaryapatel7393 11th ka chapter hai...hopefully 11th just like me

[@sushantfuse4650]

@Devarsh Raval questions kya tha bhool gaya Bhoot din ho gaye ye chapter dekh kr 😂😂

[@yashbihany7074]

@@sushantfuse4650 din nahi mahine😂...7 months lol

[@yashbihany7074]

@@sushantfuse4650 and i have liked the comment....matlab mera bhi D hi aya hoga probably

[@sushantfuse4650]

@Devarsh Raval 😂😂

[@shubhsings_]

Itna hi kahunga , ki kuch kehne ke liye sabd nahi🙏🙏. Sir tusi great ho

[@shivamarora2969]

23:00 Answer of homework question: D. 3ML²/4

[@Teletoon43]

How you got bro please reply

[@anantgupta1192]

@@Teletoon43 height of equilateral triangle is equal to (√ 3 ×l)\2 This will be the perpendicular distance. I hope now you can understand .

[@mihirsingh8047]

@@Teletoon43 Lsin60 ka square multiply by M

[@Akashkumar-ot1sw]

@@mihirsingh8047 bro simply Lcos30 just simple

[@Akashkumar-ot1sw]

@@Teletoon43 I thought to try pythagorus but it came by vectors instead

[@NILOY640]

Height of equilateral triangle =√3/2 a Given,a = L MOI of both the masses that passes through the axis will be 0 since distance is 0. MOI of the 3rd mass from the axis = M (√3L/2)² = 3/4ML²(d)

[@dhruvalpatel250]

Sir, Answer of last question is option (d)3/4ml^2

[@vikramnishad4846]

Ans D

[@meersadaansadaan6987]

Nice teacher sir

[@meersadaansadaan6987]

Love u sir

[@vanshdesai7917]

Yes it is correct

[@veerchoudharyvlogs6481]

Yes d option the aara h mera bi.

[@notsaiffffff]

For everyone who's struggling to solve last question, actually its kinda tricky so you might find it hard at first but iA I'll make it easy for u. So basically we have to find MOI of mass at C(m3) bcz other 2 are lying on the axis of rotation and we know that when a mass is lying on AOR its MOI is 0. Now net MOI will be determined by m3. So r for m3 is a perpendicular drawn from AB to C. If you do that u can see that we've got vector L divided in its perpendicular components. And the compound adjacent to the theta is providing us the required value of r. So its simple just find L cos 30°. I=mr2 =m.((√3/2)L)² = m.3/4L² or 3/4mL² (option D) Hope u got it!! ❤️

[@mrscomedyian1655]

thanks I also struggle for solve this question 👍

[@rameshkumarshukla3698]

I know it also

[@mrscomedyian1655]

@@rameshkumarshukla3698 ok that good

[@Beyondtheobvious-f3e]

Thanks a lot

[@thesiblingsway2830]

Thanks bro

[@virendrakumarshrivastava7320]

22:44 option (d) 3/4mL²

[@itz_aman.gupta2008]

Correct ✅

[@SumitYadav-mq4nb]

Yes bro

[@Vijay3.0m]

You are very good teacher

[@Vijay3.0m]

Welcome to my student

[@Thatvam]

Yaar tu tho Kamal hey.what a clarity of thought u have in subject.i never thought u can explain in such a critical clear.great and hats off .

[@premat.j.2333]

The answer for last question is d.)3/4ML^2. I=0+0+M(LSIN60°) I=ML(√3/2)^2 I=3/4ML^2

[@ranjitroy01]

Same

[@Yt_awanali]

Yess same!

[@Artoscope1]

Yes ..mera bhi D aaya :)

[@ritach75]

Me also is it right.

[@premat.j.2333]

@@marathimedia7597 you're welcome.

