Continuous, Discontinuous, and Piecewise Functions

[@rik9833]

Your intro and outro reminds me of some old educational cartoon I use to watch when I didn't go to school as a child. I love that vibe

[@yogeshdharshan9588]

Your intro song was soo funny, it's like retro cartoon song

[@amjadhossain4901]

You are one of the best mathematics teachers l have seen ever. Your videos are too helpful for the students like us.We get immense help from your videos.These videos make our topics quite easier.Carry on.

[@PeakOfPeace]

There is a lot of intensity in your voice, your words directly go into my head.😄

[@Alpha-bz6ke]

Great tutorial. I completely understood continuous and discontinuous with just one explanation.

[@eternal___official]

2:45 - so... (x^2-1)/x-1 = x-1 but x cannot equal 1 for the first case but CAN be 1 for the second case of function. Wouldn't that mean that we are "wrong" when we say (x^2-1)/x-1 = x-1??? i'm confused...

[@karam3045]

Never seen a better teacher

[@CartoonKidOLLY]

3:05 that was totally you scratching your beard

[@Meowhoraga420]

😩

[@YG-yg-rz]

😂😂omg I love how you guys pay attention to such things

[@a.danielking5397]

10/10 for quiz music. Spot on with the content, too.

[@longlostwraith5106]

Sorry professor, but I disagree with 2:55 . 0/0 is not undefined, it is indeterminate. Not the same. 0/0 can actually be anything we want, as any real number can be the solution to the equation "0x = 0". Therefore, since "(x-1)/(x-1)" CAN be 1 for all real values including 1, it can be safely simplified without having to exclude 1. If I'm wrong and you have the time to explain this to me, please do.

[@manaarikicarpentier6038]

Nope, you can't do 0/0 simply because you can't divide by 0 because this implies that 0 has an inverse which is false. Because if there's an x such that 0x = 1 that's absurde because for all x, 0x = 0. so for all x, x/0 is undefined in particular, 0/0 is undefined. We talk about indeterminate when we are dealing with limits (which we were not in this case)

[@longlostwraith5106]

@@manaarikicarpentier6038 No, sorry, you are utterly wrong about this.

[@manaarikicarpentier6038]

@@longlostwraith5106 why?

[@longlostwraith5106]

@@manaarikicarpentier6038 Because "0x = 1" and "0x = 0" are two completely different beasts. In the first one, "x" can't be any real number. In the second one, "x" can be any real number you want it to be.

[@manaarikicarpentier6038]

@@longlostwraith5106 exactly, you can't find any x such that 0x=1 so 0 isn't inversible thus you can't divide by 0

[@tino_]

MR PROFESSOR DAVE THANK YOU SO MUCH I DONT KNOW WHAT I WOULDVE DONE IF IT WERENT FOR YOU THANK YOU AGAIN

[@mubeenkhan6131]

Sir please make a lecture on how a discontinuous function is converted into a continuous function with the use of unit step function.

[@nikocvitanic7701]

bro that's about as simple as it gets. you're a fucgggging G

[@physics_enthusiast_Soorya]

Any function with a vertical asymptote must be a "Continuous" function, according to my textbooks.. My teacher told me that they will never meet, but that doesn't mean there's a gap, they'll meet at infinity.

[@algorithme1950]

Yes this videos is wrong

[@WeSoldOurLives]

Thank you professor Dave!

[@ummahyehmmm7403]

Thanks for saving me again!

[@Stoirelius]

At 3:00 how would I know 1 is not a value if I was just seeing the simplified function of x +1??

[@ummehabibahappy2161]

if we put value 1 for x then it will undefined that's why here 1 cant be the value of x..

[@heydrianluisanilao1757]

Then x + 1 is the only thing you have to be concerned about

[@mansanasmdelf0759]

Thabk you so much!!! This helps me a lot

[@leetoka2292]

Thank you professor dave! Liked and subbed

[@ThWRizzler]

W you remind me of my younger days in elementary school but for harder math!

[@beyondartists7641]

Well detailed explanation. Wasted 3 hr trying to understand my professor 😒

[@anmolkotiyal6272]

The way he Explains.... Like puts effort in his voice..... I get it Totally.... Humble guy 😄

[@lunes-1]

📚great video,keep it up!

