Comparing linear rates word problems : Khan Academy

[@nancysmith2449]

Thank you. I just saw a word problem on Khan academy's site that threw me into cold shiver. It literally is like a mathematical voodoo, with the teacher going from simple equations to linear equations and word problems with no formulas or explanations whatsoever. It brought me to tears. Thank you for taking the time to break it down. And bring some hope .... I really do appreciate your help.

[@khanmanmath3810]

That is great (other than the tears part). If you have any questions or requests, please let me know.

[@ASTRONAUTGORP]

lmao had the same issue and this vid helped a ton!

[@khanmanmath3810]

@@ASTRONAUTGORP That is awesome! Thanks for the kind words.

[@azgaming9291]

this is actually so simple bro thank you so much! i was here thinking this was so much more difficult but its actually fairly easy.

[@khanmanmath3810]

That is great news! Glad you worked it out.

[@blueice999uk]

Doing the Khan Academy course, Algebra one 'Comparing linear rates word problems,' spooked me and some people out according to the Khan comments. Looking through the lens D=R*T , I can now transfer the wording into something that I understand.

[@khanmanmath3810]

That is great news.

[@v-reads]

This was so helpful! You're a great teacher

[@khanmanmath3810]

Great to hear! Thanks.

[@Mandy_Wiles]

Thank you so much! I was struggling a lot with this and it took me a bit to get the hang of it after watching your video, but I just got all four questions right in two lessons! Your videos have truly given me so much hope for accomplishing my goals despite my dyscalculia!

[@khanmanmath3810]

That's fantastic! I was hoping I made the video clear enough. If you can through those types of problems, you're doing very well.

[@fld0389]

Super annoyed. I'm doing the kahn academy college algebra and it didn't state this formula d=rt It just jumped into problems about dragons etc, and then problems to work out on your own. Thanks for making this video

[@khanmanmath3810]

You're welcome and I'm glad it helped! I don't know if the d = rt formula is how other teachers cover it. That is just how my mind sees it.

[@azgaming9291]

lol im doing algebra one right now is that really college level because im stuck on the same dragon thing

[@MalefiicusSTR]

@@azgaming9291 I think I speak for all of us when I say, fuck that dragon!

[@azgaming9291]

@@MalefiicusSTR Amen, brother!

[@lm_____cali]

I'm doing algebra 1 courses on there and it does show d = rt in unit 1 (I'm also on the dragon problem haha)

[@obsessed92]

You sound like you want to beat my ass while teaching but thanks to you I understand the topic much better now. Thank you ! 😀

[@khanmanmath3810]

Really? Why is that? Anyhow, I'm glad the video helped! Thanks for the kind words.

[@dogtooth32]

literally made me understand everything

[@khanmanmath3810]

That is great news!

[@goosestrangler6420]

thank you! You explained this much better than khan academy did, they just kinda jumped into it. I will be referring to you from now on when i am having trouble.

[@khanmanmath3810]

That is great news! Thanks for watching.

[@jehriko7525]

you're telling me I'm only just now realizing/learning it's as simple as distance = rate*time????!?!! Thank you lol

[@khanmanmath3810]

No problem. Glad it worked for you!

[@JustinUrban1]

Wow this cleared everything up for me. My brain just wasn’t grasping this on Khan’s website for some reason

[@khanmanmath3810]

Glad you worked it out.

[@Kenjitsyu]

thanks a lot bro I am dying right now trying to learn this stuff.

[@khanmanmath3810]

You got it man! Hope it helped.

[@EnniodBleu]

@Kahnmanmath3810 I'm having a problem with this question on Kahn Academy: Jaquan passed a checkpoint jogging at a constant speed of 9km/hour. Then, 2 minutes later, Odalis passed the same checkpoint. If Odalis runs at a constant speed of 12km/hour , then how far past the checkpoint will Odalis be when they catch up to Jaquan? Distance = ? I am having trouble formulating the equation. How do I solve for distance when there is a 2minute offset?