[@enrichenglishacademy3349]

Bolo alakh sir ki JAI ...... Duniya bhar ki physics cover kar denge hamare alakh sir #gr8Alakhsir

[@karman8832]

This video is 4 years old but still it is the best one

[@shobhadas5245]

Jab bhi mai khi atakti hu sir ka video dekh leti hu. He clears all my doubts. Thank you so much sir🙏 you are the best teacher.❤️

[@ziyaziya7237]

Same

[@notyourpriyanka]

One of the easiest way to do the last question is, after you draw a perpendicular line from the point C to the AB line, you drew nothing but the altitude of an equilateral triangle. And as we all have learnt in earlier classes that height or altitude of Eq. ∆ is a√3/2, a being the side. Here our side is L so simply answer is L√3/2. Now in MOI formula I=MR² so just square this => (L√3/2)² = 3L²/4 and multiply it with m (mass). You get answer easily without any calculations at all.

[@Alakhsir-is-love]

Wow , nice ☺️

[@rajkumarimali9555]

But you don't need much calculation you just have to take a component lsin60° and done but your method was also 👍🏻😃

[@epikherolol8189]

​@@rajkumarimali9555how is it "much" calculation?? Doesn't everyone know the height of equilateral triangle to be root3/2h?

[@Navi-b7h]

Oh really

[@shobhitsingh8794]

To all those who are asking what is moment of inertia (MOI) it tells us how farther or closer mass is spread from the axis. If moi more then mass is spread over larger distances then more effort will be required to produce rotational motion compared to when mass is spread over smaller distances.i.e. small moi. Sorry if my English is wrong anywhere

[@sheero231]

@Vipul Yadav roasted in seconds.

[@maggumagar]

ty

[@pleasegetsomesleepugh]

Thanks

[@noxstudios69yago..99]

moi moi, moi moieeeee

[@rajkumarimali9555]

​@@sheero231ayei?

[@itz_Krishna_Jagtap]

गुरुर ब्रह्मा गुरुर विष्णु गुरुर देवो महेश्वरः गुरुः साक्षात्परब्रह्मा, गुरुः साक्षात्परब्रह्मा तस्मै श्री गुरुवे नमः

[@baradalaxmi5524]

Option d is the most appropriate ☝ one

[@motivationalreader4410]

Great sir you give opportunity to every child to show their abilities (Ab raja ka beta raja nhi banega raja wahi banega jo uska asli hakdar hoga

[@Beardgurl]

Anyone watching in 2025😅

[@sheragamerz3849]

Yeah

[@ankitbhaskar333]

Me.....😂

[@AnasAhmed-z8y]

Me

[@AkhtarMemon-ie3gj]

Me

[@Priyankakumari-r1j1e]

Neet vale hai ​@@AkhtarMemon-ie3gj

[@hsd_1729]

"Exams are near" "Nothing is clear" "No need to fear" "When ALAKH SIR is here" 💫💫🔥🔥🔥🔥🔥

[@Tommy_59]

Op❤

[@bhava1_2_3]

❤

[@sarthakchavan4549b]

I have huge respect and love for this man dude... ❣️

[@araj1045]

More simplified , we know root3/2 A is length of perpendicular of equ triangle. So I = m x p(sq), I =3 m l(sq)/4

[@vishnuteja99]

Yea

[@gautam_706]

No channel in this world can compete this ❤️☺️

[@ds_007yt]

This 20:50 calculation trick is super awesome tnx sir 🤩🤩

[@dark_soulgamerz1905]

Are you talking about the square of 55²??

[@ds_007yt]

@@dark_soulgamerz1905 yes just click on 20:50

[@Rishabh_Patel_018]

By using cos 30° we get perpendicular distance to be L√3/2 of Mass C as MOI of A and B will be zero as R= 0 for them , then total MOI of system will be MR²=ML²3/4

[@epikherolol8189]

Kyu itni trigonometry use karte ho bhai. Ek trigonometric equation dunga halat kharab ho jayegi😂 Just use pythogoras theorem

[@rashmijha5261]

kyu bhai sb to shi h aur ye sb jaante h ki pythagoras bahut lengthy hota h aur trigo short hota h @@epikherolol8189

[@nidhireddy2978]

Alakh sir "THE LEGEND OF PHYSICS" no one can beat him✌🏻✌🏻👍🏻👌🏻👌🏻👌🏻

[@vinaydhakar8397]

I am of 10th then also studying this😂😂

[@_CHE_PrabandhaMaiti]

@@vinaydhakar8397 honestly said I am read in class X.

