Class 9th model paper maths| Mathematics Model Paper NBF Maths SSC -1

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Sir solved paper upload Kara..

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Yes sir

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Iska solution kha ha ?

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You are the best teacher in the world ❤

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Thank you so much sir.. Salamat rahien

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Sir MCQs upload ker dan please sir Kal paper ha

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Sir please solve ker dea it will be very helpfull ❤

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Thanks sir for the updates

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Thank you soo much sir ❤

[@EhtishamAhmed-di1dc]

Sir kal maths ka sendups ka paper ha Dua kren hm sb students ka paper bohot acha ho jae Ameen ❤ 😊😊

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ameen

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sir plzz class 8 😢😢

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Very very thanks sir ❤🎉❤❤❤❤❤❤❤❤❤❤❤😊😊😊😊😊

[@SirNadeemMunawar]

Welcome beta.

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Sir solve b upload kr ly

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Thanks sir ggg 😊

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Always welcome

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Sir pray for me as my paper is tmr

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Sir is mein to Kafi concept hamara wala Nia hain

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bro kiyunkeh Ch6 hamra excluded h or ismy kafi kch chp6 sy h

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Bro hmary chapter 4,5,7,9,11 hn​@@m0hamamd

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Aanish

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Not excluded​@@m0hamamd

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❤ Sir ❤️

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Solve also sir please ❤

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Sir please solve modal paper as soon as possible please

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Nice🎉

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mil gya sir❤

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Sir you are the best teacher Allah pak ap ko piyari si bho or damaad da

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kya

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Thank you sir

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Welcome

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Sir plz class 7 ka b paper upload kr dyn 2nd term ka

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Sir plz

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Sir please pin yaha pai ma solve paper comment mai bata rahi ho Please pray for exam

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Question 1: Simplify the expression [(125)⅓ × (25)² + (64)⅓ × 6 + (8)⅔] ÷ 2½ Solution Process: 1. Simplify the terms inside the brackets: - (125)⅓ = 5 (since 5³ = 125) - (25)² = 625 - (64)⅓ = 4 (since 4³ = 64) - (8)⅔ = (2³)⅔ = 2² = 4 2. Substitute the simplified terms into the expression: [5 × 625 + 4 × 6 + 4] ÷ 2½ = [3125 + 24 + 4] ÷ 2.5 = 3153 ÷ 2.5 = 1261.2 Answer: The simplified expression evaluates to 1261.2 Question 2: The attached figure shows the position of three points A, B, and C. State the bearing of: B from A; A from B; B from C; and C from B. Solution Process: The image shows a triangle ABC with angles and directions. To find the bearing, we need to assume a North direction. Let's assume North is pointing upwards. Bearings are measured clockwise from North. The angles provided are insufficient to precisely determine the bearings without additional information or assumptions about the orientation of the triangle. Therefore, I will make assumptions to provide example bearings. Assumptions: - Point A is located at the origin (0,0) - Point B is located in the first quadrant - Point C is located in the second quadrant Example Bearings (based on assumptions): - Bearing of B from A: Let's assume the angle from North to B is 40°. Therefore, the bearing is 040°. - Bearing of A from B: This requires knowing the angle from North to A from point B's perspective. Let's assume this angle is 220°. Therefore, the bearing is 220°. - Bearing of B from C: Let's assume this angle is 310°. Therefore, the bearing is 310°. - Bearing of C from B: Let's assume this angle is 130°. Therefore, the bearing is 130°. Answer: The bearings are approximate and based on assumptions about the orientation of the triangle. With the provided information, precise bearings cannot be calculated. The example bearings are: B from A = 040°, A from B = 220°, B from C = 310°, C from B = 130°. Question 3: Bani Gala had a population of 10,000 people in the year 2015. The population has been growing exponentially at a rate of 2.5% per year. Using the exponential growth formula, find the population in 2023. Solution Process: The exponential growth formula is: P(t) = P₀(1 + r)^t Where: - P(t) is the population at time t - P₀ is the initial population - r is the growth rate (as a decimal) - t is the time elapsed (in years) In this case: - P₀ = 10,000 - r = 0.025 (2.5% as a decimal) - t = 2023 - 2015 = 8 years Substituting these values into the formula: P(8) = 10000(1 + 0.025)^8 = 10000(1.025)^8 ≈ 12184 Answer: The population in 2023 is approximately 12184. Question 4: Find the equation of the family of lines passing through a point (5,2) and through the intersection of lines x + 2y - 10 = 0 and 2x + y - 10 = 0. Solution Process: First, find the intersection point of the two given lines: x + 2y = 10 (1) 2x + y = 10 (2) Multiply (1) by 2: 2x + 4y = 20 Subtract (2) from this: 3y = 10 => y = 10/3 Substitute y back into (1): x + 2(10/3) = 10 => x = 10 - 20/3 = 10/3 The intersection point is (10/3, 10/3). Now, find the equation of the line passing through (5,2) and (10/3, 10/3): The slope m = (10/3 - 2) / (10/3 - 5) = (4/3) / (-5/3) = -4/5 Using the point-slope form: y - y₁ = m(x - x₁) y - 2 = (-4/5)(x - 5) y - 2 = (-4/5)x + 4 y = (-4/5)x + 6 Answer: The equation of the family of lines is y = (-4/5)x + 6.

