At 4:27, there is a typo. The acceleration should be negative in that step, since we picked up to be positive. However, the next step is correct and this does not affect the final answer.
@eksp.13 жыл бұрын
This deserves a million views. Thanks a lot, Sir!
@QuestionSolutions3 жыл бұрын
You're very welcome!
@aidenbrown72007 ай бұрын
You are by far the best dynamics online instructor I've found! your videos are simple to understand and tackle some hard problems. PLEASE keep up the great work you're amazing!!
@QuestionSolutions7 ай бұрын
Thank you very much for your kind comment. I really appreciate it. I wish you the best with your studies and to you also, keep up the great work!
@joshuacharlery58264 жыл бұрын
I finished Dynamics! This channel did help me!
@QuestionSolutions4 жыл бұрын
I am really glad to hear that. Well done with your Dynamics class!
@jaycivandehey144 жыл бұрын
This is my favorite channel to prepare for exams! Please do lots more example videos on work, conservation of energy, and impulse and momentum
@QuestionSolutions4 жыл бұрын
I am really glad to hear that. I hope your exams go well! :)
@jadkhalil92633 жыл бұрын
I am almost done my first year of engineering and would like to thank you for getting me through dynamics :D
@QuestionSolutions3 жыл бұрын
That's awesome to hear! I wish you the best on your upcoming years, may success follow you everywhere. :D
@abdallababikir91543 жыл бұрын
same here
@jadkhalil92633 жыл бұрын
@@abdallababikir9154 isn't it the greatest felling in the world first year is very rough
@KwetsimaChauke-bo8ww7 күн бұрын
@@jadkhalil9263 hey, so are you done now??😭😭
@Tund_2 ай бұрын
For question 2, if anyone finds it challenging to identify the integrals, I found that using the work-energy method is more intuitive. It avoids dealing with integrals and is simplified as: 1/2(Ma+Mb)(v)^2 - (N)(k)(s) = 0 and solve for s
@QuestionSolutionsАй бұрын
👍
@exotic50353 жыл бұрын
The work that is done on these video is unreal, keep it up :)
@QuestionSolutions3 жыл бұрын
Many thanks :)
@vn81622 жыл бұрын
@4:27 when you calculate the normal force N, you said that upwards was positive so I think the equation would have been N(t) - 9.81(2.02)(t) = 0.
@QuestionSolutions2 жыл бұрын
Yes! Good catch, it's a typo. 😅
@justinbeck5602 жыл бұрын
@@QuestionSolutions you should mention that in the title just because.
@QuestionSolutions2 жыл бұрын
@@justinbeck560 I pinned a comment saying it in case anyone was wondering.
@thenellecornejo37243 жыл бұрын
this is so clear and helpful, thank you!
@QuestionSolutions3 жыл бұрын
You're very welcome!
@r2k31411 ай бұрын
On the last problem at 7:25, I think it should be V a/b because we know from B's perspective A moved .5 meters. We don't know yet what b/a is. If we get it wrong in a case would it make a difference if we keep our signs correct? I can't figure that out. Thanks for your hard work.
@QuestionSolutions11 ай бұрын
Did you see this video first? kzbin.info/www/bejne/paG5fIF5msmeiNE The whole answer will change if you use a/b vs b/a. It's very important you distinguish which you use because the equation changes based on it. If you have the time, please watch that video.
@Ankit-135715 күн бұрын
hey guys In 2:56 question, if you use work energy principle then it will be far more easier. T1+U=T2 (;T2=0) we have all value except the distance traveled, easy! Also thanks to you I can pass my dynamic exam.
@QuestionSolutions15 күн бұрын
A lot of these questions can be solved in more than one way. I only show case a single method, usually one pertaining to a chapter. Best wishes with your dynamics exam! :)
@wilordsanmiguel75163 жыл бұрын
thanks a lot for this video, GOD Bless
@QuestionSolutions3 жыл бұрын
You're very welcome!