[@vinaydhakar8397]

Shi h yaar👍🏼 Keep it up.

[@_ankit_nain]

right

[@gameyatra6284]

it's never about beating some one it's about teaching some one

[@prakharpanther9652]

Sir The Length I got When Drawn A Perpendicular To AB is √3L/2 And Squared It And Multiplied It With Mass I Got 3ML^2/4 🗿 Loved The Video... 🙏🤗

[@prakharpanther9652]

@@Weirdproking Thanks Bro...👍🤡

[@itachu.]

@@prakharpanther9652 is there any point of using clown emoji , i dont get it.

[@prakharpanther9652]

@@itachu. clown Always Makes People Happy...And If Someone Was Looking For The Answer For The Homework Which Alakh Sir Gave Us Then I Was Definitely Able To Make A Smile On Their Face...🙂

[@anshumanjaiswal1062]

@@prakharpanther9652 tumhare coaching ka 11th syllabus khatam hogya kya?

[@prakharpanther9652]

@@anshumanjaiswal1062 I Don't Go Coaching Bro... Alakh Sir Se Hi Padhta Hoon...🙂

[@gayatrikumar1633]

the answer is option D because as centre of mass is measured from the shortest distance and the shortest distance from the mass placed as C is the distance found by pythagorus that os the square of 3 upon 4 th of the sides of triangle.

[@angelnama4321]

ANS OF THIS UESTION IS D.. 3/4 ML^2

[@aakanshasingh1865]

Yepp

[@roshini5340]

Correct

[@anshuthakur2766]

Right bro

[@manasmahesh1234]

Correct bro........

[@bhumibhati4382]

Yrrrr mera nhiii aa rhaaa h

[@Arshadkhan-official]

Sir , you are the heart beats of millions of student

[@mysticsupriyo]

Option is D,,, Love from Bangladesh Sir❤❤❤❤

[@deepalirathore188]

Option d) is the answer Best of luck to everyone for ur respective aims......!!!!! Helpful vdo as always......

[@adityagandhi4848]

Congratulations sir...finally 300k ho gye ;) 😍😍😉😀😊 Abhi toh bohot aage jana hai 😊

[@anishasingh8836]

U know what sir someone abuse u just because those people are jealous of u that how someone can teach physics like this Nd can make it easy🤗🤗 Tnku sir ♥️

[@Sadia_afrin17]

Ans: d..... i am watching from Bangladesh 😊

[@pratikshawaghmare591]

Sir seriously ..ur teaching is very nice .... I have secured 63.5 out of 70 in physics ....it is just because of u .sir ....thank u Soo much for this videos ...

[@epikherolol8189]

Meanwhile me getting 43 out of 70🥺💀🌚

[@abhirupkundu2778]

rip@@epikherolol8189

[@vishwashkumar2882]

Best award for TEACHING goes tooooooooooooooooooo ALAKH sir ❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️

[@NirabChoudhury]

Option D 22:36

[@Deepakkumar-ry9of]

Thank you so much sir

[@Vivek-ry5lt]

Sir the mantr -"Ding Ding Ding Ding Jing Ding Ding Ding" sab yaad aa jaata hai is mantr ke jaap se🤣🤣

[@shinchan4656]

It is new version of *_aabra ka dabra_* 😂😂

[@na-546]

@@shinchan4656 r u girl ??????

[@shinchan4656]

@@na-546 *_NOPE_*

[@bhaskarsingha2387]

Best physics teacher on KZbin , I am studying in b.sc 1st semester still watching

[@vishnureddy7194]

@Bhaskar Singha where are you doing your b.sc? i too am interested in doing b.sc course rather than b.tech as my interests are on the field astrophysics. also of how many years is b.sc course?

