Computing Laplace Transforms (Using the Integral Definition)

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Houston Math Prep

Houston Math Prep

Күн бұрын

Пікірлер: 9
@earthworm02
@earthworm02 4 жыл бұрын
I feel lucky that I've found you! Thanks a lot for your lectures.
@HoustonMathPrep
@HoustonMathPrep 4 жыл бұрын
Thank you for sharing your kind words and support! You are welcome :)
@kavyarayidi1839
@kavyarayidi1839 4 жыл бұрын
You have really helped me a lot If I score well this semester, it's all thanks to you!!!!!!!!!!!!!❤💕
@HoustonMathPrep
@HoustonMathPrep 4 жыл бұрын
Happy to help!
@turbothrottletrouble4217
@turbothrottletrouble4217 4 жыл бұрын
I just love your videos. These will probably prepare me for my electrical and electronic engineering course
@HoustonMathPrep
@HoustonMathPrep 4 жыл бұрын
Really glad you like them and they are helping you! Good luck with your course :)
@curtpiazza1688
@curtpiazza1688 Жыл бұрын
Great examples. Thanx for covering this topic using limits! Very informative! 😊
@lynou-cats
@lynou-cats 3 жыл бұрын
I'm sorry for this debutant question but I must ask : at 3:42, how come v = (-1/s)*e^(-st) ? I'm trying to wrap my head around the (-1/s) : for me the antiderivative of e^(-st), following the de^(u) = e^(u)*u' rule, would be -s*e^(-st).. I don't understand. Would someone be patient enough to explain it to me?
@HoustonMathPrep
@HoustonMathPrep 3 жыл бұрын
Hello! Remember that for the derivative of e^(-st), the chain rule tells us that the constant multiple "-s" would multiply the exponential. Since this is the antiderivative, the answer would have us dividing by the "-s" multiple, or you can think of it as multiplying by the reciprocal if you like. That's where we get the -1/s.
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