@BhrweBhrwe7 ай бұрын
love to watch your videos thankyou for creating such a nice content for students that struggling in their studies hope to see more videos like these thankyou buddy again
@QuestionSolutions7 ай бұрын
You're very welcome, and thank you for taking the time to write a nice comment like this. I appreciate it and I wish you the best with your studies.
@NzamurambahoJd-r8p18 күн бұрын
can you solve that question A5kg mass moving with velocity 10m/s collides with 10kg mass moving with velocity of 7m/s along the same line . if the two masses join together on impact find their common velocity if they were moving a) in opposite direction b)in the same direction
@QuestionSolutions18 күн бұрын
Sorry but I don't solve questions like this because then I have to solve everyone's questions and it's not doable :( Please ask your professors/TAs during their office hours. You can also ask on forums for help.
@michaelsedillo4723 Жыл бұрын
For problem 2, using linear impulse and momentum, would it be correct if you instead did s=integral (t to 0) 3.196-1.962t dt? And then set s=0 and solve for time? Or would you have to find the bounds of integration for time?
@QuestionSolutions Жыл бұрын
You need the bounds of the integral to solve the problem. Otherwise, you will have final distance as a variable and final time as a variable.
@sakn415 Жыл бұрын
For the bullet block problem. wouldn't it be much easier to use work energy principle?
@QuestionSolutions Жыл бұрын
You can use any method you like. You can get the answer to these problems in so many different ways. I just showcase a single method per video. :)
@aidenbrown72007 ай бұрын
I paused the video and solved it that way and got exactly 3.996m and then played it and saw he did something else and it scared me XD then he got the same answer as I did! i was looking for somebody who also did this and it looks like i found you. good thought!
@mebawubeshet67294 ай бұрын
@@aidenbrown7200 how do u solve it. what do u use for the intial kinetic , the friction forcse
@Tund_2 ай бұрын
@@mebawubeshet6729 For question 2, if anyone finds it challenging to identify the integrals, I found that using the work-energy method is more intuitive. It avoids dealing with integrals and is simplified as: v = 3.9604 as solved for in part 1 1/2(Ma+Mb)(v)^2 - (N)(k)(s) = 0 and solve for s
@alaukwuanozie14153 жыл бұрын
Thanks so much for posting these! A question about the second question. I used the equations of motion in y to find the Frictional force, then I used them again in x to find acceleration. Plugged it into the kinematic equation a ds = v dv, integrated and solved. I got the correct answer but I was wondering if it's another valid method or just a fluke. Thanks again!
@QuestionSolutions3 жыл бұрын
More often than not, there is more than one way to solve a problem. You used kinematics to solve the problem, which works as well. Try to solve it in both ways so you learn the new concepts as well :)
@ElCrankoPunko3 жыл бұрын
yup got the same. You have done correctly
@d7ooomymc3463 жыл бұрын
On first thought, I thought about using conservation of energy and that also worked well👍🏻
@JyotiSingh-on4ml3 жыл бұрын
Very nice pedagogy and all concepts in a nutshell
@QuestionSolutions3 жыл бұрын
Many thanks!
@michellamarj8537 Жыл бұрын
Hello, I don't get why in the first example, we applied conservation of energy on the system of particles (car A and B) and not only on A. Doesn't the spring become an internal force? In other examples like this, we only applied conservation of energy on the car with the spring attached on it. How do we know when to do that? Also, when does max compression occur in this example? does it stay compressed to the max even after the collision?
@QuestionSolutions Жыл бұрын
I can't answer your question since I don't know what other examples you are referring to. It might be different, or you used a different method at getting the answer. There are usually more than one way of getting to same answer so it's hard to say, and if you get the same answer, then your method is also just as valid as what's shown here. I only showcase a single method. For max compression, the train will couple when it hits another car, and the spring will stay constantly compressed due to the coupling, which is why they both have the same velocity after they have the impact. I show this at 0:52 :)
@viralcat-w4x3 жыл бұрын
3:43 We can also determine the distance using energy method right? Rather than determining the time (t).