[@rajnikant1243]

Congratulation for having 300k+ subscriber .I hope you have 1 million subscribers very soon

[@tejasvani7163]

CONGRATS 🎉🎊🎉🎉🎊🎊 SIR 💕 💕 💕 💕 💕 💕 💕 💕 💕 💕 4 300K+

[@shivanijatc.no.2648]

Congratulation sir

[@dshah1708]

500k ho ne wallah hai

[@samarthshetty1327]

600 k se jada ho gaya abhi

[@priyankagupta6273]

700 hone bala hai sir congrats.. 😃

[@sumit3466]

Pichle video wale m last question khud nikala bahut khusi mili . Jaisa aapne Kia vaise hi kia mne

[@sensationalgamer193]

According to Alakh sir's T-shirt,It means whatever the situation is,I will teach my students ❤️❤️.

[@abhishekdhawan143]

Best ever teacher.U are forever in my heart.🎀 Our Indian's will remember him always and appreciate his work. Love u so much Sir - Alakh pandey💖🥰🤗

[@KHAMA_10]

not only Indians bro... He is now international 💚

[@rohitjhajhriajhajhria]

Hii

[@rohitjhajhriajhajhria]

Ka s hoo

[@harshpratapsingh2055]

Sir u r toooooooo good,,😆😆 lekin ye video unlike karne wale bhi kam intresting wale nahi hai!!! 😀😀🤔🤔

[@okmylifemyrules]

Moment of inertia about the axix AB is 0+0+m(lcos30)^2 =3/4ml^2 Draw a perpendicular line about A and take component of L along the perpendicular line you drawn i.e. Lcosine30

[@ramansharma4403]

For the ones who are still struggling to solve this last question MOI of the masses lying on AB is 0 MOI of M3 is MOI ~ MR^2 M (root 3 L )^2 = 3/4 ML^2 2 How to find R From AB draw a perpendicular to Mass 3 Now apply the theorm P^2 = H^2 - B^2 = L^2 - L^2 4 = 3L^2 / 4 = root 3 L by 2 All the best everyone !😊

[@urvishjain-m7k]

excellent

[@parthchavan548]

Sir, when I asked Google to play the vidoe on moment of inertia on yt, it directly shown your video!🤩🤩 Sir, really love you! You have created a never ending empire!🥳🥳🥳🥳🥳🤩🥰🥰🥰

[@satyambarnwal5255]

Congrats sir 👍👍 I'm so excited to see 1 million subscribers on your channel,, " 915k subscribers are already done

[@maxash264]

915k to 9M 🤣🤣

[@pandit__2233]

915 K to 91.4 lakh

[@aishwaryadiggal7192]

Sir answer is (L²M)3/4

[@saptarshibhattacharya]

could u plz explain

[@nishchalbadyal1939]

Answer is 3ML^2/4, 4th option.

[@04j6uday4]

Yes

[@maryamkhan1183]

How? I didn't understand. Can you please explain

[@pratyushkumarmaharana5431]

Maryam Khan , see brother just draw a perpendicular line for the axis to c point. Then apply asin60 to get length and apply formula. Ignore the other 2 masser as they are on the axis

[@nishchalbadyal1939]

Pratyush Maharana right bro

[@mathematicsfanatic832]

Yes

[@ankitgouda7502]

3/4 ml^2 is the answer. Thanks sir for your help and support. Looking forward for rolling motion video.

[@tanujthakur3794]

Ni bhi this is wrong

[@tanujthakur3794]

Correct is (c) option

[@ankitgouda7502]

Abhi bolne se kya fayda mera toh selection ho chuka

[@tonyyboii8865]

@@ankitgouda7502 lol 🤣😆

[@ankitgouda7502]

@@tonyyboii8865 😂😂

[@frozen2355]

sir aap itni saari chisen yaad kaise rakh lete ho? I feel like aap itne experienced hoge ki agar koi bhi aadhi raat mein bhi aapko chemistry ka ya physics ka class 9,10,11,12 kisi bhi class ka koi bhi numerical de de to bhi aap use aasani se usi vakt kar sakte hain...proud to be your student sir!! jai hind...

