why 8C4 instead of 8P4 for S? Arrangements are permutations, not combinations.
@bharatvekariya19733 жыл бұрын
8c4.4!/4!= 8p 4
@MOENGMOSWAANE4 ай бұрын
Good Question
@mr.Anand_kr2 ай бұрын
if you take 8P4 then you have to take 4! in denominator for 4 S's like this (8P4/4!). And rather than taking this we can also take 8C4 which value is also same as 8P4/4! so if you take either permutation or combination the answer will be same .....
@lastchance81422 ай бұрын
@@mr.Anand_kr correct. Answered my own question 4Y ago...LOL
@mr.Anand_kr2 ай бұрын
@@lastchance8142 😄😄😂😂
@samamaya80432 жыл бұрын
Thank you so much! Your explanation was very clear and helped me understand permutations much better.
@meghakanchan28112 жыл бұрын
I am so lucky ki mujhe video on KZbin aapki Mili I can't tell you kitna sara confusion dur hua h thanks sir😁
@MathematicsTutor2 жыл бұрын
Here is related Playlist for you: kzbin.info/www/bejne/ppizdId_jLKKfc0 Let me know if that helps. Thanks
@lastchance81425 жыл бұрын
Ok, so I'm going to answer my own question. For the S's, the order doesn't matter because it looks the same no matter which S is placed in any of the eight places. Therefore it is correct to say 8C4. It is equivalent to dividing 8P4 by the 4! repeats of S.
@shaanautotools66054 жыл бұрын
Thanks for answering that ! I had the same doubt !
@as.i.am_121 Жыл бұрын
Hello. I was watching your video. How do the combination play a role in filling up the gaps . Help me understand
@priyabhalla902 жыл бұрын
When to take permutations and when to take combinations. In one of the question, you had taken permutations for the different spaces to be filled and here you have taken combinations.
@MathematicsTutor2 жыл бұрын
When and how to use Permutation: kzbin.info/www/bejne/r6nZqoFrp5KqrtU Hope that helps. Thanks
@golang23513 жыл бұрын
I have a doubt sir..why we devide the common arrangements from total arrangements instead of substract them
@jrrj9402 жыл бұрын
Me too 🧐
@mridulgoinka3239 Жыл бұрын
sir in part b it can also be possible that 2s or 3s are together , as question does not say that all s are together
@Pratibha-fb3nn3 жыл бұрын
Awsome explanation ✌✌
@Bollyking19882 жыл бұрын
Well done sir, please do video on this type of logarithm question: 4.664³+6 all divided by 4.664³-6 The question says: Evaluate without using calculator.
@MathematicsTutor2 жыл бұрын
Thanks. Will do
@sagarvanave6 жыл бұрын
Thank you so much sir. Lecture was very good thank you once again😇
@morengothemoringapeople7 ай бұрын
Thank you for your videos. I'm looking at coming up with names of products by combining words. Is there a software that would offer all these permutations and combinations please
@MathematicsTutor7 ай бұрын
Good idea. Thanks
@MathematicsTutor7 ай бұрын
I can share a related Playlist: kzbin.info/www/bejne/poW7fnymbsSEqMU All the Best
@medievalchallenges52463 жыл бұрын
Hi sir can you tell me in how many different 4 letter words can be formed from ellipse
@CatherineMwenda-s6p4 ай бұрын
Thank you so much sir this has really helped ☺
@lalintuguic5613 жыл бұрын
pacing is just right
@fasihullisan30669 ай бұрын
in part B ,do we not take the arrangement of s with itself?
@lalintuguic5613 жыл бұрын
what if either of the all the I's are consecutive or all the S are cosecutive or all P's are consecutive sir
@surens17305 жыл бұрын
Thanks for explanation
@pimmipatel.2124 Жыл бұрын
helpful
@abaegbuemmanuel65453 жыл бұрын
Please am confused for your video on correction where the vowels are together you ooie where together you did did 4 factori over two factorial why not here
@rv0_05 жыл бұрын
this is permutation not combination
@b-shahdarshb26123 ай бұрын
The last one I am not able to understand properly, as well as not getting correct solution ( i.e Ans ). 🤔
@MathematicsTutor3 ай бұрын
Last another Approach: kzbin.info/www/bejne/d5PFdKKOg9ash5o Hope that helps. Thanks
@MathematicsTutor3 ай бұрын
also no boys together: kzbin.info/www/bejne/p3bMkqqEbK5mlbs
@b-shahdarshb26123 ай бұрын
Respected sir, this is because in the word CLASS we had only one repeating letter 'S'. While in the word MISSISSAUGA we have 2 repetitions i.e 2 A's and 2 I's and therefore we have divided by 2!×2!. Thank you sir so much. 🙏🙏🙏🙏🙏
@b-shahdarshb26123 ай бұрын
If we try to to calculate for the word MISSISSAUGA by old method ( i. e total no. of arrangements less no. of arrangements in which S's are together ) correct ans is not being received :- 11!/ 4!×2!×2!= 415800 S's together= 8!/ 2!×2! = 10080 And 415800-10080= 405720, while the correct ans is 88200. What' s the reason ?? How to calculate for the word Mississauga By old method ????
@b-shahdarshb26123 ай бұрын
I am understanding the new method but not getting answer for the word 'MISSISSAUGA' by old method. 😔😔😔
@domalapallivinesh62133 жыл бұрын
Find the no. Of arrangements of the letter in TALLAHASSEE which have no adjacent A's. Answer pls sir
@vibhashukla75185 жыл бұрын
Hi Dr Kumar, I will appreciate your help in solving the following problem- "When all the letters in T,E,N,N,E,E,S,S,E,E are arranged.(i) what is the probability that an arrangement starts from TEN? (ii) also starts from TEN and ends with SEE? " Thanks for your time
@Webster4554 жыл бұрын
No
@majestic77683 жыл бұрын
The last one is tricky.
@shashankpandey19666 жыл бұрын
Thnku sir
@silentlipzz27233 жыл бұрын
Tnku sir
@RitvikPathak-t7z3 ай бұрын
Wrong solution Wrong combination It will be 4C8 not 8C4 Hence it cannot be applied here Answer will be 33810