@QuestionSolutions3 жыл бұрын
You can solve these questions in more than one way, sometimes, it might even be easier/faster to use another method, I just show this method because it pertains to the topic we are talking about. 😅
@userutoob72 жыл бұрын
Thanks for your great videos. Note that after I calculated v = 3.96 m/s (as you did), I then applied the following simple suvat equation to determine the stopping distance: final velocity squared = initial velocity squared + 2*acceleration (negative, due to the friction force)*s. Note final velocity squared = 0. My answer is 4.036 m, which is very close to your answer of 3.996 m. It looks like my method is simpler and quicker in this case. Was I correct in applying this formula, or was it a coincidence that I got the correct answer (or one very close to the correct answer)?
@QuestionSolutions2 жыл бұрын
There is usually multiple ways to get to the same answer, I only showcase what's pertaining to a certain chapter. But in general, there are tons of ways to get to it. 👍
@captain_ali_012 жыл бұрын
I did the same method as you did and got 3.996m. I think you rounded off the acceleration too much.. I used a = -1.962
@slimlady99233 жыл бұрын
hi really helpful big thanks...but i have i question when we use (linear impulse and momentum or conservation of energy or others) cuz i really confused.
@QuestionSolutions3 жыл бұрын
If you look at the 2 equations given, you can see when to use it. Impulse has to do with time, so if time is given, you can use it with an equation of linear impulse and momentum. If it's just velocity and mass, you can use conservation of momentum. 👍 The more questions you do for each topic, the faster you will realize which equations to use in what situations :)
@slimlady99233 жыл бұрын
@@QuestionSolutions really thx...im sorry ,but I'm going ask another question (in the example number 2 there is no time?) it just masses ,velocities and foresees...and you used linear impulse and momentum thank you
@QuestionSolutions3 жыл бұрын
@@slimlady9923 Don't be sorry about asking questions, the more you ask, the more you learn. I was able to use impulse and momentum because time would get cancelled out. So notice how I started off with a conservation of energy equation because we had mass and velocity. After that, we still didn't get the answer we need, so we then switch to a linear impulse and momentum equation. You can also notice that we are looking for distance, and distance is related to speed, which is related to time. So you sort of have to work through these steps in your mind and see what can be done. Even if you take the wrong path, you will see that you're not getting the value you need, so you can retrace your steps and come back to an equation that works. In more advanced problems, you will definitely have to use both to get to an answer. This is just a tip, and in no way a solid factor, but in most final exams, the questions your professor will create will require you to use at least 2 of the main equations, if not more to arrive at an answer.
@slimlady99233 жыл бұрын
@@QuestionSolutions thanks and sorry again , wish me luck i have an exam
@QuestionSolutions3 жыл бұрын
@@slimlady9923 Really, you don't have to be sorry for asking questions. Feel free to ask, and I'll do my best to explain. I wish you the best of luck with your exam! 👍
@milkman589410 ай бұрын
Why is S_B/A in the last example 0.5 m, isn't that S_A because it originated from 0.5 m away from point O? I'm having trouble visualizing what the 0.5 m means in the diagram, it looks like it means the width of the triangle B. Thanks
@QuestionSolutions10 ай бұрын
So an easier way to think about it is to imagine the origin at block A. In that case, block B "moves" 0.5 m. It's really just the difference in the starting points of A and B, hence B/A.
@joaobrites59313 жыл бұрын
Hello. once again a excellent video. I have a question: in the last problem, could we say that the normal force exerted by B in A as a contrary force exerted by A in B, because of newtons third law? and thus we would apply the similarity of triangles and discover the X component of this force. then we would find out that that component is in fact the total force aplied in B ( the forces in Y axis cancel), therefore we would need to calculate the distance A did ( by applying trignometry ) and with the kinematics equations for A discover the time it took A to reach the end. With that value of time and the value for acceleration of B ( applying newtons second law, we have the total force and the mass) we plug in the values in the kinematics equations for B and discover the distance he covered in the X axis in that time period. The problem is, if you do so, you get a absurd value of 2.02m. what did i do wrong?? Thank you and keep up with the great job.