[@vedikaraginiveera6513]

Sir you're not just Alakh Pandey You are one in" A..Lakh " .... Thank you sir for your wonderful explaination ..🙏🙏

[@killmonger3142]

that was so bad

[@izanmohammed3584]

For the last question it is option d. Since it is equilateral triangle that distance we take it as root 3×l /2 . So I = mr square so m ×( root 3 × l / 2)2 m × 3 × l square /2 so 3/4ml2

[@Saswat_94]

✓5 hoga na

[@raktimjyotikashyap6130]

Option d..since we need the perpendicular distance and 60 degree is already there because its an equilateral triangle we have to take the perpendicular distance as lcos30 degree..so we get 3/4ML²

[@vivekpatel7452]

22:44 ans ...option (c) Thank you sir ☺️☺️

[@adityasamal6710]

Niche 2 ka square toh karle bhai

[@adityasamal6710]

Option d correct hai bro.

[@Allofusaredead521]

5 years old lecture still helping me to solve my doubts😅 Thank you Alakh Sir😊 You are so amazing teacher 🥰✨ I wish to have a teacher like you in my college too🥺😩

[@satyaprakashpandey7839]

Taking the vertical component of C we have sin 60° because it is equilateral triangle So I=0+0+mr^2sin^260° I=3/4mr^2 Thank you sir for making physics easy

[@atulanand9282]

18:06 ding ding ding Ninja Hattori 🤣 Thank u sir.

[@dhanashrimanohargore]

😆

[@subbumuvvala4346]

😝😝👍👍

[@CrazyBoy-ie4vi]

Hw question... D option... Mechanics is love.. Credit goes to u sir ♥

[@kartikrathore3025]

Me too bro

[@vvsnnp]

All Generations (past present n Future,) thank Alakhsir

[@ashish007shivhare]

You are teaching for JEE but you are better than engineering professors. The understanding of topic and explanation is exceptional. Thank you

[@abhirupkundu2778]

solved the last questoin?

[@PrathameshMandpe]

did u clear jee?

[@ashish007shivhare]

@@PrathameshMandpe no

[@tech4nerds815]

Sir really you r a best teacher....,.

[@directionsinfinite4446]

Sir you are very ambitious towards the explanation. Thankyou Sir... ❤️❤️❤️

[@leenadevitiwari6625]

Aa gaya sir❤❤❤❤

[@DataDynamics25]

Homework Answer is ML^2/4 (D) Thank you sir for the awesome lecture 🙏🥰

[@saurabhKumar-rb7jq]

3/4 ml^2

[@Tummuskuraoyaar]

D is correct,

[@sumantakumardutta986]

Option (d). (3/4)ML^2. 😀 Thanks for such a clear explanation. 🙏

[@saswatadebsarkar1797]

Yes

[@s.poornachandu5503]

Yes

[@RkChemistry_Shorts]

Sabse acha physics wallah..

[@vipinkosik6804]

Till today no one like alakh sir 🙏🙏he is the best explainer of both physics and chemistry

[@abhaylokhande4852]

Sir option d is right 1st draw perpendicular distance c to AB by Pythagoras yoget value of length I= mr2 =m× +(√3/2)2 =3/4

[@samujwalhazarika277]

We can't forgot your help in our whole life

[@aktarhussainbarbhuyan7404]

samujwal hazarika , ki khobor moi guwahatir pora koisu?