[@khanmanmath3810]

Great question! Let's say the checkpoint distance = 0. When Odalis catches up to Jaquan, their distances are the same (equal). So d = d in both cases. Since d = rt, we can set rt = rt. For Jaquan, r = 9 and time = t. For Odalis, r = 12 and time = t - 2. 9t = 12(t - 2) Solve for t (should get 8), and plug in to either d = rt equations (should get 72).

[@EnniodBleu]

@@khanmanmath3810 Thank you for answering my question. Your instructions, they seem to make sense as I wrote it out, as that is a simple enough equation, but the answer ,8 ,back into distance= rate*time = 72km, is incorrect!? Apparently it is supposed to be 1.2km according to the KA step-by-step for this question but I don't understand their workings. I am so confused...

[@khanmanmath3810]

@@EnniodBleu I'm sorry. I mismatched the units. If the rate is in km/hr , then t has to be in hours. 2 minutes = 2/60 hours For Jaquan, r = 9 and time = t. For Odalis, r = 12 and time = t - 2/60 9t = 12(t - 2/60) Solve for t (should get 2/15), and plug in to either d = rt equations (should get 1.2).

[@khanmanmath3810]

@@EnniodBleu I'm sorry. I mismatched the units. If the rate is in km/hr , then t has to be in hours. 2 minutes = 2/60 hours For Jaquan, r = 9 and time = t. For Odalis, r = 12 and time = t - 2/60 9t = 12(t - 2/60) Solve for t (should get 2/15), and plug in to either d = rt equations (should get 1.2).

[@darkofthunder34]

12:27 why is it not 13T + 9.5T? The total cost is 13 + 9.5 right?

[@khanmanmath3810]

She *makes* 13 dollars per shirt, but she *spends* 9.50 per shirt. To find the profit, you have to subtract what you spend from what you make. If I buy a car for $100, and sell it for $200, what is the profit? 200 minus 100.

[@YoanGonzalez-yr2rf]

You are a God

[@iivniki]

you just gained a new subscriber. the downside of khan academy is that it always jumps on practice questions without even talking about the overview context of the lessons, formulas, and key points. we have to do it by ourselves. it shouldn't be a problem, only i'm a little bit dumb so i'm stuck. thank you sir !!

[@khanmanmath3810]

You're very welcome! Thanks for the kind words and advice.

[@elishuuujjj]

Thank you!😄

[@khanmanmath3810]

No problem. Thanks for watching!

[@1707EYES]

Thank you so much man! This problem pissed me off but your video is very helped!!!

[@khanmanmath3810]

You got it! Glad you worked it out.

[@Katellx]

Thanks for this, the simplified formula in 3:51 helped a lot. I realized I could actually use variants of this formula to solve the rest of the equations. ex: for the beads and cm questions I did: 306 - 40s = 210 - 24s (s representing segments) Since the solution wanted cm, I multiplied the solution for segments by 5 to find the answer.

[@khanmanmath3810]

You're welcome. Glad you worked it out!

[@socorrespecial]

thank you bro i'm still having trouble but this helped

[@khanmanmath3810]

You got it man! If you have a question, let me know.

[@damienjones1487]

Thanks a ton, i forgot d=r×t. Made these problems very simple

[@khanmanmath3810]

No prob. Glad it helped.

[@fatmamafrahamn]

youre amazing i love u youre so amazing thank u thank u thank u love u ur amazing have a great day

[@khanmanmath3810]

Thanks for the kind words.

[@YoanGonzalez-yr2rf]

Thanks a lot

[@khanmanmath3810]

Glad I could help.

[@AaravGupta-hx9lk]

Thx so much... EDIT: u explained it better than Sal himself.

[@khanmanmath3810]

You're welcome.

[@inferno3345]

❤

[@gwennnnnnnnnnnn]

what

[@thatboy799]

I love khan academy but jeez the video lesson on this is horrible. Thanks

[@khanmanmath3810]

Glad you worked it out!