@QuestionSolutions3 жыл бұрын
That seems like a lot of steps to get to this answer, doesn't it? I mean was your method faster? I have no idea 😅 Again, I don't know what you did wrong without seeing your steps :) With this method, I think you can solve the problem easier and faster than going through a lot of trigonometry and all the other parts you did. Though I do like how you always try to solve the questions in different ways, since there is always more than 1 way to solve them. The only problem is that sometimes, there aren't enough values given, or some just don't help out.
@joaobrites59313 жыл бұрын
@@QuestionSolutions they were indeed a lot of steps... i suppose your method is much better but i did not see it crystal clear at first.. nevertheless i continue to be confused on what i did wrong, because something must be wrong with my way of thinking.. i dont know how i could show you just like i said in the other comment. but thank you a lot!
@allaberdishamadov42872 жыл бұрын
Thanks you for huge inf video you made sir.
@QuestionSolutions2 жыл бұрын
You're very welcome!
@siddhirajput3142 жыл бұрын
I never really comment but Damn! This is perfect, I was searching for this kinda channel , thankyou for clearing all our doubts! Loads of love ❤️❤️❤️❤️❤️
@QuestionSolutions2 жыл бұрын
I am glad to hear this was helpful. I hope all of the videos help you out and wish you the best with your studies! ❤
@runejanssens76819 ай бұрын
In the last example, why is the small box’s velocity pointed tot the left? And not pointed in the direction of the 30 degree plain? I find it difficult to see that.
@QuestionSolutions9 ай бұрын
Take note of the notations used. It shows V_Ax, which represents the x-component of the velocity, which will be parallel to the x-axis, in this case, the grey base.
@Robtmmartine773 жыл бұрын
For finding the distance on the second part of the problem can't you just use the principle of work and energy which is easier than first finding t. I did that and got 4.03m which is the same answer.
@QuestionSolutions3 жыл бұрын
You can use many different methods to arrive at the answer. I just use the methods pertaining to the topic. There are many ways to get to the same answer with these problems, some are much easier than others, some take the long route, but I try to stick to whatever is relating to a chapter, otherwise, it's sort of pointless to do a video on that topic 😅
@Robtmmartine773 жыл бұрын
@@QuestionSolutions true. Thanks for these videos. They are great. Im using them to study for the FE.
@QuestionSolutions3 жыл бұрын
@@Robtmmartine77 You're welcome, I wish you the best!
@EngSereneJibreen3 жыл бұрын
thank U soooo much
@QuestionSolutions3 жыл бұрын
You are very welcomeeee.
@qusiaamer6931 Жыл бұрын
Bro , really you are so amazing thank you ❤
@QuestionSolutions Жыл бұрын
You're very welcome! ❤
@saiprasadsatya36772 жыл бұрын
Please make videos on complex streeses
@QuestionSolutions2 жыл бұрын
Normally, complex stresses aren't covered in 1st year courses, so I didn't make a video on it. But I will keep it in mind for the future.
@saiprasadsatya36772 жыл бұрын
@@QuestionSolutions thank you,and your explanation is great
@e-nes40422 жыл бұрын
why did we use linear ımpulse and momentum equation at 4.25 question. why didnt we use t1+v1 = t2+v2 ? how will we distinguish?
@QuestionSolutions2 жыл бұрын
You can solve these questions anyway you like, but this video is about linear momentum, so that's what's shown here. Usually, if time is given, it's going to involve impulse.
@najibnassiri70424 жыл бұрын
Is it be possible in the last question to find the speed of B when the box reaches the ground? If yes. how is it possible? Thank you
@QuestionSolutions4 жыл бұрын
Yes, it's possible, along with the equation already shown on the video, you'll need one more, an equation of work and energy, or conservation of energy. Because right now, we only have 1 equation with 2 unknowns. That should allow you to find the speed of B when the box reaches the ground.
@clearflow792511 ай бұрын
2:08 if this is an inelastic collision, why do we use the conservation of energy if energy isn't conserved in an inelastic collision?
@QuestionSolutions11 ай бұрын
You are confusing different topics together. When you need the coefficient of restitution, then you will need to use that equation. Here, it's only the conservation of energy, so in this topic, we are excluding things like noise, heat, friction...
