Class A Commutation (Basics, Circuit, Working, Waveform & Modes) Explained in Power Electronics

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[@AyushKumar-yh4em]

Loved it. Tomorrow i am having power electronics internal

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[@skshareena5013]

Your explanation made me interest to study subject 👍

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[@VIKASKUMAR-qz2lg]

Very good explanation in simple steps. Thanks

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[@ManishKumar-iu8cf]

Thank you sir for the excellent explanation

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[@amitkionlineclasses3313]

Sir very good explanation, keep it up

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[@shashanksahu2326]

Thank u so much sir for this helpful video.

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[@-A-VikasBalaga]

Sir,in the waveforms how can scr current become negative?

[@ritikbhagat8456]

Nice explanation but i have one doubt that you said that after output current became zero then capacitor got discharged but how is this even possible as SCR doesnot support conduction in reverse direction. Please explain!

[@EngineeringFunda]

Didn't get your question dear.

[@ShatruVinashak]

@@EngineeringFunda if scr isn't bidirectional how does capacitor current flow?

[@shrutigupta5598]

SCR in reverse baising behave like an open circuit and it having high resistance that's why voltage tends to infinite across SCR.

[@srisolutions7722]

Staring we study the underdamped RLC circuit. Current flows same as underdamped graph my dear frnd

[@satyamkumarshrivastav8287]

Ache se smjh aa gya,thankuu

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@@EngineeringFunda keep it up sir, u r doing a grt job🙏

[@stormx7050]

One question. At the end the capacitor is discharging. But the scr is turned off. So how will it discharge as there is no closed path as turned off scr means open circuit

[@sohanurrahman9136]

i also have doubt about this....

[@lijojohnson4001]

Very useful class sir👍

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[@perfecta1453]

Sir shahed me adrak dalkar pijiye kafi farq hoga awaz me...sardi kam hojaingi...baqi teaching achi hai

[@subhashismaitra7204]

Please can you explain how the current is decreasing when capacitor gets charged upto VS, though the direction of current is the same as in the previous case.

[@UpendraKumar-pm6ur]

Because inductor energy start to decreasing so current decreasing and capacitor further charge with same polarity

[@arunpradaap]

basically it is like natural commutation we are giving an negative pulse to the scr with the help of inductor when the polarites changes it is like an negative halfcycle in the ac sin wave

[@architkulkarni8493]

I have a doubt sir, i.e. Class E commutation is categorised under which type?

[@subhashismaitra7204]

I am not understanding when capacitor gets charged upto VS, then the direction of current flow is in the same direction as the previous, then how current will decrease.

[@Nani444Nani]

I have a dought Is the capacitor will allows the dc?

[@Akash-ih5zb]

No

[@mahfuzurrahmanmunna8138]

thank you sir. I am from Bangladesh

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Your positive comments motivates me.

[@immanuelreuben9828]

How did you even derive those equations from the previous da? Can’t you explain that?

[@Nani444Nani]

Perfect Explanation 👌

[@EngineeringFunda]

Glad you think so!

[@nabzero6528]

Why is the current flow still the same when inductor is releasing energy

[@Nani444Nani]

Sir main dought is if we want to turn off the SCR then we want to Connect L and C are in underdamped mode? Or At the start of the circuit it will be in under damped mode? Pls explain this

[@EngineeringFunda]

L C oscillation means it is critical damped system.

[@rajsaru8790]

I have one doubt , in control system for resonant frequency you mentioned as omega r = root of 1-(2zetta^2), but here you mentioned as omega r =. Root of 1-zetta^2. Why here not 2 zetta square?

[@alokpradhan4879]

U did not explain how the capacitor got discharged, how the voltage decreases to zero in capacitor.....

[@p_r_a_t_i_k_0_7]

can not understand ta laplace transform plz help me

[@bhavyavuyyuru1550]

Sir impulse communication related to classes D, not for class C

[@saiprasadma4726]

Bro e kaanum 3:03

[@abdullahaamirparacha7024]

waveform smjh nahi aayi

[@hakuna3132]

But I have a doubt,how can we apply dc across l or c element

[@EngineeringFunda]

You can apply DC across L and C elements, where L will act like short circuit and C will act like open circuit as if you connect DC across it.

[@akshikagarg9774]

Where can I get this ppt?

[@KingKoduku33]

❤️

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Thank you sir

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❤

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Thank you sir

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Thank you sir

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It really helped me a lot

[@saiprasadma4726]

Bro e kaanum 3:03