[@alburnto]

Dave, isn't the function 1 / x - 1 not graphed as it should be? For example, if you plug x = 2, y gives back 1, and the coordinate (2, 1) is not in the curve.

[@ProfessorDaveExplains]

hmm yeah it's not perfect, the asymptotes are correct but it's not a flawless representation. i don't really have a way to get the curves perfect as i just paste them together from a stock image of a parabola or something, please excuse the approximation!

[@alburnto]

@@ProfessorDaveExplains totally excusable :) Thanks for your work!

[@ashutoshtiwari3785]

@@ProfessorDaveExplains You should use Manim if you know Python for visualisations.

[@atullizard5219]

2:17 can this function be called piecewise function?

[@vardhan5939]

Very helpful for jee aspirants 🤘

[@bryanjaviercancejo]

Thank you Sirrrr

[@psstudycentre5568]

Superb sir... I understood in a easy way.. 😇

[@AlessandroZir]

thank you!! very clear and intuitive; you do know how to teach;

[@WilhemHohenzollen]

i mean f(x)=5 when x

[@abdurrahmansembiring5862]

thank you professor

[@claressalatia]

Hello Professor Dave. At 2:54, how would i know that x cannot be equal to 1 if it shows only the simplified function?

[@BankBlitz818]

Then you won't have to worry about it. :)

[@anishpalabatla4543]

The function is (x^2-1)/(x-1) by default hence, 1 is a point of discontinuity. But, if the function is x-1, there is no restricted domain, i.e x€R. Hope this helps you :)

[@heydrianluisanilao1757]

Then x + 1 is the only thing you have to be concerned about

[@cometolearn8598]

because if x is equal to 1 then we get x^2 - 1/1-1 which here 1-1 makes the denominator = to 0 meaning the function will become undefined and the function would be discontinuous Hope this helped :)

[@isabellawilliams52]

super helpful!

[@christinejoyceballos2076]

OMG THANK YOU SO MUCH GOD BLESS YOU

[@pripsshorts0516]

Can someone please explain me the example of piecewise function..i didn't get how the coordinates (-2,5) and (-2,-3)were found .

[@vodiact]

do you still need help

[@Butterfly-bs7jp]

@@vodiact please explainnn 🥺

[@vodiact]

@@Butterfly-bs7jp actually i have no idea now

[@AhmadNour]

very helpful ♥

[@pranavsblog9782]

Your a great teacher amazing exmalantion

[@charblaze1231]

Thanks

[@ankitasaxena9724]

Very helpful

[@deloriadaniellemariea8184]

Thank you!!

[@sarathkumar4504]

Sir can u give me any application of discontinuity in science

[@timothymcglynn1935]

Thanks 👍

[@tGoldenPhoenix]

Done this lesson.

[@mustafasaber5076]

Continuous Piecewise Discontinuous

[@Nishantmakadiya]

I am literally Speed running mathamatics🏃💨

[@miguelcielos9442]

Bro's locking in

[@sue4552]

do you understand how the thing became -3?

[@heinhengjohnwu5998]

Thank you Math Jesus

[@nurain2843]

Do u have any video that teach about limit n continuous...

[@SamuelCarlton_]

Life saver

[@medotedo8410]

so most rational functions are discontinuous functions

[@alexandroskourtis5268]

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[@jonykhan4395]

Good explanation. If a function is discontinuous then why we call it A FUNCTION ANYMORE? it is in the definition of a function that its all domain members MUST have unique image But one of the domain members does not have value then Why call it a function?? If the function is producing Irrational numbers then is it a continuous or discontinuous? if a function outputs Infinity it will be a continuous or discontinuous? if a function outputs a non-terminating value it will be a continuous or discontinuous? if a function outputs indeterminate forms type values is it a continuers or discontinuous?

[@dextermiguel21]

Professor Jesus Explains

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Thank You Calculus Jesus

[@serbrad6426]

worst math crack

[@basketguitar9768]

Math is like crack

[@christophersanders6871]

I'm literally gonna puke

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Thank you papa jesus

[@ARK4N]

first

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❤❤

[@clarag.5337]

If we are clever....

[@manuelsantos7075]

Jesus christ

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you are Jesus christ

[@sameedansar3552]

Thank you🌟