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Question i(v): Prove that: 1 + cos x / 1 - cos x = 2 + 2 cot²x Solution Process: We will start with the left-hand side (LHS) and manipulate it to match the right-hand side (RHS). LHS = (1 + cos x) / (1 - cos x) Multiply the numerator and denominator by (1 + cos x): LHS = (1 + cos x)² / (1 - cos²x) Using the trigonometric identity 1 - cos²x = sin²x: LHS = (1 + cos x)² / sin²x Expanding the numerator: LHS = (1 + 2cos x + cos²x) / sin²x Separate the terms: LHS = 1/sin²x + 2cos x/sin²x + cos²x/sin²x Using the identities 1/sin²x = cosec²x, cos x/sin x = cot x and cos x/sin x = cot x: LHS = cosec²x + 2cot x cosec x + cot²x Using the identity cosec²x = 1 + cot²x: LHS = 1 + cot²x + 2cot x cosec x + cot²x This doesn't directly simplify to the RHS. There may be a typo in the original question or an alternative trigonometric identity needs to be applied. Let's explore an alternate approach. Let's start from the RHS: RHS = 2 + 2cot²x = 2(1 + cot²x) = 2cosec²x This also doesn't appear to directly match the LHS. There might be an error in the problem statement. Answer: The given identity does not appear to be true based on standard trigonometric identities. There might be a typo in the question. Question 1 (iv): Solve the linear equation: 3(x - 2) + 2 / 2 - 3x = x + 5 / 5 Solution Process: First, simplify the equation: 3x - 6 + 2 / 2 - 3x = x/5 + 1 3x - 6 + 1 - 3x = x/5 + 1 -5 = x/5 + 1 -6 = x/5 x = -30 Answer: The solution to the linear equation is x = -30. Question 1 (iii): People in the year 2015. The population has been growing exponentially at a rate of 2.5% per year. Using the exponential growth formula, determine the year when population reaches up to 25,000. Solution Process: This is similar to a previous problem. We use the exponential growth formula: P(t) = P₀(1 + r)^t Where: - P(t) = 25000 - P₀ = 10000 - r = 0.025 - t is the number of years since 2015 25000 = 10000(1.025)^t 2.5 = (1.025)^t Taking the logarithm of both sides: log(2.5) = t * log(1.025) t = log(2.5) / log(1.025) ≈ 37.15 Since t represents the number of years since 2015, the year is approximately 2015 + 37 = 2052. Answer: The population will reach 25,000 in approximately the year 2052. Question 1 (ii): Simplify: (5 + p - 18p²) / (2 + 5p + 2p²) Solution Process: This expression cannot be simplified further without additional information or assumptions. The numerator and denominator do not share any common factors that can be canceled out. Answer: The expression (5 + p - 18p²) / (2 + 5p + 2p²) is already in its simplest form. Question 1 (i): In the given figure, find area of a regular hexagonal roof of a building shown below. Solution Process: The image is unclear, and I cannot see the dimensions of the hexagon. To calculate the area, I need the side length (s) or apothem (a) of the hexagon. The formula for the area of a regular hexagon is: Area = (3√3/2) * s² or Area = 3as where 's' is the side length and 'a' is the apothem (distance from the center to the midpoint of a side). Answer: I need the side length or apothem of the hexagon to calculate the area. Question 2: Find equation of the family of lines passing through the intersection of lines x + 2y - 10 = 0 and 2x + y - 10 = 0 and through a point (5,2). Solution Process: This question is a repeat of a previous question. The solution is the same. First, find the intersection point of the two given lines: x + 2y = 10 (1) 2x + y = 10 (2) Multiply (1) by 2: 2x + 4y = 20 Subtract (2) from this: 3y = 10 => y = 10/3 Substitute y back into (1): x + 2(10/3) = 10 => x = 10/3 The intersection point is (10/3, 10/3). Now, find the equation of the line passing through (5,2) and (10/3, 10/3): The slope m = (10/3 - 2) / (10/3 - 5) = (4/3) / (-5/3) = -4/5 Using the point-slope form: y - y₁ = m(x - x₁) y - 2 = (-4/5)(x - 5) y - 2 = (-4/5)x + 4 y = (-4/5)x + 6 Answer: The equation of the family of lines is y = (-4/5)x + 6.