@vigneshwaranrm62772 жыл бұрын
@7:14 why can't we proceed by conservation of energy change in potential energy of block A = change in K.E of block B + change in K.E of block A ??
@QuestionSolutions2 жыл бұрын
Did you try it with that method? So the goal in this video is to use conservation of linear momentum, which is what I showcase. But you can use any method you like to get to an answer, since there are multiple ways to solving the same problem.
@vigneshwaranrm62772 жыл бұрын
@@QuestionSolutions yes but there is variation in ans...i am getting 0.095m according to your solution it is 0.07m.
@QuestionSolutions2 жыл бұрын
@@vigneshwaranrm6277 Then I am thinking maybe there is a numerical error or a part is missing on your equation? I am not sure, it's hard to say since I didn't solve it with conservation of energy. 😅 See your professor during office hours and show him your method so he can check over your work.
@WOLFEARO3 жыл бұрын
Thanks
@QuestionSolutions3 жыл бұрын
You're very welcome!
@jayvenlarsen3689 Жыл бұрын
What would change if there was friction in between A and B?
@QuestionSolutions Жыл бұрын
Please give me a timestamp so I know where you're referring to. Thanks!
@jayvenlarsen3689 Жыл бұрын
@@QuestionSolutions No need anymore, I just finished the class!
@malyarfeyzullah7492 ай бұрын
Wouldn't it be easier to solve the second question using the work energy equations after finding N , since it directly provides the horizontal displacment.
@QuestionSolutionsАй бұрын
You can solve these problems in so many ways and get to the same answer 👍
@vikramnagarjuna35494 жыл бұрын
Great
@QuestionSolutions4 жыл бұрын
Thanks!
@ziyadgames53403 жыл бұрын
4:16 in the y-direction why weight is not negative?
@QuestionSolutions3 жыл бұрын
It should be negative, good catch, it's a typo :)
@ElCrankoPunko3 жыл бұрын
solved the second question using conservation of momentum & then work energy principle got the same distance
@QuestionSolutions3 жыл бұрын
You can use many different methods to arrive at the same answer. 👍
@ElCrankoPunko3 жыл бұрын
@@QuestionSolutions yea true. thanks for the reply, great videos & content tbh
@QuestionSolutions3 жыл бұрын
@@ElCrankoPunko You're very welcome!
@hermionegranger97423 жыл бұрын
nice explanation (:
@QuestionSolutions3 жыл бұрын
Many thanks!
@deyardeyar81633 жыл бұрын
why we did not put zero for velocity directly at 4:59
@QuestionSolutions3 жыл бұрын
We needed to find the velocity time equation to figure out the distance travelled in the next step.
@deyardeyar81633 жыл бұрын
Thanks a lot sir
@QuestionSolutions3 жыл бұрын
@@deyardeyar8163 You're very welcome!
@uvanistedy28403 жыл бұрын
good
@QuestionSolutions3 жыл бұрын
👍👍👍👍
@迪安-z6i Жыл бұрын
7:40 why is S B/A= 0.5? Isn’t that the displacement of B with respect to A? Why isn’t it 0.5+SB?
@QuestionSolutions Жыл бұрын
So we are only interested in the relative displacement, so in other words, where "A" is with respect to "B". Another way to think about it is to realize that in the horizontal plane, "A" moves 0.5m when it slides down to the bottom.
@迪安-z6i Жыл бұрын
Ohhhhh that makes sense. Thank you for your help!
@QuestionSolutions Жыл бұрын
@@迪安-z6i You're very welcome!
@clearflow792511 ай бұрын
4:44 why is the force of the bullet not in this equation?
@QuestionSolutions11 ай бұрын
What do you mean by force here? Are you referring to energy instead? Work?
@clearflow792511 ай бұрын
@@QuestionSolutions like friction has a force in the principle equation but the force applied by the bullet isn’t in the equation. I’m assuming it’s because this moment is already after the impact
@germananibalmendezmerchan3924 ай бұрын
Hi, mmm what is the text?
@QuestionSolutions4 ай бұрын
Any book used is always listed in the description.