[@crystaleagle6210]

Right broo

[@priyadarshibhattacharjee5088]

Absolutely

[@quicktech7450]

Yeah

[@arshdeep011]

*SIR* *COngratulatins For 300k subscribers* parmatama app ko 10 Oct tak 500k subs. de *god bless you* Keep it up

[@studystudy404]

Ar Sh ❤

[@studystudy404]

is month me poore ho jayege *500k*

[@harshagarwal2076]

Awesome

[@soham_jagdale]

22:50 D IS CORRECT❤❤❤

[@eshamitra6339]

I have never seen or heard anyone teaching physics in such a funny aacent ( children friendly way ) Thanku sir... BTW answer is (3ML)^2 /4

[@PunitKumar-uk4qs]

Hasu kya ab ??

[@harshita7133]

@@harshtak791 🤣🤣🤣🤣🤣🤣🤣🤣🤣🤣

[@harshtak791]

@@harshita7133 what does that mean

[@krishboy6446]

Hi

[@sarthakgupta8526]

Sir I requested to u that please do work on redox reactions soon Me and my friends is waiting for..... Because your teaching style makes us knowledgeable...... And gives confidence...... THANK YOU SIR FOR ALL YOUR EFFORTS FOR US...............☺

[@akhilajay1864]

Super explanation sir. Entertaining and not at all boring.😀

[@rockleee9265]

7:15 Note moment of inertia is a tensor quantity not scalar quantity

[@saheb1009]

Did sir tell??? Plzzz tell

[@rockleee9265]

@@saheb1009 no he told it as a scalar quantity but it is a tensor quantity No problem upto 12th if u say it as a scalar no matters even lot of books giving current as a scalar quantity But current , torque , moment of inertia this and all tensor quantity only because it has direction but it won't follow any vector laws

[@vishalpatel7113]

thanks brother!

[@arjubogati1476]

Yup it is a tensor. I was also confuse in this cuz sir told it is a scalar quantity 😅

[@mujahedahmed4902]

Sir d option is correct ✅✔

[@ubkofficial9117]

The answer of last question is 3/4 ml*2 😃😃😃 Hint - Just move the triangle and make side ab as the base and draw perpendicular from mass c to side ab and then use phythagoras therom for perpendicular side and substitute the value in formula and you will get answer

[@virallobby2133]

Hahahah😂😂

[@mehtabbakhtawar9108]

Can you write this on page ? Send me a pic

[@ubkofficial9117]

@@mehtabbakhtawar9108 yeah sure bro just give me 5 to 10 min

[@ubkofficial9117]

@@mehtabbakhtawar9108 I can't send a pic. it's not a option here to send a pic

[@mehtabbakhtawar9108]

@@ubkofficial9117 its ok

[@mdriadmobarokredoy9266]

ধন্যবাদ ভাইয়া🌸

[@progressivepakistan9726]

Thank you sir. I am from Pakistan and i see your lecture daily.

[@yanshikakamboj8214]

Is the syllabus same there also I am from india🙄

[@yagamilight568]

Kya bhai smjh me to aarhaa hain..n

[@rabindrakumarsahoo1157]

Thanku 4 accepting us

[@harshmistry3018]

Sheraz Khan :- salaam Bhai 🧔 Bhai thuje sammaj to AAA Raha hai

[@kanuchauhan6035]

thank u sir,....great job sir..

[@shakeelkayani333]

Sir you are really fantastic 😊😊 😊😊...sab students ki good wishes hen ap k liye....you are great...I am student of pre-medical and your videos are helping me a lot 😊😊😊

[@divyabotule6081]

Thank you sooo much sir 🙏 🙌

[@pushanmukhopadhyay5795]

Now I am in IITB because of him❤️❤️❤️ He is the best teacher 😘😘😘 His video is better than other coaching centre.💗💗

[@anshuman8147]

Are you for real in IITB ???

[@pushanmukhopadhyay5795]

@@anshuman8147 yes brother ❤️

[@anshshukla6797]

Lier

[@itachu.]

@@pushanmukhopadhyay5795 i actually have trust issues , sorry to be rude but can you upload the video of your campus for a short period then you may delete it