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THE POWER OF CHAT GBT

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Solved Kar ke upload Karen❤

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first viqe

[@SirNadeemMunawar]

Yes

[@AsmaDildar-r9q]

Ge Sr Kya is Mai sy a skta hai paper ?

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Sir AP Kal Mera math ka paper da dein please 🥺😂

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2024 ka. Paper. Hn ya old

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Sir plz solve it

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Sir g Punjab ka board paper pr video bnya😊plz 🥺😔✅

[@SirNadeemMunawar]

Okay soon InshaAllah

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Sir paper ko solve bhi karien

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Sir please send solve modal paper

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I'll try soon InshaAllah

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@@SirNadeemMunawar ok sir lnshallah

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Sir please class 7 ka finnal term matha ka paper ki video banaya

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Please f.g junior public school kashmiri road Rawalpindi

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Sir solved paper monday ko paper ha maths ka ar model paper ki tayari karni ha 😢😢

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Sir plzzzz aj video upload kar dan 😢😢😢😢

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Kl paper haaa

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Thanx sir g pls give pdf plz

[@MuhammadShafique-n3y]

Sir please solve this modal paper

[@EhtishamAhmed-di1dc]

Sir is model paper ka solution upload kren ge kia?

[@SirNadeemMunawar]

No

[@EhtishamAhmed-di1dc]

@SirNadeemMunawar sir why? Please upload ker den Hm students ke lie bohot help ful ho gaa please

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@@EhtishamAhmed-di1dc Bas Kro Yaar Sir ne Aage hi hamaari Bohot Ziada help ki ha

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sir plzz is model paper ki google link de dein print krwana hai plz monday ko paper hai

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Assalamualaikum sir ? Sir solved paper kab apload karein Gei ???

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sir class 8 ka b kal exam ha hamara 😢?

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Sir plz solve Kar da

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Sir iska solution kindly upload krdain aesy sary concepts mix horhy Kindly krdain raat tk Regards!

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I hope ap krdaingy!

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Sir today 11 november my math paper but this is not please upload first term paper😢

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Sir please aps school p.s paper chhor cantt ka bhejo

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❤sir ham is paper ki tayari kary to sendup me pass ho jae gy

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Your school teacher tell you better about your asking question

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Aoa sr kl paper hai plz dua kijye ga acha ho jye 😔

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Best wishes for you

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Sir plzz reply me plzz sir k ye paper kal subah 11 november ka paper h 9th ka

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Fg school ka

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Cancel​@@KashanKashanHussain

[@Girls-Queen837]

Aoa sir I hope u are fine Sir I have a little request..sir please upload the 1st term maths solved paper ... please sir

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As soon as possible sir please upload it

[@SirNadeemMunawar]

I don't have paper

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Sir solve upload kar de

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Sar logarithmic world problem ki samajh Nahin I( question 3)

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Important information ha paper ka hawala sa pattern

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😮

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Sir please physics ka numerical karwai

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sir ye to bohot mushqil lag rha hai kal paper hai

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Any APS Student Present lagao❤ 👇

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I am also here

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Sir. Plz sloved paper update kara plzzzzzz

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sir please bta dain 8 main calculatar allow hay

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Depends on your school But in FG schools calculator is allowed

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@@SirNadeemMunawar sir fde board government school

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Sir just mcqs solve krwa dei

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sir pls upload miscellaneous exercise 8

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@@shabbirshahzaib3981 Bhai ab bas Jo kia Howa ha usse repeat kar time nai ha hamara pass

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Where can i download this ?

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sie is ka solution bhi plz

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Sir g ye course iss Saal ka ha , ya phir pichle Saal ka ?

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Bhai isi saal ka ha

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Kon Kon aps ma Partha ha

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Sir is paper ko AJ hi solve kar Kay bhaj daye Kal paper hay

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Not possible

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KYAIII :( NOT POSSIBLE HAM TO GAI 😢

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PLEASE SIR AP KONTO ATA HAI SARIF ASWERS HI MARK KAR DE KAM SE KAM

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NO EXPLANATION JUST ANSWERS PLEASE 😭

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Asslam o alikom! Sir I've a request. Kindly in sare papers ke picture upload/post kar de and please not in the form of video. I shall be very thankful to you Allah hafiz!